Laws of Limits: Theorems and Proofs

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to Lesson

Podcast

Play an AI-generated podcast conversation about this lesson

Questions and Answers

According to Theorem 1.1, for any real number $c$, the limit of $x$ as $x$ approaches $c$ is equal to $x$.

False (B)

Theorem 1.2 states that for any constant $m$ and real number $c$, $lim_{x \to c} m = m$.

True (A)

If $lim_{x \to c} f(x) = L$ and $k$ is any constant, then $lim_{x \to c} [k + f(x)] = k + L$.

False (B)

If both $lim_{x \to c} f(x)$ and $lim_{x \to c} g(x)$ exist, then $lim_{x \to c} [f(x) + g(x)] = lim_{x \to c} f(x) + lim_{x \to c} g(x)$.

<p>True (A)</p> Signup and view all the answers

If $lim_{x \to c} f(x)$ and $lim_{x \to c} g(x)$ both exist, then $lim_{x \to c} [f(x)g(x)] = [lim_{x \to c} f(x)][lim_{x \to c} g(x)]$.

<p>True (A)</p> Signup and view all the answers

For any functions $f(x)$ and $g(x)$, $lim_{x \to c} [f(x) / g(x)] = [lim_{x \to c} f(x)] / [lim_{x \to c} g(x)]$ always holds true, regardless of the limit of $g(x)$.

<p>False (B)</p> Signup and view all the answers

If $lim_{x \to c} f(x)$ exists, then $lim_{x \to c} [5f(x)] = 5 lim_{x \to c} f(x)$ according to the scalar multiple rule.

<p>True (A)</p> Signup and view all the answers

The proof of Theorem 1.1, which states $lim_{x \to c} x = c$, involves setting $\delta = \epsilon^2$ to show that $|x - c| < \epsilon$ whenever $0 < |x - c| < \delta$.

<p>False (B)</p> Signup and view all the answers

The proof of Theorem 1.2, which addresses the limit of a constant function, uses $\delta = \epsilon$ to show that $|f(x) - k| < \epsilon$ whenever $0 < |x - c| < \delta$.

<p>True (A)</p> Signup and view all the answers

Flashcards

Limit of x as x approaches c

For any real number c, the limit as x approaches c of x equals c.

Limit of a Constant

For any constant k and real number c, the limit as x approaches c of k equals k.

Limit of a Constant Times a Function

The limit of a constant times a function is the constant times the limit of the function.

Limit of a Sum or Difference

The limit of a sum (or difference) is the sum (or difference) of the limits.

Signup and view all the flashcards

Limit of a Product

The limit of a product is the product of the limits.

Signup and view all the flashcards

Limit of a Quotient

The limit of a quotient is the quotient of the limits, provided the limit of the denominator is not zero.

Signup and view all the flashcards

Study Notes

  • Laws of limits are mathematical concepts describing function behavior as input values approach a certain value.
  • These laws are foundational to calculus, aiding in the understanding and analysis of functions.

Theorem 1.1

  • States for any real number 𝑐, the limit as x approaches 𝑐 of x is equal to 𝑐.
  • Proof: For any 𝜀 > 0, if 𝛿 = 𝜀, then whenever 0 < |𝑥 − 𝑐| < 𝛿, |𝑥 − 𝑐| < 𝜀.

Theorem 1.2

  • States for any constant 𝑘 and real number 𝑐, the limit as x approaches 𝑐 of 𝑘 is equal to 𝑘.
  • Proof: Let 𝑓(𝑥) = 𝑘 and 𝜀 > 0, then |𝑓(𝑥) − 𝑘| = |𝑘 − 𝑘| = 0, take 𝛿 to be any positive number, say 𝛿 = 𝜀. Therefore if 0 < |𝑥 − 𝑐| < 𝛿, then |𝑓(𝑥) − 𝑘| = 0 < 𝜀.

Theorem 1.3

  • States if lim (x→𝑐) 𝑓(𝑥) and lim (x→𝑐) 𝑔(𝑥) both exist, and 𝑘 is any constant, the following rules apply:
  • lim (x→𝑐) [𝑘 𝑓(𝑥)] = 𝑘 lim (x→𝑐) 𝑓(𝑥)
  • lim (x→𝑐) [𝑓(𝑥) ± 𝑔(𝑥)] = lim (x→𝑐) 𝑓(𝑥) ± lim (x→𝑐) 𝑔(𝑥)
  • lim (x→𝑐) [𝑓(𝑥)𝑔(𝑥)] = [lim (x→𝑐) 𝑓(𝑥)][lim (x→𝑐) 𝑔(𝑥)]
  • lim (x→𝑐) [𝑓(𝑥) / 𝑔(𝑥)] = [lim (x→𝑐) 𝑓(𝑥)] / [lim (x→𝑐) 𝑔(𝑥)], if lim (x→𝑐) 𝑔(𝑥) ≠ 0
  • Proof (i): Given lim (x→𝑐) 𝑓(𝑥) = 𝐿1, for any 𝜀1 > 0, there exists a 𝛿1 > 0 for which |𝑓(𝑥) − 𝐿1| < 𝜀1 whenever |𝑥 − 𝑐| < 𝛿1.

Studying That Suits You

Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

Quiz Team

More Like This

Limits Theorems Part 1
10 questions
MATH 102 Calculus 1: Evaluating Limits
42 questions
Use Quizgecko on...
Browser
Browser