Ionic Equilibria of Weak Acids and Bases
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Questions and Answers

What is the oxidation product of the oxidation of iodide ion (I-) by permanganate ion (MnO4-) in basic solution?

  • Permanganate ion (MnO4-)
  • Molecular iodine (I2) (correct)
  • Manganese (IV) oxide (MnO2)
  • Iodide ion (I-)

    • What is the reducing agent in the oxidation of iodide ion (I-) by permanganate ion (MnO4-) in basic solution?

  • Manganese (IV) oxide (MnO2)
  • Water (H2O)
  • Iodide ion (I-) (correct)
  • Permanganate ion (MnO4-)

    • What is the oxidation number of manganese in the oxidation of iodide ion (I-) by permanganate ion (MnO4-) in basic solution?

  • +7
  • +1
  • +4 (correct)
  • +2

    • What is the oxidation number of iodine in the oxidation of iodide ion (I-) by permanganate ion (MnO4-) in basic solution?

    <p>-1</p> Signup and view all the answers

    What is the purpose of adding two H2O molecules to the right-hand side of the reduction half-reaction?

    <p>To balance the O atoms</p> Signup and view all the answers

    What is the purpose of adding four H+ ions to the left-hand side of the reduction half-reaction?

    <p>To balance the H atoms</p> Signup and view all the answers

    What is the purpose of adding three electrons to the left-hand side of the reduction half-reaction?

    <p>To balance the charges</p> Signup and view all the answers

    What is the overall reaction obtained by adding the oxidation and reduction half-reactions?

    <p>4 MnO4- + I- → MnO2 + I2</p> Signup and view all the answers

    What is the oxidation half-reaction in the oxidation of iodide ion (I-) by permanganate ion (MnO4-) in basic solution?

    <p>2I- → I2 + 2e-</p> Signup and view all the answers

    What is the reduction half-reaction in the oxidation of iodide ion (I-) by permanganate ion (MnO4-) in basic solution?

    <p>MnO4- + 4 H+ + 3e- → MnO2 + 2 H2O</p> Signup and view all the answers

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