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Henry Cavendish's Gravitational Constant Experiment
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Henry Cavendish's Gravitational Constant Experiment

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Questions and Answers

What is the relationship between the period of oscillation of a pendulum and the gravitational acceleration?

  • Directly proportional
  • Inversely proportional to the square root (correct)
  • Inversely proportional
  • Directly proportional to the square
  • What is the purpose of using the same pendulum at two locations?

  • To measure the length of the pendulum
  • To estimate the variation in gravitational acceleration at two locations (correct)
  • To measure the gravitational acceleration at one location
  • To calculate the constant of proportionality, k
  • What does the constant k describe in a spring system?

  • The mass of the object hung on the spring
  • The gravitational acceleration
  • The distribution of mass about the pivot point
  • The stiffness of the spring (correct)
  • What is the proportionality between the stretch of the spring and the gravitational acceleration?

    <p>Directly proportional to the magnitude of the mass</p> Signup and view all the answers

    What is the accuracy required to achieve a precision of 0.001 mgal?

    <p>0.001 ∆ x and x of about 980 cm</p> Signup and view all the answers

    What is the purpose of instruments such as the LaCoste and Romberg gravimeter?

    <p>To measure changes in the Earth's gravitational acceleration</p> Signup and view all the answers

    What is the precision of modern gravimeters?

    <p>1 part in 1000 million</p> Signup and view all the answers

    What is the relationship between the gravitational acceleration and the stretch of the spring?

    <p>The stretch of the spring is directly proportional to the gravitational acceleration</p> Signup and view all the answers

    What is the unit of measurement for the precision of modern gravimeters?

    <p>Milligal</p> Signup and view all the answers

    What is the purpose of the beam Instruments of this type?

    <p>To measure changes in the Earth's gravitational acceleration</p> Signup and view all the answers

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