Group Theory: Cocycles and Extensions

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Questions and Answers

A parallelogram PQRS has QM as the height from Q to SR and QN as the height from Q to PS. SR = 12 cm and QM = 7.6 cm. If QN = 8 cm, what is the length of PS?

  • 9.8 cm
  • 10.2 cm
  • 11.4 cm (correct)
  • 10.8 cm

If the area of a parallelogram is 1470 $cm^2$, and one of its sides (AB) is 35 cm and another side (AD) is 49 cm, what are the lengths of the heights DL and BM respectively on sides AD and AB?

  • DL = 42 cm, BM = 30 cm
  • DL = 30 cm, BM = 42 cm (correct)
  • DL = 35 cm, BM = 49 cm
  • DL = 49 cm, BM = 35 cm

In right-angled triangle ABC, right-angled at A, AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm, and AC = 12 cm, what is the length of AD?

  • 6.15 cm
  • 7.03 cm
  • 5.54 cm
  • 4.62 cm (correct)

Triangle ABC is isosceles, with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC is 6 cm. What will be the height from C to AB (i.e., CE)?

<p>4.8 cm (A)</p> Signup and view all the answers

A circle of radius 2 cm is cut out from a square piece of an aluminium sheet of side 6 cm. What is the area of the aluminum sheet that is left over, rounding $\pi$ to 3.14?

<p>23.36 $cm^2$ (D)</p> Signup and view all the answers

The circumference of a circle is 31.4 cm. Determine the radius of the circle, rounding $\pi$ to 3.14.

<p>5 cm (A)</p> Signup and view all the answers

A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of the path, using $\pi = 3.14$?

<p>942.04 $m^2$ (C)</p> Signup and view all the answers

A circular flower garden has an area of 314 $m^2$. A sprinkler at the center of the garden can cover an area that has a radius of 12 m. Will the sprinkler water the entire garden, using $\pi = 3.14$?

<p>Sprinkler covers the entire garden because the garden's radius is approximately 10 m. (C)</p> Signup and view all the answers

How many times must a wheel of radius 28 cm rotate to go 352 m, using $\pi = \frac{22}{7}$?

<p>200 times (D)</p> Signup and view all the answers

The minute hand of a circular clock is 15 cm long. How far does the tip of the minute hand move in 1 hour, using $\pi = 3.14$?

<p>94.2 cm (A)</p> Signup and view all the answers

Flashcards

Area of a Parallelogram

Area of parallelogram is calculated by multiplying its base by its height.

Area of a Triangle

Area of a triangle is half the product of its base and height.

Circumference

The distance around the circular region.

π (Pi)

The ratio of circumference to diameter.

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Circumference of a Circle

Circumference is calculated by π times the diameter.

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Area of a Circle

Area of a circle is calculated by π times the square of the radius

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Study Notes

Cocycles

  • For group G and abelian group A, a 2-cocycle is map α: G × G -> A
  • 2-Cocycle condition is α(x, y) + α(x y, z) = α(x, y z) + α(y, z) ∀ x, y, z ∈ G
  • Z^2(G, A) denotes the set of 2-cocycles.
  • A 1-cochain is a map β: G -> A.
  • δ: (1-cochains) -> (2-cochains) is defined by δ β(x, y) = β(x) - β(x y) + β(y).
  • δ β is a 2-cocycle.
  • B^2(G, A) denotes 2-cocycles of the form δ β for some 1-cochain β.
  • The second cohomology group is H^2(G, A) = Z^2(G, A) / B^2(G, A).
  • Similar definitions exist for Z^n(G, A), B^n(G, A), and H^n(G, A).

Group Extensions

  • An extension of G by A is a group E where 1 -> A -> E -> G -> 1 is a short exact sequence.
  • A -> E is represented by a -> ā, and E -> G as x ->underline{x}
  • This implies underline{ā} = 1, and every element of G has the form underline{x} for some x ∈ E.
  • A section s: G -> E is a map where underline{s(x)} = x ∀ x ∈ G.
  • e: G × G -> A is defined by s(x) s(y) = ē(x, y) s(x y).
  • e(x, y) determines the multiplication in E.
  • e ∈ Z^2(G, A).
  • Evaluating s(x) s(y) s(z) in two ways yields e(x, y) + e(x y, z) = e(x, y z) + e(y, z).
  • E1 and E2 are equivalent extensions of G by A if ψ: E1 -> E2 exists, making a diagram commute.
  • If E1 and E2 are equivalent extensions, cocycles e1, e2 differ by a coboundary.
  • There is a 1-1 correspondence between equivalence classes of extensions of G by A and H^2(G, A).

Schur Multiplier

  • Schur Multiplier of G is H2(G, Z).
  • H2(G, Z) is the second homology group of G with coefficients in Z.
  • For a free presentation 1 -> R -> F -> G -> 1, H2(G, Z) ≅ (R ∩[F, F])/[R, F].
  • Additionally, H2(G, Z) ≅ H^2(G, C*), where C* is the multiplicative group of nonzero complex numbers.

Caching

  • Caching stores data in local, fast memory for later use, with RAM as a cache for disk, and L1 cache for L2 data.
  • Caching leverages temporal locality (accessing data again soon) and spatial locality (accessing nearby data soon).
  • Key questions in caching: placement (where to put new data), identification (how to find data), replacement (what data to remove), and write policy (how to handle writes).

Simple Cache

  • A small cache with 8 slots, each holding one word (4 bytes), where the address space is 64 words (256 bytes), needs 6 bits to address.
  • 6 bits are divided into 3 bits for the index and 3 bits for the tag.
  • Each cache slot has a valid bit (1 if data, 0 if empty).
  • To read, with the example word 22 (binary 010110), cache index is 110 (6), and tag is 010 (2).
    • First go to set 6, check if the valid bit is 1 and tag is 2 for a hit, or miss.

Cache Organization

  • Direct-mapped cache has each address mapping to one slot.
  • Cache size = C, block size = B, number of sets = S, then direct-mapped has S = C/B.
  • N-way set-associative cache has S = C/(N*B).
  • Fully-associative cache has S = C/B.

Cache Replacement policies

  • Direct-mapped cache replacement is trivial.
  • N-way set-associative cache replacement policies include:
    • Least Recently Used (LRU): replaces least recently used data.
    • First-In, First-Out (FIFO): replaces the oldest data.
    • Random: replaces a random piece of data.
  • LRU is most common but expensive, FIFO is simpler but performs worse, and random is simplest and performs well.

Cache Write Policy

  • Write-Through writes to both cache and main memory simultaneously, is simple but slow.
  • Write-Back writes only to the cache, marks the line as dirty, and writes to main memory on eviction, is faster but complex.
  • Handling write misses:
    • Write-Allocate allocates a cache line and writes there.
    • Write-No-Allocate writes directly to main memory, is simpler but slower.
  • Write-allocate is common, and write-no-allocate is simpler

Real Numbers

  • The axiom of addition includes closure, associativity, commutativity, and the identity and inverse properties
  • Multiplication axioms include closure, associativity, commutativity, identity, and inverse existence for nonzero elements
  • Distributive axiom states a ⋅ (b + c) = a ⋅ b + a ⋅ c.

Axioms of Order

  • There exists a set P of positive real numbers.
  • The trichotomy law: for any real number a, either a is in P, a = 0, or -a is in P, exclusively.
  • Closure axioms specify if a, b ∈ P, then a + b ∈ P and a ⋅ b ∈ P

Definitions

  • a > b if and only if a - b ∈ P.
  • a < b if and only if: b > a.
  • a ≥ b if and only if a > b or a = b.
  • a ≤ b if and only if a < b or a = b.

Theorems

  • a > b implies a + c > b + c.
  • a > b and c > 0, then ac > bc.
  • a > b and c < 0, then ac < bc.
  • If a > b, then -b > -a.
  • If a ≠ 0, then a² > 0.
  • The number 1 is greater than 0 (1 > 0).
  • If a > 0, then 1/a > 0.
  • For positive a and b, if a > b, then 1/a < 1/b.

Partial Differential Equations

  • PDEs are differential equations (DE) with multiple independent variables
  • For u = f(x,y,z,t), a PDE might be A ∂u/∂x + B ∂u/∂y + C ∂u/∂z + D ∂u/∂t = 0
  • Contrast with ODEs, such as du/dt = -ku
  • PDEs are generally more difficult to solve than ODEs.
  • Focus is on linear, 2nd order PDEs common in physics.
  • u_x ≡ ∂u/∂x, u_{xx} ≡ ∂²u/∂x², u_{xy} ≡ ∂²u/∂x∂y

Wave equation

  • u_{tt} = c² u_{xx}, with constant speed c
  • Describes wave motions, such as vibrations of a string, sound, and light waves

Diffusion Equation

  • u_t = k u_{xx}
  • Describes diffusion, such as a chemical in a liquid

Laplace's Equation

  • u_{xx} + u_{yy} = 0
  • Describes steady-state potential in a region with no charge, or steady-state temperature distribution

Solving PDEs

  • There is no universal method for solving all PDEs
  • The solution depends on the equation and boundary conditions
  • Solution methods:
    • Separation of variables
    • Fourier transforms
    • Numerical methods

Boundary conditions

  • PDEs require these for unique solutions, specifying the solution's value at the domain's boundary
  • Dirichlet boundary condition: u = f(x) on the boundary
  • Neumann boundary condition: ∂u/∂n = g(x) on the boundary, where n is the normal vector. For example, the 1D heat equation may have u(0,t) = 0 and u(L,t) = 0.

Wave equation example

  • String of length L with fixed ends, displacement u(x,t)
  • The wave equation is u_{tt} = c² u_{xx}
  • Boundary conditions: u(0,t) = u(L,t) = 0 for all t
  • Initial conditions: u(x,0) = f(x) and u_t(x,0) = g(x)
  • This can be solved using separation of variables

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