Geometry Class: Triangles and Area Calculations

Questions and Answers

2°, 2°, 176° (correct)

11.9°, 19.1°, 149°

55°, 55°, 71°

58°, 63°, 59°

A = (6 cm)(4 cm)

A = \frac{1}{2}(6 cm)(4 cm) (correct)

A = (6 cm)(5 cm)

A = \frac{1}{2}(6 cm)(5 cm)

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Study Notes

The sum of angle measures in a triangle is always 180°.
Set of measures that cannot form a triangle: 2°, 2°, 176° (sum = 180° but two angles are too small).

Triangle area can be found with the formula: ( A = \frac{1}{2} \times \text{base} \times \text{height} ).
For a triangular tile with a base of 6 cm and height of 4 cm, the correct equation: ( A = \frac{1}{2}(6 , \text{cm})(4 , \text{cm}) ).

The area is calculated as ( \text{Base} \times \text{Height} ).
Given dimensions for a parallelogram: base = 7 in, height = 5 in, area = 35 in².

The area of a trapezoid formula: ( A = \frac{1}{2} \times (b_1 + b_2) \times h ).
For a trapezoidal concrete base with bases of 7 ft and 5 ft and height of 2 ft, area calculation yields 26 ft².

Volume of solids varies based on shape and dimensions.
Understanding which solid has the greatest volume requires calculation based on provided dimensions.