Geometry Class: Triangles and Area Calculations
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Questions and Answers

Which set of measures CANNOT be angle measures of a triangle?

  • 2°, 2°, 176° (correct)
  • 11.9°, 19.1°, 149°
  • 55°, 55°, 71°
  • 58°, 63°, 59°
  • Which equation can be used to calculate the area of the triangular tile?

  • A = (6 cm)(4 cm)
  • A = \frac{1}{2}(6 cm)(4 cm) (correct)
  • A = (6 cm)(5 cm)
  • A = \frac{1}{2}(6 cm)(5 cm)
  • What is the area of the parallelogram in square inches?

    35

    What is the area of the concrete base proposed by the planning committee in square feet?

    <p>26</p> Signup and view all the answers

    Which solid has the greatest volume?

    <p>1 in.³</p> Signup and view all the answers

    Study Notes

    Triangle Angle Measures

    • The sum of angle measures in a triangle is always 180°.
    • Set of measures that cannot form a triangle: 2°, 2°, 176° (sum = 180° but two angles are too small).

    Area of a Triangle

    • Triangle area can be found with the formula: ( A = \frac{1}{2} \times \text{base} \times \text{height} ).
    • For a triangular tile with a base of 6 cm and height of 4 cm, the correct equation: ( A = \frac{1}{2}(6 , \text{cm})(4 , \text{cm}) ).

    Area of a Parallelogram

    • The area is calculated as ( \text{Base} \times \text{Height} ).
    • Given dimensions for a parallelogram: base = 7 in, height = 5 in, area = 35 in².

    Isosceles Trapezoid Area

    • The area of a trapezoid formula: ( A = \frac{1}{2} \times (b_1 + b_2) \times h ).
    • For a trapezoidal concrete base with bases of 7 ft and 5 ft and height of 2 ft, area calculation yields 26 ft².

    Comparison of Geometric Solids

    • Volume of solids varies based on shape and dimensions.
    • Understanding which solid has the greatest volume requires calculation based on provided dimensions.

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    Description

    Test your understanding of triangle angle measures and area calculations for various geometric shapes, including triangles, parallelograms, and trapezoids. This quiz will challenge your knowledge on the formulas and properties associated with these shapes.

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