Gauss’ Law and Electric Fields
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Questions and Answers

What is the direction of the electric field for a dipole?

  • Points radially outward
  • Starts from the negative charge and ends at the positive charge
  • Points radially inward
  • Starts from the positive charge and ends at the negative charge (correct)
  • In Gauss' law for electric fields, what is the relationship between electric field strength and the number of field lines passing through a unit area?

  • They are inversely proportional
  • They are directly proportional (correct)
  • There is no relationship between them
  • They are related by a square root function
  • For a charged solid conducting sphere, what is the expression for the total flux through the spherical surface?

  • $\Delta s \sum_{i=0} E_i \Delta s_i$
  • $k \times q \sum_{i=0} E_i \Delta s_i r^2$ (correct)
  • $4 \pi r^2$
  • $k \times q \sum \Delta s$
  • What is the direction of the electric field at every point on the surface of a sphere with a charge located at its center?

    <p>Normal to the surface and points outward</p> Signup and view all the answers

    What is the formula for electric flux according to Gauss' law?

    <p>$\phi_E = k \times q \sum_{i=0} E_i \cdot \Delta s_i$</p> Signup and view all the answers

    Which statement about electric field lines is true?

    <p>Field lines indicate the direction of electric field at any point</p> Signup and view all the answers

    What does Gauss' law relate to in the context of electric fields?

    <p>The divergence of an electric field</p> Signup and view all the answers

    For a conducting shell, where is the charge distributed?

    <p>Uniformly on the outer surface</p> Signup and view all the answers

    What is the magnitude of the electric field at every point on a conducting shell?

    <p>$0$</p> Signup and view all the answers

    According to Gauss' law, how does the total flux through a closed surface relate to the charge enclosed within that surface?

    <p>The total flux is directly proportional to the charge enclosed.</p> Signup and view all the answers

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