FET Fixed Bias Configuration

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Questions and Answers

Why is the relationship between input and output quantities in an FET considered nonlinear?

  • Due to the inverse relationship between drain current and gate-source voltage.
  • Since the gate current is exponentially related to the gate-source voltage.
  • Because it involves the squared term in Shockley's equation. (correct)
  • As a result of the transistor's saturation region.

What is the primary difference in the input controlling variable between a BJT transistor and an FET?

  • A BJT is controlled by power, while an FET is controlled by impedance.
  • A BJT is controlled by resistance, while an FET is controlled by capacitance.
  • A BJT is controlled by voltage, while an FET is controlled by current.
  • A BJT is controlled by current, while an FET is controlled by voltage. (correct)

In a fixed-bias configuration for an n-channel JFET, what determines the gate-source voltage ($V_{GS}$)?

  • The fixed DC supply voltage ($V_{GG}$). (correct)
  • The internal resistance of the JFET channel.
  • The value of the drain resistor ($R_D$).
  • The magnitude of the drain current ($I_D$).

In a fixed-bias configuration, if the dc supply voltage ($V_{GG}$) is -5V, what is the gate-source voltage ($V_{GS}$)?

<p>$V_{GS}$ = -5V (C)</p> Signup and view all the answers

In the dc analysis of a JFET fixed-bias configuration, how is the gate resistor ($R_G$) treated?

<p>It is replaced by a short circuit. (D)</p> Signup and view all the answers

What is the implication of $V_{GS}$ being a fixed quantity in a fixed-bias configuration?

<p>It means the magnitude and sign of $V_{GS}$ can be directly substituted into Shockley's equation to find $I_D$. (C)</p> Signup and view all the answers

What is one advantage of the self-bias configuration compared to the fixed-bias configuration?

<p>It requires only one DC supply. (A)</p> Signup and view all the answers

In a JFET self-bias configuration, how is the gate-to-source voltage ($V_{GS}$) determined?

<p>It is determined by the voltage across a resistor ($R_S$) introduced in the source leg. (A)</p> Signup and view all the answers

In a self-bias configuration, what is the relationship between $V_{GS}$, $I_D$, and $R_S$?

<p>$V_{GS} = -I_D R_S$ (C)</p> Signup and view all the answers

Why is it necessary to identify two points on a graph when obtaining a mathematical solution for a self-biased JFET?

<p>To draw a straight line representing the bias condition and find the Q-point. (B)</p> Signup and view all the answers

What does the 'Q-point' represent in the context of FET biasing?

<p>The quiescent or operating point of the FET. (C)</p> Signup and view all the answers

In a self-bias configuration, if $I_D$ = 0A, what is the value of $V_{GS}$?

<p>$V_{GS}$ = 0V (D)</p> Signup and view all the answers

What is the primary advantage of using a voltage-divider bias configuration in FET amplifiers?

<p>It provides a stable gate voltage independent of device variations. (D)</p> Signup and view all the answers

In a voltage-divider bias configuration, how is the gate voltage ($V_G$) typically determined?

<p>Using the voltage-divider rule on the gate resistors. (D)</p> Signup and view all the answers

In a voltage-divider biased JFET, if $V_G$ = 3V and $I_D R_S$ = 2V, what is the value of $V_{GS}$?

<p>1V (A)</p> Signup and view all the answers

For a voltage-divider configuration, what happens to the Q-point as the value of $R_S$ increases?

<p>The Q-point shifts towards lower $I_D$ values. (B)</p> Signup and view all the answers

What is the primary characteristic of a depletion-type MOSFET that distinguishes it from an enhancement-type MOSFET?

<p>Depletion-type MOSFETs can operate with both positive and negative gate voltages. (B)</p> Signup and view all the answers

In an n-channel depletion-type MOSFET, what happens when a positive gate voltage is applied?

<p>The channel is enhanced, allowing more current flow. (A)</p> Signup and view all the answers

In a zero-biased depletion-type MOSFET, what determines the drain current ($I_D$)?

<p>$I_D = I_{DSS}$ because $V_{GS} = 0$ (D)</p> Signup and view all the answers

For an n-channel enhancement-type MOSFET, what is the state of the drain current when the gate-to-source voltage ($V_{GS}$) is less than the threshold voltage ($V_{GS(Th)}$)?

<p>The drain current is zero (A)</p> Signup and view all the answers

In an enhancement-type MOSFET, what equation defines the drain current ($I_D$) when $V_{GS}$ is greater than $V_{GS(Th)}$?

<p>$I_D = k(V_{GS} - V_{GS(Th)})^2$ (B)</p> Signup and view all the answers

Why is a large resistor ($R_G$) used in the feedback biasing arrangement for enhancement-type MOSFETs?

<p>To provide a suitably large voltage to the gate to drive the MOSFET 'ON'. (C)</p> Signup and view all the answers

In the feedback biasing arrangement for enhancement-type MOSFETs, assuming $I_G$ = 0mA, how are $V_{DS}$ and $V_{GS}$ related?

<p>$V_{DS} = V_{GS}$ (A)</p> Signup and view all the answers

For an enhancement-type MOSFET with feedback biasing, if the supply voltage $V_{DD}$ is 15V, what is the maximum possible value of $V_{GS}$?

<p>15V (C)</p> Signup and view all the answers

What is the first step in analyzing a combination network with both JFET and MOSFET transistors?

<p>Analyze the JFET portion of the circuit first. (C)</p> Signup and view all the answers

What role does the bypass capacitor play in the design of FET amplifiers?

<p>It provides an AC ground while maintaining a DC bias. (D)</p> Signup and view all the answers

Which of the following parameters is most critical when designing a stable FET amplifier at high frequencies?

<p>Miller capacitance (A)</p> Signup and view all the answers

How can thermal runaway be prevented in a BJT amplifier?

<p>By using a heat sink (C)</p> Signup and view all the answers

What is the main advantage of using a current mirror in biasing a differential amplifier?

<p>It provides a constant bias current regardless of temperature variations (D)</p> Signup and view all the answers

In what scenario would a JFET source follower configuration be preferred over a common-source amplifier?

<p>When impedance matching is necessary (D)</p> Signup and view all the answers

Which biasing technique is generally considered the most stable against variations in transistor parameters and temperature?

<p>Voltage-divider bias (D)</p> Signup and view all the answers

How do changes in $V_{DD}$ affect the bias point in a MOSFET circuit?

<p>It can change the operating region of the transistor (D)</p> Signup and view all the answers

What is the purpose of swamping resistors in differential amplifiers?

<p>To stabilize the bias current and reduce distortion (A)</p> Signup and view all the answers

What effect does increasing the channel length of a MOSFET have on its drain current, assuming all other parameters remain constant?

<p>Decreases the drain current (B)</p> Signup and view all the answers

In a common-source amplifier, what is the typical phase relationship between the input and output signals?

<p>180 degrees out of phase (C)</p> Signup and view all the answers

What parameter is most enhanced when using a cascode configuration in an amplifier?

<p>Bandwidth and stability (D)</p> Signup and view all the answers

Flashcards

FET Nonlinearity

Due to the squared term in Shockley's Equation, the FET's relationship between input and output quantities is nonlinear.

BJT vs FET Control Variable

The input controlling variable for a BJT transistor is current, while for a FET it is voltage.

FET Amplifier Relationships

In FET amplifiers, the gate current (IG) is approximately zero, and the drain current (ID) equals the source current (IS).

Fixed-Bias Configuration

A simple biasing arrangement for n-channel JFETs, solvable mathematically or graphically.

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VGS in Fixed-Bias

In a fixed-bias configuration, the gate-source voltage (VGS) is equal to the negative of the gate supply voltage (VGG).

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ID Control in Fixed-Bias

In a fixed-bias configuration, the drain current (ID) is controlled by Shockley's equation, based on the fixed VGS.

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Purpose of RG in FET circuits

Ensures that V; appears at the input to the FET amplifier for the AC amplifier, for DC analysis, think short-circuit equivalent

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Calculating VDS

The drain-to-source voltage (VDS) is calculated by subtracting the voltage drop across the drain resistor (RD) from the drain supply voltage (VDD).

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Self-Bias Configuration

A biasing method with one DC supply where gate-to-source voltage is determined by a source resistor.

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Self Bias Equation

With Self Bias, the Gate-Source voltage is equal to: VGS = -IDRS

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Voltage-Divider Biasing

A biasing method where the gate voltage is obtained using a voltage divider network.

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Voltage-Divider Bias Equation

With Voltage-Divider Bias, the Gate-Source voltage is equal to: VGS = VG - IDRS

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Using Voltage-Divider Bias to find Drain Source Voltage

The equation for the Drain-Source voltage using voltage-divider biasing: VDS = VDD – ID(RD + RS)

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Depletion-Type MOSFET

Depletion Enhancement MOSFETs are Field Effect Transistors that can operate in both depletion and enhancement modes.

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Enhancement-Type MOSFET

Enhancement-type MOSFETs require a gate-source voltage greater than the threshold voltage to create a channel for current flow.

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Enhancement-Type Calculating Drain Current

In enhancement-type MOSFET the equation for drain current is: Ip = k(VGs - VGS(Th))2

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Feedback Biasing

A biasing arrangement for enhancement-type MOSFETs that uses a resistor from the drain to gate to drive the MOSFET 'ON'. With Feedback Biasing

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Determining VD with Feedback Biasing

Uses resistor RG to bring a suitably large voltage to the gate to drive the MOSFET 'ON'

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Study Notes

  • FET biasing involves nonlinear relationships between input and output due to the squared term in Shockley's Equation.
  • Nonlinear functions yield curves, unlike linear relationships.
  • The nonlinear relationship between drain current (ID) and gate-source voltage (VGS) makes DC analysis complex.
  • The input controlling variable for a BJT transistor is current, while for an FET it is voltage.
  • Relationships applicable to DC analysis of FET amplifiers:

DC Analysis

  • IG = 0 A
  • ID = IS
  • Applies to JFETs, depletion-type MOSFETs, and MESFETs:
    • ID = IDSS (1 - VGS/VP)^2
  • Applies to enhancement-type MOSFETs and MESFETs:
    • ID = k(VGS - VT)^2
  • Fixed Bias Configuration is one of the simplest biasing arrangements for n-channel JFETs.
  • It can be solved directly using math or a graph.

Fixed Bias Configuration

  • Includes AC levels Vi and Vo, and uses coupling capacitors (C1 and C2).
  • Coupling capacitors are open circuits for DC, and short circuits for AC analysis.
  • The resistor R_G ensures V_i appears at the input to the FET amplifier.
  • The zero drop across R_G means it is replaced by a short-circuit equivalent for DC analysis.
  • The negative terminal of the battery connected to VGS indicates opposite polarity to VGG.
  • Applying Kirchhoff's voltage law: -VGG - VGS = 0, therefore VGS = -VGG.
  • Since VGG is a fixed DC supply, VGS is fixed in magnitude, hence the name "fixed-bias".
  • The level of drain current ID is now controlled by Shockley's equation.
  • As VGS is fixed, magnitude is substituted into Shockley's equation to calculate ID.
  • Choosing VGS = VP/2 results in drain current of IDSS/4.
  • For analysis, three points (IDSS, VP, and the described intersection) are sufficient.
  • The fixed VGS level is superimposed as a vertical line at VGS = -VGG.
  • At any point on the vertical line, the level of VGS is – VGG and Ip must be determined.
  • The intersection of the two curves is the common solution/operating point.
  • Once the network is constructed and operating, DC levels of ID and VGS are the quiescent values.
  • Drain-to-source voltage can be determined by applying Kirchhoff's voltage law: VDS = VDD - IDRD.

Single Subscript Voltages

  • Single-subscript voltages refer to voltage at a point relative to ground.
  • For the configuration: Vs = 0V
  • Using double-subscript notation:
    • VDS = VD - VS
    • VD = VDS + VS = VDS + 0V, therefore VD = VDS
    • VGS = VG - VS
    • VG = VGS + VS = VGS + 0V, therefore VG = VGS

Self Bias Configuration

  • Self-bias eliminates the need for two DC supplies.
  • The controlling gate-to-source voltage is determined by the voltage across a resistor Rs.
  • For DC analysis, the capacitor is an open circuit, and RG is a short circuit equivalent since IG = 0 A.
  • The current through Rs is the source current ISS = ID and VRS = IDRS.
  • Applying Kirchhoff’s voltage in closed loop: -VGS - VRS = 0 so VGS = -VRS thus VGS = -IDRS.
  • Self Bias configuration voltage VGS is a function of the output current ID.
  • Mathematical solution obtained by substituting in Shockley's equation.
  • ID = IDSS[1 + (IDRS/VP)]^2, subsequently ID^2 + K1ID + K2 = 0
  • To identify two points on the graph, a straight-line can be drawn between the two points.
  • Applying Ip = 0 A results in VGs = -IDRS = (0 A)RS = 0 V.
  • To find two points in (7.10), one point on the straight-line is defined by Ip=0 A and VGs = 0 V.
  • Shockley's equation requires level of VGs or ID be chosen and the level of the other quantity determined with Eq. (7.10).
  • An example is choosing I_D level equal to half saturation level, which is ID = IDSS/2.
  • Thus $V_{GS}=-I_DR_S = \frac{-I_{DSS}R_S}{2}$
  • Straight line is then drawn and the quiescent point is obtained at the intersection.
  • Kirchhoff's voltage law will determine the level of $V_{DS}$ VR_S + V_DS + V_RD - V_DD = 0
    • Therefore $V_{DS} = V_{DD} - V_{RS} - V_{RD} = V_{DD} - I_SR_S - I_DR_D$

Voltage-Divider Bias

  • Applied to BJT transistor amplifiers, and also to FET amplifiers.
  • All capacitors, including bypass capacitor, are replaced by open circuit equivalents.
  • The source VDD is two equivalent sources.
  • A condition applies since IG = 0 A as K's current requires IR1 = IR2
  • Applying Kirchhoff's voltage law gives: VG - VGS - VRS = 0, and subsequently VGS = VG - VRS.
  • VGS = VG - IDRS

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