FET Amplifiers: An Overview

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Questions and Answers

Which of the following is a key advantage of field-effect transistor (FET) amplifiers?

  • Higher power consumption for similar voltage gain.
  • Lower input impedance compared to BJTs.
  • Excellent voltage gain combined with high input impedance. (correct)
  • Limited frequency range and larger size.

How does a JFET control its drain-to-source current?

  • By using a small input (base) current.
  • By varying the collector current.
  • By using a small input (gate-voltage) voltage. (correct)
  • By varying the gate-to-source resistance.

What is the term for the parameter that describes the relationship between the change in drain current and the change in gate-to-source voltage in a JFET?

  • Transconductance ($g_m$). (correct)
  • Input impedance ($Z_i$).
  • Amplification factor (β).
  • Output conductance ($g_{os}$).

In the context of a JFET small-signal model, what does the 'trans' prefix in 'transconductance' signify?

<p>It denotes a relationship between an output and an input quantity. (D)</p>
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The slope of the tangent line on the transfer characteristic curve of a JFET at a specific operating point represents:

<p>The transconductance ($g_m$) at that point. (D)</p>
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Given the equation $g_m = \frac{2I_{DSS}}{|V_P|} [1 - \frac{V_{GS}}{V_P}]$, under what condition is $g_m$ maximized?

<p>When $V_{GS}$ is equal to 0V. (C)</p>
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If a JFET has $I_{DSS} = 12 \text{ mA}$ and $V_P = -6 \text{ V}$, what is the maximum possible value of $g_m$ ($g_{m0}$)?

<p>4 mS (B)</p>
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For a commercially available JFET, what is a typical practical value for the input impedance?

<p>Approximately 10^9 Ω (D)</p>
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In a JFET AC equivalent circuit, if the output impedance ($Z_o$) is approximately equal to $R_D$, what can be inferred about the relationship between $r_d$ and $R_D$?

<p>$r_d$ is significantly larger than $R_D$. (D)</p>
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What does a negative voltage gain ($A_v$) in a JFET amplifier indicate?

<p>There is a phase shift of 180 degrees between the input and output signals. (B)</p>
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Flashcards

FET Amplifier Advantages

Field-effect transistor amplifiers provide excellent voltage gain with high input impedance and low-power consumption.

FET Device Control

Controls output (drain) current by means of a small input (gate-voltage).

JFET Current Control

The gate-to-source voltage controls the drain-to-source (channel) current of a JFET.

Prefix 'trans' Meaning

The prefix 'trans' indicates a relationship between an output and an input quantity.

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Transconductance (g m)

g m is determined by a current-to-voltage ratio, similar to the ratio that defines the conductance of a resistor.

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Derivative Definition

The derivative of a function at a point is equal to the slope of the tangent line.

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Maximum gm Condition

The maximum value of gm occurs when VGS = 0 V.

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JFET Input Impedance

The input impedance of all commercially available JFETs is sufficiently large to assume that the input terminals approximate an open circuit.

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Output Impedance Definition

The slope of the horizontal characteristic curve at the point of operation.

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Output Impedance (Zo)

rd || RD

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Study Notes

Introduction to FET Amplifiers

  • Field-effect transistor amplifiers provide excellent voltage gain and high input impedance.
  • They also offer low-power-consumption configurations with good frequency range, minimal size, and weight.
  • JFETs, depletion MOSFETs, and MESFETs can be used to design amplifiers with similar voltage gains.
  • Depletion MOSFET (MESFET) circuits have a much higher input impedance than similar JFET configurations.
  • BJT devices control a large output (collector) current with a relatively small input (base) current.
  • FET devices control an output (drain) current with a small input (gate-voltage) voltage.
  • BJTs are current-controlled devices, while FETs are voltage-controlled devices.
  • FETs have a high input characteristic, making their AC equivalent model simpler than that of BJTs.
  • BJTs have an amplification factor, β (beta), while FETs have a transconductance factor, gm.

JFET Small-Signal Model

  • The gate-to-source voltage controls the drain-to-source (channel) current of a JFET.
  • The change in drain current from a change in gate-to-source voltage can be determined using the transconductance factor gm.
  • The prefix "trans" in transconductance establishes a relationship between an output and an input quantity.
  • Conductance is used because gm is determined by a current-to-voltage ratio, similar to the ratio that defines the conductance of a resistor.

Mathematical Definition of Transconductance (gm)

  • The derivative of a function at a point equals the slope of the tangent line at that point.
  • The magnitude ensures a positive value for gm.
  • The slope of the transfer curve is at its maximum when VGS = 0 V.
  • The subscript 0 indicates that it is the value of gm when VGS = 0 V.

Example 1: Determining the Magnitude of gm

  • Determine the magnitude of gm for a JFET with IDSS = 8 mA and VP = -4 V at various DC bias points: VGS = -0.5 V, VGS = -1.5 V, VGS = -2.5 V.
  • gm is calculated at each VGS value using the change in drain current divided by the change in gate-source voltage.
  • gm values: At −0.5 V = 3.5 mS, At −1.5 V = 2.57 mS, At −2.5 V = 1.5 mS.
  • gm decreases as VGS approaches VP.

Example 2: Finding Maximum gm and Comparing with Graphical Results

  • Determine the maximum value of gm and the value of gm at each operating point from Example 1 using the formula and compare with graphical results.
  • Calculated maximum possible value of gm: 4 mS
  • Compared to original calculations at same voltages, the new values are; At VGS = -0.5 V = 3.5 mS. At VGS = -1.5 V = 2.5 mS. At VGS = -2.5 V = 1.5 mS.

Transconductance (gm) on Specification Sheets

  • On specification sheets, gm is often provided as gfs or yfs, where y indicates it's part of an admittance equivalent circuit.
  • The 'f' signifies forward transfer conductance, and 's' indicates connection to the source terminal.

General Properties of gm

  • The maximum value of gm occurs where VGS = 0 V, and the minimum value occurs at VGS = VP.
  • When VGS is one-half the pinch-off value, gm is one-half the maximum value.

Effect of ID on gm

  • The mathematical relationship between gm and the DC bias current ID is derived from Shockley's equation.
  • The highest values of gm are obtained when VGS approaches 0 V and ID approaches its maximum value of IDSS.
  • If ID = IDSS, gm = gm0
  • If ID = IDSS/2, gm = 0.707gm0
  • If ID = IDSS/4, gm = 0.5gm0

JFET Input Impedance (Zi)

  • The input impedance of commercially available JFETs is large enough to assume the input terminals approximate an open circuit.
  • ZI (JFET) = ∞ Ω
  • A practical value for a JFET is 10^9 Ω (1000 MΩ), while for MOSFETs and MESFETs, it's typically 10^12 Ω to 10^15 Ω.

JFET Output Impedance (Zo)

  • Zo (JFET) = rd = 1/gos = 1/yos
  • The output impedance of JFETs is similar in magnitude to that of conventional BJTs.
  • Output impedance typically appears as gos or yos, with units of µS.
  • The parameter yos is a component of an admittance equivalent circuit, with the subscript 'o' signifying an output network parameter and 's' indicating the terminal (source).
  • Output impedance is defined as the slope of the horizontal characteristic curve at the point of operation.
  • The more horizontal the curve, the greater the output impedance.
  • A perfectly horizontal curve indicates infinite output impedance (an open circuit).

JFET AC Equivalent Circuit

  • The JFET AC equivalent circuit includes a voltage-controlled current source (gmVgs) and an output resistance (rd).

Example 3: Sketching the FET AC Equivalent Model

  • Given gfs = 3.8 mS and gos = 20 µS.
  • Calculate the value of the certain parameters to sketch the FET ac equivalent model.
  • Solution; gm = gfs = 3.8 mS, rd = 1/gos = 1/(20 μS) = 50 kΩ

Fixed-Bias Configuration

  • Zi = RG due to infinite input impedance.
  • Setting Vi = 0 V establishes Vgs as 0 V, resulting in the current source being replaced by an open circuit, resulting in Zo = RD||rd
  • If rd is significantly larger than RD (at least 10:1), Zo ≈ RD.
  • Voltage gain: Av = Vo/Vi = -gm(rd||RD), or if rd ≥ 10RD, Av = -gmRD.
  • Phase Relationship: A negative sign indicates a 180° phase shift between input and output voltages.

Example 8.7:

  • The fixed-bias configuration operating point is defined by VGSQ = -2 V and IDQ = 5.625 mA, with IDSS = 10 mA and VP = -8 V; yos is 40 μS.
  • gm0 = 2.5 mS
  • gm = 1.88 mS
  • rd = 25 kΩ
  • Zi = 1 MΩ
  • Zo = 1.85 kΩ
  • Av = -3.48 (accounting for rd)
  • Av = -3.76 (ignoring rd)
  • The 8% difference in solution results because a ratio of 25 kΩ:2 kΩ = 12.5:1 exists between rd and RD.

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