Equilibrium Concentrations

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Questions and Answers

In the equilibrium calculation process, what does the 'change in concentration' row typically represent?

  • A factor of 'x' based on the reaction's stoichiometry. (correct)
  • The equilibrium constant, K, for the reaction.
  • The actual concentrations at equilibrium.
  • The initial concentrations of reactants.

When solving for 'x' in an equilibrium problem using the quadratic formula, how should you handle multiple solutions for 'x'?

  • Use the smallest positive value.
  • Use the largest positive value.
  • Average the solutions to find the most accurate value.
  • Reject any solutions that result in physically impossible (e.g., negative) concentrations. (correct)

For the reaction $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$, if the volume of the container is decreased, how will the equilibrium shift?

  • The reaction will stop.
  • Shift to the left, favoring the reactants.
  • No shift will occur.
  • Shift to the right, favoring the products. (correct)

Consider the endothermic reaction: $A(g) \rightleftharpoons B(g) + C(g)$. What effect will increasing the temperature have on the equilibrium constant (K)?

<p>K will increase. (C)</p> Signup and view all the answers

How do catalysts affect chemical equilibria?

<p>They increase the rate at which equilibrium is achieved but do not alter the equilibrium composition. (A)</p> Signup and view all the answers

If a system at equilibrium is disturbed, which principle is used to predict the shift in the equilibrium position?

<p>Le Châtelier's Principle (D)</p> Signup and view all the answers

For the reaction $2A(g) \rightleftharpoons B(g)$, what effect does increasing the pressure (by decreasing the volume) have on the equilibrium?

<p>Shifts towards the side with fewer moles of gas (products). (B)</p> Signup and view all the answers

Which of the following, when changed, will alter the value of the equilibrium constant, K?

<p>Changing the temperature. (D)</p> Signup and view all the answers

For an exothermic reaction, how does decreasing the temperature affect the equilibrium?

<p>Shifts equilibrium to favor the products. (B)</p> Signup and view all the answers

Consider the gas-phase reaction: $A + B \rightleftharpoons C$. If adding more of reactant A to the system increases the amount of C formed, what happens to the equilibrium?

<p>The equilibrium shifts right. (A)</p> Signup and view all the answers

In the reaction $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$, what happens to the equilibrium if an inert gas is added at constant volume?

<p>There is no change in the equilibrium. (A)</p> Signup and view all the answers

For the endothermic reaction $X(g) \rightleftharpoons Y(g) + Z(g)$, which change will NOT shift the equilibrium to the right?

<p>Adding more Y. (A)</p> Signup and view all the answers

For a reaction at equilibrium, if the forward reaction is endothermic, what effect will cooling the reaction have on the concentration of products?

<p>The concentration of products will decrease. (D)</p> Signup and view all the answers

What is the primary effect of a catalyst on a reversible reaction at equilibrium?

<p>It speeds up the rate at which equilibrium is reached. (A)</p> Signup and view all the answers

Consider the following equilibrium: $A(g) + B(s) \rightleftharpoons C(g)$. If the partial pressure of A is increased, what will happen to the amount of solid B?

<p>It will decrease. (A)</p> Signup and view all the answers

Which of the following changes will affect the equilibrium constant ($K$) for the synthesis of ammonia ($N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)$)?

<p>Changing the temperature. (C)</p> Signup and view all the answers

For a gas-phase reaction, if increasing the volume of the container shifts the equilibrium towards the product side, what can be concluded about the number of moles of gas?

<p>There are more moles of gas on the product side. (B)</p> Signup and view all the answers

In an exothermic reaction, if you increase the temperature, what happens to the equilibrium constant, K?

<p>K decreases. (B)</p> Signup and view all the answers

Consider the reaction $A(g) + B(g) \rightleftharpoons 2C(g)$. If the reaction is started with only A and B, and at equilibrium, it is found that the partial pressures of A, B, and C are all equal, what can be said about the equilibrium constant Kp?

<p>Kp = 1 (C)</p> Signup and view all the answers

If a reaction is endothermic, how does decreasing the temperature affect both the equilibrium and the equilibrium constant?

<p>Shifts towards reactants, K decreases. (A)</p> Signup and view all the answers

For the equilibrium reaction $H_2(g) + I_2(g) \rightleftharpoons 2HI(g)$, if more $H_2(g)$ is added to the system, what will happen to the concentration of $I_2(g)$ at the new equilibrium?

<p>It will decrease. (D)</p> Signup and view all the answers

Which of the following is true regarding the effect of an inert gas on a reaction at equilibrium in a closed system at constant pressure?

<p>It has no effect if the number of moles of gas is the same on both sides. (A)</p> Signup and view all the answers

Consider the equilibrium: $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$. If the volume of the reaction vessel is increased, how will the equilibrium shift?

<p>Towards the reactants ($SO_2$ and $O_2$). (A)</p> Signup and view all the answers

If the reaction $A(g) \rightleftharpoons B(g)$ has an equilibrium constant K much less than 1, and heat is added, how will the concentrations change if the reaction is exothermic?

<p>[A] will increase, [B] will decrease. (A)</p> Signup and view all the answers

Which of the following statements accurately describes the effect of a catalyst on an endothermic reaction at equilibrium?

<p>It will lower the activation energy for both the forward and reverse reactions but will not affect the equilibrium. (D)</p> Signup and view all the answers

Flashcards

Calculating Equilibrium Concentrations

Equilibrium concentrations can be found from initial concentrations and changes based on stoichiometry, using the equilibrium constant.

Change in concentration

Change in concentration during a reaction will be a factor of 'x' based on stoichiometry

Le Châtelier's Principle

It states that if a system at equilibrium is disturbed, it will shift to counteract the disturbance.

Adding a reaction component

Adding a reaction component causes the system to use it up.

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Removing a reaction component

Removing a reaction component results in more of it being produced.

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Volume/Pressure Change

Higher volume or lower pressure favors the side with more moles of gas

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Endothermic and Heat

Endothermic: Heat acts like a reactant, drives reaction toward products.

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Exothermic and Heat

Exothermic: Heat acts like a product, drives reaction towards reactants.

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Catalysts

They increase the rate of forward and reverse reactions, achieving equilibrium faster.

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Catalyst and Equilibrium

Equilibrium can be achieved faster, but the equilibrium composition remains unaltered.

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Study Notes

Calculating Equilibrium Concentrations

  • Equilibrium concentrations can be derived from the equilibrium constant, initial concentrations, and stoichiometric changes.
  • Set-up a table to determine equilibrium concentration, the "change in concentration" row relates to "x" based on the stoichiometry.

Example Problem

  • A 1.000 L flask contains 1.000 mol of H2(g) and 2.000 mol of I2(g) at 448 °C.
  • The equilibrium constant K is 50.5 at 448 °C.
  • The goal is to find the equilibrium concentrations of H2, I2, and HI.

Solution

  • Write the balanced equilibrium equation: H2(g) + I2(g) ⇌ 2 HI(g)
  • Set up the table (ICE table)
    • Initial concentrations: [H2] = 1.000 M, [I2] = 2.000 M, [HI] = 0 M
    • Change in concetrations: [H2] = -x, [I2] = -x, [HI] = +2x
    • Equilibrium concentrations: [H2] = 1.000 - x, [I2] = 2.000 - x, [HI] = 2x
  • Write and solve for the equilibrium constant expression.
    • Kc = [HI]^2 / [H2][I2] = (2x)^2 / (1.000 - x)(2.000 - x) = 50.5
  • Solve for x using the quadratic formula, resulting in x = 2.323 or 0.935.
  • Choose the physically sensible x value.
    • Since subtracting x from 1.000 M must yield a positive value, x = 0.935 M.
  • Calculate the equilibrium concentrations.
    • [H2]eq = 1.000 - 0.935 = 0.065 M
    • [I2]eq = 2.000 - 0.935 = 1.065 M
    • [HI]eq = 2(0.935) = 1.87 M

Key takeaway

  • One of the solutions to the quadratic formula will give a value that leads to a chemically impossible negative concentration, hence reject this solution.

LeChâtelier's Principle

  • If a system at equilibrium is disturbed by a change in temperature, pressure, or component concentration, the system will shift its equilibrium position to counteract the disturbance.

Changing Conditions and Equilibrium Shifts

  • LeChâtelier's Principle predicts shifts in equilibrium based on changes in conditions
  • Concentration: Adding a substance shifts the equilibrium to consume it, while removing a substance shifts the equilibrium to produce it.
  • Pressure: Reducing volume (increasing pressure) shifts the equilibrium towards fewer moles of gas.
  • Temperature:
    • Increasing temperature shifts the equilibrium as if heat were added as a reactant for endothermic reactions or as a product for exothermic reactions.
    • This causes a shift away from the side where heat is effectively added.

Change in Reactant/Product Concentration

  • Adding a reaction component causes the system to use up some of it.
  • Removing a reaction component causes the system to produce more of it.

Change in Volume/Pressure

  • Gas equilibrium is affected by pressure or volume changes.
  • Higher volume/lower pressure favors the side with more moles of gas, and vice versa.

Change in Temperature

  • Endothermic reactions treat heat like a reactant; adding heat shifts the reaction toward products.
  • Exothermic reactions treat heat like a product; adding heat shifts the reaction toward reactants.

Catalysts

  • Catalysts increase the rate of both forward and reverse reactions equally.
  • Equilibrium is reached faster, but the equilibrium composition remains unchanged.
  • Activation energy is lowered, allowing equilibrium at lower temperatures.

Using Le Châtelier's Principle: Predicting Shifts

  • N2O4(g) ⇌ 2 NO2(g), ΔH° = 58.0 kJ:
    • Adding N2O4 shifts the equilibrium to the right (products).
    • Removing NO2 shifts the equilibrium to the right (products).
    • Adding N2 (inert gas) has no effect on the equilibrium position.
    • Increasing volume shifts the equilibrium to the right (more gas molecules).
    • Decreasing temperature shifts the equilibrium to the left (reactants), since reaction is endothermic.

Predicting Effect of Temperature on K

  • Reaction: N2(g) + 3H2(g) ⇌ 2 NH3(g)
  • The reaction is exothermic, and the forward direction generates heat.
  • Increasing temperature causes the reaction to shift toward less NH3 and more N2 and H2.
  • The effect can be seen by the values ​​for K, which become larger at lower temperatures.

Thermodynamic Considerations

  • Using standard enthalpies of formation (ΔHf°) at 25 °C:
    • ΔHf° values for elements in their normal states (e.g., H2(g), N2(g)) are zero.
    • For NH3(g), ΔHf° = -46.19 kJ/mol.
    • The total enthalpy change is: (2 mol)(-46.19 kJ/mol) - 0 = -92.38 kJ

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