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Questions and Answers

Which form of the straight line equation is most suitable when you are given two points on the line?

  • Standard form
  • Gradient-intercept form
  • Gradient-point form
  • Two-point form (correct)

If a line has a gradient of 2 and passes through the point (1, 4), which equation represents the line in gradient-point form?

  • $y - 4 = 2(x - 1)$ (correct)
  • $y - 1 = 2(x - 4)$
  • $y + 4 = 2(x + 1)$
  • $y = 2x + 4$

What is the y-intercept of the line represented by the equation $y = 3x - 5$?

  • 0
  • -5 (correct)
  • 3
  • 5

A line passes through the points (2, 3) and (4, 7). What is the equation of the line in two-point form?

<p>$\frac{y - 3}{x - 2} = \frac{7 - 3}{4 - 2}$ (C)</p> Signup and view all the answers

A line has a gradient of -1 and passes through the point (-2, 5). What is the equation of the line in gradient-intercept form?

<p>$y = -x + 3$ (C)</p> Signup and view all the answers

The equation of a line is given as $2y = 6x + 4$. What is the gradient of this line?

<p>3 (D)</p> Signup and view all the answers

What is the inclination (angle with the positive x-axis) of a horizontal line?

<p>0° (B)</p> Signup and view all the answers

A line has a gradient of $\sqrt{3}$. What is its inclination to the nearest degree?

<p>60° (C)</p> Signup and view all the answers

If a line has a negative gradient, in which quadrant does its angle of inclination lie, relative to the positive x-axis?

<p>Second quadrant (B)</p> Signup and view all the answers

A line has an inclination of 135°. What is its gradient?

<p>-1 (A)</p> Signup and view all the answers

What is the inclination of a vertical line?

<p>90° (D)</p> Signup and view all the answers

Line A has a gradient of 3. If line B is parallel to line A, what is the gradient of line B?

<p>3 (A)</p> Signup and view all the answers

A line is given by the equation $y = 2x + 5$. What is the equation of a line parallel to this line and passing through the point (0, 1)?

<p>$y = 2x + 1$ (B)</p> Signup and view all the answers

If a line has the equation $y = mx + c$ and it is parallel to the x-axis, what is the value of 'm'?

<p>m = 0 (A)</p> Signup and view all the answers

Line A has a gradient of 2. If line B is perpendicular to line A, what is the gradient of line B?

<p>$-\frac{1}{2}$ (B)</p> Signup and view all the answers

A line is given by the equation $y = 3x + 2$. What is the equation of a line perpendicular to this line and passing through the point (3, -1)?

<p>$y = -\frac{1}{3}x$ (D)</p> Signup and view all the answers

Which of the following conditions must be met for two lines to be perpendicular?

<p>The product of their gradients must be -1. (D)</p> Signup and view all the answers

Given two lines, $ax + by = c$ and $dx + ey = f$, derive a concise condition to determine if these lines are parallel.

<p>$\frac{a}{d} = \frac{b}{e}$ (D)</p> Signup and view all the answers

Consider a line $L_1$ described by $y = m_1x + c_1$. Another line, $L_2$, is perpendicular to $L_1$ and intersects it at a point $(x_0, y_0)$. If a third line, $L_3$, is parallel to $L_1$ and passes through the origin, determine the Euclidean distance between the intersection point of $L_1$ and $L_2$, and the line $L_3$.

<p>$\frac{|c_1|}{\sqrt{1 + m_1^2}}$ (B)</p> Signup and view all the answers

Given two points (1, 5) and (3, 9) on a line, what is the equation of the line in two-point form?

<p>$ rac{y - 5}{x - 1} = rac{9 - 5}{3 - 1}$ (C)</p> Signup and view all the answers

A line has a gradient of 3 and passes through the point (2, 7). What is the equation of this line in gradient-point form?

<p>$y - 7 = 3(x - 2)$ (B)</p> Signup and view all the answers

What is the gradient-intercept form of a line?

<p>$y = mx + c$ (D)</p> Signup and view all the answers

If a line passes through the points (0, -3) and (2, 1), what is its gradient?

<p>2 (A)</p> Signup and view all the answers

A line has the equation $y = -2x + 3$. What is its y-intercept?

<p>3 (D)</p> Signup and view all the answers

What is the inclination of a line with a gradient of 1?

<p>45 (B)</p> Signup and view all the answers

A line has an angle of inclination of 60. What is its gradient?

<p>$\sqrt{3}$ (A)</p> Signup and view all the answers

Which of the following is true about the inclination of a line with a gradient of zero?

<p>It is 0. (A)</p> Signup and view all the answers

What is the relationship between the gradients of two lines that are parallel?

<p>They are equal. (D)</p> Signup and view all the answers

If a line has an undefined gradient, what is its inclination?

<p>90 (C)</p> Signup and view all the answers

Consider a line $L_1$ with a gradient of $m_1$. A line $L_2$ is perpendicular to $L_1$. What is the gradient of $L_2$?

<p>$-\frac{1}{m_1}$ (C)</p> Signup and view all the answers

A line is represented by the equation $y = 4x - 3$. What is the equation of a line parallel to this line that passes through the point (0, 5)?

<p>$y = 4x + 5$ (D)</p> Signup and view all the answers

A line is given by the equation $y = -\frac{1}{2}x + 1$. What is the equation of a line perpendicular to this line and passing through the point (1, 1)?

<p>$y = 2x - 1$ (A)</p> Signup and view all the answers

Two lines have gradients $m_1$ and $m_2$. If the lines are perpendicular, which equation must be true?

<p>$m_1 \cdot m_2 = -1$ (A)</p> Signup and view all the answers

Given the line $y = -x + 2$, determine the inclination $\theta$ that this line forms with the positive x-axis.

<p>135 (C)</p> Signup and view all the answers

Consider a line described by the equation $ax + by + c = 0$. What condition must be met for this line to be parallel to the x-axis?

<p>$a = 0$ (D)</p> Signup and view all the answers

A line $L_1$ is defined by the equation $y = m_1x + c_1$. A second line, $L_2$, passes through the point $(0, c_2)$ and is perpendicular to $L_1$. Determine the equation of line $L_2$.

<p>$y = -\frac{1}{m_1}x + c_2$ (D)</p> Signup and view all the answers

A line $L_1$ is given by $y = m_1x + c_1$. Another line $L_2$ is parallel to $L_1$, but passes through the point $(x_0, y_0)$. Derive a general expression for the y-intercept of $L_2$.

<p>$y_0 - m_1x_0$ (A)</p> Signup and view all the answers

Consider two distinct, non-vertical lines, $L_1$ and $L_2$, in the Cartesian plane. $L_1$ has a gradient $m_1$ and $L_2$ has a gradient $m_2$. If $L_1$ and $L_2$ intersect at a single point and $m_1 \neq m_2$, what geometric shape is formed if a third line, $L_3$, is constructed such that it is perpendicular to $L_1$ and passes through the intersection point of $L_1$ and $L_2$?

<p>The lines form a right-angled triangle. (C)</p> Signup and view all the answers

Which form of the straight line equation is most readily used when the gradient and y-intercept are known?

<p>Gradient-Intercept Form (C)</p> Signup and view all the answers

Given a line with the equation $y = mx + c$, what does 'c' represent?

<p>The y-intercept of the line (A)</p> Signup and view all the answers

What is the value of $\tan \theta$ for a line that has an inclination of 45 degrees with respect to the positive x-axis?

<p>1 (D)</p> Signup and view all the answers

A line has a gradient of -1. What is the measure of its angle of inclination with the positive x-axis?

<p>135° (A)</p> Signup and view all the answers

Which of the following is true for a line with an inclination greater than 90 degrees but less than 180 degrees?

<p>The gradient is negative. (C)</p> Signup and view all the answers

What is the relationship between the inclinations $\theta_1$ and $\theta_2$ of two lines that are parallel?

<p>$\theta_1 = \theta_2$ (D)</p> Signup and view all the answers

If two lines are perpendicular, and one has a gradient of 2, what is the gradient of the other line?

<p>$-\frac{1}{2}$ (C)</p> Signup and view all the answers

Given a line with equation $y = 5x + 3$, which of the following lines is parallel?

<p>$y = 5x - 1$ (B)</p> Signup and view all the answers

What is the gradient of a line that is perpendicular to the line described by the equation $y = -3x + 4$?

<p>$\frac{1}{3}$ (A)</p> Signup and view all the answers

The gradient of line A is $m$. Line B is perpendicular to line A. What is the gradient of line B?

<p>$-\frac{1}{m}$ (A)</p> Signup and view all the answers

Which of the following statements is true about two lines with gradients $m_1$ and $m_2$ if they are parallel?

<p>$m_1 = m_2$ (B)</p> Signup and view all the answers

Consider a line with the equation $y = 2x + 3$. What is the equation of a line that is parallel to this line and passes through the point (1, 5)?

<p>$y = 2x + 1$ (B)</p> Signup and view all the answers

A line is defined by the equation $y = -\frac{1}{3}x + 2$. Determine the equation of a line perpendicular to this line that passes through the point (1, 1).

<p>$y = 3x - 2$ (C)</p> Signup and view all the answers

Given the line $y = -x + 5$, what is the angle of inclination, $\theta$, that this line forms with the positive x-axis?

<p>135° (D)</p> Signup and view all the answers

Consider two lines: $L_1$ with equation $y = 2x + 3$ and $L_2$ with equation $y = 2x - 1$. What can be said about these two lines?

<p>They are parallel. (B)</p> Signup and view all the answers

A line $L_1$ has a gradient of 4 and passes through the point (2, 3). A line $L_2$ is perpendicular to $L_1$. Determine the equation of $L_2$ if it also passes through the point (2, 3).

<p>$y = -\frac{1}{4}x + \frac{7}{2}$ (B)</p> Signup and view all the answers

Imagine a line, defined by the equation $ax + by + c = 0$, is parallel to the x-axis. Which condition must be satisfied?

<p>$a = 0$ (B)</p> Signup and view all the answers

Consider a vertical line. What is its angle of inclination with respect to the positive x-axis?

<p>90° (A)</p> Signup and view all the answers

Given two distinct non-vertical lines, $L_1$ and $L_2$, with gradients $m_1$ and $m_2$ respectively. They intersect at a single point. A third line, $L_3$, is constructed perpendicular to $L_1$ and passes through the intersection point of $L_1$ and $L_2$. If a circle is drawn such that it touches all three lines, what is the location of the center of this circle?

<p>The intersection point of $L_2$ and $L_3$ (C)</p> Signup and view all the answers

Line $L_1$ is defined by $y = m_1x + c_1$. Line $L_2$ is parallel to $L_1$, but passes through the point $(x_0, y_0)$. Line $L_3$ is perpendicular to $L_1$ and also passes through $(x_0, y_0)$. Determine the area of the triangle formed by the x-intercept of $L_1$, the y-intercept of $L_2$, and the intersection of $L_1$ and $L_3$

<p>$\frac{|c_1|(y_0 - m_1x_0)^2}{2m_1^2}$ (A)</p> Signup and view all the answers

Flashcards

Two-Point Form

The equation of a line given two points ( (x_1, y_1) ) and ( (x_2, y_2) ) is: [ \frac{y - y_1}{x - x_1} = \frac{y_2 - y_1}{x_2 - x_1} ]

Gradient-Point Form

The equation of a line given a gradient (m) and a point ( (x_1, y_1) ) is: [ y - y_1 = m(x - x_1) ]

Gradient-Intercept Form

The equation of a line given a gradient (m) and y-intercept (c) is: [ y = mx + c ]

Gradient (m)

Measures the steepness of a line; rise over run.

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Y-intercept (c)

The (y)-value where the line crosses the (y)-axis; where (x = 0).

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Inclination of a Line

The angle (\theta) a line makes with the positive (x)-axis, where the gradient ( m = \tan \theta ).

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Gradient and Inclination

For lines with gradient (m), the tangent of the angle (\theta) is: [ m = \tan \theta \text{ for } 0^\circ \leq \theta < 180^\circ ]

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Vertical Lines

For a vertical line, (\theta = 90^\circ), gradient is undefined, as (\Delta x = 0).

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Horizontal Lines

For a horizontal line, (\theta = 0^\circ); the gradient is zero, as (\Delta y = 0).

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Negative Gradients

If (m < 0), the angle (\theta) is obtuse. To find (\theta): [ \theta = 180^\circ + \tan^{-1}(m) ]

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Parallel Lines

Parallel lines have the same gradient: [ m_1 = m_2 ]

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Parallel Line Equation

To find the equation, use the gradient and a point ((x_1, y_1)) in: [ y - y_1 = m(x - x_1) ]

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Perpendicular Lines

Perpendicular lines have gradients that multiply to [ m_1 \times m_2 = -1 ] or [ m_1 = -\frac{1}{m_2} ]

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Perpendicular Line Equation

To find the equation, use the perpendicular gradient and a point ((x_1, y_1)) in: [ y - y_1 = m(x - x_1) ]

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What is the inclination of a line?

The angle that a straight line makes with the positive x-axis.

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What is the inclination of vertical lines?

Vertical lines have an undefined gradient. The angle ( \theta = 90^\circ ).

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What is the inclination of horizontal lines?

Horizontal lines have a gradient equal to 0. The angle ( \theta = 0^\circ ).

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Lines with a negative gradient?

When the gradient is negative, the angle (\theta) is obtuse and calculated as: [ \theta = 180^\circ + \tan^{-1}(m) ]

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Equation Form for Gradient Identification

Ensuring the equation is in ( y = mx + c ) form allows direct identification of the gradient ( m ).

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When to use Two-Point Form?

This form is used when you are given two points on the line.

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When to use Gradient–Point Form?

This form is most useful when you know the gradient of a line and the coordinates of one point on the line.

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Gradient and Tangent

The gradient of a line is equal to the tangent of the angle formed between the line and the positive x-axis.

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What is the steepness of Parallel Lines?

Parallel lines have the same steepness or slope.

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Equation form for gradient

Make sure the equation is in the form such as y = mx + c to easily identify the gradient m.

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Angle of Perpendicular Lines

Perpendicular lines form a right angle at their intersection.

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Study Notes

Equation of a Line

  • Straight line equations come in different forms, each useful depending on the given information.

  • Two-Point Form:

    • Used when two points on the line are known.
    • Equation: (\frac{y - y_1}{x - x_1} = \frac{y_2 - y_1}{x_2 - x_1})
  • Gradient–Point Form:

    • Used when the gradient and one point on the line are known.
    • Equation: (y - y_1 = m(x - x_1))
  • Gradient–Intercept Form:

    • Used when the gradient and the y-intercept are known.
    • Equation: (y = mx + c)

The Two-Point Form

  • Determines the equation of a line given two points ((x_1, y_1)) and ((x_2, y_2)).
  • Equation: (\frac{y - y_1}{x - x_1} = \frac{y_2 - y_1}{x_2 - x_1})

The Gradient–Point Form

  • Derived from the definition of gradient and the two-point form.
  • Start with (\frac{y - y_1}{x - x_1} = \frac{y_2 - y_1}{x_2 - x_1})
  • Substitute (m = \frac{y_2 - y_1}{x_2 - x_1})
  • Simplified equation: (y - y_1 = m(x - x_1))
  • Requires the gradient of the line and the coordinates of one point on the line.

The Gradient–Intercept Form

  • Derived from the gradient–point form.
  • Start with (y - y_1 = m(x - x_1))
  • Expand and rearrange:
    • (y = mx - mx_1 + y_1)
    • (y = mx + (y_1 - mx_1))
  • (c = y_1 - mx_1), so the equation becomes (y = mx + c)
  • (c) is the y-intercept of the straight line (when (x = 0), (y = c)).
  • Also called the standard form of the straight line equation.

Key Points Summary

  • Two-Point Form: Use when given two points on the line.
  • Gradient–Point Form: Use when given the gradient and a point on the line.
  • Gradient–Intercept Form: Use when given the gradient and y-intercept.

Important Concepts

  • Gradient (m): Measures the steepness of the line.
  • Y-intercept (c): The value of (y) where the line crosses the y-axis.
  • Equation Forms: Different forms are useful based on the given information.

Inclination of a Line

  • The inclination of a straight line is the angle ( \theta ) it makes with the positive x-axis.

Relationship between Gradient and Inclination

  • Gradient ( m ) is the ratio of the change in the y-direction ((\Delta y)) to the change in the x-direction ((\Delta x)):
    • ( m = \frac{\Delta y}{\Delta x} )
  • From trigonometry:
    • ( \tan \theta = \frac{\text{opposite side}}{\text{adjacent side}} )
  • For a line with gradient ( m ):
    • ( \tan \theta = \frac{\Delta y}{\Delta x} )
    • ( \therefore m = \tan \theta ) for ( 0^\circ \leq \theta < 180^\circ )

Special Cases

  • Vertical Lines:
    • ( \theta = 90^\circ )
    • Gradient is undefined since ( \Delta x = 0 ).
    • ( \tan \theta ) is also undefined.
  • Horizontal Lines:
    • ( \theta = 0^\circ )
    • Gradient is equal to 0 since ( \Delta y = 0 ).
    • ( \tan \theta ) is also equal to 0.
  • Lines with Negative Gradients:
    • If ( m < 0 ), then ( \tan \theta < 0 ), indicating the angle formed between the line and the positive x-axis is obtuse.
    • ( \theta = 180^\circ + \tan^{-1}(m) )

Key Points Summary

  • Gradient and Inclination:
    • ( m = \tan \theta ) for ( 0^\circ \leq \theta < 180^\circ )
  • Special Cases:
    • Vertical lines: ( \theta = 90^\circ ), ( m ) is undefined.
    • Horizontal lines: ( \theta = 0^\circ ), ( m = 0 ).
    • Negative gradients: ( \theta = 180^\circ + \tan^{-1}(m) )

Important Concepts

  • Gradient (m): Measures the steepness of the line.
  • Inclination (θ): The angle a line makes with the positive x-axis.
  • Trigonometric Relationship:
    • For acute angles (0 < θ ≤ 90°), ( \tan \theta ) is positive.
    • For obtuse angles (90° < θ < 180°), ( \tan \theta ) is negative.

Parallel Lines

Gradient Relationship for Parallel Lines

  • For two lines to be parallel, their gradients must be equal:
    • ( m_1 = m_2 )

Finding the Equation of a Parallel Line

  • Identify the gradient (( m )) of the given line from the standard form ( y = mx + c ).
  • Use the point-slope form with the identified gradient and a given point ((x_1, y_1)).
    • Equation: (y - y_1 = m(x - x_1))
  • Simplify the equation to the standard form ( y = mx + c ).

Important Considerations

  • Ensure the given line's equation is in gradient-intercept form (( y = mx + c )).
  • Parallel lines must have the same gradient but can have different y-intercepts.

Perpendicular Lines

Gradient Relationship for Perpendicular Lines

  • For two lines to be perpendicular, the product of their gradients must be (-1):
    • ( m_1 \times m_2 = -1 )

Finding the Equation of a Perpendicular Line

  • Identify the gradient (( m )) of the given line from the standard form ( y = mx + c ).
  • Calculate the perpendicular gradient ( m_1 ) using the relationship ( m_1 = -\frac{1}{m_2} ).
  • Use the point-slope form with the perpendicular gradient and a given point ((x_1, y_1)).
    • Equation: ( y - y_1 = m(x - x_1) )
  • Simplify the equation to the standard form ( y = mx + c ).

Important Considerations

  • Ensure the given line's equation is in gradient-intercept form (( y = mx + c )).
  • Perpendicular lines have gradients that multiply to (-1).

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