Electric Charge and Fields Quiz
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Questions and Answers

Explain the concept of quantization of charge.

Quantization of charge refers to the fact that electric charge is always found in discrete, indivisible amounts, and cannot be divided into smaller parts.

Describe the conservative nature of charge.

The conservative nature of charge means that the total electric charge in an isolated system remains constant over time, it can neither be created nor destroyed.

What are two basic properties of electric charge?

Two basic properties of electric charge are quantization and conservation.

Explain why no two electric lines of force cross each other.

<p>No two electric lines of force cross each other because at the point of intersection, there would be two different directions of the electric field, which is not physically possible.</p> Signup and view all the answers

Why is no work done in moving a test charge over an equi-potential surface?

<p>No work is done because the potential on an equipotential surface is constant; hence, there is no change in potential energy of the test charge as it moves over the surface.</p> Signup and view all the answers

Define electric potential energy and provide the relation for it due to two charges.

<p>Electric potential energy is the work done in assembling a system of charges. For two charges q1 and q2 separated by distance r, the electric potential energy is given by: $U = \dfrac{kq_1q_2}{r}$</p> Signup and view all the answers

Define electric dipole moment and derive the relation for electric potential at any point due to an electric dipole.

<p>Electric dipole moment is the product of the magnitude of one of the charges and the vector separating the charges. The electric potential at a point P due to an electric dipole is given by: $V = \dfrac{k \cdot p \cdot \cos(\theta)}{r^2}$, where p is the dipole moment, θ is the angle between the dipole moment vector and the line connecting the point to the midpoint of the dipole, and r is the distance between the point and the midpoint of the dipole.</p> Signup and view all the answers

Explain the concept of electric flux and derive the relation for electric field intensity due to a charged thin sheet.

<p>Electric flux is the total number of electric field lines passing through a given area. For a charged thin sheet with charge density σ, the electric field intensity at a point outside the sheet is given by: $E = \dfrac{\sigma}{2\varepsilon_0}$, and inside the sheet, the electric field intensity is zero.</p> Signup and view all the answers

What is the definition of electric potential and what is the relation for it due to a monopole?

<p>Electric potential is the electric potential energy per unit charge. For a monopole of charge Q at a distance r, the electric potential is given by: $V = \dfrac{kQ}{r}$</p> Signup and view all the answers

Define capacitance of a parallel plate capacitor and derive an expression for it with a dielectric as the medium introduced between the plates.

<p>Capacitance of a parallel plate capacitor is the ability of the capacitor to store charge per unit voltage. When a dielectric is introduced, the capacitance increases and is given by $C = \varepsilon_r \varepsilon_0 \frac{A}{d}$, where $\varepsilon_r$ is the relative permittivity of the dielectric.</p> Signup and view all the answers

Explain the principle of a capacitor and derive the relation for the capacitance of a parallel plate capacitor.

<p>The principle of a capacitor is to store electric charge by creating an electric field. The capacitance of a parallel plate capacitor is given by $C = \varepsilon_0 \frac{A}{d}$, where $\varepsilon_0$ is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.</p> Signup and view all the answers

What is the relation for the energy stored in a capacitor? Where and in what form is this energy stored?

<p>The energy stored in a capacitor is given by $U = \frac{1}{2} CV^2$, where C is the capacitance and V is the voltage across the capacitor. This energy is stored in the electric field between the capacitor plates.</p> Signup and view all the answers

Define a Gaussian surface and derive the relation for electric field intensity due to a charged hollow conducting shell (i) inside, (ii) outside, and (iii) on the surface.

<p>A Gaussian surface is an imaginary closed surface used to calculate the electric field. For a charged hollow conducting shell, the electric field intensity is: (i) inside the shell, E = 0, (ii) outside the shell, $E = \dfrac{kQ}{r^2}$, and (iii) on the surface, E = 0.</p> Signup and view all the answers

When a dielectric slab is introduced between the plates of a capacitor, what happens to (a) Capacitance (b) Charge (c) Potential (d) Electric field (e) Total energy stored?

<p>When a dielectric is introduced, (a) Capacitance increases, (b) Charge remains the same, (c) Potential decreases, (d) Electric field decreases, and (e) Total energy stored increases.</p> Signup and view all the answers

If the distance between the plates of a capacitor doubles while the area remains the same, what happens to (a) Capacitance (b) Charge (c) Potential (d) Electric field (e) Total energy stored?

<p>When the distance doubles, (a) Capacitance decreases, (b) Charge remains the same, (c) Potential decreases, (d) Electric field decreases, and (e) Total energy stored decreases.</p> Signup and view all the answers

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