Podcast
Questions and Answers
Explain how the Meselson-Stahl experiment demonstrated that DNA replication is semi-conservative, and why this model is essential for maintaining genetic information?
Explain how the Meselson-Stahl experiment demonstrated that DNA replication is semi-conservative, and why this model is essential for maintaining genetic information?
The Meselson-Stahl experiment used isotopes of nitrogen to show that after replication, each DNA molecule consists of one original strand and one new strand, supporting the semi-conservative model. This ensures genetic information is passed accurately across generations.
Describe the roles of helicase, primase, and DNA polymerase III in prokaryotic DNA replication, and explain why their coordinated action is essential for accurate genome duplication.
Describe the roles of helicase, primase, and DNA polymerase III in prokaryotic DNA replication, and explain why their coordinated action is essential for accurate genome duplication.
Helicase unwinds DNA, primase synthesizes RNA primers for initiation, and DNA polymerase III extends the primers, adding nucleotides complementary to the template strand. Their coordinated action ensures accurate and efficient replication across the genome.
Why is telomerase necessary in eukaryotic cells but not in prokaryotic cells? Relate this to the structure of their chromosomes and how replication occurs.
Why is telomerase necessary in eukaryotic cells but not in prokaryotic cells? Relate this to the structure of their chromosomes and how replication occurs.
Telomerase is necessary in eukaryotes to extend the 3' end of the lagging strand because linear chromosomes shorten with each replication due to the inability to replicate the ends. Prokaryotes have circular chromosomes, so they don't have this problem.
Explain the difference between a transition and a transversion mutation. Which type of mutation is more likely to occur and why?
Explain the difference between a transition and a transversion mutation. Which type of mutation is more likely to occur and why?
Describe how frameshift mutations can have a more severe impact on protein structure compared to point mutations, providing an example to illustrate your point.
Describe how frameshift mutations can have a more severe impact on protein structure compared to point mutations, providing an example to illustrate your point.
What is DNA slippage and how does it lead to insertions or deletions in DNA sequences, especially in regions with repeated sequences?
What is DNA slippage and how does it lead to insertions or deletions in DNA sequences, especially in regions with repeated sequences?
Explain how tautomeric shifts in nucleotide bases can result in mutations if not corrected. Provide an example of how such a shift can lead to a base pairing error.
Explain how tautomeric shifts in nucleotide bases can result in mutations if not corrected. Provide an example of how such a shift can lead to a base pairing error.
Contrast the mechanisms of nucleotide excision repair (NER) and mismatch repair (MMR) in addressing DNA damage, highlighting the types of errors each system targets.
Contrast the mechanisms of nucleotide excision repair (NER) and mismatch repair (MMR) in addressing DNA damage, highlighting the types of errors each system targets.
Explain how non-homologous end joining (NHEJ) and homologous recombination (HR) differ in their approaches to repairing double-strand DNA breaks, and discuss the circumstances under which each pathway is typically used.
Explain how non-homologous end joining (NHEJ) and homologous recombination (HR) differ in their approaches to repairing double-strand DNA breaks, and discuss the circumstances under which each pathway is typically used.
What is the purpose of PCR, and what are the three main steps involved in each cycle? How do these steps contribute to the amplification of a specific DNA region?
What is the purpose of PCR, and what are the three main steps involved in each cycle? How do these steps contribute to the amplification of a specific DNA region?
Flashcards
Conservative replication
Conservative replication
The entire DNA molecule is copied making a second, completely new DNA molecule.
Semi-conservative replication
Semi-conservative replication
The two strands of DNA separate, with each strand acting as a template to copy a new strand.
Dispersive replication
Dispersive replication
The DNA cleaved into small fragments, the fragments were copied and then re-attached.
Telomerase
Telomerase
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Nonsense mutation
Nonsense mutation
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Missense mutation
Missense mutation
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Silent mutation
Silent mutation
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Base substitution
Base substitution
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DNA Slippage
DNA Slippage
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Tautomeric Shifts
Tautomeric Shifts
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Study Notes
- DNA encodes genetic information for RNA and proteins
- Double helix
- Sugar-phosphate backbone and nucleotide bases
- Complementary strands are anti-parallel
- Runs from 5' to 3'
- Nucleotide bases are connected by hydrogen bonds
- Adenine (A) pairs with Thymine (T)
- Guanine (G) pairs with Cytosine (C)
- Purines (Adenine and Guanine) hydrogen bond with pyrimidines
- Pyrimidines are Thymine and Cytosine
- In RNA, Uracil (U) replaces Thymine (T)
- Guanine and Cytosine forms three hydrogen bonds; Adenine and Thymine forms two
- The bonds between Guanine and Cytosine is harder to break and require more energy
Mnemonic for Nucleotides
- "CUT the Py" to remember that Cytosine, Uracil, and Thymine are pyrimidines
- "Pure As Gold" to remember that Purines are Adenine and Guanine
Phosphodiester Bonds
- Phosphodiester bonds join the 3' -OH group of one nucleoside to the 5' phosphate group of an incoming nucleoside
Replication Theories
- Conservative: Entire DNA molecule is copied into a second, completely new DNA molecule
- Semi-conservative: DNA strands separate, each acting as a template to copy a new strand
- Dispersive: DNA is cleaved into small fragments, fragments are copied and then re-attached
Meselson-Stahl Experiment.
- Designed by Matthew Meselson and Franklin Stahl in Escherichia Coli (E. coli) to determine how DNA replication occurs
- E. coli was grown in "heavy" nitrogen (15N) for all the bacterial DNA to become labelled with 15N
- DNA was extracted and centrifuged which resulted in all DNA becoming heavy
- Cells are transfered to "light" nitrogen (14N) for one replication cycle
- After DNA extraction and centrifuge all DNA= 50% "heavy"/ 50% "light" -This excludes the conservative theory
- DNA replicates in "light" nitrogen (14N) one more time ○ When DNA centrifuged, either 50% "heavy"/ 50% "light" OR all "light"
DNA Replication in Cells
- It is semi-conservative
- The origin of replication in prokaryotes has a special name called Ori
DNA synthesis steps
- Helicase unwinds DNA leaving antiparallel strands and a replication fork
- Single stranded binding proteins (ssb) keep strands apart
- Topoisomerase is responsible for "relaxing" the supercoiling
- DNA Polymerase III grabs new nucleotides and matches them to create a new strand
- It can only bind to the parental DNA and start creating a new strand with an RNA primer, created by primase
- Reads DNA in the 3' to 5' direction and creates a new strand in the 5' to 3' direction
- DNA goes both ways (3' to 5' to 5' to 3')
- Polymerase moves towards the replication fork (leading strand), and away from the replication fork (lagging strand)
- Sliding clamp tethers DNA polymerase to the strand
- Replication continues until the adjacent replication bubble is met.
- Leading strand: DNA polymerase III adds nucleotides to the newly forming strand as helicase unwinds the DNA
- Lagging strand: parent DNA requires multiple primers and polymerases, creating Okazaki Fragments.
- DNA polymerase I removes the primer and replaces deoxyribonucleotides
- DNA Ligase moves along the lagging strand and ties the Okazaki fragments
Prokaryotes vs Eukaryotes
Prokaryotes | Eukaryotes | |
---|---|---|
Replication Origin | One | Multiple |
Rate of Replication | Faster (~1000 nt/s) | Slower (50-100 nt/s) |
Polymerase Types | 5 | 14 |
Primer Removal Enzyme | DNA Pol I | RNase H |
Strand Elongation Enzyme | DNA Pol III | POL a, 6, Ɛ |
Telomerase
- RNA primers cannot be added to the 3' end of the DNA (lagging strand)
- Telomerase extends the 3' end of the lagging strand and a DNA polymerase III replicate the 3' end
- Prokaryotic cells don't have telomerase and have circular chromosomes
Mutations
- Occur when there is a change in the normal DNA sequence
- Point mutation means that only one base pair is mutated
- Errors in DNA replication
- Environmental exposure to damaging agents like UV light, radiation, etc.
- Harmful chemicals/ toxins and byproducts of normal cell metabolism
Point mutations
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Nonsense: premature stop codon
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Missense: amino acid change
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Silent: no change in amino acid sequence
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Beneficial: improves the fitness of an organism
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Benign: doesn't change the overall fitness of an organism
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Harmful: negatively impacts the fitness of an organism
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Base substitution is when a nucleotide is replaced by another
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Point mutations are base substitutions
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Transitions are purine for purine, pyrimidine for pyrimidine
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Transversion is purine for pyrimidine and vice-versa
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Frameshift mutations cause changes in the reading frame
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Result from mutations such as insertions/deletions of DNA
DNA Slippage
- DNA polymerase falls off the template strand and when it comes back together
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- The newly synthesized strand "slips" backward resulting in a 1 bp insertion.
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- The template strand "slips" forward resulting in a 1 bp deletion
Tautomeric Shifts
- DNA nucleotides have inherent instability and exists in equilibrium between two forms
- Thymine & Guanine = keto vs. enol
- Adenine & Cytosine = Amino vs. imino
- Equilibrium lies heavy towards usual base-pairing: C-G & A-T
- In alternate form, base pairing changes to T-G & C-A
- 5-bromouracil are in an equal equilibrium between two forms
- Source of single nucleotide polymophisms
Copy Number Variations
- Different number of copies of genes/gene regions
- Unequal cross-over during homologous recombination in prophase I of meiosis
- Non-homologous end joining causes loss of large chromosome regions
- Mobile elements
Transposons
- Regions of the genome are trapped viruses
- Retain the ability to move within the genome, but cannot leave the cell
- Do not increase copy number variations if they just "jump"
- Increase copy number variations if they move through a copy & paste mechanism
Alu Elements
- in the human genome are called Alu elements
- LINES = Long interspersed elements
- SINEs = Short interspersed elements
- Represent about 11% of the human genome
- Move through a retrotransposon copy & paste mechanism
- Paste causes insertional mutagenesis and disrupt genes
- Causes changes in gene expression or regulation, and recombination events to occur where they shouldn't
- Diseases attributed to Alu elements: Hemophilia, leukaemia, muscular dystrophy
Repair of DNA Mutations
- Point mutations (base-pair substitutions)
- Insertion and deletion mutations (addition or removal of base pairs)
DNA Polymerase Exonuclease Activity
- Polymerase III can proofread, prevent mutations, Synthesizes 5' -> 3' and Corrects 3' -> 5'.
- Exonuclease activity breaks phosphodiester bonds to correct mistakes
- Bases are Improper placements by checking geometry to polymerize copy strand
DNA Mismatch Repair
- If DNA Polymerase does not correct mismatched bases during DNA polymerization, other mechanisms are in place
- Specific DNA repair enzymes (endonucleases) recognize incorrect geometry
- and repair the DNA by excising the incorrect nucleotide
- The gap is filled in later by DNA polymerase
- Nick is sealed by DNA ligase
- Bacteria's parent strand usually has methylated adenines
Nucleotide Excision Repair
- Mechanism repairs damaged DNA rather than incorrectly paired ones
- Environmental mutagens damages like ultraviolet (UV) radiation, create covalent bonding of two pyrimidines within DNA
- Enzymes (endonucleases) detect the improper geometry of the DNA
- Remove the damaged nucleotides from the DNA
- DNA polymerase adds new nucleotides
- DNA ligase bonds them
Repair of DNA Strand Breaks
- Double-stranded breaks in DNA
- Incorrect joining of the strands reorganizes of the genes affecting chromosome structure.
- Two main systems for repairing double stranded DNA breaks: non-homologous end joining and homologous recombination
- Non-homologous End Joining (NHEJ) joins two non-homologous ends of DNA together
Non-homologous End Joining Problems
- Base pairs from either ends of the DNA fragments are lost
- Genes can end up joined forming chimeric genes
- this can change cell function or cause cancer
Homologous Recombination
- Damaged DNA sequence is copied from an undamaged or highly similar copy
- Two strands exchange to repair the break through recombination
Polymerase Chain Reaction
- In vitro method of replicating/amplifying DNA that uses the same concepts of DNA replication to amplify a target DNA
- Components in tube: thermostable DNA polymerase (Taq polymerase), deoxyribonucleotides, DNA template, and primers
- A thermocycler is used
- 3 steps involves: Denaturation, Annealing, Elongation
Distinctions from DNA replication in the cell
- Heat is used to unwind DNA strands instead of helicase
- Primers are artificially designed, made of DNA instead of RNA, and dictates the replication
- Only a small region is amplified
- Millions of copies of the target region are produced
- No lagging or leading strands are involved
Primes
- Are in order to only amplify the required region of the genome
- These primers must flank to the DNA that to desired area and be complementary to the strands.
- Have around 18-22 base pairs
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