DNA Replication: Models and Accuracy

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Questions and Answers

If a DNA polymerase has an error rate of one in every million base pairs, what would be the approximate number of mistakes after one cell division, given the E. coli genome size is approximately 4.6 million base pairs?

  • 4 to 5 (correct)
  • 46
  • 4600
  • 460

In the Meselson-Stahl experiment, what observation after the first generation of replication supported semiconservative replication over conservative replication?

  • The presence of a single light band.
  • The presence of a single intermediate band. (correct)
  • The absence of any DNA.
  • The presence of two distinct bands, one heavy and one light.

What would be observed after two rounds of replication in the Meselson-Stahl experiment if DNA replication was dispersive?

  • One heavy band and one light band.
  • A single band of intermediate weight. (correct)
  • A gradient of bands ranging from heavy to light.
  • One intermediate band and one light band.

How does theta replication differ from rolling circle replication in terms of the template DNA and the resulting DNA molecules?

<p>Theta replication uses a circular template and produces two circular DNA molecules, whereas rolling circle uses a circular template and can produce multiple circular DNA molecules or a long linear molecule. (A)</p> Signup and view all the answers

In eukaryotic DNA replication, what is the role of multiple origins of replication along each chromosome?

<p>To speed up the replication process of long, linear DNA molecules. (D)</p> Signup and view all the answers

If a mutation occurred that prevented the 3' hydroxyl group from being available on the last nucleotide of a DNA strand during replication, what would most likely happen?

<p>A phosphodiester bond could not form with the next nucleotide. (A)</p> Signup and view all the answers

Considering the properties of DNA polymerase, why are Okazaki fragments formed during DNA replication?

<p>Because DNA polymerase can only add nucleotides to the 3' end of a growing strand and DNA strands are antiparallel. (D)</p> Signup and view all the answers

What would happen if a bacterial cell's DNA ligase enzyme was non-functional?

<p>Okazaki fragments would not be joined together. (A)</p> Signup and view all the answers

How do single-strand binding proteins (SSBs) contribute to DNA replication?

<p>By preventing the reformation of the double helix after it has been unwound. (B)</p> Signup and view all the answers

Why is DNA gyrase necessary for DNA replication?

<p>It prevents the tangling of DNA ahead of the replication fork by making and resealing breaks in the DNA. (D)</p> Signup and view all the answers

What is the role of the initiator protein (DnaA in E. coli) in bacterial DNA replication?

<p>To bind to the origin of replication and initiate unwinding of the DNA. (C)</p> Signup and view all the answers

What is the primary function of DNA polymerase I in E. coli DNA replication?

<p>To remove RNA primers and replace them with DNA nucleotides. (A)</p> Signup and view all the answers

What is the function of the 3' to 5' exonuclease activity of DNA polymerase during replication?

<p>To remove incorrectly paired nucleotides from the 3' end of the growing strand. (A)</p> Signup and view all the answers

What is the role of autonomously replicating sequences (ARSs) in eukaryotic DNA replication?

<p>They are the sequences to which the origin-recognition complex binds to initiate DNA replication. (A)</p> Signup and view all the answers

Unlike bacterial DNA replication, eukaryotic DNA replication requires a licensing step. What best describes this licensing process?

<p>The ORC attaches to each origin of replication and forms a complex with licensing factors. (B)</p> Signup and view all the answers

Why might a cell utilize an error-prone DNA polymerase during replication, even though it increases the risk of mutations?

<p>To bypass lesions or damage in the DNA template that stall high-fidelity polymerases. (A)</p> Signup and view all the answers

How does the process of nucleosome reassembly occur during eukaryotic DNA replication?

<p>Original nucleosomes are disrupted, and pre-existing and newly synthesized histones are redistributed on the new DNA. (A)</p> Signup and view all the answers

What is the primary challenge that telomeres and telomerase help to overcome during DNA replication?

<p>The loss of genetic information at the ends of linear chromosomes during replication. (D)</p> Signup and view all the answers

What would happen to a cell's chromosomes over many generations if telomerase were non-functional?

<p>Chromosomes would gradually shorten. (B)</p> Signup and view all the answers

What is the significance of homologous recombination?

<p>It is a DNA repair mechanism and can increase genetic variation. (C)</p> Signup and view all the answers

What is the ultimate result of the Holliday model of homologous recombination?

<p>The exchange of genetic information between two DNA molecules. (C)</p> Signup and view all the answers

What role does resolvase play in homologous recombination?

<p>It cleaves Holliday structures to separate recombined DNA molecules. (C)</p> Signup and view all the answers

How does the double-strand break model of recombination differ from the Holliday model?

<p>The double-strand break model initiates with a double-strand break in one of the DNA molecules, whereas the Holliday model starts with single-strand breaks in both molecules. (A)</p> Signup and view all the answers

During bacterial DNA replication, primase is essential for synthesizing primers. Where are these primers synthesized?

<p>At the beginning of every Okazaki fragment on the lagging strand. (B)</p> Signup and view all the answers

If a newly synthesized DNA strand in E. coli is accidentally not methylated, what would occur?

<p>The newly synthesized strand would be recognized by mismatch repair enzymes and corrected using the template strand as a guide. (C)</p> Signup and view all the answers

What is the functional consequence of the location of DNA replication within the eukaryotic nucleus?

<p>DNA polymerase fixed in location and template DNA threaded through it. (D)</p> Signup and view all the answers

Which of the enzymes listed below are responsible for DNA repair?

<p>DNA Polymerase I, II, IV, V. (C)</p> Signup and view all the answers

Which of the following characteristics are associated with rolling-circle replication?

<p>Unidirectional (C)</p> Signup and view all the answers

Which is not a component of bacterial DNA replication?

<p>Telomerase (A)</p> Signup and view all the answers

If the sequence of a strand of DNA is 5’-CCGGAATT-3’, what is the sequence of the other parental strand?

<p>5'-AATTCCGG-3' (A)</p> Signup and view all the answers

Which of the following is true of DNA replication?

<p>DNA replication is semiconservative (B)</p> Signup and view all the answers

In which direction relative to synthesis can DNA Polymerase add nucleotides?

<p>Only 5' -&gt; 3' (A)</p> Signup and view all the answers

Why in lagging strand synthesis are Okazaki fragments ultimately needed?

<p>Because DNA synthesis is anti-parallel (C)</p> Signup and view all the answers

Which of the following choices describe primase?

<p>RNA Polymerase (D)</p> Signup and view all the answers

What would be observed in the absence of primase?

<p>Elongation would not occur properly (D)</p> Signup and view all the answers

Which protein or class of proteins assist in preventing secondary structures from developing during DNA replication?

<p>Single-strand binding proteins (D)</p> Signup and view all the answers

In the double-strand break model, how is the double-strand separated and repaired?

<p>With assistance between homologous chromosomes (A)</p> Signup and view all the answers

What enzyme facilitates the cleavage of a Holliday Junction?

<p>Resolvase (C)</p> Signup and view all the answers

What role do the proteins Mcm2-7 play?

<p>Helicases (B)</p> Signup and view all the answers

Why is high accuracy essential during DNA replication?

<p>To minimize the number of mutations that occur each time a cell divides. (B)</p> Signup and view all the answers

If Meselson and Stahl had observed a single band of DNA at an intermediate density after each generation, what conclusion would be most accurate?

<p>DNA replication is dispersive. (C)</p> Signup and view all the answers

During theta replication, if both replication forks stall, what would be the most likely outcome?

<p>Replication would likely cease, possibly leading to cell cycle arrest or cell death. (A)</p> Signup and view all the answers

In rolling circle replication, if the linear strand fails to circularize, how does this affect the outcome?

<p>DNA polymerase will still replicate the linear strand, producing a linear copy. (B)</p> Signup and view all the answers

Why is it important for eukaryotic chromosomes to have multiple origins of replication?

<p>To ensure that the entire large linear chromosome can be replicated in a reasonable amount of time. (C)</p> Signup and view all the answers

If a mutation occurs that disrupts the function of DNA polymerase's ability to add nucleotides, how would replication be affected?

<p>No nucleotides can be added, so DNA synthesis would halt. (A)</p> Signup and view all the answers

What is the consequence if Okazaki fragments were not synthesized during DNA replication?

<p>The lagging strand would not be synthesized. (C)</p> Signup and view all the answers

If a cell lacked single-strand binding proteins, what would be the most likely result during DNA replication?

<p>The DNA strands would re-anneal, preventing replication. (D)</p> Signup and view all the answers

What is the role of DNA gyrase in bacterial DNA replication?

<p>Prevent supercoiling of the DNA. (D)</p> Signup and view all the answers

What is the role of DnaA in bacterial DNA replication?

<p>Recognizing and binding to the origin of replication to initiate unwinding. (B)</p> Signup and view all the answers

If the 5' to 3' exonuclease activity of DNA polymerase I was non-functional, what would be the most likely immediate consequence during DNA replication?

<p>RNA primers would not be removed from Okazaki fragments. (B)</p> Signup and view all the answers

If ARSs (autonomously replicating sequences) were moved from their original location to a different location on a chromosome, what would likely occur?

<p>The location of replication initiation would change. (C)</p> Signup and view all the answers

How does the licensing of DNA replication origins in eukaryotes prevent re-replication within a single cell cycle?

<p>By preventing the assembly of pre-replicative complexes until after mitosis. (D)</p> Signup and view all the answers

Why might cells use error-prone DNA polymerases, despite the increased risk of mutations?

<p>Error-prone polymerases can bypass DNA lesions and allow replication to proceed. (C)</p> Signup and view all the answers

What is the outcome of the disruption of the original nucleosomes during eukaryotic DNA replication?

<p>It facilitates the reassembly of nucleosomes, using both preexisting and newly synthesized histones. (B)</p> Signup and view all the answers

What problem arises because DNA polymerase can only add nucleotides to the 3' end of a pre-existing strand?

<p>The ends of linear chromosomes shorten with each replication. (C)</p> Signup and view all the answers

What would happen if chromosome telomeres were lost?

<p>Chromosomes would shorten with each replication cycle. (C)</p> Signup and view all the answers

Why is homologous recombination important in cells?

<p>It ensures genetic stability and repairs double-strand DNA breaks. (B)</p> Signup and view all the answers

What is the fundamental outcome of the Holliday model of homologous recombination?

<p>It produces either crossover or noncrossover recombinant DNA with heteroduplex regions. (D)</p> Signup and view all the answers

What is the primary role of resolvase in homologous recombination?

<p>Cleaving Holliday junctions. (B)</p> Signup and view all the answers

How does the double-strand break model of recombination initiate the process differently from the Holliday model?

<p>It initiates with a double-strand break in one of the DNA molecules. (D)</p> Signup and view all the answers

Primase synthesizes short RNA stretches, providing a 3'-OH group to which DNA polymerase can add nucleotides. Where are these primers synthesized?

<p>At the 5' end of the newly synthesized, and at the beginning of each Okazaki fragment of the lagging strand. (C)</p> Signup and view all the answers

Which of the following explains what would happen if a recently synthesized DNA strand in E. coli was mistakenly not methylated?

<p>The mismatch repair system will recognize it as the new strand and correct it using the methylated strand as the template. (D)</p> Signup and view all the answers

Why does DNA synthesis occur in the cell nucleus of eukaryotes?

<p>DNA polymerase and helicase proteins are transported into the nucleus to perform replication. (D)</p> Signup and view all the answers

Which of the following enzymes are NOT directly involved in DNA repair?

<p>DNA Polymerase III (A)</p> Signup and view all the answers

What is one important characteristic of rolling-circle replication?

<p>It has a requirement for breakage of the nucleotide strand to begin. (B)</p> Signup and view all the answers

Which of the following proteins will NOT assist to unwinding and stabilizing DNA?

<p>DNA ligase (C)</p> Signup and view all the answers

If there is a single strand of DNA (5’-CCGGAATT-3’), then what is its other parental strand?

<p>3’-GGCCTTAA-5’ (D)</p> Signup and view all the answers

Which of the following characteristics are associated with DNA replication?

<p>It takes place with high accuracy and speed. (C)</p> Signup and view all the answers

Since DNA synthesis only goes from 5’ to 3’ which of the following is needed to assist?

<p>Okazaki fragments (B)</p> Signup and view all the answers

Which of the following would occur in the ABSENCE of primase?

<p>The lagging strand cannot be synthesized. (C)</p> Signup and view all the answers

In the double-strand break model for repairing DNA, what is the first step?

<p>Double-stranded DNA molecules from Homologous chromsomes align. (C)</p> Signup and view all the answers

What is the purpose of MCM proteins regarding linear eukaryotic replication?

<p>MCM, or minichromosome maintenance, is the double strand helicase that forms. (D)</p> Signup and view all the answers

Flashcards

Accuracy in Replication?

DNA replication must be extremely accurate to avoid catastrophic errors.

Semiconservative replication

The model where one double-stranded DNA molecule consists of one new and one old strand.

Conservative Replication

Model where both strands of DNA remain together after replication.

Dispersive Replication

Model where parental strands are dispersed into new double helices.

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Meselson and Stahl's Experiment

They grew E. coli in different nitrogen isotopes and used density gradient centrifugation.

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Replicons

These are the units of replication, each with its own origin.

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Theta Replication

DNA replication of circular DNA with a single origin, forming a replication fork.

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Rolling-Circle Replication

This is replication used by viruses and the F factor of E. coli, starting at a single origin.

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Linear Eukaryotic Replication

This replication occurs in eukaryotic cells, using thousands of points of origin.

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Replication Origin

The location where DNA unwinds and replication begins.

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Deoxyribonucleotides (dNTPs)

They are the raw materials for DNA synthesis.

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DNA Polymerase

Enzyme that adds nucleotides to the 3' end of a growing DNA strand

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5' to 3' Replication

The direction of DNA synthesis is read from 5' to 3'.

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Leading Strand

Synthesized continuously towards the replication fork.

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Lagging Strand

Synthesis that occurs discontinuously, away from the replication fork.

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Okazaki Fragments

Short DNA fragments synthesized discontinuously on the lagging strand.

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Bacterial DNA Replication

Bacterial DNA replication requiring enzymes/proteins.

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oriC

It's the specific DNA sequence where replicationstarts.

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Initiator Protein

It binds to oriC to initiate replication.

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DNA Helicase

Protein that unwinds double-stranded DNA.

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Single-Strand-Binding Proteins

They prevent single strands from forming secondary structures.

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DNA Gyrase (Topiosomerase)

Enzyme that relieves strain ahead of the replication fork.

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Primers

Short sequences to which nucleotides are added.

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Primase

It synthesizes short RNA sequences, providing a 3'-OH group.

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DNA Polymerase I

It removes RNA primers and replaces them with DNA.

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DNA Ligase

It joins Okazaki fragments, sealing breaks.

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Proofreading

3' to 5' exonuclease activity removes mismatched basepairs.

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Mismatch Repair

Corrects errors after replication by distinguishing between new and old strands.

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Polymerase Proofreading

DNA Polymerase I 3'->5' exonuclease activity removes incorrect nucleotides.

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ARSs (Autonomously Replicating Sequences)

DNA sequences where replication starts in eukaryotic cells.

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ORC (Origin Recognition Complex)

Complex binding to ARSs to initiate DNA replication.

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Licensing Factors (MCM)

They maintain the new strands for replication.

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Eukaryotic DNA

They’re complexed with histone proteins in nucleosomes.

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Telomeres and Telomerase

Telomeres protect the ends of chromosomes, with telomerase adding more.

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Homologous Recombination

Exchange between homologous DNA molecules during crossing over.

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Holliday Junction

Joining of strands that can form noncrossover or crossover recombinants.

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Double-Strand Break Model

This model involves enzymatic removal of nucleotides and strand displacement.

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Study Notes

DNA Replication Accuracy

  • Replication must be extremely accurate to avoid catastrophic consequences.
  • One error per million base pairs can lead to 6400 mistakes each cell division.
  • Replication is also very fast
  • E. coli replicates DNA at a rate of 1000 nucleotides per second.

DNA Replication Models

  • There are 3 proposed models of DNA replication: conservative, dispersive, and semiconservative.
  • In the conservative model, the entire original DNA molecule serves as a template for a completely new molecule.
  • In the dispersive model, regions of both strands of the original DNA molecule are interspersed with regions of new DNA in both strands of the new molecule.
  • In the semiconservative model, the 2 original DNA strands separate, and each strand serves as a template for a new strand.

Meselson and Stahl Experiment

  • Meselson and Stahl tested the 3 models of DNA replication in E. coli.
  • They used 2 nitrogen isotopes: the common form, 14N, and a rare, heavy form, 15N.
  • First, E. coli were grown in 15N media and then transferred to 14N media.
  • Cultured E. coli were then subjected to equilibrium density gradient centrifugation
  • After one round of replication, the DNA appeared as a single band at intermediate weight.
  • After a second round of replication, the DNA appeared as 2 bands, one light and one intermediate in weight.
  • These results support the semiconservative replication model.

Modes of Replication

  • Replicons are units of replication that contain a replication origin
  • Theta replication occurs in circular DNA with a single origin and forms a replication fork, typically proceeding bidirectionally.
  • Rolling-circle replication can be found in viruses and the F factor of E. coli and features a single origin of replication.
  • Linear eukaryotic replication happens in in eukaryotic cells, with thousands of origins and a replicon size of ~200,000–300,000 bp.

Linear Eukaryotic Replication Requirements

  • Linear eukaryotic replication necessitates a template strand, raw nucleotide materials, and certain enzymes and other proteins.
  • DNA polymerase adds nucleotides exclusively to the 3' end of the extending strand, meaning replication proceeds only in the 5' to 3' direction.
  • Replication is continuous on the leading strand and discontinuous on the lagging strand.
  • Okazaki fragments consist of discontinuously synthesized short DNA sequences forming the lagging strand.

Characteristics of Theta, Rolling-Circle, and Linear Eukaryotic Replication

  • Theta replication uses a circular template without nucleotide strand breakage, has 1 replicon, and may be unidirectional or bidirectional, resulting in 2 circular molecules.
  • Rolling-circle replication employs a circular template, involves nucleotide strand breakage, has 1 replicon, is unidirectional, and yields one circular and one linear molecule.
  • Linear eukaryotic replication utilizes a linear template, does not involve nucleotide strand breakage, has many replicons, is bidirectional, and results in 2 linear molecules.

Bacterial Replication: Initiation and Unwinding

  • Bacterial DNA replication initiates at a 245 bp sequence in the oriC (single origin replicon).
  • This process requires an initiator protein, DnaA in *E. coli
  • Unwinding also needs an initiator protein and DNA helicase.
  • Single-strand-binding proteins (SSBs) and DNA gyrase (topoisomerase) are also required.

Bacterial Replication: Elongation

  • Elongation is carried out by DNA polymerase III.
  • Primers consist of existing RNA nucleotides with a 3'-OH group for new nucleotide additions and are typically 10–12 nucleotides long
  • Primase is an RNA polymerase.
  • The leading strand requires a primer only at the 5' end.
  • The lagging strand requires a new primer at the beginning of each Okazaki fragment.

Bacterial Replication: Elongation Requirements

  • An active replication fork necessitates:
    • DNA helicase to unwind DNA.
    • Single-strand-binding proteins to protect single nucleotide strands.
    • DNA gyrase to relieve strain.
    • Primase to synthesize RNA primers w/ a 3'-OH group.
    • DNA polymerase to produce leading and lagging nucleotide strands.

Bacterial Replication: Termination

  • Elongation is carried out by DNA polymerase III.
  • RNA primers are removed via DNA polymerase I and connecting the nicks after RNA primers are removed, via DNA ligase.
  • Termination occurs when replication forks meet or by a termination protein.

Characteristics of E. coli DNA Polymerases

  • DNA polymerase I removes and replaces primers.
  • DNA polymerase II is involved in DNA repair and restarts replication, but halts synthesis.
  • DNA polymerase III elongates DNA.
  • DNA polymerase IV and V participate in DNA repair; translesion DNA synthesis.
  • All DNA polymerases synthesize any sequence specified by the template strand with the help of dNTPs to synthesize new DNA
  • They synthesize in the 5' - 3' direction by adding nucleotides to a 3'-OH group, and require a 3'-OH group to initiate synthesis and need other proteins
  • They catalyze the formation of a phosphodiester bond by joining the 5 -phosphate group of the incoming nucleotide to the 3 -OH group of the preceding nucleotide on the growing strand.
  • They produce newly synthesized strands that are complementary and antiparallel to the template strands
  • All polymerases has 5’ - 3’ polymerase activity but differ in exonuclease activity
  • DNA polymerase I has both 3’ - 5’ and 5’ - 3’ exonuclease activity
  • DNA polymerase II and III have 3’ - 5’ exonuclease activity
  • DNA polymerase IV and V have no exonuclease activity

Main Components of Bacterial Replication

  • Initiator proteins binds the origin to separate DNA strands.
  • DNA helicase unwinds DNA at the replication fork.
  • Single-strand-binding proteins attach to single-stranded DNA and prevent secondary structures.
  • DNA gyrase moves ahead of the replication fork and reseals breaks to release torque.
  • DNA primase synthesizes a short RNA primer to provide a 3'-OH group for DNA nucleotides.
  • DNA polymerase III elongates a new nucleotide strand from the 3' end.
  • DNA polymerase I removes RNA primers and replaces them with DNA.
  • DNA ligase joins Okazaki fragments by sealing breaks in the sugar-phosphate backbone.

The Fidelity of DNA Replication

  • DNA polymerase I's 3' to 5' exonuclease activity removes incorrectly paired nucleotides (proofreading).
  • Mismatch repair corrects errors after replication.

Eukaryotic DNA Replication Initiation

  • Eukaryotic DNA replication begins with autonomously replicating sequences (ARSs) that measure 100–120 bps.
  • The origin-recognition complex (ORC) binds to ARSs to start DNA replication.
  • ORC recruits and loads helicase, and eukaryotes don't require an initiator protein.

Licensing of Eukaryotic Replication

  • Licensing ensures DNA replication by the licensing factor.
  • ORC attaches to each origin of replication and joins with licensing factors to form MCM (minichromosome maintenance).
  • It involves eukaryotic DNA polymerase.

Eukaryotic DNA Polymerases

  • DNA polymerase alpha initiates nuclear DNA synthesis and DNA repair and has primase activity.
  • DNA polymerase delta participates in lagging-strand synthesis of nuclear DNA, DNA repair, and translesion DNA synthesis.
  • DNA polymerase epsilon leads strand synthesis.
  • DNA polymerase gamma replicates and repairs mitochondrial DNA.
  • DNA polymerase zeta, eta, iota, and kappa participate in translesion DNA synthesis.
  • DNA polymerase theta and lambda participates in DNA repair.
  • DNA polymerase mu and sigma possibly participates in nuclear DNA replication, DNA repair, and sister-chromatid cohesion
  • DNA polymerase phi (φ) and Rev1 participates in translesion DNA synthesis.

Creation of Nucleosomes in Eukaryotic Replication

  • Creation of nucleosomes requires original nucleosome disruption on the parental DNA, redistribution of preexisting histones, and new histones being synthesized.

The End-Replication Problem and Telomeres

  • Replication around the circle provides a 3'-OH group in front of the primer, nucleotides can be added when the primer is replaced.
  • Linear DNA telomeres, the terminal primer, are positioned 70-100 nucleotides from the chromosome's end, leaving a gap that can't be replicated.
  • To solve the end-replication problem, telomerase extends DNA, filling gaps from RNA primer removal.
  • Telomerase contains a protruding end w/ a G-rich repeated sequence and binds it, with the help of an RNA template.
  • Nucleotides are added to the 3' end of the G-rich strand and after several nucleotides have been added, the RNA template moves along the DNA,
  • More nucleotides are added and then the telomerase is removed.
  • Synthesis takes place on the complementary strand, filling in the gap due to the removal of the RNA primer at the end.

Recombination

  • Homologous recombination involves the exchange of homologous DNA molecules during crossing over for genetic variation and DNA repair
  • Recombination utilizes the Holliday junction and single-strand breaks.
  • The double-strand break model of recombination is also utilized.

The Holliday Model of Homologous Recombination

  • First, homologous chromosomes align and single-strand breaks occur in the same position on both DNA molecules.
  • A free end of each broken strand joins to the broken end of the other DNA molecule, creating a Holliday junction, and begins to displace the original complementary strand.
  • Branch migration takes place as the two nucleotide strands exchange positions, creating the two duplex molecules.
  • This view of the structure shows the ends of the two inter-connected duplexes pulled away from each other, and is rotated.
  • Cleavage and rejoining, of the nucleotide strands produces noncrossover recombinants consisting of two heteroduplex molecules
  • Noncrossover or crossover recombinant DNA, depending on whether cleavage is in the horizontal or the vertical plane.

Double-Strand Break Model of Recombination

  • 2 double-stranded DNA molecules from homologous chromosomes align, before a double-strand break occurs in one of the molecules.
  • Nucleotides are enzymatically removed, producing single-stranded DNA on each side, before a free 3' end invades and displaces a strand of the unbroken DNA molecule.
  • The 3' end then elongates, further displacing the original strand
  • The displaced strand forms a loop that base pairs with the broken DNA molecule, and DNA replicates on the bottom strand.
  • The resulting strand attachment produces two Holliday junctions.

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