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Calculate the induced EMF of a 4-pole dynamo having 1000 rpm lap wound and a total of 600 conductors, with a flux per pole of 0.064 Wb?
Calculate the induced EMF of a 4-pole dynamo having 1000 rpm lap wound and a total of 600 conductors, with a flux per pole of 0.064 Wb?
- 160V
- 480V
- 640V
- 320V (correct)
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Study Notes
DC Generator Induced EMF Calculation
- The question asks for the induced EMF of a DC generator.
- The generator has 4 poles, 600 conductors, and a flux per pole of 0.064 Wb.
- The generator is lap wound and rotates at 1000 rpm.
- The formula for induced EMF in a DC generator is: E = (P * Φ * Z * N) / (60 * A), where:
- E is the induced EMF
- P is the number of poles
- Φ is the flux per pole
- Z is the number of conductors
- N is the speed in rpm
- A is the number of parallel paths
- For a lap winding, the number of parallel paths is equal to the number of poles (A = P).
- Substituting the given values into the formula: E = (4 * 0.064 * 600 * 1000) / (60 * 4) = 320V.
- Therefore, the induced EMF of the DC generator is 320V, and the correct answer is (B).
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