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Calculate the induced EMF of a 4-pole dynamo having 1000 rpm lap wound and a total of 600 conductors, with a flux per pole of 0.064 Wb?
Calculate the induced EMF of a 4-pole dynamo having 1000 rpm lap wound and a total of 600 conductors, with a flux per pole of 0.064 Wb?
Study Notes
DC Generator Induced EMF Calculation
- The question asks for the induced EMF of a DC generator.
- The generator has 4 poles, 600 conductors, and a flux per pole of 0.064 Wb.
- The generator is lap wound and rotates at 1000 rpm.
- The formula for induced EMF in a DC generator is: E = (P * Φ * Z * N) / (60 * A), where:
- E is the induced EMF
- P is the number of poles
- Φ is the flux per pole
- Z is the number of conductors
- N is the speed in rpm
- A is the number of parallel paths
- For a lap winding, the number of parallel paths is equal to the number of poles (A = P).
- Substituting the given values into the formula: E = (4 * 0.064 * 600 * 1000) / (60 * 4) = 320V.
- Therefore, the induced EMF of the DC generator is 320V, and the correct answer is (B).
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Description
This quiz tests your understanding of the induced EMF calculation for a DC generator. It covers the application of the formula involving parameters such as poles, conductors, and rotational speed. Calculate the induced EMF using the provided values and confirm your answer based on the choices given.