DC Generator Induced EMF Calculation

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Questions and Answers

Calculate the induced EMF of a 4-pole dynamo having 1000 rpm lap wound and a total of 600 conductors, with a flux per pole of 0.064 Wb?

  • 160V
  • 480V
  • 640V
  • 320V (correct)

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Study Notes

DC Generator Induced EMF Calculation

  • The question asks for the induced EMF of a DC generator.
  • The generator has 4 poles, 600 conductors, and a flux per pole of 0.064 Wb.
  • The generator is lap wound and rotates at 1000 rpm.
  • The formula for induced EMF in a DC generator is: E = (P * Φ * Z * N) / (60 * A), where:
    • E is the induced EMF
    • P is the number of poles
    • Φ is the flux per pole
    • Z is the number of conductors
    • N is the speed in rpm
    • A is the number of parallel paths
  • For a lap winding, the number of parallel paths is equal to the number of poles (A = P).
  • Substituting the given values into the formula: E = (4 * 0.064 * 600 * 1000) / (60 * 4) = 320V.
  • Therefore, the induced EMF of the DC generator is 320V, and the correct answer is (B).

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