Circuit Diagram Equivalent Resistance Quiz

Study Notes

Circuit Diagram 1

A 30 Ω resistor is connected in series with a 20 Ω resistor.
The combination of the 30 Ω and 20 Ω resistors is then connected in parallel with a 60 Ω resistor
To find the equivalent resistance at terminals a-b, we first calculate the series combination of the 30 Ω and 20 Ω resistors.
The total resistance of the series combination is 30 Ω + 20 Ω = 50 Ω.
This 50 Ω resistor is then in parallel with the 60 Ω resistor.
The equivalent resistance of a parallel combination can be calculated using the formula: 1/R_eq = 1/R_1 + 1/R_2.
In this case, 1/R_eq = 1/50 + 1/60.
Solving for R_eq gives us approximately 27.27 Ω.

Circuit Diagram 2

A 30 Ω resistor is connected in parallel with a 60 Ω resistor.
A 40 Ω resistor is connected in parallel with an 80 Ω resistor.
The equivalent resistance of the parallel combination of the 30 Ω and 60 Ω resistors can be calculated using the formula: 1/R_eq = 1/R_1 + 1/R_2.
In this case, 1/R_eq = 1/30 + 1/60.
Solving for R_eq gives us 20 Ω.
The equivalent resistance of the parallel combination of the 40 Ω and 80 Ω resistors can be calculated using the formula: 1/R_eq = 1/R_1 + 1/R_2.
In this case, 1/R_eq = 1/40 + 1/80.
Solving for R_eq gives us 26.67 Ω.
The 20 Ω resistor is then connected in series with a 10 Ω resistor and a 50 Ω resistor.
The 26.67 Ω resistor is then connected in series with the combination of the 20 Ω, 10 Ω and 50 Ω.
The total resistance of the series combination is 20 Ω + 10 Ω + 50 Ω + 26.67 Ω = 106.67 Ω.
Therefore, the equivalent resistance at terminals a-b is 106.67 Ω.

Description

Test your knowledge on calculating equivalent resistance in circuits with resistors in series and parallel configurations. This quiz covers important formulas and calculations for finding the total resistance in different circuit arrangements.