Chemistry: Masking and Demasking Agents
This quiz covers the concepts of masking and demasking agents in chemistry, including their roles in titration and equilibrium reactions.
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Chemistry: Masking and Demasking Agents
Quiz • 24 Questions
Study Notes
2 min • Summary
Chemistry: Masking and Demasking Agents - Podcast
Podcast
Materials
List of Questions24 questions
- Question 1
- To react with the interfering metal ions
- To remove the masking agent
- To reverse the masking reaction and titrate the metal ion
- To form a more stable complex with the metal ion
- Question 2
- Only Cu is titrated
- Cu and Cd are titrated, but not Ca
- The sum of the three metals is titrated
- Only Ca is titrated
- Question 3
- To mask Cu and Cd, leaving only Ca to be titrated
- To demask the metal ions
- To remove the EDTA from the solution
- To react with EDTA and form a complex
- Question 4
- To mask Sn, Sb, Cd, and Hg
- To demask Sn, Sb, Cd, and Hg
- To mask Ni, Co, Zn, Cd, Cu, and Fe2+
- To react with EDTA and form a complex
- Question 5
- Direct titration
- Replacement titration
- Residual titration
- Back titration
- Question 6
- To selectively react with interfering metal ions and prevent them from reacting with the EDTA
- To react with the EDTA and form a complex
- To demask the metal ions
- To remove the EDTA from the solution
- Question 7
- Only Cu is demasked and titrated
- Both Cu and Cd are demasked and titrated
- Only Cd is demasked and titrated
- Neither Cu nor Cd is demasked
- Question 8
- To react with the metal ions and form a complex
- To mask the metal ions
- To demask the metal ions
- To remove the masking agent from the solution
- Question 9
- To determine the concentration of EDTA chelate
- When direct or back titrations do not give sharp end points
- To analyze barbiturate concentration
- To determine the concentration of Mn2+ ions
- Question 10
- It reacts with the Zn2+ ions
- It forms a complex with the barbiturate anion
- It precipitates with the EDTA chelate
- It displaces the Mg from the Mg-EDTA chelate
- Question 11
- To precipitate out Ca ions
- To remove EDTA chelate
- To dissociate the Mg-EDTA chelate
- To react with Zn2+ ions
- Question 12
- EDTA4- + Zn2+ ↔ Zn-EDTA2-
- Mg2+ + EDTA4- ↔ Mg-EDTA2- + 2H+
- Mn2+ + Mg-EDTA2- ↔ Mg2+ + Mn-EDTA2-
- Hg-B complex + excess EDTA4- ↔ B- + Hg-EDTA2- + EDTA4-
- Question 13
- To dissociate the Mg-EDTA chelate
- To precipitate out Ca ions
- To react with Al ions
- To remove EDTA chelate
- Question 14
- Determining the concentration of EDTA chelate
- Analyzing the concentration of barbiturate anions
- Titration of Zn2+ ions
- Determining the concentration of Mn2+ ions
- Question 15
- Because they react with a specific metal ion
- Because they usually give the total metal content
- Because they are not stable complexes
- Because they do not react with EDTA chelate
- Question 16
- To dissociate the Mg-EDTA chelate
- To remove EDTA chelate
- To precipitate out Ca ions
- To react with some transitional metals, Fe and Mn
- Question 17
- Because the pH affects the rate of complexation reaction
- Because the buffer solution is not effective at all pH levels
- Because the concentration of metal ions varies with pH
- Due to the effect of pH on the formation of complex ions
- Question 18
- Residual Titration
- Replacement Titration
- Direct Titration
- Complexometric Titration
- Question 19
- To control the role of H+ ion in chelation
- To maintain the stability of the complex formed
- To prevent the interference of other ions
- To ensure the formation of complex ions
- Question 20
- The pH of the solution
- The number of steps involved in complex formation
- The concentration of metal ions
- The stability of the complex formed
- Question 21
- It indicates the formation of complex ions
- It indicates the equivalence point in the titration
- It indicates the removal of traces of metal ions from solution
- It indicates the completion of complexation reaction
- Question 22
- Complexometric Titration
- Direct Titration
- Replacement Titration
- Residual Titration
- Question 23
- To stabilize the complex formed
- To provide a medium for complex formation
- To maintain the pH of the solution
- To control the rate of complexation reaction
- Question 24
- It increases the break in the titration curve
- It affects the rate of complexation reaction
- It decreases the break in the titration curve
- It has no effect on the titration curve