18 Questions
The weight of the liquid in the capillary is equal to the volume of the liquid multiplied by the acceleration due to gravity.
False
The pressure on the concave side is always lesser than the pressure on the convex side.
False
The mass of the liquid in the capillary rise is proportional to the square of the radius of the capillary tube.
True
The weight of the liquid in the capillary must be equal and opposite to the vertical component of the force due to gravity.
True
The density of the liquid in the capillary has no impact on the weight of the liquid.
False
The angle of contact of the liquid has no influence on the weight of the liquid in the capillary.
True
The phenomenon of rise or fall of a liquid inside a capillary tube is called capillarity.
True
When a capillary is dipped in a liquid, the liquid level can only rise in the capillary.
False
In the given scenario, it is mentioned that the points B and D are at different horizontal levels.
False
The text suggests that the mercury in the capillary rushes out to maintain different pressures between points A and C.
False
When a capillary tube is dipped in a liquid that does not wet its surface, such as mercury in glass, the liquid level in the capillary rises.
False
Blotting paper absorbing ink is an example where capillarity is not in action.
False
The force due to surface tension is given by T × 2πr.
True
The vertical component of the force due to surface tension is T × 2πr × cos(180°).
False
Einstein's first ever published scientific article was about the flow of water through capillaries.
False
The branch of Physics that studies properties of fluids in motion is called hydrodynamics.
True
The surface tension force is always directed perpendicular to the surface of the liquid.
False
The vertical component of the surface tension force can be calculated using T × 2πr × cos(θ).
True
This quiz discusses the phenomenon of capillary rise in liquids, explaining the behavior of liquid inside a capillary tube. The quiz refers to specific points and figures to illustrate the concept clearly.
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