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What is the maximum allowable compressive load on a column with a cross-sectional area of 144 ft² and a compressive stress limit of 200 psf?
What is the maximum allowable compressive load on a column with a cross-sectional area of 144 ft² and a compressive stress limit of 200 psf?
If the compressive stress on the column were to be increased to 250 psf while maintaining the same cross-sectional area, what would the maximum load be?
If the compressive stress on the column were to be increased to 250 psf while maintaining the same cross-sectional area, what would the maximum load be?
A column has a cross-sectional area that is half of 144 ft², maintaining the same compressive stress limit. What is the new maximum load?
A column has a cross-sectional area that is half of 144 ft², maintaining the same compressive stress limit. What is the new maximum load?
What would be the effect on the maximum load if the compressive stress limit is decreased to 150 psf while keeping the original cross-sectional area?
What would be the effect on the maximum load if the compressive stress limit is decreased to 150 psf while keeping the original cross-sectional area?
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If two identical columns, each with a maximum load of 28.8 kips, are connected in parallel, what is their combined maximum load?
If two identical columns, each with a maximum load of 28.8 kips, are connected in parallel, what is their combined maximum load?
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Study Notes
Calculating Maximum Load on a Column
- Given cross-sectional area (A) = 144 ft²
- Given maximum compressive stress (σ) = 200 psf
- Formula for stress: Stress = Force/Area (σ = F/A)
- To find the maximum force (F), rearrange the formula: F = σ * A
- Substitute the given values: F = 200 psf * 144 ft²
- Calculate the force: F = 28,800 lb
- Convert the force to kips: 28,800 lb = 28.8 kips
- Therefore, the maximum load that can be on the column is 28.8 kips.
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Description
This quiz aims to test your understanding of calculating the maximum load on a structural column based on given area and compressive stress. You'll apply the stress formula and perform unit conversions to find the final load. Perfect for students in engineering or physics courses.
