CHAPTER 10 : INDEPENDENCE AND CONDITIONAL PROBABILITIES

Choose a study mode

Play Quiz
Study Flashcards
Spaced Repetition
Chat to Lesson

Podcast

Play an AI-generated podcast conversation about this lesson
Download our mobile app to listen on the go
Get App

Questions and Answers

In a random individual with skin cancer, what is the probability that their cancer is located on their limbs?

  • 0.41
  • 0.44 (correct)
  • 0.80
  • 0.15

What is the probability that a randomly chosen individual with skin cancer on their head is a woman?

  • 0.37
  • 0.56 (correct)
  • 0.15
  • 0.44

What is the formula for Bayes' Rule?

  • P(A|B) = P(B|A) / P(A)
  • P(A|B) = P(A) * P(B|A) / P(B) (correct)
  • P(A|B) = P(B) / (P(A) * P(B|A))
  • P(A|B) = P(B) * P(A|B) / P(A)

What is the term used to describe the probability that a person actually has a disease given a positive test result?

<p>Positive Predictive Value (B)</p> Signup and view all the answers

What is the probability that a person with skin cancer will have the disease on their trunk?

<p>0.41 (B)</p> Signup and view all the answers

What is the probability of getting a heads result on a coin toss?

<p>0.5 (B)</p> Signup and view all the answers

Bayes’s theorem states that the probability of an event Ai given another event B is equal to:

<p>P(B|Ai)P(Ai) / P(B|A1)P(A1) + P(B|A2)P(A2) + ... + P(B|Ak)P(Ak) (A)</p> Signup and view all the answers

Calculate the probability that someone will get lung cancer given that they don't smoke.

<p>0.03 (C)</p> Signup and view all the answers

Calculate the probability that someone is a smoker and has lung cancer.

<p>0.0394 (A)</p> Signup and view all the answers

Are the events 'Smoker' and 'Lung cancer' independent?

<p>No (A)</p> Signup and view all the answers

What formula should be used to calculate the probability of two events A and B both occurring?

<p>P(A and B) = P(A)P(B|A) (B)</p> Signup and view all the answers

What is the probability of randomly catching two female frogs in a row from the artificial pond?

<p>0.25 (A)</p> Signup and view all the answers

Which of these is a correct interpretation of the formula P(A or B) = P(A) + P(B) - P(A and B)?

<p>The probability of event A or event B occurring is equal to the sum of the probabilities of each event occurring, minus the probability of both events occurring. (A)</p> Signup and view all the answers

Which of the following is NOT a true statement about independent events?

<p>The probability of event A and event B occurring is equal to the sum of the probabilities of each event occurring. (B)</p> Signup and view all the answers

If P(A) = 0.4 and P(B) = 0.5, and A and B are independent events, then what is P(A and B)?

<p>0.2 (B)</p> Signup and view all the answers

Which statement best defines independent events in probability?

<p>Two events are independent if knowing that one is true does not change the probability of the other. (A)</p> Signup and view all the answers

In a survey with 50 frogs, where there are 25 males and 25 females, what is the probability of picking a male frog first and then a male frog second when sampling without replacement?

<p>0.48 after getting the first male (B)</p> Signup and view all the answers

What is the primary concept illustrated by Bayes’s theorem in probability?

<p>Determining the conditional probability of events. (B)</p> Signup and view all the answers

Which situation exemplifies dependent events?

<p>Choosing a card from a deck and not replacing it before drawing another. (B)</p> Signup and view all the answers

What does conditional probability measure?

<p>The likelihood of an event given that another event has occurred. (C)</p> Signup and view all the answers

Flashcards

Independent Events

Two events are independent if the occurrence of one does not affect the probability of the other.

Conditional Probability

The probability of an event occurring given that another event has occurred.

Sampling without Replacement

A sampling method where selected individuals are not returned to the population, affecting subsequent probabilities.

General Addition Rule

A rule used to calculate the probability of the union of two events, considering their intersection.

Signup and view all the flashcards

Bayes’s Theorem

A mathematical formula that describes how to update the probability of a hypothesis based on new evidence.

Signup and view all the flashcards

Probability of type O

The likelihood that two visitors are both type O blood.

Signup and view all the flashcards

Tree Diagrams

A graphical method to visualize and calculate probabilities.

Signup and view all the flashcards

P(woman | head)

The probability a person is a woman given they have head skin cancer.

Signup and view all the flashcards

Positive Predictive Value (PPV)

The probability of having a disease given a positive test result.

Signup and view all the flashcards

Bayes' Rule

A formula to connect conditional probabilities of events.

Signup and view all the flashcards

Disjoint Events

Events A and B cannot both happen, thus P(A or B) = P(A) + P(B).

Signup and view all the flashcards

Multiplication Rule

P(A and B) = P(A)P(B|A), probability of both events occurring.

Signup and view all the flashcards

Multiplication Rule for Independents

If A and B are independent, P(A and B) = P(A)P(B).

Signup and view all the flashcards

Probability Example: Dalmatian

P(HI | B) = P(HI and B) / P(B) to determine dependence.

Signup and view all the flashcards

Smoker and Lung Cancer

Given data on smokers, consider if smoking is independent of lung cancer risk.

Signup and view all the flashcards

Study Notes

Course Information

  • Course Title: BMS 511 Biostats & Statistical Analysis
  • Chapter: 10
  • Topic: Independence and Conditional Probabilities

Previous Learning Objectives

  • Probability concepts
  • Randomness and probability
  • Probability models
  • Probability rules
  • Discrete vs. continuous models
  • Random variables
  • Mean and variances for discrete models
  • Risk and odds

Learning Objectives

  • Define general rules of probability
  • Independent events
  • Conditional probability
  • General addition rule
  • Multiplication rule
  • Tree diagrams
  • Bayes's theorem
  • Diagnosis test

Independent Events

  • Two events are independent if one event's outcome doesn't change the other's probability
  • Examples:
    • "Male" and "getting heads when flipping a coin" are independent
    • "Male" and "taller than 6 ft" are NOT independent
    • "Male" and "high cholesterol" are likely independent
    • "Male" and "pregnant" are NOT independent

Sampling without Replacement

  • Picking one item from a group and not putting it back affects the next selection's probability
  • Successive picks are NOT independent in smaller groups
  • Successive picks are "nearly" independent in larger groups (e.g., thousands of frogs)

Conditional Probability

  • Conditional probability of event B, given event A: (P(A and B)) / (P(A))
  • If A and B are independent: P(B | A) = P(B)

Independence Example

  • Example shows probabilities of hearing impairment and blue eyes in Dalmatians
  • P(HI and B) = 0.05
  • P(HI) = 0.28
  • P(B) = 0.11
  • P(HI | B) ≈ 0.45
  • Events are not independent

Another Independence Example

  • (1 of 2) 11% of the population smokes,
  • probability a smoker gets lung cancer: 0.34,
  • probability a non-smoker gets lung cancer is 0.03.
  • (2 of 2) Determine if smoking and lung cancer are independent.

General Addition Rule

  • (1 of 2) Addition rule for disjoint events: P(A or B) = P(A) + P(B)
  • (2 of 2) General addition rule for any two events A and B: P(A or B) = P(A) + P(B) − P(A and B)

Multiplication Rule

  • General multiplication rule: P(A and B) = P(A)P(B|A)
  • Multiplication rule for independent events: P(A and B) = P(A)P(B)

Multiplication Rule Examples

  • Example of frogs in an artificial pond
  • Example of unrelated blood donors

Tree Diagrams

  • Used to visually represent probabilities and facilitate calculations
  • Example: Skin cancer probabilities among men and women based on body locations

Tree Diagram Example - Diagnostic Tests

  • Shows disease rate, sensitivity, specificity
  • Explains positive predictive value (PPV)

Bayes' Theorem

  • Formula: (P(A|B) = (P(A) * P(B|A)) / P(B))
  • Example: Probability of rolling a 3 and 4 on a die.

Bayes's theorem

  • A¡, A2, ..., Ak are disjoint events with probabilities that add to 1
  • B is any other event
  • P(A¡|B) =((P(B|A¡) * P(A¡)) / Σ (P(B|Ai) * P(Ai)))

Diagnosis Tests

  • Includes prevalence, sensitivity, specificity
  • Shows calculation of probability of having a disease given a positive test result (positive predictive value)

Diagnostic Tests Examples: HIV-AIDS

  • Example using an enzyme immunoassay test.

Another Diagnostic Tests Example (prostate cancer)

  • Prostate cancer rates
  • PSA test sensitivity and specificity
  • Calculating positive predictive value

Comparison of Screening/Diagnostic Test Results with Actual Disease Status

  • Summarizes test results for disease vs. no disease.

Studying That Suits You

Use AI to generate personalized quizzes and flashcards to suit your learning preferences.

Quiz Team

Related Documents

More Like This

Use Quizgecko on...
Browser
Browser