Balancing Chemical Equations Quiz

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Questions and Answers

How many moles of nitrogen trifluoride are produced when 3.5 moles of nitrogen react with excess fluorine?

  • 10.5 moles
  • 1.75 moles
  • 7.0 moles (correct)
  • 3.5 moles

If 0.034 moles of nitrogen are reacted, how many moles of fluorine will react?

  • 0.034 moles
  • 0.017 moles
  • 0.051 moles
  • 0.068 moles (correct)

How many moles of water are produced when 0.00901 moles of oxygen are reacted with excess hexane?

  • 0.0045 moles (correct)
  • 0.0182 moles
  • 0.01352 moles
  • 0.00901 moles

How many molecules of water are produced from the reaction of 0.00901 moles of oxygen?

<p>3.01 x 10^20 molecules (D)</p> Signup and view all the answers

How many moles of carbon dioxide will be produced from the reaction of 6.70 moles of potassium bicarbonate with excess hydrobromic acid?

<p>3.35 moles (A)</p> Signup and view all the answers

If 0.45 moles of hydrobromic acid reacts with excess potassium bicarbonate, how many molecules of water will be produced?

<p>1.35 x 10^23 molecules (A)</p> Signup and view all the answers

How many moles of sodium bromide will be produced from 70.9 moles of sodium sulfite reacting with excess gallium bromide?

<p>70.9 moles (C)</p> Signup and view all the answers

How many molecules of sodium bromide are produced from 70.9 moles of sodium sulfite?

<p>4.27 x 10^24 molecules (A)</p> Signup and view all the answers

How many moles of nitrogen trifluoride are needed to react with 2.3 x 10^-3 moles of tin (II) oxide?

<p>0.00115 moles (B)</p> Signup and view all the answers

How many molecules of tin (II) oxide are required to produce 7.02 x 10^24 molecules of nitrogen trifluoride?

<p>1.40 x 10^24 molecules (B)</p> Signup and view all the answers

How do you balance the equation ___ N2 + ___ F2 → ___ NF3?

<p>1 N2 + 3 F2 → 2 NF3 (A)</p> Signup and view all the answers

When 0.00901 moles of oxygen reacts with excess hexane, how many moles of carbon dioxide are produced?

<p>0.004505 moles (A)</p> Signup and view all the answers

In the reaction ___ HBr + ___ KHCO3 → ___ H2O + ___ KBr + ___ CO2, how many moles of water are produced when 6.70 moles of potassium bicarbonate react with excess hydrobromic acid?

<p>6.70 moles (A)</p> Signup and view all the answers

How many molecules of carbon dioxide are produced from the reaction of 6.70 moles of KHCO3 with excess HBr?

<p>1.34 x 10^24 molecules (B)</p> Signup and view all the answers

In the reaction of gallium bromide with sodium sulfite, if 70.9 moles of sodium sulfite reacts, how many moles of gallium sulfite are produced?

<p>70.9 moles (D)</p> Signup and view all the answers

How many molecules of sodium bromide will be produced from the reaction of 70.9 moles of sodium sulfite?

<p>8.54 x 10^24 molecules (C)</p> Signup and view all the answers

What is the balanced equation for the reaction of tin (II) oxide with nitrogen trifluoride?

<p>2 SnO + 6 NF3 → 2 SnF2 + 3 N2O3 (C)</p> Signup and view all the answers

If 2.3 x 10^-3 moles of tin (II) oxide is used in reaction with nitrogen trifluoride, how many moles of nitrogen trifluoride are needed?

<p>6.9 x 10^-3 moles (B)</p> Signup and view all the answers

How many molecules of nitrogen trifluoride are produced from 7.02 x 10^24 molecules of nitrogen trifluoride?

<p>1 mol (A)</p> Signup and view all the answers

What is the balanced chemical equation for the reaction of nitrogen and fluorine to produce nitrogen trifluoride?

<p>1 N2 + 3 F2 → 2 NF3 (B)</p> Signup and view all the answers

In the balanced equation of the reaction between hexane and oxygen, how many moles of carbon dioxide are produced when oxygen reacts with excess hexane?

<p>2 moles (A)</p> Signup and view all the answers

How many molecules of water are produced from 0.00901 moles of oxygen reacting with excess hexane?

<p>3.61 x 10^22 molecules (B)</p> Signup and view all the answers

What is the number of moles of carbon dioxide produced in the reaction of potassium bicarbonate with hydrobromic acid when 6.70 moles of KHCO3 are used?

<p>3.35 moles (D)</p> Signup and view all the answers

How many moles of sodium bromide are produced when 70.9 moles of sodium sulfite react with excess gallium bromide?

<p>141.8 moles (B)</p> Signup and view all the answers

If 0.45 moles of hydrobromic acid react with potassium bicarbonate, how many moles of water are produced?

<p>0.30 moles (B)</p> Signup and view all the answers

In reactions involving tin (II) oxide and nitrogen trifluoride, if 2.3 x 10^-3 moles of tin (II) oxide are used, how many moles of nitrogen trifluoride are required?

<p>4.6 x 10^-3 moles (C)</p> Signup and view all the answers

Calculate how many molecules of water could be produced if 6.70 moles of potassium bicarbonate react completely with hydrobromic acid.

<p>1.61 x 10^24 molecules (B)</p> Signup and view all the answers

When reacting with nitrogen trifluoride, how many moles of tin (II) fluoride can be obtained from a given amount of tin (II) oxide?

<p>Directly relates to the moles of nitrogen trifluoride used (A)</p> Signup and view all the answers

Flashcards

Balancing Chemical Equations

Adjusting coefficients in a chemical equation to ensure the same number of atoms of each element are present on both sides of the equation.

Moles of Reactants

The amount of a substance measured in moles, directly related to the number of molecules.

Moles of Products

The amount of a substance produced from a reaction, quantifiable in moles.

Mole Ratio

The ratio between the moles of one reactant or product to the moles of another.

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Avogadro's Number

The number of atoms or molecules in one mole of a substance (approximately 6.022 x 10^23).

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Stoichiometry

The calculation of reactants and products in a chemical reaction using mole ratios from the balanced equation.

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Reaction Balancing Example

Adjusting the coefficients in a chemical equation to ensure equal number of atoms of each element on each side of the equation, e.g. N2 + 3F2 → 2NF3.

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Calculating Moles of Reactant or Product

Using the given amounts (moles) of one substance in a balanced chemical reaction to determine the moles of another substance involved in the reaction, applying the mole ratio.

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Calculating molecules

Using Avogadro's Number to convert moles of a substance into molecules.

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Gallium bromide reacts with sodium sulfite to produce gallium sulfite and sodium bromide.

A chemical reaction where gallium bromide interacts with sodium sulfite to yield gallium sulfite and sodium bromide. This chemical reaction has a definite stoichiometry.

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Tin(II) Oxide Reacts with Nitrogen Trifluoride

In a chemical reaction, tin(II) oxide reacts with nitrogen trifluoride, creating tin(II) fluoride and dinitrogen trioxide.

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Balancing Chemical Equations N2 + F2

Adjusting the coefficients in a chemical equation to have an equal number of atoms of each element on both sides of the equation. Example: N2 + 3F2 → 2NF3

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Moles of Nitrogen Trifluoride from 3.5 moles N2

If 3.5 moles of Nitrogen react, then 7 moles of Nitrogen Trifluoride will be produced given the balanced chemical equation N2 + 3F2 → 2NF3

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Moles of Fluorine with 0.034 moles N2

0.102 moles of Fluorine will react with 0.034 moles of Nitrogen, based on the mole ratio from the balanced equation.

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Mole Ratio N2 and NF3

The mole ratio between nitrogen and nitrogen trifluoride in the reaction N2 + 3F2 → 2NF3 is 1:2

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Moles of Water from 0.009 moles Oxygen (C6H10 + O2)

Given that 0.00901 moles of oxygen reacts with excess hexane, 0.00901 moles of water will be produced (assuming excess of hexane and no other factors), based on the balanced reaction.

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Molecules of Water from 0.00901 moles

0.00901 moles of water contain approximately 5.42 x 10^21 molecules, using Avogadro's number.

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Balancing Chemical Equation HBr + KHCO3

Balancing the equation HBr + KHCO3 → H2O + KBr + CO2. This yields HBr + KHCO3 → H2O + KBr + CO2 using correct coefficients

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Moles of CO2 from 6.70 moles KHCO3

6.70 moles of potassium bicarbonate will produce 6.70 moles of carbon dioxide, based on the balanced equation.

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Moles of water From HBr and KHCO3

From 0.45 moles of HBr with excess KHCO3, approximately 0.45 moles of water is produced, based on the balanced chemical equation.

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Balanced Reaction: Gallium Bromide and Sodium Sulfite

3Na₂SO₃ + 2GaBr₃ → 3NaBr + Ga₂(SO₃)₃, representing the balanced reaction.

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Moles of NaBr from 70.9 moles Na₂SO₃

If 70.9 moles of sodium sulfite react, 106.35 moles of sodium bromide are created

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Molecules of NaBr from 70.9 moles Na₂SO₃

Approx. 6.45 x 10^25 molecules of Sodium Bromide are created (70.9 Moles x 6.02 x 10²³).

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Balanced Reaction: Tin (II) Oxide and Nitrogen Trifluoride

SnO + 3NF3 → SnF2 + N2O3

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Moles of NF3 from 2.3 x 10⁻³ moles SnO

2.3 x 10⁻³ moles of Tin (II) oxide require 6.9 x 10⁻³ moles of Nitrogen Trifluoride

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Moles of SnO for 7.02 x 10²⁴ molecules NF3

Producing 7.02 x 10²⁴ molecules of nitrogen trifluoride needs 1.17 x 10⁻³ moles of SnO

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Balance N2 + F2 → NF3

Adjust the coefficients in the chemical equation N2 + F2 → NF3 to have equal numbers of each atom on both sides of the equation.

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Moles NF3 from 3.5 mol N2

Calculate the moles of nitrogen trifluoride (NF3) produced when 3.5 moles of nitrogen (N2) react, given the balanced equation.

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Moles F2 needed for 0.034 mol N2

Determine the moles of fluorine (F2) required to react with 0.034 moles of nitrogen (N2), based on the balanced equation.

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Moles NF3 from 0.034 mol N2

Calculate the moles of nitrogen trifluoride (NF3) produced when 0.034 moles of nitrogen (N2) reacts, given the balanced equation.

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Molecules NF3 from moles

Convert the moles of NF3 to the number of molecules using Avogadro's number.

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Balance C6H10 + O2 → CO2 + H2O

Adjust the coefficients in the chemical equation C6H10 + O2 → CO2 + H2O to have equal numbers of each atom on both sides of the equation.

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Moles H2O from 0.009 mol O2

Calculate the moles of water (H2O) produced when 0.00901 moles of oxygen (O2) react with excess hexane (C6H10).

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Molecules H2O from moles

Convert moles of water to molecules using Avogadro's number.

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Balance HBr + KHCO3 → H2O + KBr + CO2

Adjust coefficients in HBr + KHCO3 → H2O + KBr + CO2 to equal the number of atoms on each side of the equation.

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Moles CO2 from 6.70 mol KHCO3

Calculate moles of CO2 produced from 6.70 moles of KHCO3, given the balanced equation in the reaction.

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Moles H2O from 0.45 mol HBr

Calculate moles of H2O produced when 0.45 moles of HBr reacts with excess KHCO3, based on the balanced equation.

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Balance Gallium Bromide and Sodium Sulfite

Determine the coefficients to balance the reaction: 3Na₂SO₃ + 2GaBr₃ → 3NaBr + Ga₂(SO₃)₃

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Moles NaBr from 70.9 mol Na₂SO₃

Calculate the moles of NaBr produced when 70.9 moles of Na₂SO₃ react, based on the balanced reaction.

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Molecules of NaBr from 70.9 mol Na₂SO₃

Determine the number of NaBr molecules produced from 70.9 mole of Na₂SO₃, utilizing the balanced chemical equation and Avogadro's number.

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Balance Tin (II) Oxide and Nitrogen Trifluoride

Determine correct coefficients to balance SnO + NF3 → SnF2 + N2O3

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Moles NF3 from 2.3 x 10⁻³ moles SnO

Calculate moles of NF3 required to react with 2.3 x 10⁻³ moles of SnO, considering the balanced equation for SnO + NF3 reaction.

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Moles SnO for 7.02 x 10²⁴ molecules NF3

Calculate moles of SnO required to produce 7.02 x 10²⁴ molecules of NF3, based on the balanced reaction between Tin (II) oxide and Nitrogen Trifluoride.

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Study Notes

Balancing Chemical Equations

  • N₂ + 3F₂ → 2NF₃ (Balanced equation)

  • If 3.5 moles of nitrogen react, 7 moles of NF₃ will be produced (using stoichiometry)

  • 0.034 moles of nitrogen will react with 0.102 moles of fluorine (using stoichiometry)

  • 0.068 moles of nitrogen trifluoride will be produced (using stoichiometry)

  • 4.1 x 10²² molecules of NF₃ will be produced (using Avogadro's number)

  • C₆H₁₀ + 9O₂ → 6CO₂ + 5H₂O (Balanced equation)

  • If 0.00901 moles of oxygen react, 0.00451 moles of water will be produced (using stoichiometry)

  • 2.72 x 10²² molecules of water will be produced (using Avogadro's number)

  • HBr + KHCO₃ → H₂O + KBr + CO₂ (Balanced equation)

  • If 6.70 moles of KHCO₃ react, 6.70 moles of CO₂ will be produced (using stoichiometry)

  • 2.7 x 10²³ molecules of water will be produced from 0.45 moles of HBr (using stoichiometry and Avogadro's number)

Gallium Bromide and Sodium Sulfite Reaction

  • GaBr₃ + Na₂SO₃ → Ga₂(SO₃)₃ + 6NaBr (Balanced equation)
  • If 70.9 mol of Na₂SO₃ reacts, 425.4 mol of NaBr will be produced (using stoichiometry)
  • 2.56 x 10²⁶ molecules of NaBr (using stoichiometry and Avogadro's number)

Tin (II) Oxide and Nitrogen Trifluoride

  • SnO + 2NF₃ → SnF₂ + N₂O₃ (Balanced equation)
  • 4.6 x 10⁻³ moles of NF₃ are needed to react with 2.3 x 10⁻³ moles of SnO (using stoichiometry)
  • 1.5 x 10²² molecules of SnO are required to produce 7.02 x 10²⁴ molecules of NF₃. (using Avogadro's and stoichiometry)

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