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Questions and Answers
Which of the following assignment operators is equivalent to 'x = x + 20'?
Which of the following assignment operators is equivalent to 'x = x + 20'?
- x -= 20
- x += 20 (correct)
- x *= 20
- x /= 20
What is the value of x after the following code is executed?
int x = 5;
x -= 6;
What is the value of x after the following code is executed? int x = 5; x -= 6;
- 11
- 0
- -1 (correct)
- 1
What is the value of x after the following code is executed?
int x = 2, y = 8;
x *= y - 4;
What is the value of x after the following code is executed? int x = 2, y = 8; x *= y - 4;
- 22
- 16 (correct)
- 20
- 18
What is the value of x after the following code is executed?
int x = 2, y = 8;
x *= y - 4;
x *= y - 4;
What is the value of x after the following code is executed? int x = 2, y = 8; x *= y - 4; x *= y - 4;
What is the value of x after the following code is executed?
int x = 5;
x %= 2;
What is the value of x after the following code is executed? int x = 5; x %= 2;
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Study Notes
Assignment Operators
- The operator equivalent to
x = x + 20isx += 20.
Value of x after Operations
-
After executing
int x = 5; x -= 6;, the value of x becomes -1.- This is due to subtracting 6 from the initial value of 5.
-
After executing
int x = 2, y = 8; x *= y - 4;, the value of x becomes 8.- The calculation is
x *= 4(asy - 4equals 4), resulting in2 * 4 = 8.
- The calculation is
-
After executing
int x = 2, y = 8; x *= y - 4; x *= y - 4;, the value of x becomes 32.- The first calculation gives 8 (as previously noted), and the second one computes
x *= 4, leading to8 * 4 = 32.
- The first calculation gives 8 (as previously noted), and the second one computes
-
After executing
int x = 5; x %= 2;, the value of x becomes 1.- The modulus operation
5 % 2computes the remainder of dividing 5 by 2, which is 1.
- The modulus operation
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