AS Level Mathematics Test: Graph Transformations, Trigonometry, and Quadratics
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Questions and Answers

Explain the transformation $y = |2x - 3| + 4$ in terms of shifts and reflections.

The transformation involves a horizontal shift of 3 units to the right, a vertical shift of 4 units upwards, and a reflection in the x-axis.

Solve the equation $2 ext{cos}(x + rac{ ext{$rac{ ext{$ ext{$ ext{$rac{ ext{$ ext{$ ext{$ ext{$ ext{$ ext{$ ext{$ ext{$ ext{$ ext{$ ext{$ ext{$ ext{$ ext{1}}{2}$} ext{cos}(x + 1)) = 0$ for $0 extless x extless 2 ext{$ ext{$ ext{pi}$}$}.

The solutions are $x = rac{ ext{$ ext{$ ext{3}}{2}$}$} ext{pi}$ and $x = rac{ ext{$ ext{$ ext{5}}{2}$}$} ext{pi}$.

Find the x-coordinate of the vertex of the quadratic function $f(x) = 3x^2 + 4x - 6$.

The x-coordinate of the vertex is $-rac{4}{6} = -rac{2}{3}$.

Study Notes

Transformation of the Absolute Value Function

  • The transformation $y = |2x - 3| + 4$ can be broken down into several components:
    • Horizontal shift 3 units to the right
    • Horizontal scaling by a factor of 2
    • Reflection over the x-axis
    • Vertical shift 4 units up

Solving a Trigonometric Equation

  • The equation $2\cos(x + \frac{1}{2}) = 0$ is a trigonometric equation
  • To solve for $x$, we need to find the values of $x$ in the interval $0 \leq x \leq 2\pi$ that satisfy the equation
  • The solution involves finding the inverse cosine of both sides of the equation

Quadratic Function Vertex

  • The quadratic function $f(x) = 3x^2 + 4x - 6$ has a vertex
  • To find the x-coordinate of the vertex, we can use the formula $x = -\frac{b}{2a}$
  • Plugging in the values $a = 3$ and $b = 4$, we get the x-coordinate of the vertex

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Description

This test paper covers AS level topics including graph transformations, trigonometry (excluding cosec/sec/cot), and quadratics. Test your knowledge and understanding of these key mathematical concepts.

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