AQA A-Level Physics 2.2 Electromagnetic Radiation and Quantum Phenomena Flashcards

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Questions and Answers

What happens when high voltage is applied across mercury vapor in a fluorescent tube?

  • Mercury atoms are excited and then return to the ground state, releasing UV photons.
  • The tube's phosphorus coating absorbs UV photons.
  • Fast-moving free electrons collide with the mercury atoms. (correct)
  • Mercury atoms cascade down energy levels and emit visible light photons.

Which process leads to the emission of visible light photons in a fluorescent tube?

  • Return of mercury atoms to the ground state
  • Absorption of UV photons by the phosphorus coating
  • Excitation of mercury electrons (correct)
  • Collision of free electrons with mercury atoms

What evidence supports the existence of discrete energy levels in atoms?

  • Variable emission wavelengths
  • Continuous emission spectra
  • Line emission and absorption spectra (correct)
  • Random absorption of photons

Which phenomenon states that all particles exhibit both wave and particle properties?

<p>Wave-particle duality (A)</p> Signup and view all the answers

In a fluorescent tube, what role does the phosphorus coating play?

<p>Absorbing UV photons (B)</p> Signup and view all the answers

What triggers the emission of UV photons in a fluorescent tube?

<p>Excitation of mercury atoms by absorbed UV photons (D)</p> Signup and view all the answers

Why do we observe lines at discrete points in line emission and absorption spectra?

<p>Because electrons can only absorb an exact amount of energy (A)</p> Signup and view all the answers

What property of waves do particles exhibit according to wave-particle duality?

<p>Diffraction (A)</p> Signup and view all the answers

How do line emission and absorption spectra relate to discrete energy levels in atoms?

<p>They indicate where specific energy transitions take place in atoms. (B)</p> Signup and view all the answers

What happens to the electrons in a fluorescent tube's phosphorus coating after absorbing UV photons?

<p>They are excited and cascade down energy levels. (D)</p> Signup and view all the answers

Flashcards

Excitation of mercury atoms

Electrons in mercury atoms absorb energy and jump to higher energy levels.

Emission of UV photons

Excited mercury atoms release energy by emitting photons.

Electron excitation

The process by which electrons in atoms absorb energy and jump to higher energy levels.

Line emission spectrum

The specific wavelengths of light emitted by excited atoms.

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Discrete energy levels

The energy levels that electrons in atoms can occupy are discrete and not continuous.

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Wave-particle duality

The phenomenon where particles, such as electrons, exhibit both wave-like and particle-like properties.

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Diffraction of light

The phenomenon where light bends around obstacles, demonstrating its wave-like nature.

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UV photon conversion

The process of converting UV photons into visible light photons.

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Phosphorus coating

The material that absorbs UV photons and emits visible light photons.

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Electron de-excitation

The process by which excited electrons in phosphorus atoms release energy and cascade down to lower energy levels.

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Study Notes

Electromagnetic Waves

  • Electromagnetic waves are classified as transverse waves.

Particle Behavior of Light

  • The photoelectric effect demonstrates the particle nature of light.

Photoelectric Effect

  • Occurs when light above a specific frequency shines on metal, releasing electrons known as photoelectrons.

Threshold Frequency

  • Defined as the minimum frequency of light necessary for an electron to be emitted from a metal surface.

Photon Energy Calculation

  • The energy of a photon can be calculated using the equation E = hf = hc/λ, where:
    • E = energy
    • h = Planck’s constant
    • f = frequency
    • c = speed of light (3 x 10^8 m/s)
    • λ = wavelength

Minimum Frequency Requirement

  • A photon must exceed a certain frequency for electron liberation, as its energy must surpass the work function (the energy needed to free an electron).

Effects of Higher Frequency Photon

  • If a photon’s frequency is above the threshold, the electron is liberated, and any excess energy translates into the electron's kinetic energy.

Effect of Increased Light Intensity

  • If photoelectric emission does not occur, increasing light intensity means more photons strike the metal, but unless the photon energy is sufficient, electron emission will not occur.

Photoelectric Equation

  • The equation representing the photoelectric effect is given by:
    • Planck’s constant × frequency = work function + maximum kinetic energy of emitted photoelectrons.

Work Function Definition

  • The work function is the energy required to free an electron from the metallic bonds holding it within a metal.

Electron Volt Explanation

  • An electron volt (eV) is defined as the kinetic energy gained by an electron when accelerated through a potential difference of 1 volt.

Conversion Between Electron Volts and Joules

  • To convert between electron volts and joules, use the conversion factor: 1 eV = 1.6 x 10^-19 joules.

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