Podcast
Questions and Answers
What is the value of $\sqrt{2} \sqrt{18}$?
What is the value of $\sqrt{2} \sqrt{18}$?
What is the value of $\frac{\sqrt{8}}{\sqrt{18}}$?
What is the value of $\frac{\sqrt{8}}{\sqrt{18}}$?
What are the values of $x$ and $y$ in the equation $4y + 2x = 3$?
What are the values of $x$ and $y$ in the equation $4y + 2x = 3$?
x=1.5, y=0; x=0, y=0.75
What does $\frac{10}{\sqrt{5}}$ simplify to?
What does $\frac{10}{\sqrt{5}}$ simplify to?
Signup and view all the answers
What is the slope of the line from the points (0,1) and (3,-8)?
What is the slope of the line from the points (0,1) and (3,-8)?
Signup and view all the answers
If a pizzeria charges 14.99 cents for 2 pizzas and 12.99 cents for 3 pitchers of soda with a max spend of $75, how many pizzas can they buy?
If a pizzeria charges 14.99 cents for 2 pizzas and 12.99 cents for 3 pitchers of soda with a max spend of $75, how many pizzas can they buy?
Signup and view all the answers
Study Notes
Square Root Calculations
- √2 * √18 simplifies to 6.
- √8 divided by √18 results in 12/18 (or 2/3 after simplification).
Linear Equations
- The equation 4y + 2x = 3 has multiple solutions including:
- x = 1.5, y = 0
- x = 0, y = 0.75
Simplifying Expressions
- The expression 10 divided by √5 simplifies to 2√5.
Finding Slope from Points
- Slope calculation from points (0,1) and (3,-8) is -3.
- The line equation can be represented as Y = (-3/9)x + 1.
Inequalities and Budgeting
- A pizzeria charges $14.99 for 2 pizzas and $12.99 for 3 pitchers of soda.
- With a maximum budget of $75, the problem asks how many pizzas can be purchased (let x equal the number of pizzas).
Studying That Suits You
Use AI to generate personalized quizzes and flashcards to suit your learning preferences.
Description
Test your understanding of algebraic concepts including square root calculations, linear equations, simplifying expressions, and finding slopes. This quiz will challenge your ability to apply these principles in practical scenarios, such as budgeting for pizza purchases. Get ready to solve and simplify!