Algebra 2: Final Exam Review - Part 3
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Algebra 2: Final Exam Review - Part 3

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Questions and Answers

What is the value of 3!?

6

What is the value of 4!/2!?

12

What is the value of 7C2?

21

What is the value of 4C3 + 6C5?

<p>10</p> Signup and view all the answers

What is the value of 6P2?

<p>30</p> Signup and view all the answers

Are the two events of randomly selecting a student and then another student from the same class independent or dependent?

<p>Dependent</p> Signup and view all the answers

Are the two events of tossing a number cube to select a number, and then tossing it again to select another number independent or dependent?

<p>Independent</p> Signup and view all the answers

How many ways can you choose 3 food items for the first dinner if you bring 12 food items?

<p>220</p> Signup and view all the answers

How many different combinations of food can you make if the cafeteria offers 4 sandwiches, 3 sides, 2 desserts, and 5 drinks?

<p>120</p> Signup and view all the answers

How many ways can you arrange 8 file folders?

<p>40,320</p> Signup and view all the answers

Study Notes

Factorial and Combinations

  • 3! (factorial) equals 6, calculated as 3 × 2 × 1.
  • 4!/2! equals 12, derived from the formula for combinations where 4! represents total arrangements divided by 2! for the arrangement of 2 items.
  • 7C2 (combinations) gives 21; it counts the ways to choose 2 out of 7 without regard for order.

Additional Combinations

  • 4C3 + 6C5 equals 10; combines two different combinations from distinct groups.
  • 6P2 (permutations) equals 30, indicating the number of ways to arrange 2 items from 6 distinct options.

Probability: Independent vs. Dependent Events

  • Randomly selecting a student and then another from the same group is a dependent event, as the first selection affects the second's options.
  • Selecting a number by rolling a die twice constitutes independent events because the outcome of the first roll does not influence the result of the second.

Combinatorial Choices

  • Choosing 3 items from 12 for the first dinner can be done in 220 ways, illustrating the concept of combinations in selecting a subset.
  • A cafeteria menu with 4 sandwiches, 3 sides, 2 desserts, and 5 drinks results in a total of 120 unique meal combinations available for selection.

Arranging Items

  • Arranging 8 file folders in a drawer results in 40,320 different configurations, emphasizing the importance of factorial calculations in permutations.

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Description

This quiz reviews key concepts in Algebra 2, focusing on permutations, combinations, and independence of events. Each flashcard presents a problem or concept that is essential for mastering the material covered in the final exam. Test your knowledge and preparation for Algebra 2!

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