Algebra 1 Chapter 5 Review Flashcards

<p>Choice 3 (D)</p> Signup and view all the answers

<p>1.25</p> Signup and view all the answers

<p>This situation can be modeled by a linear equation due to its constant monthly fee.</p> Signup and view all the answers

<p>C = 78 + 33.32m</p> Signup and view all the answers

<p>Represents a different cost model (C)</p> Signup and view all the answers

<p>They are parallel. (D)</p> Signup and view all the answers

<p>$77</p> Signup and view all the answers

<p>6</p> Signup and view all the answers

<p>175</p> Signup and view all the answers

<p>10</p> Signup and view all the answers

The value represented by the letter D is 'Choice 4'.

The value represented by the letter A is 'Choice 1'.

The value represented by the letter B is 'Choice 2'.

The value represented by the letter C is 'Choice 3'.

5/4 represents the numerical value of 1.25.

A constant monthly fee indicates a linear equation, making the model applicable to situations with consistent charges.

The equation C = 78 + 33.32m models a cost with a fixed initial charge of $78 and a variable cost of $33.32 per unit represented by 'm'.

The line C = 155 + 33.32m represents a different cost model, possibly with a higher initial cost but the same per-unit charge.

The equations C = 78 + 33.32m and C = 155 + 33.32m are parallel because they have the same slope, meaning the cost changes at the same rate for each unit.

The constant difference between the equations C = 78 + 33.32m and C = 155 + 33.32m is $77, which is the difference in their initial costs.

When substituting 6 into the equation, the output is 6.

175 cans are represented by the numerical value 175.

The numerical representation of 10 is simply 10.