Chemistry Past Paper PDF - Jharkhand 19-09-2024

झारखण्ड शैक्षिक अनुसंधान एवं प्रक्षशिण पररषद, रााँची ( Jharkhand Council of Educational Research And Training, Ranchi) PROJECT RAIL...

झारखण्ड शैक्षिक अनुसंधान एवं प्रक्षशिण पररषद, रााँची ( Jharkhand Council of Educational Research And Training, Ranchi) PROJECT RAIL (REGULAR ASSESSMENT FOR IMPROVED LEARNING) GENERAL SCHOOL क्षवषय(sub) – CHEMISTRY ( 19-09-24) किा (Class)– 11th समय(Time)- 90 min. पण ू ाां क ( Marks) -40 सामान्य ननदेश :- 1. सभी प्रश्नों के उत्तर देना अननवायय हैं। (All questions are compulsory) 2. इस प्रश्न-पत्र में कुल 16 प्रश्न हैं। ( There are total 16 question in this question paper. ) 3.वस्तुननष्ठ प्रश्न के नलए 2 अंक, अनतलघउु त्तरीय प्रश्न के नलए 2 अंक, लघउु त्तरीय प्रश्न के नलए 3 अंक और दीघयउत्तरीय प्रश्न के नलए 5 अंक ननधायररत है। (2 marks are given for objective question, 2 marks for very short answer question, 3 marks for short answer question and 5 marks for long answer question.) 4. गलत उत्तर के नलए कोई ऋणात्मक अंक नहीं हैं । ( There is no negative marking for any wrong answer.) 5.वस्तुननष्ठ प्रश्न 1 से10 के नलए चार नवकल्प नदए गए हैं, सही नवकल्प (a ,b ,c ,d) का चयन कर उत्तरपुनस्तका में नलखना है। (Objective Question 1 to 10 has four options, choose the correct option’s (a, b, c, d) and write down in the answer sheet.) 6. अनतलघउु त्तरीय प्रश्न 11 से 12 , लघउु त्तरीय प्रश्न 13 से 14 ,और दीघयउत्तरीय प्रश्न 15 से 16 का उत्तर अपनी उत्तरपुनस्तका में नलखना है। (Write the answers to very short answer questions 11 to 12, short answer questions 13 to 14, and long answer questions 15 to 16 in your answer sheet. 7.परीक्षा की समानि से पहले नकसी भी परीक्षाथी को परीक्षा कक्ष से बाहर जाने की अनुमनत नहीं होगी। ( No students shall be allowed to leave the examination hall before the completion of the exam) SECTION – A ( 2 X 10 = 20 ) (objective question ) 1. The system which can exchange both mass and energy with the surrounding is called og fudk; ftlesa mtkZ ,oa nzO;eku nksuksa dk fudk; ,oa ifjos'k ds e/; fofue; gksrk gS] dgykrh gS& a) closed system ( can fudk; ) b) open system ( [kqyk fudk; ) c) isolated system ( foyfxr fudk; ) d) none of these (buesa ls dksbZ ugh) 02. The process in which heat remains constant throughout is known as ? og izdze ftlesa m’ek fLFkj cuh jgrh gS] dgykrk gS& a) isothermal process (lerkih; izdze) b) adiabatic process (:nzks’e izdze) c) reversible process ( mRdze.kh; izdze ) d) isobaric process (lenkch; izdze) 03. The reaction in which heat is absorbed known as - ? og vfHkfdz;k ftlesa m’ek dk vo”kks’k.k gksrk gS dgykrh gS& a) endothermic reaction (m’ek”kks’kh vfHkfdz;k ) b) exothermic reaction (m’ek{ksih vfHkfdz;k ) c) polymerization reaction (cgqyhdj.k vfHkfdz;k d) addition reaction ( la;kstu vfHkfdz;k) 04. “The total energy of universe is constant”.This is the statement of- “czkgek.M dh dqy mtkZ fLFkj gksrh gS”A ;g dFku gS& a) zeroth law of thermodynamics (m’ekxfrdh ds tsjksFa k fu;e dh ) b) first law of thermodynamics (m’ekxfrdh ds izFke fu;e dh c) second law of thermodynamics (m’ekxfrdh ds f}fr; fu;e dh ) d) 3rd law of thermodynamics (m’ekxfrdh ds r`rh; fu;e dh) 05. For the reaction - N2(g)+3H2(g) 2NH3(g) The relationship between ∆H and ∆E can be represented as- fuEu vfHkfdz;k ds fy, N2(g)+3H2(g) 2NH3(g) ∆H ,oa ∆E ds e/; ds laca/k dks lwfpr fd;k tk ldrk gS - a) ∆H= ∆E – 3RT b) ∆H= ∆E + 2RT c) ∆H= ∆E - 2RT d) ∆H= ∆E + 3RT 06. The Heat of Formation of NH3 (Ammonia) is – N2(g) + 3H2(g) 2NH3 + 92KJ veksfu;k ds fy, xBu dh m’ek gksxh ;fn vfHkfdz;k bl izdkj gS& N2(g) + 3H2(g) 2NH3 + 92KJ -1 a) 46 KJ mol b) -46 KJ mol-1 c) 92 KJ mol-1 d) -92 KJ mol-1 07. The Heat of neutralisation of strong acid & strong base is always equal to – izcy vEy ,oa izcy {kkjd ds mnklhuhdj.k dh m’ek loZnk gksrh gS& a) 57.1 KJ mol-1 b) 13.7KCal mol-1 c) both a & b d) none 08. For the transformation – H = -394KJ mol-1 C(S) + O2 (g) Co2(g) 02 02 H1 =-110.5KJ mol-1 H2 = ?? CO Calculate H2 here – fuEu :ikarj.k ds fy, & H = -394KJ mol-1 C(S) + O2 (g) Co2(g) 02 02 -1 H1 =-110.5KJ mol H2 = ?? CO H2 dh x.kuk djsa %& a) 283.5 KJ mol-1 b) -283.5 KJ mol-1 c) 394 KJ mol-1 d) -394 KJ mol-1 09. ENTROPY is found least in – ,UVªkWih dk eku fuEure gksrk gS& a) solids ( Bkslksa esa ) b) liquids (nzoksa es)a c) gases (xSlksa esa ) d) all have equal entropy (lHkh esa ,UVªWih ,dleku gksrk gSA) 10. At Equilibrium ∆G is – lkE;oLFkk ij ∆G - a) equals to ZERO ( “kwU; gksrk gSA ) b) Greater then ZERO ( “kwU; ls vf/kd gksrk gSA) c) lesser then ZERO ( “kwU; ls de gksrk gSA) d) ∆G ≥ 0 “kwU; ds cjkcj o “kwU; ls vf/kdA) SECTION – B ( 2 X 2 = 4 ) ( Very short answer question) 11. Define state functions, Give one example of it ? voLFkk Qyu dks ifjHkkf’kRk djsAa bldk ,d mnkgj.k nsAa 12. State second law of thermodynamics. ? m’ekxfrdh ds f}rh; fu;e dks fy[ksAa SECTION – C ( 2 X 3 = 6 ) ( short answer question) 13. When 430J of work was done on a system. it lost 120J of energy as heat. calculate the value of internal energy change (∆U) for this process. tc fdlh fudk; ij 430J dk dk;Z djrs gSa] rks og m’ek ds :Ik esa 120J dh mtkZ [kks nsrk gSA bl izdze ds fy, vkarfjd mtkZ ifjorZu dh x.kuk djsAa 14. Determine the shape geometry & hybridization in the following molecules - fuEu v.kqvksa esa vkd`fr T;kferh ,oa izladj.k crk,¡A (a) S (b) Xe SECTION – D ( 2 X 5 = 10 ) ( Long answer question) 15. Write short notes on the following ? fuEu ij laf{kIr fVIIk.kh fy[ksAa a) Heat of combustion (ngu dh m’ek ) b) Lattice energy (tkyd mtkZ) c) Heat of reaction (vfHkfdz;k dh m’ek ) 16. a) State and explain third law of thermodynamics. m’ekxfrdh ds r`rh; fu;e dks fy[ksa ,oa O;k[;k djsAa b) Differentiate between Extensive & Intensive properties. foLrh.kZ ,oa xgu Xkq.kksa es foHksn fdft, ) c) = ………….