NS 101 HW 9 PDF
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2024
Marc Ruiz
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Summary
This assignment is a chemistry homework for a course called NS 101, due October 7, 2024. The assignment requires students to calculate the molar mass and percentage composition of various chemical compounds and elements.
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Marc Ruiz 14/14 October 07,2024 NS 101 HW 9 Mrs. Liban Answer the following questions: (14 pts.) Solve the following Problems: 2 points each A. Calculate the molar mass of the following: 1. N2O - 2(14)...
Marc Ruiz 14/14 October 07,2024 NS 101 HW 9 Mrs. Liban Answer the following questions: (14 pts.) Solve the following Problems: 2 points each A. Calculate the molar mass of the following: 1. N2O - 2(14) + 1(16) > 28 + 16 = 44 amu 2. PbS - 1(207) + 1(32) > 207 + 32 = 239 amu 3. MgSO4 - 1(24) + 1(32) + 4(16) > 24 + 32 + 64 = 120 amu 4. HgCl2 - 1(201) + 2(35) > 200 + 72 = 271 amu B. Calculate the percentage composition of the following: 5. K2CO3 Mass of K = 2(39.09) = 78.18 g/mol Mass of C = 12.01 g/mol Mass of O = 3(16.00) = 48.00 g/mol Percentage of K = (78.18 / 138.21) × 100% = 56.57% Percentage of C = (12.01 / 138.21) × 100% = 8.69% Percentage of O = (48.00 / 138.21) × 100% = 34.74% 6. CaSO4 Mass of Ca = 40.08 g/mol Mass of S = 32.06 g/mol Mass of O = 4(16.00) = 64.00 g/mol Percentage of Ca = (40.08 / 136.14) × 100% = 29.44% Percentage of S = (32.06 / 136.14) × 100% = 23.55% Percentage of O = (64.00 / 136.14) × 100% = 47.01% 7. KNO3 Mass of K = 39.09 g/mol Mass of N = 14.01 g/mol Mass of O = 3(16.00) = 48.00 g/mol Percentage of K = (39.09 / 101.11) × 100% = 38.65% Percentage of N = (14.01 / 101.11) × 100% = 13.86% Percentage of O = (48.00 / 101.11) × 100% = 47.49%
