Gas Laws and Processes PDF

Document Details

TrustedWilliamsite8946

Uploaded by TrustedWilliamsite8946

Adamson University

Tags

thermodynamics gas laws isometric processes engineering

Summary

The document provides a detailed overview of gas laws and processes, ideal gas equation, and different thermodynamic properties such as internal energy, enthalpy, and entropy. It also discusses work done in various situations and their correlations with different system types. The content appears to cover fundamental thermodynamics principles and concepts.

Full Transcript

Isometric Process PV – T relation Change in Enthalpy = 𝐶; if V = constant 𝑑ℎ 𝑷𝟏 𝑷𝟐 𝐶𝑝 = = 𝑑𝑡 𝑻...

Isometric Process PV – T relation Change in Enthalpy = 𝐶; if V = constant 𝑑ℎ 𝑷𝟏 𝑷𝟐 𝐶𝑝 = = 𝑑𝑡 𝑻𝟏 𝑻𝟐 ∆𝑯 = 𝒎𝑪𝒑∆𝑻 Change in Internal Energy Work Non – Flow 𝐶 = ; 𝑑𝑢 = 𝐶 𝑑𝑡 𝑊 = 𝑃𝑑𝑉 ; 𝑉 = 𝐶 ∆𝑼 = 𝒎𝑪𝒗 ∆𝑻 𝑾𝒏𝒇 = 𝟎 Isometric Process Work Steady – Flow Considering Ideal Gas Equation; 𝑃𝑣 = 𝑚𝑅𝑇 W = −𝛥𝑃𝐸 − ∆𝐾𝐸 − ∆𝑃𝑉 𝐖𝒔𝒇 = −𝒎𝑹∆𝑻 If 𝛥𝑃𝐸 & ∆𝐾𝐸 is neglected, therefore W = −𝑉 ∆𝑃 W =− vdP −𝑽 ∆𝑷 = − 𝒗𝒅𝑷 For non – flow system with paddle work (𝑊 ) considering figure, Isometric Process Change in Entropy 𝑄 𝑆= ∆𝑇 𝑑𝑄 𝑚𝐶𝑣𝑑𝑇 ∆𝑆 = = ∆𝑇 𝑇 ∆𝑆 = 𝑚𝐶𝑣𝑙𝑛 ; = 𝑄 + 𝑊 = 𝛥𝑈 + 𝑊 𝑷𝟐 𝑄 = 𝛥𝑈 + 𝑊 − 𝑊 ∆𝑺 = 𝒎𝑪𝒗𝒍𝒏 𝑷𝟏 Hence, for constant volume process 𝑸 = ∆𝑼 − 𝑾𝒑 Isometric Process, V=C PV – T relation 𝑷𝟏 𝑷𝟐 = 𝑻𝟏 𝑻𝟐 Change in Internal Energy ∆𝑼 = 𝒎𝑪𝒗 ∆𝑻 Change in Enthalpy ∆𝑯 = 𝒎𝑪𝒑∆𝑻 𝑾𝒏 𝒇 = 𝟎 Work Non- Flow Work Steady – Flow W = −𝛥𝑃𝐸 − ∆𝐾𝐸 − ∆𝑃𝑉 Change in Entropy 𝑷𝟐 ∆𝑺 = 𝒎𝑪𝒗𝒍𝒏 𝑷𝟏 Isometric Process PV – T relation Change in Enthalpy = 𝐶; if V = constant 𝑑ℎ 𝑷𝟏 𝑷𝟐 𝐶𝑝 = = 𝑑𝑡 𝑻𝟏 𝑻𝟐 ∆𝑯 = 𝒎𝑪𝒑∆𝑻 Change in Internal Energy Work Non – Flow 𝐶 = ; 𝑑𝑢 = 𝐶 𝑑𝑡 𝑊 = 𝑃𝑑𝑉 ; 𝑉 = 𝐶 ∆𝑼 = 𝒎𝑪𝒗 ∆𝑻 𝑾𝒏𝒇 = 𝟎 Isometric Process Work Steady – Flow Considering Ideal Gas Equation; 𝑃𝑣 = 𝑚𝑅𝑇 W = −𝛥𝑃𝐸 − ∆𝐾𝐸 − ∆𝑃𝑉 𝐖𝒔𝒇 = −𝒎𝑹∆𝑻 If 𝛥𝑃𝐸 & ∆𝐾𝐸 is neglected, therefore W = −𝑉 ∆𝑃 W =− vdP −𝑽 ∆𝑷 = − 𝒗𝒅𝑷 For non – flow system with paddle work (𝑊 ) considering figure, Isometric Process Change in Entropy 𝑄 𝑆= ∆𝑇 𝑑𝑄 𝑚𝐶𝑣𝑑𝑇 ∆𝑆 = = ∆𝑇 𝑇 ∆𝑆 = 𝑚𝐶𝑣𝑙𝑛 ; = 𝑄 + 𝑊 = 𝛥𝑈 + 𝑊 𝑷𝟐 𝑄 = 𝛥𝑈 + 𝑊 − 𝑊 ∆𝑺 = 𝒎𝑪𝒗𝒍𝒏 𝑷𝟏 Hence, for constant volume process 𝑸 = ∆𝑼 − 𝑾𝒑 Isometric Process, V=C PV – T relation 𝑷𝟏 𝑷𝟐 = 𝑻𝟏 𝑻𝟐 Change in Internal Energy ∆𝑼 = 𝒎𝑪𝒗 ∆𝑻 Change in Enthalpy ∆𝑯 = 𝒎𝑪𝒑∆𝑻 𝑾𝒏 𝒇 = 𝟎 Work Non- Flow Work Steady – Flow W = −𝛥𝑃𝐸 − ∆𝐾𝐸 − ∆𝑃𝑉 Change in Entropy 𝑷𝟐 ∆𝑺 = 𝒎𝑪𝒗𝒍𝒏 𝑷𝟏 Relation of Specific heat ratio in Ideal Gas If =k If =k Where: C = C k and C = C +R Where: C = and C = C + R C = +R C k= C +R C − =R C k−C =R C 1− =R C =R C k−1 =R 𝐑𝐤 𝐂𝐯 = 𝐑 𝐂𝐩 = (𝐤 𝟏) 𝐤−𝟏 Combined Gas Law = constant = 𝒎𝑹 𝑷𝒗 = 𝒎𝑹 𝑻 R = Gas Constant its value is 8.3143 kJ/kg mol K Specific Heat Capacities of Ideal Gas If at constant Volume System If at constant Pressure System Q = mC ∆T = ∆U Q = mC ∆T = ∆H

Use Quizgecko on...
Browser
Browser