Alcohols, Phenols And Ethers Class 12 CBSE Notes PDF

For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 163 UNIT-10 ALCOHOLS, PHENOLS AND ETHERS Quick Concepts to Remember 1. Hydroxyl (− OH) derivatives...

For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 163 UNIT-10 ALCOHOLS, PHENOLS AND ETHERS Quick Concepts to Remember 1. Hydroxyl (− OH) derivatives of alkane are called alcohols. 2. Alcohols are classified as 1º, 2º and 3º. 3. −OH group is attached to sp3 hybridized carbon. Alcohols further may be monohydric, dihydric and polyhydric on the basis of OH group. 4. Phenols : Compounds containing – OH group bound directly to benzene ring. 5. Structure : Oxygen atom is sp3 hybridised and tetrahedral geometry of hybrid atomic orbitals ROH bond angle depends upon the R group. R – O – H angle for CH3 – OH is 108.9º. 6. Isomerism : (i) Functional isomerism (ii) Chain isomerism (iii) Positional isomerism 7. General Methods of Preparation : (i) Acid catalysed hydration of alkenes : (ii) Hydroboration oxidation : For more FREE DOWNLOADS, visit www.aspirationsinstitute.com 164 | Chemistry-XII (iii) From carbonyl compounds with Grignard’s reagent : Formaldehyde gives 1º alcohol and ketones gives tertiary alcohol. (iv) By reduction of carbonyl compounds : RCHO + 2[H]  Pd → RCH2OH H NaBH4 H C = O + 2[H] CH2OH R R R NaBH4 R C = O + 2[H] CHOH R R (v) By reduction of esters with LiAlH4 or Na/C2H5OH : O LiAlH4 R – C – OR' + 4[H] R – CH2OH + R' – OH (vi) By hydrolysis of esters : O O conc R – C – O – R' + H2O R – C – OH + R' – OH H2SO4 (vii) From alkyl halides : R – X + KOH (aq) → R – OH + KX (viii) By reduction of acids and their derivatives : R – COOH  LiAlH 4 → RCH2OH R – COCl + 2H2  Ni → R.CH2OH + HCl (ix) From 1º amines : NaNO 2 + HCl R – NH2  → ROH + H 2 O + N 2 For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 165 NAME REACTIONS 1. Reimer Tiemann Reaction x – – OH O Na+ O Na+ CHCl 2 CHO CHCl 3 + aq NaOH NaOH Intermediate OH CHO H+ Salicyaldehyde 2. Kolbe reaction OH ONa OH COOH NaOH (i) CO2 (ii) H+ 2-Hydroxybenzoic acid (Salicylic acid) 3. Friedel craft reaction OCH3 OCH3 OCH3 CH3 Anhyd. AlCl 3 + CH3CI CS2 + CH3 2-Methoxy- toluen 4-Methoxy (Minor) toluen (Major) OCH3 OCH3 OCH3 COCH3 Anhyd. AlCl3 + CH3COCl + Ethanoyl 2-Methoxy- COCH3 chloride acetophenone 4-Methoxy- (Minor) acetophenone (Maior) For more FREE DOWNLOADS, visit www.aspirationsinstitute.com 166 | Chemistry-XII 4. Williamson synthesis: Reaction with alkyl halide with sodium alkoxide or sod. Phenoxide is called Williamson synthesis. 1 1 R – X + R – O – Na R – O – R + NaX CH3I + CH3CH2ONa CH3O.CH2 – CH3 + Nal ONa CH3CH2 – I + + Nal Both simple and mixed ether can be produced. Depending upon structure and cleavage of unsymmetrical ethers by halogen acid may occur either by SN2 or SN1 mechanism. MECHANISMS 1. Hydration of Alkene : H' C—C C =C + H2O H OH H' CH3CH = CH2 + H2O CH3 – CH – CH3 OH Mechanism The mechanism of the reaction involves the following three steps: Step 1: Protonation of alkene to form carbocation by electrophilic attack of H3O+. + + H2O + H H3O H H + : : C = C + H – O+ – H C C + H2O Step 2: Nucleophilic attack of water on carbocation. H H H : : C C+ + H2O C C O –H + Step 3: Deprotonation to form an alcohol. : H H H : OH : C C O+ – H + H2 O : C C + H3O+ : For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 167 2. Dehydration Reaction 100°C/373 K CH3 – CH2HSO4 H2SO4 3 2 Conc. 413 K CH – CH – OH CH3CH2 – OCH2 – CH3 433 TO 444 K CH2 = CH2 + H2O Conc. (1) 2CH3CH2OH CH3CH2OCH2CH3 H2SO4 413 k Mechanism: H : : + Step 1: CH3CH2OH + H CH3CH2O H + +.. +.. Step 2: CH3CH2 — O — H + CH3CH2OH.. CH3CH2 — O — CH2CH3+H2O.. | | H H + + Step 3: CH3CH2 — O — CH2CH3 CH3CH2OCH2CH3 + H | H (2) CH3CH 2 OH  → H= 2 C CH 2 + H 2 O 2 4 Conc. H SO 443 K H.. Fast | Step 1: CH3CH2 OH.. + H+ CH3CH2 O—H.. + + Slow + Step 2: CH3CH2 — O — H CH3CH2 +H2O | H H H | | + Step 3: H—C—C—H CH2 = CH2 + H | + H For more FREE DOWNLOADS, visit www.aspirationsinstitute.com 168 | Chemistry-XII IMPORTANT PREPARATIONS (1) Preparation of phenol from Cumene CH3 CH3 CH3 CH CH3 C–O–O–H OH + O3 H + CH3COCH3 H2O Cumene Cumene Hydroperoxide (2) Prepation os spirin COOH COOH OH + OCOCH3 H + (CH3CO)2O + CH3COOH Salicylic acid Acetylsalicylic acid (Aspirin) 8. Ethers are dialkyl derivatives of water or monoalkyl derivatives of alcohols with formula R – O – R' 9. Lucas test can be used to distinguish primary, secondary and tertiary alcohols (ZnCl2 + HCl). (3º turbidity – instant, 2º - 5 minutes, 1º - heating for 60 minutes) 10. Ethers are relatively inert and hence are used as solvents. 11. 100% ethanol is known as absolute alcohol. 12. 95% ethanol is called rectified spirit. 13. A mixture of 20% ethanol and 80% gasoline is known as power alcohol. 14. Iodoform test is used for distinguishing compounds having the groups 15. Presence of EWGs increase the acid strength of phenols while EDG decrease the acid strength. EWG : − NO2, − X, − CN, − COOH etc. EDG : − R, − OR, − OH, − NH2 etc. 16. 3º alcohols are resistant to oxidation due to lack of α-hydrogen. 17. Intermolecular H-bonds of p- and m-nitrophenol increases water solubility/acid strength while intramolecular H-bonds in o-nitrophenol decreases these properties. 18. In the reaction of alkyl aryl ether (anisole) with HI, the products are always alkyl halide and phenol because O – R bond is weak than O – Ar bond which has partial double character due to resonance. For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 169 19. C – O – C bond in ether is bent and hence the ether is always polar molecule even if both alkyl groups are identical. MULTIPLE CHOICE QUESTIONS 1. Arrange the following compound in decreasing order of boiling point (i) propan-1-ol (ii) butane-1-ol (iii) butan-2-ol (iv) pentan-1-ol (a) i > iii > ii > iv (b) i > ii > iii > iv (c) iv > iii > ii > i (d) iv > ii > iii > i 2. What is the correct order of reactivity of alcohols in the following reaction? R—OH + CHl  → R—Cl + H O Zn,dust 2 (a) 1° > 2° > 3° (b) 1° < 2° > 3° (c) 3° > 2° > 1° (d) 3° > 1° > 2° CH3 3. IUPAC name of the compound C3H—CH—O—CH3 is: (a) 1-methoxy-1-methyl ethane (b) 2-methoxy-2-methyl ethane (c) 2-methoxy propane (d) isopropylmethyl ether 4. The correct order of decreasing acid strength of the following compound is: OH OH OH NO2 OCH3 (i) (ii) (ii) (a) i > ii > iii (b) iii > ii > i (c) ii > i > iii (d) ii > iii > i 5. In the reaction : heat C3H—CH—CH2—O—CH2—CH3 + HI CH3 CH3 (a) CH3—CH—CH2—OH + CH3—CH3 (b) CH3—CH—CH3—CH3 + CH3CH2—OH CH3 CH3 (c) CH3—CH—CH2—OH + CH3—CH2—I (d) CH3—CH—CH2—I + CH3CH2—OH CH3 For more FREE DOWNLOADS, visit www.aspirationsinstitute.com 170 | Chemistry-XII 6. Phenol  → X  → Y  → Z, The product CH 3Cl alkaline KMnO4 alkaline KMnO4 anhydrous AlCl3 Z is (a) Benzaldehyde (b) Benzoicacid (c) Benzene (d) Toluene 7. Which is most acidic OH OH CH (a) (b) CH2—OH OH (c) (d) 8. The electrophile involved in the given reaction is: OH ONa+ CHO + CH3Cl + NaOH (a) :CCl2 (b) –CCl3 (c) +CHO (d) +CHCl2 9. The major product obtained on interactionof phenol with NaOH and CO2 is (a) Benzoic acid (b) Salicaldehyde (c) Salicylic acid (d) Pthalic acid 10. In the following sequence of reaction CH3—CH2—OH v → A  → B → C  →D PI Mg HCHO 2 H O ether The product D is: (a) n-butylalcohol (b) n-propylalcohol (c) propanal (d) butanal ONa + 125° C 11. + CO 2  5 atm → B  H AC O →C 2 OCOCH3 OCOCH3 (a) (b) COOH COOH OCOCH3 OH COCH3 COOCH3 (c) (d) COCH3 For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 171 O3 H+ 12. + CH3—CH—CH3  AlCl3 → A B → Phenol + C 130°C COCH3 Identify ‘C’ in the following is: (a) Water (b) Ethanol (c) Cumenehydroperoxide (d) acetone 13. Iodoform canbe prepared from all except (a) butan-2-one (b) acetophenone (c) propan-2-ol (d) propan-1-ol 14. The ether O CH2 when treated with HI produces CH2 I CH2 OH (a) (b) I CHO (c) (d) 15. O CH3 the products are: Br OCH3 + H2 Br + CHBr3 (a) (b) (c) Br + CH2Br4 (d) d 16. Which of the following alcohol on dehydration with conc H2SO4 gives but-2- enc? (a) 2-methylpropan-2-ol (b) Butan-1-ol (c) 2-methyl propan-1-ol (d) Butan-2-ol 17. Which of the following alcohol give iodoferm test? (a) Butan-1-ol (b) Propan-1-ol (c) Propan-2-ol (d) Ethanol 18. Which of the following is a weaker acid than phenol? (a) 4-Methoxy phenol (b) 3, 5-dinitrophenol (c) 4-Methyl phenol (d) 4-Nitrophenol O—CH2 19. The ether when treated with HI produces. (a) CH2 I (b) CH2 OH (c) I (d) OH 20. Correct statements in case of n-butanol and t-butanol are: (a) both are having equal solubility in water (b) t-butanol is more soluble in water than n-butanol (c) boiling point of t-butanol is lower than n-butanol (d) boiling point of n-butanol is lower than t-butanol For more FREE DOWNLOADS, visit www.aspirationsinstitute.com 172 | Chemistry-XII Assertion Reason Type Questions The question given below consist of an Assertionand the Reason. Use the following key to choose the appropriate answer. (a) If both assertion and reasonare CORRECT and reason is the CORRECT explanation of the assertion. (b) If both assertion and reason are CORRECT, but reason is NOT the CORRECT explanation of the assertion. (c) If assertion is CORRECT but reason is INCORRECT. (d) If assertion is INCORRECT but reason is CORRECT. (e) If both assertion and reason are INCORRECT. 21. Assertion: The boiling point of alcohol is higher than those of hydrocarbons of comparable moleculal mass. Reason: Alcohol show intramolecular hydrogen banding. 22. Assertion: O and p-nitrophenols can be separated by steam distillation. Reason: O-isomeris steamvolatile due to chelation and p-isomer is not steam volatile due to intermolecular hydrogen bonding. Matching Column Type 23. Match the column (A) Methanol and ethanol P. lucas reagent (B) Phenol and cyclohexanol Q. Sodium metal (C) n-propylalcohol and tertbutyl alcohol R. Iodoformtest (D) Methanol and diethylether S. Ferric chloride (a) A–Q, B–S, C–P, D–R (b) A–S, B–P, C–Q, D–R (c) A–P, B–Q, C–R, D–S (d) A–R, B–S, C–P, D–Q 24. Match the column (A) Willionsan synthesis P. Conversion of phenol to salicylic acid (B) Conversion of 2° alcohol to ketone Q. Conversion of phenol to salicaldehyde (C) Reimer Tiemann reaction R. Heated with Cu-573k. (D) Kolbc's reaction S. reaction of alkyl halide with sodium alkoxide (a) A–S, B–R, C–Q, D–P (b) A–R, B–S, C–Q, D–P (c) A–R, B–Q, C–P, D–S (d) A–Q, B–P, C–R, D–S For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 173 Integer Type Questions The answer to each of the following question is a single-digit integer ranging from 0 to 9. Darken the correct digit. 25. The number of alcohols giving iodoform test among the following is: CH3CH2OH, CH3OH, CH3CH2CH2OH, (CH3)2 CHOH, CH3CH2CH2CH2OH, CH3CH2CH(OH)CH3, CH3CH(OH)CH(CH3)2, (C2H5)2CHOH, (CH3)3COH 0 1 2 3 4 5 6 7 8 9 ANSWERS 1. (d) 2. (c) 3. (c) 4. (c) 5. (c) 6. (b) 7. (d) 8. (a) 9. (c) 10. (b) 11. (b) 12. (d) 13. (d) 14. (a) 15. (d) 16. (b, d) 17. (c, d) 18. (a, c) 19. (a, d) 20.(b, c) 21. (c) 22. (a) 23. (d) 24. (a) 25. 4 VERY SHORT ANSWER TYPE QUESTIONS (1 Mark) Q. 1. Write IUPAC name of the following compound : Ans. 2,5-Dimethylhexane-1, 3 diol. Q. 2. How is phenol obtained from aniline ? Ans. 0 Q. 3. Why phenol is acidic in nature ? Ans. Due to stability of phenoxide ion by resonance. Q. 4. Arrange the following in decreasing order of their acidic character : (i) (ii) C6H5OH (iii) Ans. (iii) > (ii) > (i) Q. 5. Among HI, HBr and HCl, HI is most reactive towards alcohols. Why ? Ans. Due to lowest bond dissociation energy of HI. Q. 6. Name a compound which is used as antiseptic as well as disinfectant. Ans. Solution of phenol : 0.2% antiseptic, 2% disinfectant. Q. 7. What is nitrating mixture ? For more FREE DOWNLOADS, visit www.aspirationsinstitute.com 174 | Chemistry-XII Ans. Conc. (H2SO4 + HNO3) Q. 8. Lower alcohols are soluble in water, higher alcohols are not. Why ? Ans. Due to formation of hydrogen bonds. Q. 9. What happens when CH3CH2OH heated with red P and HI ? Ans. C2H5OH + 2HI  Red P → C2H6 + I2 + H2O Q. 10. Complete the following reaction : Ans. 2, 4, 6-Trinitro phenol (Picric acid) Q. 11. Ethanol has higher boiling point than methoxy methane. Give reason. Ans. Because of H-bonds. Q. 12. How could you convert ethanol to ethene ? C2H5OH  → CH2 = CH2 + H2O Conc. H SO Ans. 2 443 K 4 Q. 13. Explain Kolbe’s reaction with example. Ans. Q. 14. Which of the following isomer is more volatile : o-nitrophenol or p-nitrophenol Ans. o-nitrophenol. SHORT ANSWER-I TYPE QUESTIONS (2 Marks) Q. 1. Write one chemical reaction to illustrate the following : (i) Reimer-Teimann reaction (ii) Williamson’s synthesis Ans. (i) For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 175 (ii) Q. 2. Account for the following : (i) Phenol has a smaller dipole moment than methanol. (ii) Phenol goes electrophilic substitution reactions. Ans. (i) Due to – ve charge on oxygen in delocalized by resonance. (ii) Due to greater electron density than benzene. Q. 3. Complete the following equations and name the products : (i) Phenol + FeCl3 → (ii) C6H5OH + CHCl3 + NaOH  340 K → (iii) C6H5OH + Br2 (aq) → (iv) Ans. (i) [(C6H5O)3Fe] + 3HCl (ii) (iii) (iv) Q. 4. Write : (i) Friedel-Crafts reaction (ii) Coupling reaction Ans. (i) pH=9-10 (ii) C6H5N2Cl + C6H5OH → Q. 5. Give one reaction of alcohol involving cleavage of : (i) C – O bond (ii) O – H bond Ans. (i) CH3CH2OH + PCl5 → CH3CH2Cl + POCl3 + HCl (ii) CH3CH2OH + Na → CH3CH2ONa + H2 For more FREE DOWNLOADS, visit www.aspirationsinstitute.com 176 | Chemistry-XII Q. 6. Etherial solution of an organic compound ‘X’ when heated with Mg gave ‘Y’. ‘Y’ on treatment with CH3CHO followed by acid hydrolysis gave 2-propanol. Identify the compound ‘X’. What is ‘Y’ known as ? Ans. Q. 7. While separating a mixture of o- and p-nitrophenols by steam distillation name the isomer which is steam volatile. Give reason. Ans. H-bonding and association of molecules. Q. 8. Account for the following : (i) Phenol has a smaller dipole moment than CH3OH. (ii) Phenol do not give protonation reactions readily. Ans. (i) Because phenol has electron attracting benzene ring. (ii) Resonance and +ve charge oxygen does not have tendency to accept a proton. Q. 9. Write the reactions and conditions involved in the conversion of : (i) Propene to propan-2-ol. (ii) Phenol to salicylic acid. Ans. (i) CH3CH = CH2 + H2O  H 2SO4 (dil.) → CH3 – CH – CH3 | OH (ii) Q. 10. Write mechanism of reaction of HI with methoxymethane. Ans. For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 177 Q. 11. Arrange in order of boiling points : (i) C2H5 – O – C2H5, C4H9COOH, C4H9OH (ii) C3H7CHO, CH3COC2H5, C2H5COOCH3, (CH3CO)2O Ans. (i) C4H9COOH > C4H9OH > C2H5 – O – C2H5 (ii) (CH3CO)2O > C2H5COOCH3 > CH3COC2H5 > C3H7CHO Q. 12. Which of the following is an appropriate set of reactants for the preparation of 1-methoxy-4-nitrobenzene and why ? (i) (ii) Ans. (ii) It is because of double bond character, (C – Br) bond in due to resonance it is less reactive towards SN, RXN. Q. 13. Ethers are relatively inert. Justify. Ans. Due to absence of any active site in their molecules, divalent oxygen is linked to carbon atoms on both sides  C − O − C ... ..  Q. 14. How will you distinguish between CH3OH and C2H5OH ? Ans. C2H5OH + 4I2 + 3Na2CO3  warm → CHI3 + HCOONa + 5NaI + 2H2O + 3CO2 Iodoform (yellow) CH3OH does not give this test. SHORT ANSWER-II TYPE QUESTIONS (3 Marks) Q. 1. Name the reagents which are used in the following conversions : (i) 1º alcohol to an aldehyde (ii) Butan-2-one to butan-2-ol (iii) Phenol to 2, 4, 6 tribromophenol For more FREE DOWNLOADS, visit www.aspirationsinstitute.com 178 | Chemistry-XII Ans. (i) PCC, a complex of chromium trioxide with pyridine and HCl. (ii) NaBH4, sodium borohydride. (iii) Br2 (water) Q. 2. Write structures of the major products of the following : (i) Mononitration of 3-methylphenol (ii) Dinitration of 3-methylphenol (iii) Mononitration of phenyl ethanoate Ans. – OH and – CH3 are o- and p-directing groups. The products are : (i) (ii) (iii) Q. 3. Complete the following reactions : (i) CH3CH2CH2CHO → 2 Pd/ H / Ni (ii) CH 3CH = CHCH 2OH  → PCC (iii) CH 3CH = CH 2  -→ 2 6 (1) B H (2) 3H 2O 2 /OH (iv) C6 H 5OH  + → (1) Aq.NaOH (2) CO 2 ,H (v) CH2Br – CH2Br  KOH → (vi) C2H5NH2  HNO 2 → Ans. (i) CH3CH2CH2CH2OH (ii) CH3CH = CHCH2 – OH OH (iii) CH3CH2CH2OH (iv) COOH (v) CH2OH – CH2OH (vi) CH3CH2OH For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 179 Q. 4. Give equations of the following reactions : (i) Oxidation of propan-1-ol with alkaline KMnO4 solution. (ii) Bromine in CS2 with phenol. (iii) Treating phenol with chloroform in presence of aqueous NaOH. Ans. (i) CH3 – CH2 – CH2OH + 2[O] → alkaline KMnO CH3CH2COO– K+ 4 (ii) (iii) Q. 5. Describe the following reactions with examples : (i) Reimer-Teimann reaction (ii) Kolbe’s reaction (iii) Friedel Crafts acylation of anisole – + OH O Na Ans. (i) CHCl2 (ii) CH3COCl Cl (iii) anhy. AlCl3 COCH3 Q. 6. Dehydration of alcohols to form an alkene is always carried out with conc. H2SO4 and not with conc. HCl or HNO3. Explain. Ans. In acidic medium alcohols protonated then loses H2O to form a carbo cation. If HCl Cl− strong nucleophile cause nucleophilic substitution, HNO3 causes oxidation. Q. 7. How will you convert : (i) Phenol to cyclohexanol (ii) Benzyl chloride to benzyl alcohol For more FREE DOWNLOADS, visit www.aspirationsinstitute.com 180 | Chemistry-XII (iii) Anisole to phenol OH OH Ni Ans. (i) + H2 (ii) (iii) LONG ANSWER TYPE QUESTIONS (5 Marks) Q. 1. An alcohol A (C4H10O) on oxidation with acidified K2Cr2O7 gives carboxylic acid ‘B’ (C4H8O2). Compound ‘A’ when dehydrated with conc. H2SO4 at 443 K gives compound ‘C’ with aqueous H2SO4. ‘C’ gives compound ‘D’ (C4H10O) which is an isomer of ‘A’. Compound ‘D’ is resistant to oxidation but compound ‘A’ can be easily oxidized. Identify A, B, C and D and write their structure. Ans. A : (CH3)2CHCH2OH B : CH3CH(CH3)COOH C : (CH3)2C = CH2 D : (CH3)3 – C – OH Q. 2. An ether ‘A’ (C5H12O) when heated with excess of hot concentrated HI produced two alkyl halides which on hydrolysis from compounds B and C. Oxidation of B gives an acid D whereas oxidation of C gave a ketone E. Deduce the structures of A, B, C, D and E. Ans. A : CH3CH2OCH B : CH3CH2OH C : CH3CHOHCH3 D : CH3COOH E : CH3COCH3 Q. 3. Which of the following compounds gives fastest reaction with HBr and why? (i) (CH3)3COH (ii) CH3CH2CH2OH (iii) (iv)  Ans. (i) (CH3)3C – OH Due to formation of EDG and formation of cation. Q. 4. Phenol, C6H5OH when it first reacts with concentrated sulphuric acid, forms Y. The compound, Y is reacted with concentrated nitric acid to form Z. Identify Y and Z and explain why phenol is not converted commercially to Z by reacting it with conc. HNO3. For more FREE DOWNLOADS, visit www.aspirationsinstitute.com ALCOHOLS, PHENOLS AND ETHERS | 181 Ans. Phenol is not reacted directly with conc. HNO3 because the yield of picric acid is very poor. Q. 5. Fill in the blanks : Zymase (i) Glucose OH (ii) + Br2 ? H2O OH COOH (CH3CO)2O (iii) + ? H CH3 HI (iv) CH3CHOCH2CH3 ? (v) Phenol + Zn (dust) → (vi) Phenol + Na → (vii) R2CHOH + HCl + ZnCl2 → R2CHCl +.......... (anhydrous) (viii) R – CHOH – R  [O] → OH Cl | | SOCl (ix) CH3 – CH – CH3 2 → CH3 – CH – CH3 + (x) CH3 – CH2 – OH  Bleaching powder → Br Ans. (i) C2H5OH (ii) Br Br OCOCH3 OH COOH (iii) (iv) (CH3)2CHOH and CH3CH2I (v) C6H6 (vi) C6H5ONa O || (vii) H2O (viii) R – C – R (ix) SO2 (x) CHCl3 Source: EDUDEL