Horizontal Alignment PDF
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Catanduanes State University
Reina Mae Chong
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Summary
This document explains horizontal alignment in highway and railroad engineering, including circular curves, sight distances, and superelevation. It includes formulas, diagrams, and examples of calculations relevant to road design. The document originates from Catanduanes State University.
Full Transcript
Appearance standards vary from agency to agency. Current California standards for instance, require a minimum vertical curve length of 60 m where grade breaks are less than 2% or design speeds are less than 60 km/h, the minimum vertical curve length is given by L = 2V, where L in the vertical curve...
Appearance standards vary from agency to agency. Current California standards for instance, require a minimum vertical curve length of 60 m where grade breaks are less than 2% or design speeds are less than 60 km/h, the minimum vertical curve length is given by L = 2V, where L in the vertical curve length in metres and V is the design speed in Km/h. Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University Determine the minimum length of a crest vertical curve between a +0.5% grade and a -1.0% grade for a road with a 100- km/h design speed. The vertical curve must provide 190-m stopping sight distance and meet the California appearance criteria. Round up to the nearest 20 m interval. Given: π1 = +0.5% π2 = -1.0% S = 190 California appearance criteria: πΉπ΄πΏππΈ 1. Design speed less than 60km/h Required: minimum length (πΏπππ ) 100 km/h > 60 km/h Therefore, check second criteria. Solution: Assume S β€ L 2. Grade breaks less than 2% ππ ππΈ π΄π 2 (0.5 β (β1.0))(1902 ) πΏ= = = 134.0 π Grade break: 0.5% + 1% = 1.5% 200( β1 + β2 )2 200( 1.070 + 0.150)2 1.5% < 2% Therefore, L = 60m 134.0 m < 190 m, S > L assumption is wrong (use other equation) 2 200 β1 + β2 200 1.070+ 0.150 2 πΏ = 2π β = 2(190) β = 380 β 269.5 = 110.5 π (0.5β β1.0 ) π΄ Therefore, use 120 m vertical curve. Sight Distances Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University CE4 - HIGHWAY AND RAILROAD ENGINEERING Horizontal Alignment Horizontal tangents are described in terms of their lengths (as expressed in the stationing of the job) and their directions. Directions may be either expressed as bearings or as azimuths and are always defined in the direction of increasing station. Azimuths are expressed as angles turned clockwise from due north; bearings are expressed as angles turned either clockwise or counterclockwise from either north or south. For instance, the azimuth 280is equivalent to the bearing north 80west (or N80W). Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 2 Circular Curves Horizontal curves are normally circular. Horizontal curves are described by radius (R), central angle (Ξ) (which is equal to the deflection angle between the tangents), length (L), semi tangent distance (T), middle ordinate (M), external distance (E), and chord (C). The curve begins at the tangent-to-curve point (TC) and ends at the curve-to-tangent point (CT). Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 4 Circular Curves In the past, severity of curvature was sometimes expressed in degree of curvature. Although obsolete in the metric system, degree of curvature may still be encountered in some situations. Degree of curvature may be defined in two ways. The arc definition is the angle subtended by a 100 ft arc. The chord definition is the angle subtended by a 100 ft chord. Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 6 POINTS PC β Point of Curve PI/V β Point of Intersection / Vertex PT β Point of Tangent ANGLE β β Angle of Intersection LINES R β Radius T β Tangent Distance C β Long Chord M β Middle Ordinate E β External Distance Circular Curves 36000 5729.58 β β π·= = π = π π‘ππ π = π β π πππ ( ) 2ππ π 2 2 R = radius of curvature (feet) π β πΈ= βπ πΆ = 2π sin( ) β 2 2ππ β cos 2 πΏ= = π βπππ 360Β° β = central angle of the curve βπππ = measured in radians Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 8 β π = π π‘ππ 2 β πΆ = 2π sin( ) 2 β π = π β π πππ ( ) 2 π πΈ= βπ β cos 2 Horizontal Alignment Circular curves are usually laid out in the field by occupying the tangent-to-curve point TC with a transit and then establishing successive points by turning deflection angles and measuring chords, as shown in the figure below. Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 10 Horizontal Alignment The deflection angle in radians ππ₯ to a point on the curve at a distance x from the TC is given by π₯ ππ₯ = ( )πππ 2π The chord ππ₯ to this point is given by ππ₯ = 2π sin ππ₯ Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 11 Horizontal Alignment Table 4.3 gives deflection angles and chords at 20 m intervals for a 500 m radius curve with a deflection angle of 15Β° and a TC at station 17+25. Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 12 Horizontal Alignment Design standards for horizontal curves establish their minimum radii and, in some cases, their minimum lengths. Minimum radius of horizontal curve is most commonly established by the relationship between design speed, maximum rate of superelevation, and curve radius. In other cases, minimum radii or curve lengths for highways may be established by the need to provide stopping sight distance or by appearance standards. Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 13 Horizontal Alignment Figure 4.15 illustrates the relationship between curve radius, stopping sight distance, and the setback distance to obstructions to vision. Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 14 Horizontal Alignment The relationship between the radius of curvature R, the setback distance m, and the sight distance s is given by 28.65π π β1 π βπ π = π [1 β cos( )] π = [πππ ( )] π 28.65 π where the angles in the formula are measured in degrees. Since these formula are hard to solve for R, design charts or tables are normally used to find the minimum radius of curvature that will provide stopping sight distance. Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 15 Superelevation Curved section roadways are usually super elevated. Provisions for gradual change from one to the other have to be considered. The centerline of each individual roadway at profile grade is maintained while raising the outer edge and lowering the inner edge to attain the desired elevation. A vehicle travelling on a horizontal curve exerts an outward force called centrifugal force. To resist this force and maintain the desired design speed, highway curves need to be superelevated. Superelevation may be defined as the rotation of the roadway cross section in such a manner as to overcome the centrifugal force that acts on a motor vehicle traversing a curve. Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 16 Superelevation On the superelevated highway, the centrifugal force can be resisted by: 1. The weight component of the vehicle parallel to the superelevated surface 2. The side friction between the tires and the pavement 3. Introduction of transition curves 4. Pavement widening. It is impossible to balance centrifugal force by superelevation alone, because for any given curve radius, a certain superelevation rate is exactly correct for only one operating speed around the curve. At all other speeds, there will be a side thrust outward or inward relative to the curve centre which must be offset by side friction Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 17 π€π£ 2 π£2 πΆπΉ = πΆπ = ππ ππ π€ = π€πππβπ‘ ππ π£πβππππ π = π ππππ ππ π£πβππππ ππ/β m CF π£ = π ππππ ππ π£πβππππ ππ‘ ππ’ππ£π in s = 0.25V π = πππππ’π ππ ππ’ππ£ππ‘π’ππ ΞΌ = πππ‘ππππ πππππππππππ‘ πππ‘π€πππ ππππ A πππ π‘ππππ πΆπΉ = ππππ‘ππππ’πππ πππππ πΆπ = ππππ‘ππππ’πππ πππ‘ππ e = superelevation of road, raising of outer edge at a rate of 1 horizontal to e vertical π tan Ξ± = 1 e π£2 π+ΞΌ= Ξ± ππ Widening Curve The provision for a wider roadway is necessary on sharp curve for two lane pavement under the following reasons: 1. To force the drivers to shy away from the pavement edge. 2. To increase the effective transverse vehicle width for non-tracking of front and rear wheels. 3. To give additional width due to the slanted position of the front wheel to the roadway centerline. 4. For a 7.20 meter wide roadway, an additional width of 0.30 is necessary on an open curve highway. Engr. Reina Mae Chong | Highway and Railroad Engineering| Catanduanes State University | 20