PHA 111 Chemical Kinetics PDF
Document Details
Uploaded by TimeHonoredSaxophone
University of Sunderland
Dr Stephen Childs
Tags
Summary
These notes cover the topic of chemical kinetics, including reaction rates and mechanisms. They are lecture notes from the University of Sunderland, and cover topics like collision theory, molecular orientation, and temperature effects on reaction rates. The notes detail topics such as reaction order and molecularity.
Full Transcript
PHA 111 Chemical Kinetics: Rate & Order of Reaction Dr Stephen Childs Senior Lecturer in Pharmaceutical Chemistry [email protected] Slide 1 PHA 111: Chemical Kinetics Recommended R...
PHA 111 Chemical Kinetics: Rate & Order of Reaction Dr Stephen Childs Senior Lecturer in Pharmaceutical Chemistry [email protected] Slide 1 PHA 111: Chemical Kinetics Recommended Reading Atkins’ Physical Chemistry Chapters 21.2 – 21.5 (9th Edition) Slide 2 PHA 111: Chemical Kinetics Why study rates of reaction? To better understand reaction mechanisms eg. SN1 & SN2 To optimise reaction rates Improve ! side-products ↑ yield / reduce To minimise drug degradation Predict / improve shelf-life eg. pH dependant hydrolysis of aspirin to salicylic acid Understand what drives a reaction forward H2 + ½ O2 → H2O ΔH = -286 kJ/mol Slide 3 PHA 111: Chemical Kinetics What affects reaction rate? Physical state Many pharmaceutically relevant reaction occur in solution Concentration Molecules must come in contact to react Increased concentration = increased frequency of collisions Temperature Increases frequency of collision Increases the (vibrational) energy of the bonds Catalysts increase the rate of reaction Alternative reaction mechanism Slide 4 PHA 111: Chemical Kinetics Collision Theory Rate of reaction will depend on how often reacting molecules collide with sufficient energy to react. Collision rate depends on: – Concentration: chances of collision increased, depends on reaction order! – Pressure : for a gas, rate increases with pressure (same mechanism as concentration) 𝒏 𝒑= 𝒙 𝑹𝑻 𝑽 – Surface area and molecular orientation – Temperature and molecular speed Slide 5 PHA 111: Chemical Kinetics Effect of Surface Area Collision rate depends available surface area Mg(s) + 2H+ (aq) -> Mg2+(aq) + H2(g) al dispersed - much more surface outside crea only available to react wr Slide 6 PHA 111: Chemical Kinetics Effect of Molecular Orientation Ethere ecoudea O other ↑ replech electroetive na - Big ex enzyme 1" Must have correct orientation – Not all collisions will produce a reaction, – Consider HCl and ethene, (electrophilic addition) – Less likely the more complex the reactants – Only occurs 1 in 105 collisions for complex reactions Slide 7 PHA 111: Chemical Kinetics Effect of Molecular Speed Collision rate depends on molecular speed – Temperature affects speed – Based on kinetic theory of gases 3RT Vrms = - root mean M squared – At 5°C Vrms = 240 m/s (120 amu) ↓ slightly ↑ as ↑ temperature ↑ temperature ↑ 4 volume speed => – At 20°C Vrms = 247 m/s (120 amu) (90s) Slide 8 PHA 111: Chemical Kinetics Activation Energy Favourable ( entropy enthalpy not energetically bonds - too many Energy barrier associated with the transition state – Distortion of molecular shape some put energy kick Sufficient energy to = (normal) thea – Energy barrier usually 50 – 100 kJ/mol ↓ – Average energy at 20°C approx. 4 kJ/mol ge – Just Most molecules have insufficient energy – Only about 1 in 109 reaction ? Slide 9 PHA 111: Chemical Kinetics Maxwell-Boltzmann Distribution For gases, the number of molecules with sufficient energy to react can be represented as below: Many particles · don't have enough energy to react ! James Clerk Maxwell 4 50k]/mol Ludwig Boltzmann Slide 10 PHA 111: Chemical Kinetics Effect of Temperature Increasing Temperature disproportionally increased the number of particles with sufficient activation energy [ ↑ temp. ↑ the number of moves to the right Particles can - No. of 293 ° K react 303 ° K - Particles smal 4 gives large fraction of particles average available for the - energy reaction over the system& Activation Energy Energy Slide 11 PHA 111: Chemical Kinetics Arrhenius Equation Increasing temperature affects rate by increasing k From a small number of experiments we can deduce k at varying temperatures, as well as determining t 50 and t90 haf shelf - life - life 𝐸𝑎 Arrhenius equation: ln 𝑘𝑟 = ln 𝐴 − 𝑅𝑇 Alternative form of Arrhenius equation relates k to temperature: * k = Ae-Ea/RT – k: kinetic rate constant - indio ) ? – A: frequency factor (a.k.a. pre-exponential factor) – Ea: activation energy (probability collision will result in reaction) – R: gas constant (8.3145 J mol-1 deg-1) – T: temperature (in Kelvin) Slide 12 PHA 111: Chemical Kinetics Effect of Temperature k = Ae-Ea/RT A is rate constant if energy barrier is absent – Also if T is infinite (or very high) e-Ea/RT is the fraction of molecules with sufficient energy to react Assuming an activation energy or 50,000 J/mol, and temperatures of 293 and 303°K respectively, the fraction of molecules able to react (e) 20 ° C 20 C · is almost doubled by a 10°C increase in temperature: most doubled with 10c Increase Slide 13 PHA 111: Chemical Kinetics Catalysts Catalysts increase the rate of reaction without being consumed – Acid catalysed hydrolysis of esters – Chlorine radicals catalyse breakdown of ozone Catalysts provide a lower activation energy pathway for the reaction half-way ex) up the hill > - Tunnel New AE Original AE X 104 Increase in rote I Energy Slide 14 PHA 111: Chemical Kinetics Catalysts Catalysts do not affect the position of equilibrium of a - reaction Catalysts do not make unfavourable reactions favourable - – Overall G does not change only speeding up ! Enzymes are proteins which act as biological catalysts Acetylcholinesterase hydrolyses acetylcholine in 100 s L transmission of signals in the brain bindstrongly Slide 15 PHA 111: Chemical Kinetics Rate of Reaction Following concentration as a function of time A+B→C - Decrease in reactant concentration (A or B) Increase in product concentration (C) −Δ𝐴 −Δ𝐵 Δ𝐶 𝑅𝑎𝑡𝑒 = = = Δ𝑡 Δ𝑡 Δ𝑡 Difference over a finite time Want change over infinitesimally small time: −𝑑𝐴 −𝑑𝐵 𝑑𝐶 𝑅𝑎𝑡𝑒 = = = 𝑑𝑡 𝑑𝑡 𝑑𝑡 Slide 16 PHA 111: Chemical Kinetics Measuring Rate of Reaction Slide 17 PHA 111: Chemical Kinetics Chemical Reactions Most reactions are multi-step Molecularity Number of molecules involved in each elementary reaction step Can be obtained from the stoichiometry 1 species = unimolecular 2 species = bimolecular 3 species = termolecular Molecularity must be an integer Not the same as reaction order! Slide 18 PHA 111: Chemical Kinetics Rate of Reaction What happens when we increase [A] ? 1) Nothing happens: Rate independent of [A] ~ Kineticrate a 2) Rate = k[A] Double [A], k is double Triple [A], k is tripled 3) Rate = k[A]2 [A] is double, k is quadrupled (22 = 4) [A] is tripled, k is increased nine-fold (32 = 9) Slide 19 PHA 111: Chemical Kinetics Reaction Order (i) Rate Multiplication Reaction Order Rate constant (k) units 1 0 M/s 2 1 1/s 4 2 1/(M*s) Units of k must give M/s when combined with concentration units (M) conc. /s The rate law is the sum of each of the reactant orders. If aA +bB + cC → dD + eE rate = k[A]x[B]y[C]z where x is the order of A, not the stoichiometry! Slide 20 PHA 111: Chemical Kinetics Reaction Order -linear Gurva Slide 21 PHA 111: Chemical Kinetics Reaction Order (ii) Calculate the reaction order for each reactant, and the overall reaction order for the following reaction: F₂ + 2ClO₂ → 2ClO₂F Experiment No. [Fl₂] (M) [ClO₂] (M) Initial Rate (M/s) 1 0.10 0.010 0.0012 2 3 0.10 0.20 ( X2 0.040 0.010 2x4 0.0048 0.0024 W Doubling [F₂] doubles the rate – therefore must be 1st order m Doubling [ClO₂] doubles the rate – therefore must also be 1st order - Overall order is 1+1 = 2nd order - Therefore the rate law is k [F₂] [ClO₂] Slide 22 PHA 111: Chemical Kinetics Reaction Order Example Calculate the reaction order for each reactant, and the overall reaction order for the following reaction: BrO3- + 5Br- + 6H+ → 3 Br2 + 3H2O Experiment [BrO3-] (M) [Br-] (M) [H+ ] (M) Initial Rate (M/s) No. 1 0.10 0.10 0.10 8.0 x 10-4 (x2)x 2 0.20 (xz 0.10 0.10 1.6 x 10-3 3 0.20 0.20 0.10 3.2 x 10-3 4 0.10 0.10 0.20 3.2 x 10-3 ist ist and Doubling [BrO3-] doubles the rate – therefore must be 1st order Doubling [Br-] doubles the rate – therefore must also be 1st order Doubling [H+] quadruples the rate – therefore must also be 2nd order Therefore the rate law is k [BrO3-]1 [Br-]1 [H+]2 (overall order = 4) Slide 23 PHA 111: Chemical Kinetics Rate Law Examples The reaction between A + B is measured in the lab: rate = k[A][B] Order or reaction w.r.t. A is first Order or reaction w.r.t. B is first Overall order is 2 rate = k[B]2 Order or reaction w.r.t. A is zero Order or reaction w.r.t. B is second Overall order is 2 rate = k[A] Order or reaction w.r.t. A is first Order or reaction w.r.t. B is zero Overall order is 1 Slide 24 PHA 111: Chemical Kinetics Reaction Mechanisms SN1 reaction: tert-Butyl chloride and hydroxyl anion Rate = k[(CH3)3CBr] Rate order of (CH3)3CBr? Rate order of OH? effect ~ no of reaction on rate (knowing these might let us determine the mechanism!) Step 1 - (rate determining) unimolecular ↳ Step 2 - Fast (does not affect overall rate of reaction) = So what is the effect of increasing [OH]? Slide 25 PHA 111: Chemical Kinetics Reaction Mechanisms SN2 reaction: Chloromethane and hydroxyl anion Rate = k[(CH3)3CBr][OH-] Both components effect the rate of run Rate order of (CH3)3CBr? Rate order of OH? Bimolecular Slide 26 PHA 111: Chemical Kinetics Determining Mechanisms For a reaction between A + B, rate =k[A][B] L means both must Which mechanism is correct? involved in step-contribute slow to the rote of rxn O If the slow step is first in the mechanism the orders tell you what is taking part in that step. First order w.r.t. A and B, so both must take part. Must be mechanism 2 (Cant be 1, as B isn’t in the slow step!) Slide 27 PHA 111: Chemical Kinetics Determining Mechanisms What if the slow step is not first in the mechanism? Rate = k[A][X] But we don’t start with X so we can’t measure it! We need to derive a new rate equation based on the equilibrium: [𝑋] 𝐾𝑐 = 𝐴 [𝐵] Re-arrange and substitute into initial rate expression: 𝑅𝑎𝑡𝑒 = 𝑘 𝐴. 𝐾𝑐 [A][B] Combine the constants to get the new rate expression: 𝑅𝑎𝑡𝑒 = 𝐾1 [𝐴]2 [B] > - when slow step is not first during the process Slide 28 PHA 111: Chemical Kinetics