CBSE New Pattern Physics 11th (Term-I) PDF

CBSE New Pattern ~ Physics 11th (Term-I) 33 Objective Questions Multiple Choice Questions 5. The displacement of a car is given as 1. Which...

CBSE New Pattern ~ Physics 11th (Term-I) 33 Objective Questions Multiple Choice Questions 5. The displacement of a car is given as 1. Which of the following is an example of - 240 m, here negative sign indicates one-dimensional motion? (a) direction of displacement (a) Landing of an aircraft (b) negative path length (b) Earth revolving around the sun (c) position of car at that point (c) Motion of wheels of moving train (d) no significance of negative sign (d) Train running on a straight track 6. Snehit starts from his home and walks 2. The coordinates of object with respect 50 m towards north, then he turns to a frame of reference at t = 0 s are towards east and walks 40 m and then ( - 1, 0 , 3). If t = 5 s, its coordinates are reaches his school after moving 20 m ( - 1, 0 , 4 ), then the object is in towards south. Then, his displacement (a) motion along Z-axis from his home to school is (b) motion along X-axis (a) 50 m (b) 110 m (c) motion along Y-axis (c) 80 m (d) 40 m (d) rest position between t = 0 s and t = 5 s 7. A vehicle travels half the distance l with 3. A person moves towards east for 3 m, speed v 1 and the other half with speed then towards north for 4 m and then v 2 , then its average speed is moves vertically up by 5 m. What is his (NCERT Exemplar) distance now from the starting point? v1 + v2 2v 1 + v 2 2v 1v 2 l (v 1 + v 2 ) (a) (b) (c) (d) (a) 5 2 m (b) 5 m (c) 10 m (d) 20 m 2 v1 + v2 v1 + v2 v 1v 2 4. For a stationary object at x = 40 m, the 8. A runner starts from O and comes back position-time graph is to O following path OQRO in 1h. What x (m) is his net displacement and average 40 speed? R (a) 20 0 t (s) 10 20 30 40 O Q x (m) 1km 40 (b) (a) 0,3.57 km/h (b) 0,0 km/h t (s) 0 20 (c) 0,2.57 km/h (d) 0,1 km/h x (m) 9. The sign ( + ve or - ve) of the average 40 velocity depends only upon (c) (a) the sign of displacement t (s) (b) the initial position of the object 30 (c) the final position of the object (d) None of the above (d) None of the above 10. Find the average velocity, when a (a) v1 >v2 particle completes the circle of radius (b) v2 >v1 (c) v1 =v2 1m in 10 s. (d) Data insufficient (a) 2 m/s (b) 3.14 m/s (c) 6.28 m/s (d) zero 14. For the x-t graph given below, the v - t 11. The displacement-time graph of two graph is shown correctly in moving particles make angles of 30° and 45° with the X -axis. The ratio of their velocities is x(m) Displacement (x) t(s) v (ms–1) (a) 45° 30° 0 0 t(s) Time (t) (a) 1 : 3 (b) 1 :2 (c) 1 :1 (d) 3 :2 v (ms–1) (b) 12. In figure, displacement-time (x - t ) graph 0 t(s) given below, the average velocity between time t = 5 s and t = 7 s is v (ms–1) (c) 35 30 x (m) 27.4 P2 0 t(s) 25 20 v (ms–1) 15 (d) 10 P1 5 0 t(s) 0 0 1 2 3 4 5 6 7 8 t (s) 15. The speed-time graph of a particle moving along a fixed direction is as (a) 8 ms-1 (b) 8.7 ms-1 shown in the figure. The distance (c) 7.8 ms-1 (d) 13.7 ms-1 traversed by the particle between t = 0 s to t = 10 s is 13. Figure shows the x-t plot of a particle in one-dimensional motion. Two different equal intervals of time show speed in time intervals 1 and 2 respectively, then v (ms–1) 12 A x C B O t (s) 2 5 10 t 1 (a) 20 m (b) 40 m (c) 60 m (d) 80 m 16. If an object is moving in a straight line, then x (m) (a) the directional aspect of vector can be specified by + ve and - ve signs (b) instantaneous speed at an instant is equal t1 to the magnitude of the instantaneous t (s) velocity at that instant (a) zero (c) Both (a) and (b) (b) positive (d) Neither (a) nor (b) (c) Data insufficient (d) Cannot be determined 17. In one dimensional motion, instantaneous speed v satisfies 22. A particle moves in a straight line. It 0 £ v < v 0. Then (NCERT Exemplar) can be accelerated (a) displacement in timeT must always take (a) only, if its speed changes by keeping its non-negative values direction same (b) displacement x in timeT satisfies (b) only, if its direction changes by keeping its - v 0 T < x < v 0T speed same (c) acceleration is always a non-negative (c) Either by changing its speed or direction number (d) None of the above (d) motion has no turning points 23. An object is moving along the path 18. The x-t equation is given as x = 2t + 1. OABO with constant speed, then The corresponding v-t graph is B (a) a straight line passing through origin (b) a straight line not passing through origin (c) a parabola O A (d) None of the above (a) the acceleration of the object while moving 19. The displacement x of an object is given along to path OABO is zero as a function of time, x = 2t + 3t 2. The (b) the acceleration of the object along the instantaneous velocity of the object at path OA and BO is zero t = 2 s is (c) there must be some acceleration along the (a) 16 ms -1 (b) 14 ms -1 path AB (c) 10 ms -1 (d) 12 ms -1 (d) Both (b) and (c) 20. The displacement of a particle starting 24. The average velocity of a body moving from rest (at t = 0) is given by with uniform acceleration travelling a s = 6t 2 - t 3. The time in seconds at distance of 3.06 m is 0.34 ms -1. If the which the particle will attain zero change in velocity of the body is velocity again is 0.18 ms -1 during this time, its uniform (a) 2 (b) 4 (c) 6 (d) 8 acceleration is (a) 0.01 ms-2 21. A car moves along a straight line (b) 0.02 ms-2 according to the x-t graph given below. (c) 0.03 ms-2 The instantaneous velocity of the car at (d) 0.04 ms-2 t = t 1 is 25. The slope of the straight line 30. The resulting a-t graph for the given v-t connecting the points corresponding to graph is correctly represented in (v 2 , t 2 ) and (v 1 , t 1 ) on a plot of velocity versus time gives 30 25 (a) average velocity 24 v(m/s) (b) average acceleration 20 15 (c) instantaneous velocity 10 (d) None of the above 5 0 26. The displacement x of a particle at time 2 4 6 8 10 12 1416 18 20 t(s) t along a straight line is given by x = a - bt + gt 2. The acceleration of the 4.8 2.4 particle is a (ms–2) 0 (a) – 2.4 2 4 6 8 10 12 14 16 18 20 22 (a) -b (b) - b + 2 g (c) 2 g (d) -2 g – 4.8 t (s) – 7.2 – 9.6 27. The displacement (in metre) of a –12.0 particle moving along X -axis is given by x = 18 t + 5t 2. The average 4.8 a (ms–2) 2.4 acceleration during the interval t 1 = 2 s (b) 0 2 4 6 8 10 12 14 16 18 20 22 and t 2 = 4 s is – 2.4 – 4.8 (a) 13 ms -2 (b) 10 ms -2 t (s) (c) 27 ms-2 (d) 37 ms-2 9.6 28. The relation between time and distance a (ms–2) is t = ax + bx , where a and b are 2 (c) 4.8 constants. The retardation is 2.4 (a) 2 av 3 (b) 2bv 3 0 2 4 6 8 10 12 (c) 2 abv 3 (d) 2b 2v 3 t (s) 29. The v -t graph of a moving object is shown in the figure. The maximum a(ms–2) acceleration is (d) 0 2 4 6 8 10 12 14 16 18 20 22 Velocity (cms−1) 80 t (s) 60 31. The kinematic equations of rectilinear 40 motion for constant acceleration for a 20 general situation, where the position coordinate at t = 0 is non-zero, say x 0 is 10 20 30 40 50 60 70 80 Time (s) (a) v = v 0 + at 1 2 (b) x = x0 + v 0 t + at (a) 1 cms -2 (b) 2 cms -2 2 -2 (c) v 2 = v 02 + 2a (x - x0 ) (c) 3 cms (d) 6 cms-2 (d) All of the above 32. The given acceleration-time graph 36. A particle is situated at x = 3 units at represents which of the following t = 0. It starts moving from rest with a physical situations? constant acceleration of 4 ms -2. The a position of the particle at t = 3 s is (a) x = + 21 units (b) x = + 18 units (c) x = -21 units (d) None of these 37. Consider the relation for relative t velocities between two objects A and B, (a) A cricket ball moving with a uniform speed v BA = - v AB is hit with a bat for a very short time interval. The above equation is valid, if (b) A ball is falling freely from the top of a (a) v A and v B are average velocities tower. (b) v A and v B are instantaneous velocities (c) A car moving with constant velocity on a (c) v A and v B are average speed straight road. (d) Both (a) and (b) (d) A football is kicked into the air vertically upwards. 38. A person is moving with a velocity of 33. An object is moving with velocity 10 m s -1 towards north. A car moving 10 ms -1. A constant force acts for 4 s on with a velocity of 20 ms -1 towards south the object and gives it a speed of 2 ms -1 crosses the person. in opposite direction. The acceleration The velocity of car relative to the produced is person is (a) 3 ms-2 (b) - 3 ms-2 (a) - 30 ms-1 (b) + 20ms-1 (c) 6 ms-2 (d) - 6 ms-2 (c) 10 ms-1 (d) - 10 ms-1 34. All the graphs below are intended to 39. A motion of a body is said to be ……, if represent the same motion. One of it moves along a straight line in any them does it incorrectly. Pick it up. direction. Velocity Distance (a) one-dimensional (b) two dimensional (a) Position (b) Time (c) three-dimensional (d) All of the above Position Velocity 40. The numerical ratio of displacement to the distance covered by an object is (c) Time (d) Time always equal to or less than ……. (a) 1 (b) zero (c) Both (a) and (b) (d) infinity 35. Velocity of a body moving along a 41. The time taken by a 150 m long train to straight line with uniform acceleration a cross a bridge of length 850 m is 80 s. It reduces by (3/4)th of its initial velocity is moving with a uniform velocity of in time t 0. The total time of motion of …… km/h. the body till its velocity becomes zero is (a) 45 (b) 90 4 3 5 8 (c) 60 (d) 70 (a) t0 (b) t0 (c) t0 (d) t0 3 2 3 3 42. The distance-time graph of …… is a With reference to the graph, which of straight line. the given statement(s) is/are incorrect? (a) uniform motion (a) The instantaneous speed during the (b) non-uniform motion interval t = 5 s to t = 10 s is negative at all (c) uniform acceleration time instants during the interval. (d) None of the above (b) The velocity and the average velocity for the interval t = 0 s to t = 5 s are equal and 43. Which of the following statement is positive. correct? (c) The car changes its direction of motion at t = 5 s. (a) The magnitude of average velocity is the (d) The instantaneous speed and the average speed. instantaneous velocity are positive at all (b) Average velocity is the displacement time instants during the interval t = 0 s to divided by time interval. t = 5 s. (c) When acceleration of particle is constant, then motion is called as non-uniformly 46. A graph of x versus t is shown in figure. accelerated motion. Choose correct statement given below. (d) When a particle returns to its starting point, x its displacement is non-zero. 44. For motion of the car between t = 18 s A B E and t = 20 s, which of the given C statement is correct? 296 D t x (m) 250 (a) The particle having some initial velocity at t = 0. 100 (b) At point B, the acceleration a > 0. (c) At point C, the velocity and the acceleration O 10 18 20 t(s) vanish. (d) The speed at E exceeds that at D. (a) The car is moving in a positive direction with a positive acceleration. 47. Match the Column I with Column II (b) The car is moving in a negative direction and select the correct option from the with a positive acceleration. codes given below (c) The car is moving in positive direction with a negative acceleration. Column I Column II (d) The car is moving in negative direction with a negative acceleration. A. d v / dt p. Acceleration 45. The x-t graph for motion of a car is B. d | v |/dt q. Rate of change of given below speed 10 dr x (m) C. r. Velocity dt d | r| Magnitude D. s. O 5 10 dt of velocity t(s)  Codes Column I Column II A B C D Position-time (a) p q r s graph of two A. p. (b) p r s q objects with x (m) (c) q p r s equal velocities. O t(s) (d) s r p q 48. Given x-t graph represents the motion Position-time of an object. Match the Column I B. graph of two q. (parts of graph) with Column II objects with x (m) (representation) and select the correct unequal option from the codes given below. velocities but O t(s) in same A direction. x Position-time C C. graph of two r. B objects with x (m) velocities in O opposite O t(s) t direction. Column I Column II Codes A. Part OA of p. Positive A B C A B C graph velocity (a) p q r (b) q p r B. Part AB of q. Object at rest (c) p r q (d) q r p graph C. Part BC of r. Negative Assertion-Reasoning MCQs graph velocity For question numbers 50 to 63, two D. Point A in the s. Change in statements are given-one labelled graph direction of Assertion (A) and the other labelled motion Reason (R). Select the correct answer to Codes these questions from the codes (a), (b), (c) A B C D and (d) are as given below (a) Both A and R are true and R is the (a) p q r s correct explanation of A. (b) p r q s (b) Both A and R are true but R is not the (c) q p r s correct explanation of A. (d) s r q p (c) A is true but R is false. (d) A is false and R is also false. 49. Match the Column I (position-time graph) with Column II (representation) 50. Assertion In real-life, in a number of and select the correct option from the situations, the object is treated as a codes given below. point object.  Reason An object is treated as point Reason Infinite acceleration cannot be object, as far as its size is much smaller realised in practice. than the distance, it moves in a reasonable duration of time. 58. Assertion In realistic situation, the x-t, v-t and a-t graphs will be smooth. 51. Assertion If the displacement of the body is zero, the distance covered by it Reason Physically acceleration and may not be zero. velocity cannot change values abruptly at an instant. Reason Displacement is a vector quantity and distance is a scalar quantity. 59. Assertion A body cannot be accelerated, when it is moving 52. Assertion An object can have constant uniformly. speed but variable velocity. Reason When direction of motion of Reason SI unit of speed is m/s. the body changes, then body does not have acceleration. 53. Assertion The speed of a body can be negative. 60. Assertion For uniform motion, velocity Reason If the body is moving in the is the same as the average velocity at all opposite direction of positive motion, instants. then its speed is negative. Reason In uniform motion along a straight line, the object covers equal 54. Assertion For motion along a straight distances in equal intervals of time. line and in the same direction, the magnitude of average velocity is equal 61. Assertion A body is momentarily at to the average speed. rest at the instant, if it reverse the Reason For motion along a straight line direction. and in the same direction, the Reason A body cannot have magnitude of displacement is not equal acceleration, if its velocity is zero at a to the path length. given instant of time. 55. Assertion An object may have varying 62. Assertion In the s-t diagram as shown speed without having varying velocity. in figure, the body starts moving in positive direction but not from s = 0. Reason If the velocity is zero at an instant, the acceleration is zero at that s instant. 56. Assertion Acceleration of a moving t particle can change its direction without t0 any change in direction of velocity. Reason If the direction of change in velocity vector changes, direction of acceleration vector does not changes. Reason At t = t 0 , velocity of body 57. Assertion The v-t graph perpendicular changes its direction of motion. to time axis is not possible in practice.