Shapes of Molecules MCQs PDF
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This document contains multiple choice questions about molecular shapes. It includes questions on topics such as identifying molecular shapes, calculating bond angles, and predicting molecular geometry using VSEPR theory. The questions relate to topics like SF6, CH3Cl, NH3, and other molecules.
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19. Which molecular shape results from six bonding pairs around a central atom like SF₆? a) Tetrahedral b) Trigonal planar c) Octahedral d) Linear Answer: c) Octahedral *Explanation: SF₆ has six bonding pairs around the sulfur atom which arrange in an octahedral shape with bond angles of 90°* 20....
19. Which molecular shape results from six bonding pairs around a central atom like SF₆? a) Tetrahedral b) Trigonal planar c) Octahedral d) Linear Answer: c) Octahedral *Explanation: SF₆ has six bonding pairs around the sulfur atom which arrange in an octahedral shape with bond angles of 90°* 20. What is the shape of the molecule CH₃Cl? a) Trigonal planar b) Tetrahedral c) Linear d) Bent Answer: b) Tetrahedral *Explanation: CH₃Cl has four regions of electron density around the central carbon atom, resulting in a tetrahedral shape with bond angles of 109.5°.* 21. Deduce the shape and bond angle of the ammonia molecule (NH₃). a) Trigonal planar, 120° b) Tetrahedral, 109.5° c) Trigonal pyramidal, 107° d) Bent, 104.5° Answer: c) Trigonal pyramidal, 107° *Explanation: NH₃ has three bonding pairs and one lone pair on the central nitrogen atom, resulting in a trigonal pyramidal shape and a bond angle of 107°.* 22. How does one deduce the shape of a molecule like water? a) Consider the electronegativity di erences b) Balance charges on the atom c) Calculate the total number of electron pairs and observe repulsions d) Consider the atomic mass Answer: c) Calculate the total number of electron pairs and observe repulsions *Explanation: VSEPR theory deduces the shape by calculating total electron pairs around the central atom and arranging them to minimise repulsions.* 23. Identify the number of lone pairs and bond pairs in the molecule ClF₃. a) 2 lone pairs, 3 bond pairs b) 0 lone pairs, 4 bond pairs c) 3 lone pairs, 2 bond pairs d) 1 lone pairs, 3 bond pairs Answer: 2 lone pairs, 3 bond pairs *Explanation: ClF₃ has ve electron pairs around the chlorine atom, of which 3 are bonding pairs and 2 are lone pairs, creating a T-shaped molecule with bond angles approximately 90°.* 24. What is the molecular geometry of SF₄, and why? a) Tetrahedral, due to strong imbalanced bonds b) Trigonal bipyramidal, securing ve electron pairs c) Seesaw, re ecting presence of lone pair d) Linear, due to symmetric atom dispersion Answer: c) Seesaw, re ecting presence of lone pair *Explanation: SF₄ adopts seesaw geometry because it has four bonding pairs and one lone pair, leading to lone-pair-bonding pair and subsequent seesaw structure.* fl fl fi fi ff 25. Which shape does the sulfate ion (SO₄⁻²) adopt and what are its bond angles? a) Linear, 180° b) Trigonal planar, 120° c) Tetrahedral, 109.5° d) Bent, 104.5° Answer: c) Tetrahedral, 109.5° *Explanation: SO₄⁻² features four regions of electron density around the sulphur atom, forming tetrahedral ions with 109.5° bond angles.* 26. In what geometry do uorine atoms around central sulfur converge in SF₆? a) Tetrahedral shape b) Trigonal bipyramidal shape c) Square planar shape d) Octahedral shape Answer: d) Octahedral shape *Explanation: In SF₆, six bonding pairs around sulfur converge symmetrically on the octahedral structure of bond angles mapped to 90°.* 27. What VSEPR shape does ICl₃ (Iodine Trichloride) adopt incorporating lone pairs' role? a) Tetrahedral b) Trigonal planar c) Trigonal bipyramidal d) T-shaped geometrics Answer: d) T-shaped geometrics *Explanation: ICl₃ features total ve pairs (dual lone pairs & three bond pairs) forming T-shape due to lone-pair-bond-pair spatial repulsion.* 28. What bond angle respects tetrahedral vacancy observed in molecular geometry like CN₄? a) 90° b) 109.5° c) 120° d) 104.5° Answer: b) 109.5° *Explanation: Triangular voluminous tetrahedral molecular geometry o ers balanced 109.5° evidenced equivalent valence distribution.* 29. Identify bond angle alteration from 109.5° tetrahedral to trigonal pyramidal impact on angle in NH₃. a) Maintained 109.5° b) Reduced to 107° c) Increased to 120° d) Diminished to 104.5° Answer: b) Reduced to 107° *Explanation: NH₃ (partial lone pairs a ect) converges electron-pair repulsion which diminishes 109.5° tetrahedral angle shape down to 107° trigonal geometry.* fl fi ff ff