Scalars and Vectors PDF
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This document provides definitions and examples of scalar and vector quantities. It explains different types of vectors, including like vectors, unlike vectors, equal vectors, and more. The document also describes how to perform vector addition, and explores concepts around dot products and cross products.
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# Vectors and Scalars All the physical quantities are classified into two groups on the basis of magnitude and direction. * **Scalars**: Those physical quantities having only magnitude are called scalars. - *Examples*: mass, time, distance, speed, area, work, energy, etc. * **Vectors**: Those p...
# Vectors and Scalars All the physical quantities are classified into two groups on the basis of magnitude and direction. * **Scalars**: Those physical quantities having only magnitude are called scalars. - *Examples*: mass, time, distance, speed, area, work, energy, etc. * **Vectors**: Those physical quantities having magnitude as well as direction are called vectors. - *Examples*: Displacement, Velocity, acceleration, force, Momentum etc. ## Notation of a Vector A vector is denoted by an alphabet giving an arrow (→) over its head. - *Velocity is denoted as V*, *force is denoted as F*, *momentum is denoted as P*. ## Representation of Vectors A vector is represented by a directed line segment i.e a straight line drawing an arrow at one end. - **The length of the line indicates magnitude.** - **The arrow sign indicates direction.** ## Modulus of a Vector Modulus of a vector gives only magnitude. Modulus of a vector is denoted by enclosing it between two vertical parallel lines. - *Modulus of a = |a| = √a² = a*. ## Classification of Vectors * **Unit Vector**: A vector whose modulus is equal to 1 is called a unit vector. - A unit vector is denoted by a small letter and the arrow (→) is replaced by a caret or hat. - *|â| = 1* * **Null Vector**: A vector whose modulus is zero is called a null vector. - *Example*: |a|=0; a= null vector - *Velocity of a body projected vertically upward at the maximum height = 0; |v|=0* - *Resultant force of two equal and opposite forces is a null vector* * **Proper Vector**: A vector whose modulus is not equal to zero. - *|a|≠0* * **Like Vectors**: Two or more vectors are called like vectors if they have the same direction and different magnitudes. * **Unlike Vectors**: Two or more vectors are called unlike vectors if they have opposite direction and different magnitudes. * **Equal Vectors**: Two or more vectors are called equal vectors if they have the same magnitude and the same direction. * **(-ve) Vectors**: Two vectors are called (-ve) vectors of each other if they have the same magnitude, but opposite directions * **Co-Linear Vectors**: Two or more vectors are called co-linear vectors if they lie in the same line. * **Co-Planner Vectors**: Two or more vectors are called co-planner vectors if they lie in the same plane. * **Co-Initial Vectors**: Two or more vectors are called co-initial vectors if they have the same origin. * **Orthogonal Vectors**: Two or more vectors are called orthogonal vectors if they are perpendicular to each other. ## Addition of Two Vectors The head-and-tail rule: 1. **Join the head of a with the tail of b**. 2. **The vector joining the tail of a to the head of b gives the resultant vector: a+b = OA + AB = OB = c** ### General Addition of Vectors: - **AB + BC = AC** - **PB + BR = PR** - **AB + CB =** (This is not added). ### Addition of Several Vectors: - **Let OA = a, AB = b, BC = c, CD = d** - **a+b = OA + AB = OB** - **(a+b) + c = OB + BC = OC** - **(a+b+c) + d = OC + CD = OD** **Rules of addition of several vectors:** 1. **The resultant of several vectors is obtained by adding tail of the first vector to the head of the last vector** 2. **The resultant of several vectors in a closed figure is zero.** ## Commutative Law **Proof**: Let us consider a parallelogram ABCD. - **AD = a, AB = b, AC = c, BD = d** - **Since ABCD is a parallelogram, a + b = c, b + d = a** ## Associative Law - **(a+b)+c = a+(b+c)** ## Subtraction of Two Vectors - **a-b = a+(-b)** **To subtract b in a means to add -b in a** **Steps to subtract b in a:** 1. Draw -b by reversing the direction of b, keeping the same magnitude. 2. Join the head of a with the tail of -b. 3. The vector joining the tail of a to the head of -b gives the resultant vector: a+(-b) = a-b. ## Multiplication of Vectors ### Multiplication of a vector with a scalar When a vector is multiplied with a scalar, then the product is a vector quantity whose direction remains the same, but the magnitude becomes scalar times of the previous vector. - *2a = scalar* - *a = vector* - *2a = 2|a|a = vector* *Example*: - *m = mass of a body (scalar)* - *a = acceleration of the body (vector)* - *m x a = F = vector = force* ### Multiplication of two vectors If two vectors are multiplied then the product is either a scalar or a vector. Therefore, there are two types of products of two vectors. 1. **Scalar product or dot product**: a.b = |a| |b| cos θ = abcos θ 2. **Vector product or cross product**: a x b = |a| |b| sin θ n = ab sin θ n #### Properties of Scalar Product (Dot Product) 1. The dot product of two vectors is maximum if the angle between them is 0. i.e. two vectors are in the same direction. - *If θ=0, then cosθ=1 (maximum)* - *a.b = abcosθ = ab = |a| |b| maximum* 2. If two vectors are perpendicular to each other, then their dot product is 0. - *If two vectors are perpendicular to each other, then θ = 90°, so cosθ = 0* - *a.b = ab cos θ = ab cos 90 = 0* 3. Dot product of a vector with itself is the square of its modulus. - *a.a =|a|² = a²* 4. Dot product of two vectors is commutative. - *a . b = bacos θ = b.a* 5. Dot Product of two unit vectors: - *î.î = |î||î|cosθ = 1 x 1 x 1 = 1* - *Similarly, j.j = k.k = 1* - *î.j = |î||j|cos90 = 1 x 1 x 0 = 0; => î.j = 0* - *Similarly, j.k = k.i = 0* 6. Dot product between two vectors - *If a = a<sub>1</sub>î + a<sub>2</sub>j + a<sub>3</sub>k* - *b = b<sub>1</sub>î + b<sub>2</sub>j + b<sub>3</sub>k* - *Then, a.b = a<sub>1</sub>b<sub>1</sub>î.î + a<sub>1</sub>b<sub>2</sub>î.j + a<sub>1</sub>b<sub>3</sub>î.k + a<sub>2</sub>b<sub>1</sub>j.î + a<sub>2</sub>b<sub>2</sub>j.j + a<sub>2</sub>b<sub>3</sub>j.k + a<sub>3</sub>b<sub>1</sub>k.î + a<sub>3</sub>b<sub>2</sub>k.j + a<sub>3</sub>b<sub>3</sub>k.k* - *a.b = a<sub>1</sub>b<sub>1</sub> + a<sub>2</sub>b<sub>2</sub> + a<sub>3</sub>b<sub>3</sub>* *Example:* - *a = 3î + 2j - 2k* - *b = 2î + j – k* - *a.b = 6 + 2 + 2 = 10* *To find the angle between two vectors* - *a = 3î + 2j - 2k* - *b = 2î + j – k* - *a.b = |a| |b| cos θ* - *cos θ = (a.b)/(|a| |b|) = (6+2+2)/ (√(9+4+4)√(4+1+1))* - *cos θ = (10)/(√17√6) => θ ≈ 90°* #### Properties of Vector Product (Cross-Product) 1. *a x b = ab sin θ n* 2. *|a x b| = ab sin θ* 3. Cross product of two vectors is maximum if the angle between them is 90°. If two vectors are perpendicular to each other. - *If θ = 90°, then sin θ = 1* - *|a x b| = ab sin θ = ab* - *And the maximum is when a and b are perpendicular to each other* 4. Cross product of two vectors is 0 if the angle between them is 0°. i.e. two vectors are in the same direction - *If θ = 0°, then sin θ = 0 * - *|a x b| = ab sin θ = 0* 5. The cross product of a vector with itself is 0. - *a x a = aa sin θ n = 0* 6. The cross product of two vectors is anti-commutative. - *(a x b) = -(b x a)* 7. Cross product of two unit vectors. - *î x î = |î| |î| sin θ n = 1 x 1 x 0 n = 0* - *Similarly, j x j = k x k = 0* - *î x j = |î| |j| sin 90 n = 1 x 1 x 1 n = n* - *Similarly, j x k = n, k x i = n* - *î x i = -n* - *Similarly, j x i = -k, k x j = -i* 8. Cross product of two vectors. Let: - *a = a<sub>1</sub>î + a<sub>2</sub>j + a<sub>3</sub>k* - *b = b<sub>1</sub>î + b<sub>2</sub>j + b<sub>3</sub>k * Method 1: *a x b = a<sub>1</sub>b<sub>1</sub>îxî + a<sub>1</sub>b<sub>2</sub>îxj + a<sub>1</sub>b<sub>3</sub>îxk + a<sub>2</sub>b<sub>1</sub>jxî+ a<sub>2</sub>b<sub>2</sub>jxj + a<sub>2</sub>b<sub>3</sub>jxk + a<sub>3</sub>b<sub>1</sub>kxî + a<sub>3</sub>b<sub>2</sub>kxj + a<sub>3</sub>b<sub>3</sub>kxk * - *(0)î + (a<sub>1</sub>b<sub>3</sub>-a<sub>3</sub>b<sub>1</sub>)j + (a<sub>2</sub>b<sub>1</sub>-a<sub>1</sub>b<sub>2</sub>)k + (a<sub>3</sub>b<sub>2</sub>-a<sub>2</sub>b<sub>3</sub>)î + (0)j + (a<sub>1</sub>b<sub>2</sub>-a<sub>2</sub>b<sub>1</sub>)k* - *(a<sub>3</sub>b<sub>2</sub>-a<sub>2</sub>b<sub>3</sub>)î + (a<sub>1</sub>b<sub>3</sub>-a<sub>3</sub>b<sub>1</sub>)j + (a<sub>2</sub>b<sub>1</sub>-a<sub>1</sub>b<sub>2</sub>)k* Method 2: [1] [2] [3] *a x b = î (a<sub>2</sub>b<sub>3</sub>-a<sub>3</sub>b<sub>2</sub>) + j (a<sub>3</sub>b<sub>1</sub>-a<sub>1</sub>b<sub>3</sub>) + k (a<sub>1</sub>b<sub>2</sub>-a<sub>2</sub>b<sub>1</sub>)* *Example:* - *If a = 3î + 2j – 3k* - *b = - 2î + 2j + 5k* [1] [2] [3] *a x b = î (10 + 6) + j (-15 + 6) + k (6 + 4) = 16î - 9j + 10k* ## Triangle Law of Vector Addition If two vectors are represented by two sides of a triangle in magnitude and direction then their resultant is represented by the third side in magnitude, but direction is taken in reverse order. **Let us consider a ∆OAB** - **Let OA = a, AB = b and OB = c** - **a + b = OA + AB = OB = c** **So, c = √(a² + b² + 2ab cos θ) (magnitude)** **Direction of c:** - **Let OM represent a, MB represent b, and OB represents c** - **tan α = BM/OM = b sin θ/a + b cos θ** **α = tan<sup>-1</sup> (b sin θ/a + b cos θ) (Direction)** **Different Cases:** ### **Case 1: θ = 0** Two vectors are in the same direction. - *cosθ = 1 (maximum)* - *sinθ = 0* - *c = √(a² + b² + 2ab cos θ)* - *c = √(a² + b² + 2ab) = √(a + b)² = a + b* - *|c| = |a| + |b| = max'm* - *tan α = b sin θ/a + b cos θ = 0* - *α = 0* ### **Case 2: θ = 180°** Two vectors are in the opposite direction. - *cos θ = -1 (minimum)* - *sin θ = 0* - *c = √(a² + b² + 2ab cos θ) = √(a² + b² - 2ab) = √(a - b)² = a - b* - *|c| = |a| - |b| = minimum* - *If a = b then |c| = 0* - *tan α = b sin θ/a + b cos θ = 0* - *α = 0* ### **Case 3: θ = 90°** - *You would calculate the resultant vector* ## Resolving a vector into its two perpendicular components Let P be a point on the x-y plane. - **P = (x, y)** - **OP = r** - The position vector of P, r, is **r = xi + yj**. - The angle between r and the x-axis is θ. - **x = r cos θ** - **y = r sin θ** - **So, r = r cos θ i + r sin θ j** Let's apply these concepts to some examples: **Example 1: When two vectors are in the same direction** Say you have a car travelling 200m East and then 300m East. Both vectors are in the same direction. Therefore, the net displacement will be 200m + 300m = 500m East. **Example 2: When two vectors are in opposite directions** Suppose you have a car travelling 200m East and then 300m West. Now you will subtract the two displacements, and the net displacement will be 300m - 200m = 100m West. We make the displacement West because the 300m displacement vector is larger than the 200m vector. **Example 3: When two vectors are perpendicular to each other** Imagine an object moving 10m north and then 10m east. Here, we have two perpendicular vectors. To get the net displacement, we can use the Pythagorean theorem: Net displacement = √(10m² + 10m²) = √200m² = 14.1m **Example 4: When two vectors are at an angle to each other** Imagine two vectors of 10m each, with an angle of 60° between them. We can use the parallelogram law to find the resultant. This means: - The magnitude of the resultant is 10√3m - The direction of the resultant is 30° Keep in mind that the concepts of vectors and scalars are crucial in physics and other fields. Understanding them is crucial for analyzing and solving a wide range of problems that involve quantities that have both magnitude and direction.