Summary

This document provides a comprehensive note on number bases for secondary school level. It covers fundamental concepts such as different number bases (decimal, binary, octal, hexadecimal), place value systems, and conversion between different bases. The note also includes arithmetic operations, emphasizing addition and subtraction in various number bases. It's suitable for high school level mathematics students.

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Number Base - SS3 Mathematics Comprehensive Note 1. Introduction to Number Bases A number base is a way to represent numbers using a specific set of digits and place values. It defines the number of unique digits, including zero, used in a numbering system. For example: Base 10 (Decimal) uses digi...

Number Base - SS3 Mathematics Comprehensive Note 1. Introduction to Number Bases A number base is a way to represent numbers using a specific set of digits and place values. It defines the number of unique digits, including zero, used in a numbering system. For example: Base 10 (Decimal) uses digits 0–9. Base 2 (Binary) uses digits 0 and 1. Base 8 (Octal) uses digits 0–7. Base 16 (Hexadecimal) uses digits 0–9 and A–F. 2. Place Value System In any base system, the value of a digit depends on: Its face value (the actual digit). Its place value, which is a power of the base. For example, in base 10, the number 345 means: 345 = ( 3 × 1 0 2 ) + ( 4 × 1 0 1 ) + ( 5 × 1 0 0 ) 345=(3×10 2 )+(4×10 1 )+(5×10 0 ) 3. Conversion Between Number Bases (i) Conversion from Base 10 to Other Bases Example 1: Convert 45 (Base 10) to Base 2. Divide by 2 and record the remainders. Continue until the quotient is 0. Write remainders from bottom to top. 45 ÷ 2 = 22 remainder 122 ÷ 2 = 11 remainder 011 ÷ 2 = 5 remainder 15 ÷ 2 = 2 remainder 12 ÷ 2 = 1 remainder 01 ÷ 2 = 0 remainder 1 45 ÷ 2=22 remainder 122 ÷ 2=11 remainder 011 ÷ 2=5 remainder 15 ÷ 2=2 remainder 12 ÷ 2=1 remainder 01÷2=0 remainder 1 Answer: 4 5 10 = 10110 1 2 45 10 =101101 2 (ii) Conversion from Other Bases to Base 10 Example 2: Convert 1011 (Base 2) to Base 10. 101 1 2 = ( 1 × 2 3 ) + ( 0 × 2 2 ) + ( 1 × 2 1 ) + ( 1 × 2 0 ) 1011 2 =(1×2 3 )+(0×2 2 )+(1×2 1 )+(1×2 0 ) = 8 + 0 + 2 + 1 = 1 1 10 =8+0+2+1=11 10 4. Arithmetic Operations in Number Bases (i) Addition Example: Add 110 1 2 + 101 1 2 1101 2 +1011 2 in Base 2. 1101 + 1011 ------ 11000 Answer: 1100 0 2 11000 2 (ii) Subtraction Example: Subtract 110 1 2 − 101 1 2 1101 2 −1011 2. 1101 - 1011 ------ 010 Answer: 1 0 2 10 2 5. Applications of Number Bases Computing Systems: Computers use binary (Base 2) for processing data. Octal and Hexadecimal: Used in programming and digital circuits to simplify binary numbers. Measurements: Time and angles are measured in base 60. 6. Base Conversion Tricks Binary → Octal: Group digits in 3s starting from the right. Binary → Hexadecimal: Group digits in 4s starting from the right. Octal/Hexadecimal → Binary: Expand each digit into binary form. Example: Convert 10110 1 2 101101 2 to Octal: Group: 101 ∣ 101 = 5 ∣ 5 101∣ 101=5∣ 5 → 55₈ 7. Exercises Convert 12 3 8 123 8 to Base 10. Convert 4 5 10 45 10 to Base 5. Add 110 1 2 + 101 1 2 1101 2 +1011 2. Subtract 1011 0 2 − 110 1 2 10110 2 −1101 2. Convert 2 F 16 2F 16 to Base 10. 8. Answers to Exercises 12 3 8 = ( 1 × 8 2 ) + ( 2 × 8 1 ) + ( 3 × 8 0 ) = 8 3 10 123 8 =(1×8 2 )+(2×8 1 )+(3×8 0 )=83 10 4 5 10 45 10 → Divide repeatedly by 5 → 140_5 110 1 2 + 101 1 2 = 1100 0 2 1101 2 +1011 2 =11000 2 1011 0 2 − 110 1 2 = 1000 1 2 10110 2 −1101 2 =10001 2 2 F 16 = ( 2 × 1 6 1 ) + ( 15 × 1 6 0 ) = 4 7 10 2F 16 =(2×16 1 )+(15×16 0 )=47 10 This note should cover all the essential concepts and operations needed to understand Number Bases at the SS3 level.

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