Kirchhoff's Laws PDF
Document Details
![DiversifiedObsidian3472](https://quizgecko.com/images/avatars/avatar-3.webp)
Uploaded by DiversifiedObsidian3472
Tags
Summary
This document explains Kirchhoff's laws, covering both current (KCL) and voltage (KVL). It includes examples and diagrams to illustrate concepts. The document is suitable for undergraduate-level electrical engineering students.
Full Transcript
Kirchhoff's Laws: Understanding Current and Voltage in Circuits Kirchhoff's Laws Kirchhoff's Current Law (KCL) Understanding Nodes Node: Point where two or more circuit elements meet Principal nodes: Points where three or more elements connect Current direction convention: Into...
Kirchhoff's Laws: Understanding Current and Voltage in Circuits Kirchhoff's Laws Kirchhoff's Current Law (KCL) Understanding Nodes Node: Point where two or more circuit elements meet Principal nodes: Points where three or more elements connect Current direction convention: Into node (+), Out of node (-) KCL Problem Example 1 KCL Problem Example 2 What is the value of I in the circuit segment shown in the figure? Kirchhoff's Voltage Law (KVL) Loop: Any closed path in a circuit Voltage rise: Battery positive terminal Understanding Loops Voltage drop: Across resistors, battery negative terminal Sign convention: clockwise direction Kirchhoff's voltage law can be summarized in this situation as: 6 V−4 V−2 V=0 6 V−(2 A×2 Ω)−(2 A×1 Ω)=0 KVL Problem Example For the circuit diagram in the figure, use Kirchhoff's voltage law to find VA and VB If R1 = 2Ω, R2 = 4Ω, R3 = 6Ω, determine the electric current that flows in the circuit below. Summary and Key Points KCL: Current entering equals current leaving KVL: Sum of voltages in loop equals zero Combined use for complex circuits 8A 2.5A Problem 1 I What is the value of I in the circuit segment 2.5A shown in the figure? 3A Problem 2 What is the value of I in the circuit segment shown in the figure? If R1 = 3Ω, R2 = 5Ω, R3 = 7Ω, determine the electric current that flows in the circuit below. V1 = 12 V V2 = 16 V