Engineering Mechanics Past Paper PDF - December 2017

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Dr. Babasaheb Ambedkar Technological University, Lonere

2017

DR. BABASAHEB AMBEDKAR TECHNOLOGICAL UNIVERSITY

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engineering mechanics mechanics forces physics

Summary

This is a past paper for an Engineering Mechanics exam, taken in December 2017 at Dr. Babasaheb Ambedkar Technological University. The paper is composed of problems in areas like force addition, support reactions, and dynamics.

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DR. BABASAHEB AMBEDKAR TECHNOLOGICAL UNIVERSITY LONERE – RAIGAD - 402 103 End Semester Examination – December - 2017 ------------------------------------------------------------------------------------------------------- Branch: B. Tech (Group A/G...

DR. BABASAHEB AMBEDKAR TECHNOLOGICAL UNIVERSITY LONERE – RAIGAD - 402 103 End Semester Examination – December - 2017 ------------------------------------------------------------------------------------------------------- Branch: B. Tech (Group A/Group B) Semester: I Subject with Subject Code: Engineering Mechanics Marks: 60 [ME102] Date:- 13/12/2017 Time: 3 Hrs. ============================================================ Instructions to the Students 1. Each question carries 12 marks. 2. Attempt any five questions of the following. 3. Illustrate your answers with neat sketches, diagram etc., wherever necessary. 4. If some part or parameter is noticed to be missing, you may appropriately assume it and should mention it clearly _____________________________________________________________________ (Marks) Q.1. A) How will you add two forces? Explain the Parallelogram Law and Law of Triangle of forces. (6M) B) Two ropes are tied together at C. If the maximum permissible tension in each rope is 3.5 kN, what is the maximum force P that can be applied and in what direction as shown in figure 1. (6M) Figure 1 Q.2. A) What are various types of supports and support reactions? Explain with its free body diagram. (4M) B) Using the method of joints, find the axial forces in all the members of a truss with the loading shown in the Figure 2. (8M) Figure 2 Q.3. A) Locate the centroid of the shaded area obtained by removing a semicircle of diameter a from a quadrant of a circle of radius a as shown in Fig. 3. (6M) Figure 3 B) A 7m long ladder rests against a vertical wall, with which it makes an angle of 45°, and on a floor. If a man, whose weight is one half of that of the ladder, climbs it, at what distance along the ladder will he be, when the ladder is about to slip shown in Figure 4? The coefficient of friction between the ladder and the wall is 1/3 and that between the ladder and the floor is 1/2. (6M) Figure 4 Q.4. A) A trolley resting on a horizontal plane starts from rest and is moved to the right with a constant acceleration of 0.18 m/s2 shown in Figure 5. Determine: i) acceleration of the block B connected to the trolley and ii) velocities of the trolley and the block after a time of 4 seconds and the distance moved by each of them. (6M) Figure 5 B) A passenger train passes a certain station at 60 km/hr and covers a distance of 12 km with this speed and then stops at the next station 15 km from the first with uniform retardation. A local train starting from the first station covers the same distance in double this time and stops at the next station. Determine the maximum speed of the local train which covers a part of the distance with uniform acceleration and the rest with uniform retardation. (6M) Q.5. A) Explain in detail: D'Alemberts principle and write the equations of dynamic equilibrium of the particle. (4M) B) Two blocks of masses M1 and M2 are connected by a flexible but (8M) inextensible string as shown in the figure. Assuming the coefficient of friction between block M1 and horizontal surface to be µ find the acceleration of the masses and tension in the string as per figure 6. Assume M1= 10 kg and M2 = 5 kg, µ = 0.25. Figure 6 Q.6. A) A spring of stiffness 1000 N/m is stretched by 10 cm from the undeformed position. Find the work of the spring force. Also find the work required to stretch it by another 10 cm. (6M) B) What do you understand by direct central impact? Also explain the coefficient of restitution. (6M) 8E FEDD93 5F3 3D3 18AAE4 7C D3DD66 F99 D F EF FED 935 5F3DD31 18A E47 7CD 3D 66F 996 6996 ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 ED 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EFE 5 D 1 7 6 6 6 E D9 935F F3D 318 8AE E47C CD3 3D6 6F9 9969 9962 28E FEDD93 35 3D 31 AE 47 D D6 6F 96 96 8E FE 93 5F 93 F3 3 8A 4 CD 3D 6F 99 99 28 F D9 5 3D 5 1 7 6 E F 35 F3DD31 8AE E47 CD 3D6 66F 996 996 628E EFE D93 35F 3D3 318A F3 31 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 E F3 D31 8A E4 7CD 3D 66F 99 699 628 EFE D9 35F 3D 318 AE 47C D 7 6 6 E Q.2. Q.1. 3D 318 8AE E47C CD3 3D6 66F9 9969 996 28E FEDD93 35F3 3D3 318AAE4 47C D3D 31 A 47 D D 6 F 96 2 D D3 8A E4 C 3D 66 99 99 962 8EF FED 935 5F3DD31 18A E47 7CD 3D 66F 18 E 7C D3 66 F9 69 62 8EF ED 935 F3 31 8A E47 CD 3D 66F 996 31 AE 47 D D6 F 96 96 8E E 93 F D3 8 E4 C 3 66 99 9 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 CE, CG and FG. 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C Date: 16 / 05 / 2018 ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 Instructions to the Students: 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 Attempt the following. 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 Attempt the following. E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 mechanics point of view? Explain with any example. Figure 1 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D the knowledge of that part is a part of examination. Time: 3 Hours D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 B. Tech Course, Semester: II 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 99628EFED935F3D318AE47CD3D66F996 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F Subject: Engineering Mechanics (EM 202) Summer Semester Examinations, May 2018 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 in figure 1. Find the tensions in the portions AB, BC and CD of the string. 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 1. Attempt ANY FIVE Questions from Question No 1 to Question No 6. 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 2. Illustrate your answers with neat sketches, diagrams etc. wherever necessary. Dr. Babasaheb Ambedkar Technological University, Lonere - Raigad 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 Max Marks: 60 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 A 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7 1) State and explain the Principle of Transmissibility. How it is useful as per engineering 3. Necessary data is given in the respective questions. If such data is not given, it means that (06X2=12) components? Explain this method with resolution and projections of the forces with any example. E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 (06X2=12) 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 C 2) How will you find out resultant of a several concurrent coplanar forces by summing rectangular 2) A truss is loaded and supported as shown in figure 2. Determine the axial forces in the member 1) Two equal loads of 2500 N are supported by a flexible string ABCD at points B and C as shown D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 99 99 28 F D9 35 3D 31 AE 47 D3 69 62 EF ED 35 F3 31 8A 47 CD D 96 8E E 93 F D3 8A E4 C 3D 28 FE D9 5F 3D 18 E 7C D3 6 EF D 35 3D 31 A 47 D D 6 ED 93 F3 3 8A E4 CD 3D 66F 93 5F3 D3 18A E4 7CD 3D 66F 5F D3 18 E 7C 3 66 9 3D 18 AE 47C D3 D6 F9 9 31 AE 47 D D6 6F 96 8A 4 CD 3D 6F 99 E4 7CD 3D 66 99 6 7C 3 66 F9 6 D 9 8E FEDD93 5F3 3D3 18AAE4 7C D3DD66 F99 D F EF FED 935 5F3DD31 18A E47 7CD 3D 66F 996 6996 ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 ED 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EFE 5 D 1 7 6 6 6 E D9 935F F3D 318 8AE E47C CD3 3D6 6F9 9969 9962 28E FEDD93 35 3D 31 AE 47 D D6 6F 96 96 8E FE 93 5F 93 F3 3 8A 4 CD 3D 6F 99 99 28 F D9 5 3D 5 1 7 6 E F 35 F3DD31 8AE E47 CD 3D6 66F 996 996 628E EFE D93 35F 3D3 318A F3 31 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 E F3 D31 8A E4 7CD 3D 66F 99 699 628 EFE D9 35F 3D 318 AE 47C D 7 6 6 E Q.3. 3D 318 8AE E47C CD3 3D6 66F9 9969 996 28E FEDD93 35F3 3D3 318AAE4 47C D3D 31 A 47 D D 6 F 96 2 D D3 8A E4 C 3D 66 99 99 962 8EF FED 935 5F3DD31 18A E47 7CD 3D 66F lamina? 18 E 7C D3 66 F9 69 62 8EF ED 935 F3 31 8A E47 CD 3D 66F 996 31 AE 47 D D6 F 96 96 8E E 93 F D3 8 E4 C 3 66 99 9 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 Attempt the following. 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 Figure 3 Figure 2 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 99628EFED935F3D318AE47CD3D66F996 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 determine what minimum horizontal force P should be applied to raise the block. 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 A 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7 (06X2=12) E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 C 1) A block A weighing 1000 N is to be raised by means of a 15 ° wedge B weighing 500 N as 2) A square hole is punched out of a circular lamina as shown in figure 4. The diagonal of the square which is punched out is equal to the radius of circle. Find the centroid of the remaining shown in figure 3. Assuming the coefficient of friction between all contact surfaces to be 0.2, D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 99 99 28 F D9 35 3D 31 AE 47 D3 69 62 EF ED 35 F3 31 8A 47 CD D 96 8E E 93 F D3 8A E4 C 3D 28 FE D9 5F 3D 18 E 7C D3 6 EF D 35 3D 31 A 47 D D 6 ED 93 F3 3 8A E4 CD 3D 66F 93 5F3 D3 18A E4 7CD 3D 66F 5F D3 18 E 7C 3 66 9 3D 18 AE 47C D3 D6 F9 9 31 AE 47 D D6 6F 96 8A 4 CD 3D 6F 99 E4 7CD 3D 66 99 6 7C 3 66 F9 6 D 9 8E FEDD93 5F3 3D3 18AAE4 7C D3DD66 F99 D F EF FED 935 5F3DD31 18A E47 7CD 3D 66F 996 6996 ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 ED 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EFE 5 D 1 7 6 6 6 E D9 935F F3D 318 8AE E47C CD3 3D6 6F9 9969 9962 28E FEDD93 35 3D 31 AE 47 D D6 6F 96 96 8E FE 93 5F 93 F3 3 8A 4 CD 3D 6F 99 99 28 F D9 5 3D 5 1 7 6 E F 35 F3DD31 8AE E47 CD 3D6 66F 996 996 628E EFE D93 35F 3D3 318A F3 31 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 E F3 D31 8A E4 7CD 3D 66F 99 699 628 EFE D9 35F 3D 318 AE 47C D 7 6 6 E Q.4. 3D 318 8AE E47C CD3 3D6 66F9 9969 996 28E FEDD93 35F3 3D3 318AAE4 47C D3D 31 A 47 D D 6 F 96 2 D D3 8A E4 C 3D 66 99 99 962 8EF FED 935 5F3DD31 18A E47 7CD 3D 66F 18 E 7C D3 66 F9 69 62 8EF ED 935 F3 31 8A E47 CD 3D 66F 996 31 AE 47 D D6 F 96 96 8E E 93 F D3 8 E4 C 3 66 99 9 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 Attempt the following. 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 Figure 5 Figure 4 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 99628EFED935F3D318AE47CD3D66F996 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4. EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C 60 o with the horizontal. Find the reactions at the points L, N and P. ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 A 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 channel is 18 cm wide at the bottom with one side vertical. The other side is inclined at an angle 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 (06X2=12) 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 C 1) Two cylinders A and B rest in a horizontal channel as shown in figure 5. The cylinder A has a weight of 1000 N and radius of 9 cm. The cylinder B has weight of 400 N and a radius of 5 cm. the D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 99 99 28 F D9 35 3D 31 AE 47 D3 69 62 EF ED 35 F3 31 8A 47 CD D 96 8E E 93 F D3 8A E4 C 3D 28 FE D9 5F 3D 18 E 7C D3 6 EF D 35 3D 31 A 47 D D 6 ED 93 F3 3 8A E4 CD 3D 66F 93 5F3 D3 18A E4 7CD 3D 66F 5F D3 18 E 7C 3 66 9 3D 18 AE 47C D3 D6 F9 9 31 AE 47 D D6 6F 96 8A 4 CD 3D 6F 99 E4 7CD 3D 66 99 6 7C 3 66 F9 6 D 9 8E FEDD93 5F3 3D3 18AAE4 7C D3DD66 F99 D F EF FED 935 5F3DD31 18A E47 7CD 3D 66F 996 6996 ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 ED 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EFE 5 D 1 7 6 6 6 E D9 935F F3D 318 8AE E47C CD3 3D6 6F9 9969 9962 28E FEDD93 35 3D 31 AE 47 D D6 6F 96 96 8E FE 93 5F 93 F3 3 8A 4 CD 3D 6F 99 99 28 F D9 5 3D 5 1 7 6 E F 35 F3DD31 8AE E47 CD 3D6 66F 996 996 628E EFE D93 35F 3D3 318A F3 31 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 E F3 D31 8A E4 7CD 3D 66F 99 699 628 EFE D9 35F 3D 318 AE 47C D 7 6 6 E Q.6. Q.5. 3D 318 8AE E47C CD3 3D6 66F9 9969 996 28E FEDD93 35F3 3D3 318AAE4 47C D3D 31 A 47 D D 6 F 96 2 D e = ½. D3 8A E4 C 3D 66 99 99 962 8EF FED 935 5F3DD31 18A E47 7CD 3D 66F 18 E 7C D3 66 F9 69 62 8EF ED 935 F3 31 8A E47 CD 3D 66F 996 31 AE 47 D D6 F 96 96 8E E 93 F D3 8 E4 C 3 66 99 9 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E equilibrium? 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D and momentum. D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 speed is reduced to 50 m/s? 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 Attempt the following. Attempt the following. 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 Figure 6 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 18 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 A 99628EFED935F3D318AE47CD3D66F996 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 8A E4 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 E 7C ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 AE 47C D3 -----%%%@@@@%%%----- 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 AE 47C D3 D6 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A 47 D D 6F 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 C 3D 66 99 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 7C D3 66 F99 69 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7C D3 D6 F9 69 96 E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 D D6 6F 96 96 28E 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 CD 3D 6F 996 99 28 FE D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD 3D 66 99 99 628 EF D D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 3D 66 F99 699 62 EF ED 935 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 66 F9 69 62 8EF ED 93 F3 99 99 28 F D9 35 3D 31 AE 47 D3 D6 F9 96 96 8E E 93 5F D3 69 62 EF ED 35 F3 31 8A 47 CD D 6F 96 99 28 FE D9 5F 3D 96 8E E 93 F D3 8A E4 C 3D 66 99 99 62 EF D 35 3D 31 28 FE D9 5F 3D 18 E 7C D3 6 F9 69 62 8E ED 93 F3 3 EF D 35 3D 31 A 47 D D 6F 96 96 8E FE 9 5F D 18 ED 93 F3 3 8A E4 CD 3D 66F 99 99 28 FE D9 35F 3D 318 93 5F3 D3 18A E4 7CD 3D 66F 99 699 628 EF D9 35 3D 318 A 5F D3 18 E 7C 3 66 9 69 62 EF ED 35 F3 31 A B) Explain the components of motion: rectangular components of velocity and acceleration. 3D 18 AE 47C D3 D6 F9 969 96 8E ED 93 F3 D3 8A E4 31 AE 47 D D6 6F 96 96 28E FE 93 5F D3 18 E4 8A 4 CD 3D 6F 99 99 28 FE D9 5F 3D 18 AE 7 (06X2=12) (06X2=12) A) Ball A of mass 1 kg moving with a velocity of 2 m/s, impinges directly on a ball B of mass 2 kg at rest. Find the velocities of the two balls after impact. Assume the coefficient of restitution B) Explain and prove D'Alembert's principle. How will you explain the concept of dynamic E4 7CD 3D 66 99 699 628 EF D 35 3D 31 AE 47 7C 3 66 F9 69 62 EF ED 935 F3 31 8A 47 C A) What is meant by impulse of a force and momentum? State and prove the principle of impulse the car is largely due to air drag which is equal to 0.004 v2. What distance will it travel before its 2) A car weighing 4000 N is moving at a speed of 100 m/s as shown in figure 6. The resistance to D3 D6 F9 969 962 8E ED 93 F3 D3 8A E4 CD D6 6F9 96 96 8E FE 93 5F D3 18A E4 7C 6F 96 996 28E FE D9 5F 3D 18 E 7C D3 99 99 28 F D9 35 3D 31 AE 47 D3 69 62 EF ED 35 F3 31 8A 47 CD D 96 8E E 93 F D3 8A E4 C 3D 28 FE D9 5F 3D 18 E 7C D3 6 EF D 35 3D 31 A 47 D D 6 ED 93 F3 3 8A E4 CD 3D 66F 93 5F3 D3 18A E4 7CD 3D 66F 5F D3 18 E 7C 3 66 9 3D 18 AE 47C D3 D6 F9 9 31 AE 47 D D6 6F 96 8A 4 CD 3D 6F 99 E4 7CD 3D 66 99 6 7C 3 66 F9 6 D 9 B 7 C D 0 A 4 B 5B 27 5A B0C BD 2E 0B0 2A 7E4 DB E6 5B 275 5AB B0C BD 2E0 0B0 2A7 7E4 DB E66 6B32 27 A 0 BD 2E B 2A E DB E6 B 1 27 5AB B0C CBD 2E 0B0 02A 7E4 4DB E66 6B3 3217 7D5 5 0 7 B 75 AB 0CB BD2 2E0 B02 2A7 E4DDBE E66B B32 217DD5B 275 AB 0C D E0 B0 A E4 B 66 3 17 5 27 A 5A 0 B 2E B 2A 7E D E6 B 21 D B2 5A B0 A) Q.3. Q.2. Q.1. B) B) A) A) B CB D2 0 02 7 4D BE 6B 32 7D 5B 75 B C B0 0CB D2 E0B B02AA7E E4D BE 66B 321 17D 5B2 275 AB 0CB BD2 C D E B 6 3 5 A 0 E 0C BD 2E0 0B0 02A 7E4 4DB E66 6B3 217 7D5 B27 75A B0C CBDD2E 0B0 B 2 B 2 7 E D E B 2 D B 5 B B 2 0 CB D2 E0B 02 A7 4D BE 66B 32 17D 5B 275 AB 0C D E0 B02 2A7 E A E 6 1 2 A 0 B 2 B E BDD2E 0B0 02A 7E4 4DB BE6 6B3 3217 7D5 5B2 75A B0 CB D2E E0B 02AA7E 4D 2 0 B 2 7 E D E 6B 2 1 D B 7 5 B CB D2 0B 02 7 4D BE A 2 diagram. D2 E0 02 7 4D BE 66B 32 7D 5B 75 AB 0C D E0 0 A7 E4 B 66 Date: 28/11/2018 E0 B02 A7 E4 BE 66 32 17 5B 27 AB 0C BD 2E0 B0 2A E4 DB E66 B3 in figure 1? B0 A E4 DB 66 B3 17 D5 27 5A 0C BD 2E B 2A 7E DB E6 B3 21 2A 7E DB E6 B3 21 D5 B2 5A B0 B 2E 0B 02A 7E 4D E6 6B 21 7D 7E 4D E6 6B 21 7D B2 75A B0 CB D2 0B 02 7E 4D BE 6B 321 7D 5B 4D BE 6B 32 7D 5B 75 B CB D2 E0 02 A7 4D BE 66 32 7D 5B 275 from collapsing. BE 66B 32 17D 5B 275 AB 0C D E0 B0 A7 E4 B 66 B32 17 5B 27 AB Instructions to the Students: 66 32 17D 5B 27 AB 0C BD 2E0 B0 2A7 E4 DB E66 B3 17 D5 27 5A 0C B3 17 5 27 5A 0 BD 2E B 2A E DB E6 B 21 D5 B2 5A B0 B 21 D5 B2 5A B0 CB 2E 0B 02A 7E 4D E 6B 321 7D B2 75 B0 CB D2 Attempt the following. Attempt the following. Attempt the following. 7D B 75 B CB D2 0 02 7 4D BE 66 32 7D 5B 75 AB C D E0 Course: B. Tech (All Courses) 5B 275 AB 0C D E0 B0 A7 E4 B 66 B32 17 5B 27 AB 0C BD 2E B0 27 AB 0C BD 2E B0 2A E4 DB E66 B3 17 D5 27 5A 0C BD 2E 0B 2A 5A 0 B 2E 0B 2A 7E D E6 B 21 D B2 5A B0 B 2 0B 02 7E B0 CB D2 0B 02A 7E 4D BE 6B 321 7D 5B2 75 B CB D2 E0B 02 A7 4D CB D2 E0B 02 7 4D BE 66B 32 7D 5B 75 AB 0C D E0 02 A7 E4D BE D2 E0 02 A7 E4D BE 66B 32 17D 5B 275 AB 0C BD 2E0 B0 A7 E4 B 66 E0 B02 A7 E4 BE 66 32 17 5B 27 AB 0C BD 2E0 B0 2A E4 DB E66 B3

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