CSIR NET Life Sciences June 2024 Shift 1 PDF

CSIR NET Life Sciences Question Paper June 2024 Shift 1 Connect with Us TELEGRAM DISCUSSION GROUP h ps://www.youtube.com/@Pathfinder-Academy h ps://t.me/CSIR_NE...

CSIR NET Life Sciences Question Paper June 2024 Shift 1 Connect with Us TELEGRAM DISCUSSION GROUP h ps://www.youtube.com/@Pathfinder-Academy h ps://t.me/CSIR_NET_Life_Sciences_GATE_BT h ps://www.instagram.com/pathfinderacademy/ h ps://www.whatsapp.com/channel/0029Va4c95aAjPXMD BoH2N  A letter from Bruce Alberts (author of Molecular Biology of the Cell) Some feedback on your two Life Sciences volumes – for authors only Bruce Alberts Dear Usha and Pranav, I have finally finished reading through many sections of your large two-volume introductory biology textbook, and I write to provide some feedback that might possibly help with your next edition. Let me start by saying how impressed I am that such a wide-ranging textbook was written by only two authors. For those sections where I am most knowledgeable – which I read closely -- I find it to be remarkably accurate. As you well know, most such textbooks that attempt to cover all of biology are written by a sizeable team of authors – each with a different expertise -- who in addition acknowledge help from a large number of other experts. And it is great to learn that you are able to provide these two volumes at a low price that Indian students can afford. My first question concerns the way that this material has been divided up into two separate volumes. If I were a student, I would have felt a need to learn about genetic mechanisms (which you call “genetics”) in volume 1, before learning about how proteins are sorted through internal membranes, for example. A major concern that I would have is one of level. I find that in many places you go into considerably more detail that we do in MBOC (molecular biology of the cell), even though the latter book is aimed at a more advanced student population than I believe yours is. Biology is such a huge subject that we can easily lose students in all the details, when what is most important for them learn are the concepts. Students often feel a need to memorize such details: in our interviews with sets of students who had just used our textbook, we found that many (most?) lack the judgement to ignore them when preparing for exams. For the same reason, we also leave out many of the scientific words in our book, like 2.27 helix, linking number, abzyme, etc. I hope that you find these comments useful, and I write to wish you the very best in 2023, as well as to encourage you in all of your future efforts! With my best wishes, Bruce Pathfinder Publication Pathfinder’s NINTH EDITION NINTH EDITION CSIR NET Life Sciences Fundamentals and Practice PART 1 Life Sciences Fundamentals and Practice PART 2 Life Sciences PRANAV KUMAR USHA MINA PRANAV KUMAR USHA MINA 7e Test and Evaluation Concept and application-based MCQS Previous Year’s Papers for LIFE SCIENCES BIOTECH Complete Study CSIR-NET Life Sciences PRACTICE BOOK FOR 2013-2023 CSIR-NET DBT-JRF ICMR GATE Special features IIT-JAM GAT-B Unit-wise segregation of questions CUCET Solution of analytical questions Material Pranav Kumar Pranav Kumar | Usha Mina by Pranav Kumar 9818063394 #1 Best Seller Click here to buy now h ps://pathfinderacademy.in/book/csir-net-life-sciences-combo-with-ecology-11.html Connect with Us TELEGRAM DISCUSSION GROUP h ps://www.youtube.com/@Pathfinder-Academy h ps://t.me/CSIR_NET_Life_Sciences_GATE_BT h ps://www.instagram.com/pathfinderacademy/ h ps://www.whatsapp.com/channel/0029Va4c95aAjPXMD BoH2N Application No Registered Photo Exam Day Photo Roll No Candidate Name Module Name Exam Date Exam Batch 1) PART A 26-Jul-2024 09:00-12:00 Question No. 1 / Question ID 703501 n Marks: 2.00 In humans, if both parents are of blood group AB, then, there is a 1/4 probab ility that their offspring wi ll be of blood group A, and 1/2 probability that the offspring will be of blood group AB. If the couple have three children, what is the probability that NONE of the child ren will be of blood group A or AB? 1. 1/4 2. 3/4 3. 1/64 4. 63/64 lfRcll lf ~ +TTill-fc@T ~™~AB q> 5 fil ~ ~ cJ'>T ™ ~ A ~ ~ ~ IR'l ctid I 1 / 4 m.ft JITT" x1-$fcn! Is:r,H I ~ ft.:141 (,I f.Q ch (,I ?t c4 c1 c1.:ttT ~ fa:I { c1 < ~.:) ~61 4. t;1?tcllc-ic1, t;;Rc11qch t- Rl@I<.:) 6~ fa:lchcqJf ~JTT t- ~ ~ chT 3TT9""ff Jr '5fl$ ~ ~ t1 2. ~ cfil~~cHc mt'la-1 ~ i;tkl{fur ~ 3TTdf ~ I 3. ~ ~m * ~ cf;'t" ~ "C!"cfi".fichfo1 ~~~I 4. ~fi"U ~ :ffl"{" ~ m - I \Jf if> ~ ca c=rm C 3. 4 9{J-tlOI; ~ ~ H, N, ca, C \Jf if> ~ N, ca, C, 0 ~ 4. 3 9{J-tIUr "' if> ~ c-1 ' N , ca ·,..:, ' 't' \Jf if> ~ ca, C , N+ 1 0  0 0 0 Question No. 22 / Question ID 703529 Marks: 2.00 What is the correct order in w hich the followi ng proteins are recruited during DNA double strand break repair in prokaryotes? 1. RecA, RecBCD , Ssb , DNA Pol Ill , DNA Ligase 2. Ssb , RecA, RecBCD , DNA Pol Ill , DNA Ligase 3. RecBCD , RecA, Ssb , DNA Pol Ill , DNA Ligase 4. RecBCD , Ssb, RecA , DNA Pol Ill , DNA Ligase l,ll#a4?141 * DNA q_Fcli-?la-S ~ ~ ~ c;lua1 fci:l'9,cfc-l ~ ~. fci:lchi-1 i;i~t'lcrl q1f ~ ~ cfm ~? 1. RecA , RecBCD , Ssb, DNA Pol 111 , DNA i l$a~-5-1 2. Ssb , RecA, RecBCD , DNA Pol Ill , DNA 11$.il-:rl 3. RecBCD , RecA Ssb , DNA Pol Ill , DNA 11$.il-:rl 4. RecBCD , Ssb , RecA, DNA Pol Ill , DNA 11$.il-:rl 0 0 0 0 Question No. 23 / Question ID 703544 Marks: 2.00 Retinal rod cell cGMP-phosphodiesterase is an enzyme with subunit structure as: 1. al3y 2. al3y2 3. al32y 4. a213y Fa-lchift.1Rsla ~ ~ ~R:o11c>1 Us ~ cGMP-lh)-Hlh)s1$Qfk~,;71 Q-511$J-i cf;)- 3'9"- ~ ti{ila-11 ~ ~ t? 1. aj3y 2. aj3y2 3. aj32y 4. a2j3y 0 0 0 0 Question No. 24 / Question ID 703560 Marks: 2.00 Wh ich one of the follow ing concepts can explain host-parasite co-evolution? 1. Kin se lection 2. Red Queen hypothesis 3. Runaw ay selection 4. Handicap principle fa.l chi ~ ~ ~ ~ "QcF 3rcJURUlT ~-9 :{ ~~ q~ cF ~-fa chi.fi cf;'(- c.Q I &ll I cf){.fichcil t? 1. ~~ 2. ts-cfaTXl a-11 3. ~~ 4. 3rarn"~ 0  0 0 0 0 Question No. 25 / Question ID 703538 Marks: 2.00 If ch imenic mouse embryos were generated using GFP-expressing embryonic stem cells and RFP-expressing induced pluripotent stem cells , which one of the followi ng tissues from any resulting embryos will not express any fluorescent protein? 1. Brain 2. Heart 3. Intestine 4. Placenta ~ GFP-~ ~ ~ ~ ~ ~3IT 3i°h" R F P - ~ ~ ~ ~ ~~lfctaq, ~ ~3IT cfiT ~4la1 ~ r:r fclfil ~q, ~ 3i°1T q,)- fcnm ~, ~ ~ 3fr qnu11Ji"1 3c-qcrvl ~ ~ ~ ~chrl 3iacti1 ~ ~ cfl'tCrl- m ~. ~ 3ft" ~fclei~ ~)tlo1 ~ ~ q,~dll? 1. 2. 3. "' 3ffi, 4. ~ 0 0 0 Question No. 26 / Question ID 703541 Marks: 2.00 Which one of the fol low ing correctly describes 'Dark Reversion ' of phytochromes? 1. Conversion of PR to PFR 2. Conversion of PFR to PR 3. Export of PFR from cytosol to nucleus 4. Export of PR from cytosol to nucleus fa.lchrl ~ *~ m ~. 91~9qU~ct,1 cf;" '31e;)ca 3c-sPJ..IUI' ~ ~ clll 2. 31scl-ilo-l - :ficrsl~crs.::> ; fcrlcf,~cif 1-l - ~-~ 3. 31scl-ilo-l - ~ - ~; fcrlcf,~~1-l - ~-~ 4. 31 Scl-i lo-I -.ficrSI.::> ~crS ; fa:lq,~ cit I{ -.ficrSI.::> ~crS 0  0 0 0 Question No. 29 / Question ID 703562 Marks: 2.00 Select the statement that describes guild coevolution , also known as diffuse coevolution. 1. One species uses the other as a resource. 2. Two species coevolve reciprocally, but only to each other. 3. Several species are involved in coevolutionary interactions. 4. A species escapes association from a predator and diversifies. Later, a different predator adapts to the host and diversifies. ~.fi (; fcl cf,l.fi, ~ fcl;;- kl.fin i;-1.fi (; fcl cf,l.fi c),- ~ H 3ft ~ aTi;-IT t, cf,f afai i;-1 ~ crrcq ~ cf,)- ilfa:l.:,.Q I 1. "QcFi" ~ ~ cf,f ~ cfl" ~ H 39.Qhl ~ ti 2. ~ -5tlkl.Ql, ~ "Q"cf," ~ c),- ~ , 9FH-9f{cf, ~ ~.fi(;klch~c1 ~ ~I 3..fi (; fcl ch I.fi Jtc>l cf, 31cr.Q~ cr.Q ~.m H ~ -511 kl.QI :fi ft;! Ci;-1 ~ ~I 4. "QcFi" ~ , ~ cfl".fi I(; il-4 ~ ~ fa:l ch~91 ~ ~ ~ m "Qcfl, ~ 3fR ~ ffl"-~ ~ ~ 1JLT ~fRTT t7 1. dorsal: I 2. torpedo : 11 1 3. gurken: II 4. cactus: Il l 0 0 0  0 Question No. 39 / Question ID 703557 Marks: 2.00 Select the correct combination of terms from plant breeding systems that represents selfing or promote selfing. 1. Autogamy and allogamy 2. Cleistogamy and geitonogamy 3. Geitonogamy and allogamy 4. Autogamy and herkogamy -crrc:q- Shilcrlci-1 en- ~ ~1~1aft4ll1 c);- ~ ~.:) qi)- ~fa.l il.:) ~ fcl;- fq9{1a101 ~ t m -Rt9{1a101 cfi)- ~~1a1 ~ cfi)- ·~ q;-ra ti 1. -Rt ll.:)aJ-1 ci-1 3fR 3-1 q { ll.:)a J-t ci-1 2. 3-lcrlfo=J.i-4 q{1a101 3-Tt{" fl-:illc-1qcs4"j q{1a101.:) ~ 3. f1..:iilc19cscfl.:) 9'(1dl01 3fR 3-19'(lJdJ-to1.:) 4. -Rt ll.:)aJ-t ci-1 3fR.fct".3-1 fa.l ~ i21 ~ ll ft;if.fl c1 I 0 0 0 Question No. 40 / Question ID 703547 Marks: 2.00 Which one of the following statements regarding principles of linkage mapping in plants is correct? 1. Genetic markers would always show higher recombination frequencies when they are closer to each other than if they are far apart. 2. The genetic distance between two markers is a true representation of the physical distance between them. 3. An ideal mapping population for a self-pollinating species is generated using polymorphic parents that are inbred lines. 4. An F2 mapping population would segregate in a 1:2:1 ratio for a dominant marker. "9lcl- * =tt~ao-1c11 J-1 1o1fth101 c),- ~ * ~ fcMJ-o-1 * ~ m "Q'cfi" ~ ~ t? 1. ~ Rlco1ch ~~rr 3TTUcfi" qo-1~it1'5lo1.:tt1crRl41 ~ ~ ~ ~..:i "Q'cfi" ¢ *~ ~ """T""""T"""TT fi c;.i'511klm cfi" ~ ~ ~~ J-lla-!Rl 310 1 '5lci-l=H m fclq,~q (.. ~ SJThhlll * ~ ~ ~ i;iau1a1 3c=qcrv-1 ~ * 3q,Qh~ tfcq, chT ~ ~ t? 1. LhI.f-lh~ fi.l fq s'8_ 2. :fisf,~.51 " 3. KCI 4. Rm 0 0 0 0 Question No. 42 / Question ID 703553 Marks: 2.00 Which one of the following options includes all plants that are major non-native invaders of aquatic ecosystems in India? 1. Parthenium hysterophorus, Pontederia crassipes , Lantana camara 2. Salvinia molesta , Prosopis Juliflora , Mikania micrantha 3. Nelumbo nucifera , Pogostemon erectus, Hygrophila serpyllum 4. Pontederia crassipes , Salvinia molesta , Alternanthera philoxeroides  ~chrlfi.1Rslc-1 R *~ m ~cfic--9 301 ~ tftur, ~ ~ * -51~')1.Q ~ ~ · c):;- m ,J m-~ft-.:tilshlo-c-11 ~ , cfiT ~11f.Ac..i ~ t? 1. ~ f&&?)l/>)?a, llfedRm J,#jt),jf, ~crC/uf! ~J/fc{)Ful211 mcJ:fcJ, 1~f9s 3919il.Q 4. 311.Q-lcrl-:fi ~.fi c:f>c1 I tI ~ CMS cf~T cfiT Rf ~T ~ "Q'"c:f>".fid-1.QJd-l~ -:> ~ fic:f>-{ □ I fcl:im "llml i;JT'C(1" F1 tlc1f°ci cp)-.fcl9-{lfJlc1 fcf;m "llml F2 tlc1f°ci ~ fchc1a-l ~Tc1" irR ~JfW=r ITTJT? 1. 0 2. 25 3. 75 4. 100 0 0 0 Question No. 48 / Question ID 703540 Marks: 2.00 Which one of the following represents the predominant 1sou rce organ durlng phloem translocation in healthy plants? 1. Roots 2. Developin g fruits 3. Immature leaves 4. Mature leaves ~ "9lm * 4)tsict1e; ~:t11a1ic·H □ 1 "ifl" ~lua-1 ~~~t? 1. ~ 2. fcl cfil ~ ~ftc;r "Cflc>f 3. J"l9P:9cfct 9falli 4. qp_qcfq 9falli 0 0 0 Question No. 49 / Question ID 703559 Marks: 2.00 In 2007 , scienti sts reported the fossi l of a deer-l ike animal in Kas hmir, India whi ch is considered the most recent terrestrial ancestor of wh ales. The name of thls foss il is 1. Jainosaurus. 2. lndohyus. 3. Rajasaurus. 4. lnd osuchus. 2007 * a-i11fci.lcf,1 ~ ~~, 3ITTc1 * ~ ~ -:ii la-lct{ "ifl" '-71~ctlft1l cfiT ft"9Tt ~ ~ ~ "cfiT a1cfla1c1cl-l ~ ~ 1TTaTT dJm ~I ~ '-71ict1~1l cf1T aITT:r ~ ~ 1.a-lFHH~ V ' 2. $S~~~ ~ 3. {1-:iil~H~ 4. $~~"ii~  0 0 0 0 Question No. 50 / Question ID 703522 Marks: 2.00 Which one of the following pairs correctly matches the enzyme with its allosteric activator? 1. Phosphofructokinase : Citrate 2. Pyruvate dehydrogenase : NADH 3. Pyruvate carboxylase : ADP 4. Pyruvate kinase : Fructose-1 ,6-bisphosphate  fci.1M ~ * ~ lIT ~ Q-511$d-l cfTT" ~ ~ fiRf,.Qcfi ~ ~ ~.!) Pl~lcrl ~ t? 1. lhlflh) lhcfc)cf>1$a-l-51 : ~ 2. 91$-t>ck. ffi(;l$~Glci-l-51 : NADH 3. 91$-t>clc cfil~fcf· fh4-51 : ADP 4. 91$-6~crl, q-fra,ur ~ ~ ~ 6 1. ~ ctll#1 cf:;'r ircfl ~.fi€ll l *, 3-ITT" ~ 311~1et * 2.5 ~ 97.5 ~lc1c1J-tch1 * m.""ll" ::ti c1 -l It cfiT.:tt Ich~ crl ~ I 2. ~ ctllt-cJ,1 cf:;'r ircfl ~ -HMI * 3-ITT" ~3l 3-ll~let * 5 ~ 95 ~klc-lcHcf,1 * m.""ll" ::ti c1 -l It cfiT.:tt Ich~ crl ~ I 3. lll£fmch ctll#1 cf:;'r ~ ~.fi€lll * 3-ITT" ~.:ttl~let cfl 5 ~ 95 ~lc1c1J-tch1 * m.""ll" ::ti c1 -l It cfiT.:tt Ich~ crl ~ I 4. lll£fmch ctllt-cJ,1 ~ ircfl ~.fi€lll * 3-ITT" ~ 3i l~let * J-tTt.""ll" cfl cJaTT" 3ITT" Jilcrlcf> fatj~crl~ cfl -1.64 3ITT" +1.64 cfl ~ 31ci-ll~ cfiT.:tt lchta-i ~ I 0 0 0 Question No. 2 / Question ID 703632 Marks: 4.00 Cystic fibros is is caused by a recessive allele. Rough ly one out of every 500 ind ividuals (0.20%) have this disease. Using the Hardy-Weinberg equation , the perce ntage of individuals who are carri ers of the recessive allele for the disease is 1. 10.2 2. 1.0 3. 15.2 4. 7.6 Rlfkcfi lhl$i!Rl.fi 1Jcf; mmrcfr Q ~ I c):; ~ ~ ~ I i;kil cfi 500 c.tl feta ll1 (0.20%) ~ ~ c>fdTWT 1Jcf; ~ ~ ~1c1-1 1fl ~ ~I ~ -Qlo-tcil i1.fi J-tl cfi{OI cfiT (,.llflJI cRa ~ , ~ ~1c1-1 1fl c):; ~ mrmcfr Q~I ~ -Hcl l~cfi c:.qfcta:m cfiT ~@ ~ 1. 10.2 2. 1.0 3. 15.2 4. 7.6 0 0 0 0 Question No. 3 / Question ID 703577 Marks: 4.00 The Ran GTPase imposes directi onality on transport through nuclear pore complexes (NPCs). Li ke other GTPases, Ran is a molecular switch that can exlst in two conformational states, depending on wh ether bound to GDP or GTP. Possible reasons for compartme ntal izati on of Ran-GTP accumulation are : A. Ran-GAP is enriched in the nucleus B. Ran-GAP is localized in the cytosol C. Ran-GEF is enriched in the nucleus D. The nuclear import receptors help in the compartmenta lization of Ran-GTP W hich of the options below has all the co rrect statements about Ran-GTP compartmentalization? 1. A only 2. A and B 3. Band C 4. C and D Ran GTPase ~a-~cf;l4 ~.fich qf{o 11 c1-1~~q ~ Pso t;ITCn ~ ti f«it J;rl f&1ffia * ~ m ~ Fct ch-9 mfr ~ ~ c):;- >H ll)-51a1 cf,)- ~ ~ t? 1. A 3ITT" B 2. B JITT"C 3. CJITT"D 4. AJITT"D 0 0 0 Question No. 5 / Question ID 703575 Marks: 4.00 Gi ven below are a few statements regardi ng the rate of glycolysis, gluconeogenes is and glycogen metabolism. A. Increased blood glucose would decrease gluconeogenesis and increase glycogen synthesis. B. Increased levels of fructose- 1, 6-bisphosphate inhibits glycolysis. C. Increased blood glucagon inhibits glycogen synthes is and stimulates glycogen break down. D. Increase in AMP levels inhibits glycolys is and stim ulates gluconeogenesis. W hich one of the follow ing options represents INCORRECT statements? 1. A and D 2. Band D 3. A and C 4. Band C ac>1 1$ch).jlqtlco1 , acicf>h4a1ct-i1a1a1 k ac41$ch)-i1a1 3414-il.Q ~ ~ * afl"it ~ ~t, A. ~ a ctch) -51 ~ ~ ~ 1W-TT, a l~ch) -H a-1 cfo1 a-1 a-1 cfi)- UcT -H cfidt ~ 3ITT" dc>l l$ch)-51a-l ffi~ qi)- ~ -Heh~ ~I B. thcfc)-51-1 , 6-Ri-Hlhlf-Qjc ~ ~ ~ 1W-TT a 1l$ch).jlqtlco1 cfi)- -tlcfi~ ~1 c. ~ sm ~ a ()f~ch)a11a-1 , a c41$ch)-51o1 ~~~ qi)-.,_~cfic11 ~ 3ITT" a11$ch)-51a-1 ~.jl9tlca-l qi)- ~ cRill ~ I D. AMP cfif ~ s3TT ~, dc>l l$ch).jlqtlca-l qi)- -t)chc-11 ~ 3ITT" d()f~ch)-Ha-lcl-51a-lo1 qi)- ~ cfi«1T ~ I fcrl chi-I * *~ m "Qqi" Fctcti~9 1Tol'tf ~ cfi)- ~nc=n- ~ 1. AJITT" D 2. B 3ITT" D 3. AJITT" C 4. B 3ITT" C 0 0 0 0 Question No. 6 / Question ID 703629 Marks: 4.00 In a line transect of length Land half-width w, designed for estimating the density of gaur (~ D=N/2Lw), N an imals were counted. The follow ing statements represent possible assumptions about popu lation sampling. A. The probability of detection is independent of distance from the transect line. B. The animals in question are uniformly distributed through the study area. C. The animals are deemed to be stationary and thus detected on ly once during the sampling. D. Animals on the line w ill be detected w ith a probabil ity equal to 1. Select the options that are considered as assumptions in line transect sampling. 1. A and B 2. C and D 3. A and C 4. Band D ~ ~ L ~.3iq_'U"-=a1$1~ w cfl" n:ID ?l~cfc "R, ~ ~ cfl" t)crf,a (~ D= N/2Lw) cfiT~~~~fctim"JT 1o11.:, -ar Q:fi9F{G=io1 3ITT)q;° ~ cf>IJicrl m°c1" ~I 1. A , B 3ftt D 2. B, C 3ftt D 3. A , B 3ftt C 4. A , C 3ftt D 0 0 0 Question No. 8 / Question ID 703639 Marks: 4.00 Given below are a few statements on transgen ic plants. A. Transgenic plants generated using a transformation vector with the CaMV35S promoter-GUS-35SpA cassette can show variations in expression levels of GUS protein in independent transgenic events due to differences in strength of promoter used to express the GUS gene. B. A transgen ic plant conta ining two insertions of the transgene cassette as inverted repeats in tandem would segregate in a 3: 1 ratio for the transgenic phenotype on backcrossing the transgenic plant with the untransformed parent. C. A transgene containing a potential polyadenylation signal in its coding sequence would generate full-length transgene mRNA but a truncated transgenic protein. D. A gene-pyramiding experiment to bring together two transgenic traits by crossing independent homozygous single-copy transgenic lines for each trait wou ld produce a plant homozygous for both the transgenes in the F2 generation. Which one of the fo llowing options represents a combination of only correct statements? 1. A and B 2. C and D 3. D on ly 4. A and C A. CaMV35S 3crvtl-llch-GUS-35SpA ~ "£lcFc=r ~ ~4ic1{ □ 1 ~ cf1f 34-t1'1a1.:) ~ m "1N" 41{-:11"1afl 'Cftu, GUS~ cf;)- ~ ~ cfl" ~ 34-llcfc1.:) 3cnrl I-ti cf, cfTT" ~ cfTT".:fFfi J-l la-i c1 I * cf, I{ □ I , -kl c1 31 41 { -,fj a-tl "Efc""CrTT3TT * GUS flli~-:if ~ 3'-5 ' Qcffl~cr~Ft(4Qfl -HF9h.l.lc1I, qPCR * Taqman ~ c).,- 3' ~ * i,!klcl~ch cA" 1fcfc,.::, ch«TT 61 1. A3ITT"D 2. B 3ITT"C 3. B3IRD 4. A3ITT"C 0  0 0 Question No. 10 / Question ID 703631 Marks: 4.00 Phylogenetic trees are used to examlne A. relatedness among different popu lations, species or genera. B. simi larity in characters among diffe rent pop ulati ons , species or genera. C. common ancestry among different populations, species or genera. D. functional significance of tra its in popu lations , species or genera. From the above stateme nts , select the correct combination of statements that best represent the utility of phylogeneti c trees. 1. B, C and D 2. A , Band D 3. A , Band C 4. A , C and D -51 1ffiqJl;q '£8:TT ~ 394)a1 ~ ~ ~ A. ~.:ttlcil lfa4~, 1,fotlffi:m 3ITT" ~IT cf;" m-l d ch ar ~ ~ cfl" RI El c:.o-1 * q:;f-Ph) $cii) i:>191 $~ck: 3,9ci-vl ~ ~ I E. CAM~ c=f"?r ~ ·~ ~ cfl" G1". lo-i ~ W ar ~~f-ch) c);- WU- 3IT{ CO2 chT ti~~c-1 ~ ti 1. A , B 3fR E 2. B, C.JfR E 3. A , C 3fR D 4. A , D 3fR E 0 0 0 0 Question No. 12 / Question ID 703584 Marks: 4.00 In order to in vestigate the involvement of the followi ng proteins in the mismatch repa ir mechan ism (MMR) , an in vitro reconstitution experiment was performed. A 5'-nicked circu lar DNA substrate having a C:C mismatch at the Pstl site was incubated with different comb ination of proteins (as shown below), where upon the repair of C:C mismatch , the Pstl site will be regenerated. Following the incubation , the resulting DNA were dlgested with Pstl and Sea l restriction endonucleases, and the products were electrophoresed in 0.8% agarose gel. Pstl MMR Pol6 - + + + + Exo l - + + - - Ra d27 - - - + - Msh 2-Msh6 ,_ - + + + - - - 3.0 -- 2.5 2.0 -- - - - - - 1.5 LO kb Based on the resu lts obtained identify the INCORRECT statement. 1. Msh2-Msh6 complex is required for the repair of the C:C mismatched DNA. 2. Polo and Msh2-Msh6 complex are necessary for the repair of the C:C mismatched DNA. 3. Polo and Msh2-Msh6 complex are sufficient for the repair of the C:C mismatched DNA. 4. Exol and Rad27 are redundant to each other for the repair of the C:C mismatched DNA. m '1~dl6Jm ~ ? " Glass needle removes cells 1. A3ft{D 2. ~D 3. B 3ft{ C 4. ~c 0  0 0 Question No. 17 / Question ID 703604 Marks: 4.00 Sucrose-phosphate synthase (SPS) is a key enzyme in the biosynthesis of sucrose in plants. Following are certain statements regarding SPS: A. Uridine-diphosphate glucose and fructose-6-phosphate are the substrates for SPS. B. SPS directly converts its substrate into sucrose. C. Phosphorylation activates whil e dephosphorylation inactivates SPS. D. SPS converts its substrate into sucrose-6-phosphate which is then converted to sucrose by the action of sucrose-phosphate phosphatase. E. Glucose 6-phosphate activates while Pi inactivates SPS. Which one of the following options represents the comb.ination of all correct statements? 1. A, C and D 2. A, Band E 3. B, C and D 4. A, D and E tHF>)'51-411-Flhc ~ (SPS),..:) °9lm * tHF>).il ~ ~ ~~..:) * "Qq, J-t~c=aqu~ ~ Qcr).il..:) * 9~ctrJa cR ~ t1 C. 41I-Ph) ft fi>l cfi-l a I SP S en)- ti fsh.Q -il isl fch ~ 411flfi) ~ ~ cfi-l a I ~ ~.Q cfR"ciT tI D. SPS ~ ~ en)-.fish)-i!-6-411-Flhc * 9~ctrJa cR ~ t ~mo..:) ~ =B~)-i!-411-Flhc 411flht-il ~ ~ ~ =Bsh)-il * q~amc-1 ~ aRTT ti ~ ~..:) E. d(>icf,).il-6-411-Flhc:. , SPS en)- tlfsh.Q.ilislfch Pi ~~.Q cfR"ciT ~ ti 1. A, CmD 2. A, BmE 3. B, CmD 4. A, DmE 0 0 0 Question No. 18 / Question ID 703611 Marks: 4.00 Given below are the blood clottin g factors in co lumn X and their names in colum n Y. Column X Column Y a. XII i. FitzQerald factor b. HMWK ii. La ki-Lorand factor C. Pre-Ka iii. Stuart-Prow er factor d. X iv. Fletcher factor Wh ich of the fo llowing comb ination is a correct match of the factor with its name. 1. a-iv b-ii i c-i d-ii ' ' ' 2. a-ii b-iii c-i d-lv ' ' ' 3. a-ii b-i c-iv d-iii I I I 4. a-i b-ii c-iv d-iii I I I ~x ~y a. XII i. fto~-:71 il {Ic>-5 ctil{cti b. HMWK ii. ~-c-n{cr~ cti l { q, C. Pre-Ka iii. RJft-" I{ cf>.:, d. X iv. y-~ ~H q,l{cf, 1. a-iv ,, b-iii ' c-i , d-ii ' 2. a-ii b-iii c-i d-iv ' ' ' 3. a-ii b-i c-iv d-iii I I I 4. a-i b-ii c-iv d-iii I I I 0 0 0 Question No. 19 / Question ID 703585 Marks: 4.00 In vivo interaction between FLAG-tagged protein P and chaperone H was examined by co-immunoprecipitatlon (co-IP). Co-chaperone A was included and the co-IP was performed in the presence or absence of cycloheximide (CHX). The results of the co-IP experiments are shown below. FLAG-P - + + + + Chaperone H + - + + + Co-chaperone A + + - + + CHX - - - - + FLAG-P I~---- -- --- ---~ l9 'LL.:5 ChaperoneH ~1----- --- -~ c.. Co-c hapero neA ~I_ _ _ _ ___ _~ FLAG-P --- - - -- - l/).....roQ) V) > - - -- -- --- Chapero neH a., u Co-chaperone A Q) 0.s= Tubu lin $ Western blot Wh ich of the fol lowing interpretations from these experiments is INCORRECT? 1. Protei n P interacts with chaperone H and co-chaperone A. 2. Chaperone H interacts only with the newly synthesized protein P. 3. Interaction between co-chaperone A and protei n P is independent of chaperone H. 4. Interaction between chaperone H and protei n P is independent of co- chaperone A. ~-~aNUT (cfi)-$J-.~a1h)fflfqe:~Tal ~ co-IP) c;crm ' FLAG-Rl~a i;i)t'la-1 P.3ITT" ~4{1a1 H ~ , m 9{-t-9{ flFim ~ ~ fclim J'fl!T I cl;T-~4{1a1 A cf))- ~11r.A1 ~ J'fllT.3ITT" -Hl$cfi:>n~cf.fi~J-11$s (CHX) ~ ~ < I T ~ ~ c o- ~ IP fcf;m dfml co-IP 1,1:q)a1~ cfi" qftu 11.1-1 ~ ~,lsll~ 1fCr ~I FLAG-P - + + + + Chaperone H + - + + + Co-chaperone A + + - + + CHX - - - - + --- - ~I=========== --- I l9 FLAG-P s LL ChaperoneH ~I_ _ _ _ __ I a.. - Co-chapero neA ~I_ _ _ _ __ --- I FLAG-P ChaperoneH - -- ---- -- Vl Q) +-' ro VJ > Q) u - --- - Co-chaperone A Cl) 0.s:::. Tubu lin 3 Western blot 1. i;i)t'la1 P, ~9Ha1 H.3ITT" q:;)--~9:(la-1 A cf;" ~ 9H--9{ fsf;m- cfi"ra 6"1 2. ~9-lla1 H, ~ a=rcr-~c>1fii1a i;i)t'la-1 P c);- ~ 4-l.f-4-l fl1l:;m ~ 6"1 3. q;)--~9:(la-1 A 3ITT" i1t'lcr1 p cf;" ~ 9H--9{ fsf;m", ~9{1ci-l H ~.fl'">l i;;i 'A' c):;- ~~ c):;- chl-{01 ~ m - m Crfti" ~I -51istfch ~n:rr * c;nt'la-1 'B' cf;T fa-l;J;;flcfi-{01, J-tf°@ISch * c;nt)a-1 'A' ~.fi ~c.t Jf ~~. ~TIT (. !.i "11 kl qiT isl I$..:) C"'ll FckH. 0 I I 3. fctffi31 ~ lhf 3ITT" B A 2. A 3ITT" C cficrc>f 3. A , B 3ITT" C cficrc>f 4. A, B, C 3ITT" D 0 0 0 0 Question No. 24 / Question ID 703612 Marks: 4.00 The fo llowing statements are made for the effect of hormones on the glomeru lar filtration rate (GFR). A. Norepinephrine, ep inephrine , and endothelin constrict renal blood vessels and decrease GFR. B. Endothelin dilates renal blood vesse ls to in crease GFR. C. Norepinephri ne and endothelin constrict renal blood vesse ls and decrease GFR, w hi le epinephrine dil ates renal blood vessels to increase GFR. D. Prostag land in (PGE2) and bradyki nin decrease renal vascu lar res ista nce and increase GFR. Wh ich one of the follow ing options represents the comb ination of correct statements? 1. A and B 2. Band C 3. C and D 4. A and D ~ Fa-lf.ti~a1 ~ (GFR) ~ 61cHT.ii1 * *,;rm ~ f":ichri ~ ~ "11V" t, A. criR"-C!f9o-l~o-t , C!f9o-l~o-t , 3ITT" ~ act4i'p~ c..(cfcidl~fa.llfi cfi)- fl ct,hl.:, c-1 cfl«f t 3ITT" GFR qi)- UcTa tI B. ~ ' GFR ~ * fi;r-cr '!_ffill -Ccfc-ld l~Fa-14~ cfi)- Ul.fc-llftc-1 ~ ~ t, C. criR"-C! fq~ ~ a1 3ITT" ~ , cpt4,'I 4 -t cfi-1 ct I~f:i 4~ cfi) :fi if Rl c-1 cfR" ~ t 3ITT" GFR UcT~t, ,5Hlfch Qfq~~cri , GFR ~ * ~ cptchlll -tcfc-ldl~fa-141 cf,)- Rlf-c-llftc-1 ~ ~ t, D. Ulf-C::ld &\fa:sa1 (PGE2) 3ITT" ~~cf,1$fa-lo-t' dffill C. :fid6o1l '1ifc-H~tf qi)- UcT ~ t 3ITT" GFR ~ ~ t1 1. A 3ITT" B 2. B 3ITT" C 3. C 3ITT" D 4. A 3ITT" D 0  0 0 0 Question No. 25 / Question ID 703598 Marks: 4.00 In a hypothetical organism , at a four-celled embryonic stage, blastomere 'X' instructs one of the daughter cells of an adjoining blastomere 'Y' to take the fate 'Ya'. The other daughter cell takes the fate 'Yp'. This is illustrated in the figure below as lineages for Ya and Yp. If the X blastomere is removed , both daughter cells take up the Yp fate. Normal development In the absence of blastomere X This instruction is mediated by a paracrine factor, Pap2 secreted by X blastomere interacting with Pap5 present on the membrane of Y blastomere. The following experimental manipulations were carried out, which involved creating partial genetically mosaic embryos in vitro and following the fate of the Y blastomere. Which one of the mosaics will show a developmental pattern similar to that when blastomere X is removed? 1. X blastomere null for Pap2 and wild type Y blastomere 2. Wild type X blastomere and constitutively activated Pap5 Y blastomere 3. X blastomere null for Pap2 and constitutively activated Pap5 Y blastomere 4. X blastomere null for Pap5 and wild type Y blastomere 1Jq, cfil ()'q Fa-l cf, ~ ~ I ~-~ ~ ~ tR, q:,);,: cfi.isi s 'X'' ti c>t da1 q:,h cfi.isi s 'Y' cfl tlc-lkl ~JIT al * *~ ~ ~ ~I 1Jcf) qi)- 'Ya ' fc;\.QQ )19a·Ha-l ~ tlc-lkl ~ 'Yp ' fc;\4fa qi)- ;fl9alktl ~I ~ Ya 3ITT" Yp * ~ ~~ qi)- ~ ~ * ~ ~ "lf.QTI ~ x q:,);,:cfi.isis cli)- ~ ~ -anr ~ cJaTT" tlc1kl ~ Yp' fa.l4Q qi)- Ji9a11JI t 1 Normal development In tl,e absence of blastom ere X ~ ~ r, Y q:,hcfi.isis * ~()'~')1 9""{ ~ Pap5 * ~~ 31crll)crllfa.i41 ~ ~ X q:,hcfi.isis ~.a1fac1 ""-15'-il$ai cfil{cfi Pap2 ~ ~ ~ ~I cfi'tar ~~ Pt;.Jfh , fu'.ltlti fcf;- X q:,){cfi.isis t,;cl.QI "1f.QT ~, ~ ~ facti1ff14 ',!Q~q ~ cfi~dll? 1. Pap2 fa i?I ai X q:,) {cfi m 3ITT" cfa-=.Q" ~ Y q:,);,: ctiI.Qa-lchl.Q ~ fcl~R.c1 ~ ~I 3. (,.fl t'I a1 A 61 §-4_~ cf-4_R.cil c ~ ~ I 4. sr1t'la1 A ~ ;JT ~lcrfl4chci c.. ~ ~I 0 0 0 0 Question No. 27 / Question ID 703642 Marks: 4.00 A researcher used CRISPR-Cas9 system and observed a different type of mutation in two alleles of a target gene in a To transgenic plant. These mutations are designated as follows: Allele 1: addition of a nucleotide Allele 2: deletion of a nucleotide The observed mutations can be classified as 1. monoallellc mutations. 2. biallelic heterozygous mutations. 3. biallelic homozygous mutations. 4. chimeric mutations. ~ ~mntff ~ CRISPR-Cas9 c=i:f cfiT s:tl4~JI ~ 3ITT" ~ To 91:J:..:n->lcrtl ~ ~ ~ ~ ~ ~ cJ Q~~1 ~ ~ m cfiT 3c-9ftaaa1 ~ fctim1 * 3c-9ftaaa1 Fa-1.hi1 m ~ ~ fctim 7fm ~: Q/4)~ 1: ~ a-4fcr-~,jfjcl$S.::, cfiT l41'5-lcrl Q/4)~ 2: ~ a-4fcr-~,jfjcl$S.::, cfiT fcl~J9crl 1. Qcf,Q~fi;lcf, 3c-9ftaaa1 I 2. ~fclQ~fi;lcf, ' fcltstJ-tl4dd-l..:nl.::, 3c-9ftaaa1 I 3. ~fcl Q~fi;lcf, t!J-14JJ-t..:71l 3c-9ftaaa1 I '.::, 4. FclRh~~c1c:fil 3,qftaaa1 1 0 0 0 0 Question No. 28 / Question ID 703589 Marks: 4.00 Wh ich one of the fo llowing options represents all correct matches between Column X and Col um n Y? Column X: Microorganism Column Y: Host receptor A. Influenza virus i. N-acetylg lucosami ne B. Entamoeba histolytica ii. C044 C. Streptococcus pyogenes iii. Sialic acid res idues of glycoproteins and glyco lipids D. Human immun odeficiency iv. C04 virus 1. A -i B-ii C-iii D-iv ' ' ' 2. A -ii B-iv C-i I D-ii i ) J 3. A-iv, B-ii, C-iii , D-i 4. A -iii B-i C-ii D-iv ' ' ' ~ fclch()'lfi **~ m "QcF, @31 xm~ Y c),- 1=ft..~ ~ ~ f1l 11o1 chT ~f@r t? ~ X : ~"'3=1~a ~Y : ~~ A.. i. $Ch~ Q-51 I fcltit101..... N-Q Rk.1 ~ ~ J ()I ct,) ti Id-1~ a1... B. "Qc~ ~~i, fc;1 ~q,I ii. C044 C. ~~ cc) ct,) cfi.fi 9141) ~ a--.fi iii. c1 ~ I$ctll\ ~"t, I- Icr1 m{ d c>f I $ch) fc;1 fq 5 'cfiT ~41fc;1q, 3fR,f ~ D. J-tla1ct $.1--ll crl)g~ 1 '-h ~Q fl~I ~ iv. C04 fcltit 101.cl 1. A -i B-ii C-iii D-iv ' ' ' 2. A -ii , B-iv , C-i'' 0-ii i 3. A -iv B-ii C-i ii D-i ' ' ' 4. A -iii B-i C-ii D-iv 1 ' ' 0 0 0 0 Question No. 29 / Question ID 703613 Marks: 4.00 Given below are a few statements on concepts of molecular breed in g. A. Correlati ons betw een quantitative tra its can be because of pleiotropic effects of the same gene and/or genetic lin kage of genes associated with the tra its. B. In a Recombi nant Inbred Li ne (RIL) popu lation , genetic segregation of both dominant and codom inant markers occurs in a 1: 1 ratio. C. Near isogen ic lines (Nils) can be prod uced by repeated backcross ing of th e F 1 to a recurrent parent. D. SN Ps are dom inant markers. W hi ch one of the follow ing options represents all correct statements? 1. A and B on ly 2. A , Band D 3. A, Band C 4. C and D only ~ cflB" -:> ~ ::,-11 o Ifcl ch t;l -51 crlcrl cfTT".fi ch ~q crl I ~ ~ dfQ" 6: A..1-11~161-ich rct~ft'ilcfiT c):; ~ ~ - ~. ~ ~ c):; ~ " ~~q ~ 3-1 q 1 fcta fctcfi~ ch)- tj~ ,.:> ii ~ @rn X 3ITT" @rn Y c)=, ~.fi°tr f.A i lcii1 cfiT ~ cfRc=IT t? 1. A-iv B-i i C-i D-iii 2. A-iii ' B-i ' C-ii ' D-iv ' ' ' 3. A-ii ' B-iii , C-iv ' D-l 4. A-i , B-iv ' C-iii' D-ii 0 0 0 0 Question No. 31 / Question ID 703626 Marks: 4.00 T he followi ng statements represent posslble outcomes of competition between two species. A. Niche diffe rentiation between species B. Expansion of fu ndamental niche of both species C. Expansion of rea lized niche of both species D. Character displacement between species Wh ich one of the follow ing options represents the correct set of possible outcomes? 1. A and C 2. Band D 3. A and D 4. A and B A..511fc-llfi ~ m fo:lc),a ~ B. ~.511fc-l.m ~ ~.... fo:lc),a q,f Ch~1a c. ~.511fd.m ~ a1-t=afacfi fo:lc),c-1 cf;f ct~1a D. -51 lkllTT ~ RL""lf ~ ~ 1. A 3ITT" C 2. B 3ITT" D 3. A 3ITT" D 4. A 3ITT" B 0 0 0 Question No. 32 / Question ID 703571 Marks: 4.00 Given below are four topology diagrams corresponding to different proteins. N and C denote the N- and C-terminal ends of the protein cha ins. A. C. N B. D. C Which one of the fol lowing statements is CORRECT? 1. All four are of different folds. 2. All four are of the same fold. 3. (A), (C) and (D) are of the same fold. 4. (A) and (C) are of the same fold. ~ i;t~t')cr11 * ~ ~ ~ 3TTTisf ~ ·~ ~ t1 N3i'R. C, i;.t~t')cr1 ~ * N- 3fR C-~t)cr1 rn"U en)- ~ll"a t I A. C. N N B. D. C N 1. ~ ~ ~ - ~ ~ t - t1 2. ~ ~.fiJ-llcrl ~ cf> t1 3. (A), (C) 3fR (D).fiJ-llcrl ~ cfi" t1 4. (A) 3fR (C).fiJ-llcrl c.R>Jo, cf> t1 0 0 0 Question No. 33 / Question ID 703635 Marks: 4.00 The following statements describe different patterns of sequence evolution. A. Most non-synonymous mutations are se lected against. B. Synonymous mutations can accumulate. C. The ratio of non-synonymous to synonymous substitutions is high. D. Non-synonymous sites accumu late mutations at higher rates. Which one of the options is NOT true about sequence evolution under purifying selection? 1. A and B 2. C and D 3. A and C 4. Band D fcrlchi-1 ~ ~ f"achl.fi cfl" ~ ~~~q~ ~ c41~1 ~ 61 A. J41c;1cn: 319.tf14cr11c1-11 3,qftc1ao1 rcruu * -c14f I D. 319414ci-llJ-t1 ~ 3vq ~ 9""{ 3,9ftctacrl -Hfilc1 ~ 61 fcrlchi-1 fach~9~ ** cfilo1" -HT 1Jcf;" ~~ ~ cfl" mfra:r ~ f"achl.fi ~ ~ * ~ alffe t? 1. A 3W B 2. C.3ITT" D 3. A 3W C 4. B 3W D 0 0 0 0 Question No. 34 / Question ID 703634 Marks: 4.00 Molecular phylogeny ind icates that whales are closely related to the artiodactyls. Given this information , select the phylogenetic tree that shows the correct set of terrestrial animals with w hich modern wh ales share their most recent ancestry. 1 2 Pigs Whale Camel Horse Pigs Horse Whale Hippo 3 4 Pigs Whale Hippo l-iorse Hippo Pigs Whale Cameli ::tt1 □ 1fclcti..:>11klq_a $fllc1 ch"«,T t fcf, ~ ::tt1fe4~~cfcl$c>i1 ~ fcrlctic ~ ti ~ -Hilcr11 ~ ~ m ~ 3"-H"..:>11klc1d~4~ cra=r cfiT ~ ch'I~ Q ~ ~ ~. ~-Hfl ~ ~ ~ ~ 3cr1ch'J ~ o1c?1cr1c1icrlSl~9 WW 61 1. _,fta1c;i~q ::tt lqJ"a41: 0.04 WW, 0.32 Ww 3-l'R 0.64 WW QJ'ic>I 311cp"alll W - 0.5 3ITT" w - 0.5 2. -,ftcr1c;i~q.j-ilqffi41: 0.32 WW, 0.64 Ww 3ITT" 0.04 WW Q~I 311cp"a41 W - 0.8 3ITT" w - 0.2 3. -,ftcr1c;i~q.j-ilqffi41: 0.64 WW, 0.32 Ww 3ITT" 0.04 WW Q~I 311cp"alll W - 0.8 3ITT" w - 0.2 4. -,ftcr1c;i~q.j11afa41: c.. 0.34 WW, 0.34 Ww 3ITT" 0.32 ww Q~I 311dffilll c.. W - 0.5 3ITT" w - 0.5 0 0 0 0 Question No. 36 / Question ID 703592 Marks: 4.00 A cancer clin ic is treating four unrelated patients suffering from chronic myelogenous leukem ia. A researcher sequences the Phi ladelphia chromosome from the leukem ic cells of these patients and makes the fol lowing statements: A. The DNA sequence was identical in the translocati on breakage and rejoining (TBR ) sections in all leu kemic ce lls in all 4 patients. B. The DNA sequence was identical in al l leukemic cells from patient 1, but every patient had a different TBR sequence. C. Al l patients have translocations between long arms of chromosomes 9 and 22. D. Al l patients have translocations between long arm of chromosome 9 and short arm of chromosome 22. Wh ich one of the following options represents a com bination of all correct statements? 1. A and D 2. Band C 3. Band D 4. A and C ~ * "Q"cfl" ru fclic--H 1;;;i.Q *,Rn: chi c4'I c1-1-,.-511 "1 fo:l c-1 ~c) c-1-< cfc-1 c-11 * cfl Vq,c-1 "iJR ~ -{)f¥141 cf;f 39i:IH ~ w ~I ~ ~~, ~ -{)f¥14~ c);- ~dc-l{cfc-lcf, ~3IT c);- fchc;i1gfc.:l.fi.QI dlUl-t-bl cf;f 3icrlsf,J-IUI ~ ~ 3fR ~ ~ dl ~.:, ".:, ~ ~ -anll A. ~ 4 -l)fil.m c);- ~dc-l{cfc-lcfi ~3IT c);- ~lcrlic-1{01 WT 9crl'8~-51crl.:, (TBR) ~.:, * DNA cf;f 3-icrlshJ-I.:, Ri(>'Cf,c;i.:, fiJ-tlcrl ~ I B. tat)- 1 c);- mfr ~d c-1-< cfc-1 ch ~ 3 i t c);- DNA.:tt crl.:,shJ-t RI 41.:, c;i -8 c1-11 crl ~ , fchcrc-1.:, i;1c--ilch M- c);- TBR cf;f.:ttcrlst,J-1.:, ~ ~I C. ~ -l)fillfi c);- JIOFH~ 9 3-ITT" 22 ~ ~ ~ c);- ~ -t=~lcrlic-l{D I ~ ~I.:, ".:, 0. ~ -l)filll1 c);- JIOlfi~ 9 ~ ~ ~ 3fR dlOlfi~ 22 ~ -=> ".:,.:, " rntr ~ c);-.:, tRf ~1cr1ic-1-l 1. i, ii, V 2. l, ii, iv 3. iii , iv, V 4. ii, iv, V 0 0 0 Question No. 43 / Question ID 703614 Marks: 4.00 The plaque morphology of w ild type and r/1 mutants of T4 bacteriophage followi ng infection of different E. coli strains is summarized below. E. coli strain T4 phage strain B K wi ld type Small and ragged Smal l and ragged r/1 mutants Large and round No plaques The following two experiments were carrl ed out Experiment I: Co-infection of two lndependent rll mutants on E. coli K strain resulted in several plaques , al l being small and ragged. Experiment II: E coli B strain w as co-infected with the above r/1 mutants. T4 phages from the resulting plaques were used to infect E. coli K strain. Few plaques were obtained , whi ch were all smal l and ragged. Based on the observations, the follow ing statements were made: A. Experiment I indicates that the two mutants are allel ic. B. Experiment 11 indicates that the wi ld type T 4 phages that infected E. coli K strain resulted from a recombination event. C. In experiment II, if the T4 phage isolated from the E coli B strain was used to infect E. coli B strain , all plaques wou ld be large and round. Which one of the follow ing options is a combination of all correct statements? 1. A only 2. B only 3. A and B 4. Band C ~ ~ 3fR r// 3,9f°tcfrff T4 ~..:, ~ -Hsh ~ o1.::) q Ic1 cFt, o-llIt;~.i:fl fa.I cA iv. m qfru:ft ~ c;)- m c;)- *~ -:11 1c-11.Q m 3 q-:71 Ic-11 ,Q ~ ~ :n Ifa.I c:fi cr:rm-, ARtia-1 ~ a-lTffi a,-A- ~ ~ ~ 1. a-iv , b-ii i ' c-ii ' d-i 2. a-l b-lv c- iii d-ii ' ' ' 3. a-i ii b-ii c-i d-iv ' ' ' 4. a-iv b-i c-iii d-ii ' ' ' 0 0 0 Question No. 50 / Question ID 703627 Marks: 4.00 For a popu lation that grow s exponentially in the time interval (t, t+1 ), we have Nt+1 = R Nt, wh ere N denotes population size and R denotes the growth rate. Under intraspecific competition where births and deaths are density dependent, we expect the pop ulation to stabilize at carrying capacity, K. In the figure below, Nt INt+1 is plotted as a linear function of Nt. 1 -------------------- -- -- -- -- ----------------- :l ~ 1 -R 0 Nr K We may write down the linear equation for the line joining A with B and derive a model for density-dependent population growth under intraspecific competition. Denoting (R-1 )/Kasa, w hich of the followi ng is the correct relationship that describes population growth? 1. 2. 3. 4. Vc:fl -iici-FH&QI ~ ~ 3icHlI (t, t+1 ) ~ iHtllc1i4i'l:ii (exponentially) ~ ~ ~. ~ ~ ~ 11Rf Nt+1 = R Nt , ~ ~ N -iiaH·ll,n~fJ.la1)fHJi.:> q;,- l:?"cfl ~ ~ * 394cfc1.:> 9)tStcf>4cfc-l.:) WITT" rn.t aTis (SA)* fsli41ru:Hcr ~ 3,91Cta-i cfi'r" ~ cfiT ~ ~ 6"1 ~ ~ ~ Bt>m cfi'r" cfi1:4c;iu11~"1 ~ ~ :fi$41Q..., ~ t: A. ,..., ~ (lh) q:;r ~ 'h' ruc;llc1..., m , jici-fcf>crl..., 3cl-5ta-il ~ ' Uc ~ 6"1 s. j1CJ1cf>c¥1.:) mu ~ '.a1ruc1 a1R-Qf9o-1fihcr1 ~1 Qffio-1~:Hcc::< ~ ~ * lhc>tf-ct~9 ~ ~ 3fRR cAMP cfi'r" qcjil- ~ 6"1 C. ' C. ~ ~ ~-~ cAMP, c>rm 11\+c::a1 (L) ca++~ cf;" ~c>to-1 ar :fit;lllc11 ~ 6"1 D. cfl t o-1 ~ Ca++ ~ (Ica) Ucc1T 6" I 1. A 3ITT" B 2. B 3ITT"C 3. C 3ffi D 4. A 3ITT" C 0 0 0 0 Question No. 54 / Question ID 703641 Marks: 4.00 Four groups of students (A - D) were asked to determine whether memory B cells generated in mice immunized with ovalbumin (OVA), in Complete Freund's adjuvant (CFA), cou ld mount a secondary antibody response (recall response) to OVA in vitro. The groups did the fo llowi ng experiments: Group A students harvested serum from the mice , loaded it on OVA-coated ELISA plates and showed that lgG and lgA anti-OVA antibod ies were present. Group B students harvested long-lived plasma cells from bone marrow of the mice, plated them in cu ltu re for 5 days and showed anti -OVA antibod ies in supernatant by ELI SA. Group C students infected an epithelial cell line with the virus and showed that spleen cells from the mice could ki ll the infected targets. Group D students stimulated spleen cells from the mouse with OVA for 5 days and showed anti-OVA anti bodies in supern atant by ELISA. Wh ich one of the fo llowi ng options represents group(s) that did the correct experiment? 1. Group A 2. Group C 3. Groups B and C 4. Group D ~ ~ ~ ~ (A- D) q;)- ~ ~ cf>{at ~ ~ ~ -aim fcl:;- cFm ~ ~ ~ (CFA) * ~~1f.Ao-1 (OVA) ~ ~ ~ * 3,9cnr1 ~ s~ , m ovA * 'Qcn ~fcli:fl4c1, s:iffic1,14 s:iffifiti41 (t-J-1{01 s:iffifih41 ) ~ ~.fichf ~). f,;jfiJ:l N-.fildo-1 di:>il$cf,~Ulfti1cfi{OI c):;- ~ ~ ~ o,ffe ~ t, c):;- C-u;rr ~ KDEL ::tiojshd-i ~ "dPTT, 3ITT" "Q'cfi" ~ { □ ~4 ~ * ~ fcf;m lTTUf cfi" 10, 20 3ITT" 60 f.Ro1c1 "d'flIT I cfi" q~:mc,, ER cfiT ~~..:, ' fcf;m CJfllT ~ o1d1o1 m~~ a ai:>il$cf,~c;nt)o-1 X-KDEL c);- ~ ~ fcl;"m CJfllT 1 -«;iTC(1" i;i Rl{m~flliDT q:;)- ~ ~nm CJfllT t 1 kDa 10 20 60 60-1 - 55- ~-----~ -- GlycoproteinX-KDEL fa.lchrl * * cf1t, m ~. 20 m 60 fAo-1c1 ~ ~ * 3uT.31101fclcfi 3lR" c:m;)- ~ ~ ~ ~ mrcfc,: c.Ql,&.lll cfi~dll? 2. i;i~t)o-1 ~~~ ~ ~ cfi" ~ all$c:f;l~~t'lo1 X-KDEL, ~:i;i?tc.ll.lfl '511fti1c:f>I * ~~nfita ~ ti 3. dll$ct,)c;nt)o-1 X-KDEL 3fOT,..:, ER cfi" q"o-1:i;i1fcn..:, * "CfcT, (.) ~ Time Time "Q'cf;" P-r 9$~1'8'1 ~31T ~ ~ctnc\iJ.-9ft ~ ~Nill31T cfiT ~ ~ 6"1 2. fclcfilft~th>r J.iR'.c16cfi ~ ~ m bfg cf>m 9$1'8'1 ~3-TT ~ ~ctnc\iJ.-9ft ~ ~Nill31T cfiT ~ ~ 6"1 3. bfg cf>P-r ~ :.fd I.ll c1 ~ 6I ~ 4. bfg cf>P-r ~ c9) chJ.-9 ft ~ 6" I 0 0 0 0 Question No. 59 / Question ID 703630 Marks: 4.00 The given table shows the annual Net Primary Productivity (NPP), season length , and Leaf Area Index (LAI) for various ecosystems. Season Annual NPP Ecosystem (g m-2) Tota l LAI (m2 m-2) length (days) Tropica l Forest 365 2482 6.0 Temperate Forest 250 1550 6.0 Tundra 100 180 1.0 Desert 100 250 1.0 Wh ich one of the follow ing options represents the correct order of decreasing NPP per day per unit leaf area? 1. Desert> Tundra > Tropical Forest> Temperate Forest 2. Tropical Forest > Temperate Forest> Tu ndra > Desert 3. Tundra > Desert> Temperate Forest > Tropical Forest 4. Temperate Forest > Tropical Forest> Desert > Tundra er ai"lfl" :fil{Uft ~ ~ c=R" cf;" fu cU~ch ~~.:, ' ~ 3c-4l~chci l (N PP), ~ ~ 3ITT".:, "Cfrft" ITT ~ (LAI), ~ ~ITTTT " 61 ~~ ~~ ctl~ch NPP ~ LAI (m 2 m-2) (~ ) (g m-2).:) ,3,ISOlcf,~~~ cro=r 365 2482 6.0 ~ (=I. I ISO I cro=r ~-I 250 1550 6.0 ~ 100 180 1.0 ~~ 100 250 1.0 fa-1.hii faq:,~q1 ~ ~ ~ m ~. ~ rr NPP ".:, ~ > ,3,&0lcfi~~'UT cro=r > ffmftcfl&UI cfci, 0 0 0 0 Question No. 60 / Question ID 703628 Marks: 4.00 Here is some data for a cohort of 400 individuals of a species whose abundance was tracked for 6 years (its maximum lifespan ). For one-year age intervals from birth to 6 years , you have the fol lowi ng numbers of survivors , 400 , 200 , 100, 40 , 20, 10, and 0. The correspond ing per capita birth rates are 0.1 , 2.0, 3.0 , 4.0 , 4.0 , 3.0 , and 0.0. What is the basic reproductive rate Ro? 1. 2.52 2. 2.92 3. 2.36 4. 3.20 ~ ~ ~ "Q"cfl ~ cf;'J- 400 c.Qfcz41 Cfi" "Q"cfl ~ (ct,)e,ll) Cfi" fc;t-Q- ~ f;ia14?J ~iHc-11 6.:) cf6lT ($=Hehl ~ s:rtlcla1c:hlc>i ) c,cFi" ~ ~I ~ ~ 6 cf6lT c,cFi" "Q"cfl ~ Cfi" 3ITTf 3ic-l-ll&n.:) 9"",{" 3ci-ls:rtl~lfl cf;'r- -HMI 400, 200 , 100, 40 , 20 , 10, 3ITT" 0 ~I fclfaF ~ 3ffc:r-Fct~ ~~ Fclcnf+ta cf;'r df$"1 ~, 3ffc:r-~ ~~fctfitmch)-~X~diIT~~ ~ ' ch)-~y~~7Tm ~I 3ffct-PcJll~.t ~~ ( ~ X) ~ (~RfY) A..fiilft:a ~eifcct ~~ (SIM) (i) 4-ifcraa 3a..i1a1 "ITTR~, sTafc Cf) 3TTcITT Cf) ~ ~.:> ~ fttt W ~ ~ ft! f lo1 "cf,)- ~ cfi«TT 61 1. A-(i) , B-(il ), C-(i ii) 2. A-(ii), B-(i), C-(i ii) 3. A-(ii i), B-(ii), C-(i) 4. A-(ii), B-(iii), C-(i) 0 0 0 0 Question No. 65 / Question ID 703637 Marks: 4.00 RPMI and DMEM , supplemented w ith serum, antibiotics, glutamine and phenol red are routinely used for tissue cu lture of human cel ls in CO2 incubators. In addition , sodi um bicarbonate (NaHCO3) and HEPES are used as buffering agents. The follow ing statements were made about the media. A. While 5% CO2 is optimal fo r cel ls cultu red in RPMI , the optim al CO2 concentration for DMEM is 7.5-10%. B. HEPES is necessary if cells are to be kept outside the in cubator in room air for long periods. C. NaHCO3 is necessary if cells are to be kept outside the incubator in room air for long periods. D. When cells grow rapidly in the cu lture medium for a few days, phenol red w ill turn the medium pink/red. Which one of fo llowin g options represents the correct comb ination of all the statements? 1. A and B 2. Band C 3. A and D 4. C and D ~ ' ~fc-l~facfi, d&(lc1-t"ia1 c=rm (l);;:11~ ts ~ -H~c-i RPM I.3ITT" DMEM cfiT ~llhl CO2 £&.Hlfll:fi dl J-lla-la ~3TT c f > ~ ~ t:c! fa.l41/lc-i ~ ~ ~ ~ -aR=rr 61 ~ ::ttkl~cfi-t tnffill.J-1 ~1$cfil~ c (NaHC03).3ITT" HEPES cfiT 3 ~ (~lhftdl) cficAcfi cf) ~ * 39.tl)dl ~ arc=IT 61 mt- c-il9J-lla-l * ,{.@a-II ITT c=n- HEPES 3,lq~~ 61 C. ~ ~3TT cfiT ~ ~ c,cfi" £GJ-I I fl!~ ~ ~ q:;m cf> c-i 19 J-l la-1 * ,< lil a-11 ITT c=n- Na HC03 ~~ 61 D. ~ ~ ~ mt--mr *~ ~ qi1J ~ ~ c), fi;:rQ" facf>Hlc-t ~ ~ c=n- (l)o1) ~ -ts, mt-1crr m "Q"cfi" fclcfic:--9 fDfr ~ ~ c), -H.tt) '51a1 en)- ~m=rr t? 1. A.3ITT"B 2. B.3ITT" C 3. A.3ITT" D 4. C.3ITT" D 0 0 0 0 Question No. 66 / Question ID 703576 Marks: 4.00  In a protein stability study, three solutions, MolA (10 kOa) at 0.5 mM , MolB (20 kOa) at 0.5 mM , and MolC (20 kOa) at 1 mM, were subjected to denaturation by urea , SOS and guanidium hydrochloride (GnHCI) , respectively. The profiles of the fraction of unfolded protein with increasing concentration of the denaturants is given below. MolA (10 liD ), 0.5 mM Mg.I.ft (20 kDa), 0.5 mM M2.!t (20 kDil). 1 mM 1.0 l.0r - - - - - - -...,,,.....- - 1.0 "O "O QI "Cl Q) Q) "O "O ;g "O ;g ~ § 0.5 § 0.5 § 0.5 1 - - - - -- s::: C c. 0 0 0 "£ B B... (Q LL. ~ ~ LL. LI.. 0 _ _::____ _ _ __ 0 - - """'------'--- - - 0 1 2 3 4 0.1 0.2 0.3 0.4 0 2 4 6 8 [Urea], M [SOS],% [§IJ.tK:H, M Which one of the following corresponds to reaction conditions at which the number of molecules of folded protein are equal, assuming the reaction volumes to be the same for all experiments? 1. 0.2 M urea; 0.05 % SOS ; 4.5 M GnHCI 2. 2 M urea; 0.05 % SOS; 1 M GnHCI 3. 0.2 M urea; 0.25% SOS; 4.5 M GnHCI 4. 2 M urea; 0.25 % SOS ; 1 M GnHCI  '1i~t'lo-t ~ c), "Q'cf; Jft..~ * ~ fa(>t4cri, MolA (10 kOa) 0.5 mM ~. MolB (20 kOa) 0.5 mM ~. {fm MolC (20 kOa) 1 mM ~. ~T: :q_ft41, SOS c=rm dqlo1~ffi4c1-1 t;l$$)cf ~ ~ ~..:) tii~al c), ~ ~ ~ dJm ~I ~olA (10 ls_D~, 0.5 mM Mole (20 ~), o.s mM M..QJ~ (20 ~), 1 mM 1.0 1.0r------------::- - 1.0 -0 "'C Cl/ -0 ~ Cl/ -0 ""O ;§ ] § 0.5 ~ :::I O.51 - - - -- 1 5 0.5 1 - - - -- C: C c: 0 0 0 '.O u ·e ·13... (11 u. ~ ~ LL u... o ~ - ~-L___ _ _ o - - - ~ - ~- - 0 - -"""----- - - - ' - - -- - o 1 2 3 4 0 0.1 0.2 0.3 0.4 O 2 4 6 8 [Urea], M [SOS],% [~ , M fa.l chrl 6l *~ ~ ~ ~TT c), ti cl-I Io-1 ~ ~ ti i:i fcti" q fi;1 c1 t;t~ t) cri cfi" 3fUT3TT..:) ~ :fi&.QI isHIGI:{ ~ 6, ~ fcti" mfr Sl4~dl' * ~ 311.Qcio-l fl.I-Ila-I 6? 1. 0.2 M 4f1:41 ; 0.05 % SOS; 4.5 M GnHCI " 2. 2 M 4f1:41 ; 0.05 % SOS; 1 M GnHCI " 3. 0.2 M 4f1:41 ; 0.25% SOS ; 4.5 M GnHCI " 4. 2 M 1_f1:41 ; 0.25 % SOS; 1 M GnHCI 0 0 0 0 Question No. 67 / Question ID 703583 Marks: 4.00 DNA polymerase PolA has high fidelity but low processivity and DNA polymerase PolB has low fidelity and high processivity. In vitro reactions for DNA synthesis using limiting amount of PolA or PolB were set to further characterise the enzymes according to the fo llowing scheme: Tube 1 Tube 2 DNAPolA DNAPolB 20 minutes) X µM T7 DNA 20 minutes) X µM T7 DNA 40 minutes) 10X µM T3 DNA 40 minutes)1OX µM T3 DNA Quantification of Quantification of the amount of T7 the amount of T7 and T3 DNA and T3 DNA synthesised synthesised Which of the following outcome do you expect? 1. Tube 1 will have more T3 DNA and tube 2 will have more T7 DNA. 2. Tube 1 wi ll have more T7 DNA and tube 2 will have more T3 DNA. 3. Both tubes will have more T3 DNA than T7 DNA. 4. Both tubes will have more T7 DNA than T3 DNA. DNA q'j'Qfll~.:;;t PolA Jr 3vcJ.fic>1aa1c11 (fidelity) fcho-1aa-1a1 c=rm 3vcJ c;isfiJ.ic1I ~ ~I DNA ffl~ ~ '9'R" ~3TT ctl" ~. PolA 3ITT" PolB ~.fi~l/lc1 m:IT cf;f 39~~JI ~ ~..:, 3ITTT Qo-.:;;ll$J.t1 cf;f il~:i!icfia-1 ~ er ~ 41.5ia-ll ctl" 31a-ltiH.:, ~ dfml Tube 1 Tube 2 DNAPolA DNAPolB 20 minutes! X µM T7 DNA 20 minutesJ X µM T7 DNA 40 minutesJ 10X µM T3 DNA 40 minutef,1ox µM T3 DNA Quantification of Quantification of the amount of T7 the amount of T7 and T3 DNA and T3 DNA synthesised synthesised 1. a1fiZlcfil 1 ~ T3 DNA 3TTUcfi" ~ m{ a1fiZlcfil 2 Jr T7 DNA 3TTUcfi" ~ I 2. a1fiZlcfil 1 Jr T7 DNA 3TTUcfi" ~ 3ITT" a1fiZlcfil 2 ~ T3 DNA 3TTUcfi" ~ I 3. T3 DNA c'JaTT" a1fiZlcfil.:ttldl"T7 DNA~ 3TTUcfi" ~ I 4. T7 DNA c'JaTT" a-IQ cfil Jtt ~ T3 DNA ~ 3TTUcfi" ~ I 0 0 0 0 Question No. 68 / Question ID 703597 Marks: 4.00  Given below are proteln domains and their binding specificities. Column X Column Y Interaction domain Binding site A. SH2 domain i. Phosphorylated tyrosine residue on receptors B. SH3 domain ii. Charged head groups of specific phosphoinositides on plasma membrane C. PH domain iii. Short praline-rich amino acld sequence on proteins D. PTB domain Which one of the follow ing options represents all correct matches between Column X and Column Y? 1. A-iii B-i C-ii O-ii 2. ' ' ' A-i ' B-ii '· C-iii '· O-i 3. A-ii i B-iii C-i O-ii ' ' ' 1 4. A-i B-iii C-ii O-i ' ' '  ~x @3'.fY 3,cr.lj~I~ -l:U ~ t;rah;r ~~ A. SH2i;rahr i. a,1 1~.ll~ cfi" \-fl!t=Ch) f< ~ cf,c-1 cl$-l)~o1 c.. ~ ~ B. SH3~ ii. Cc>ll:;;icHI 8lc--~ c);- ~ \.hl.f-Ch)$a1) ti 1$C::1$~.fi ~ ~fmr ~~ C. PH t;rm iii. sr, eio-1 ~ i"ET.::, q)~a1-~.::, 3fcJfio-lT 3-fR)f ~~ D. PTB-.;rm fcrl chii fclcf,Ml~ * * cFto-1" "Q"cfi" @rn X 3ITT" ~ Y cfi" ~ ~ ~ ft! c>I 1ci11 ~ ~m=rr t? 1. A-iii, B-i ' C-ii ' D-i i 2. A-i B-ii C-i ii D-i 3. A-iii' B-iii I ' C-i' I I D-ii 4. A-i B-iii C-ii D-i ' ' ' 0 0 0 0 Question No. 69 / Question ID 703638 Marks: 4.00 A plant breeder plans to introgress a gene for pathogen resistance (R) from a wil d species (8 ) into a cultivated vari ety (A). Panel I in the figure shows a profi le of DNA markers for A and B. Panel II shows a genetic map for the lin kage group w hich has the gene for pathogen resistance. I. II. A B Al- -Bl A2 - A2 - B2 A3- 83 - B3 R A4- A4 -04 AS- - es 82 87 A6- -B6 A7 - B7 A7- AB- -ea Wh ich one of the followi ng options has the correct cho ice of markers for foreground (FG ) and background (BG) selection , respectively? 1. FG: 83 , A4 and BG: A2 , A3, A? 2. FG: 83 , B2 and BG: A 1, A5 , A6 , AB 3. FG : 83 , B2 and BG: A2 , A3 , A4 , A? 4. FG : 83 , A4 and BG: A2 , 82, 87 and A? "Q'q, "9Tc;9" 1,fofcrlcf,, ~ fcht=.H (A) ~ qo:lf ~;::;i,Rl (B) ~ -1 ~ , F 1 ~ ~ ~.ficf>.(01 * 3ITT" ~ ;;ttaJfalc-i.fic-ikl (~ A) ~ F 1 ~ t=qfa-l~ila1 ~ * F2.fic-ikl (~ B 3ITT" C) ~ ~I (A) (B) Pl P2 F1 DH from F1 Pl P2 F1 F progeny c----i I I I - -- --- -- DH= Doubled haploid progeny from Fi (C) Pl P2 F1 F, progeny I I I I I - -- --- - - DH~ F2.fic-ikl * ~ ~ ~ 3ITTlR" -err, 3"ff ~ (A * C) ~ 9(;il la1 cf,) fdl Q ~ Q c-fl fc.l cf> DNA Rl a-t, cf> -err 3TTtTTfrc, 6? 1. A cficR.f 2. B cficR.f 3. A 3ITT" C 4. A 3ITT" B 0 0 0 0 Question No. 71 / Question ID 703616 Marks: 4.00 Recessive mutations in the human dysferlln gene lead to Limb Gird le type II muscular dystrophy. The gene is located on the second chromosome. The patient's parents do not have Limb Girdle type II dystrophy B. What is the probabi lity that at least one of the fo ur grandparents of th is patient suffered from this disease? 1. 1/4 2. 3/1 0 3. 1/2 4. 7/1 0 J.lla-lC1 ~ ffit=lllrna-1 ~ *.mmrcfr 3c-9f):e1aa1 ~.kl dig&! m II ~rm 5,fi§cf>FH ~ ~1 ~ ~ c;Rlc-11.Q... cJ1a1H::i..:, '~ ~ ~ ~1M ~ * ~ d1rn&i mc:rr-fctill m 11 ~cf>l.fi s ~ ~1 ~ M c); ~-~ 3trr a-1TcrIT-aITcrft", ~ ~ * ~ ~ ~ ~ ~ cf; ~ t!J.11t) ~ cfl1°$a ~ cf:;'r ~lfllcf>c-tl cfm ~ 1. 1/4 2. 3/1 0 3. 1/2 4. 7/1 0 0 0 0 0 Question No. 72 / Question ID 703572 Marks: 4.00 For the coupled reaction given below, the equilibriu m constants (K 'eq ) for equation and equation are 270 and 890 , respectively. Glucose 6-phosphate + H20 ➔ glucose + Pi ATP + glucose ➔ ADP + glucose 6-phosphate The standard free energy of hydrolysis of ATP at 25°C is 1. - (24 to 26) kJ / mol 2. - (18 to 20) kJ /mol 3. - (30 to 32) kJ /mol 4. - (60 to 62) kJ / mol ~ ~ ~.Q fh-frl ~ kl ~.Q 13-TT ~.3iTmfu=r.fi J-t~ cfi =la I 3ITT".fi Jfl c:fi =la I =l.fi I.Q f;l c:fi i;i cfi" ~.fic-licri ~ ~ (K 'eq ) ~r: 270 3W 890 ~I ATP + ai i , C- R.J.fo-1 " 3. A- q~41 , B- R.J.to-1 , C- ~J--.HI 4. A- !~fscf4c>i , B- lcJ71 ii ~ ') 3iil=ll-~I~~ C ?7"?>!~1~Zl7 ~j';:;l-;;f#J'