Balancing Chemical Equations PDF
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This document contains practice questions and answers for balancing chemical equations. It covers various chemical reactions and provides step-by-step solutions to help reinforce understanding. Perfect for secondary school chemistry students.
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## Balancing Chemical Equations Balance the equations below: 1. N<sub>2</sub> + H<sub>2</sub> → NH<sub>3</sub> 2. KClO<sub>3</sub> → KCl + O<sub>2</sub> 3. NaCl + F<sub>2</sub> → NaF + Cl<sub>2</sub> 4. H<sub>2</sub> + O<sub>2</sub> → H<sub>2</sub>O 5. Pb(OH)<sub>2</sub> + HCl → H<sub>2</sub>...
## Balancing Chemical Equations Balance the equations below: 1. N<sub>2</sub> + H<sub>2</sub> → NH<sub>3</sub> 2. KClO<sub>3</sub> → KCl + O<sub>2</sub> 3. NaCl + F<sub>2</sub> → NaF + Cl<sub>2</sub> 4. H<sub>2</sub> + O<sub>2</sub> → H<sub>2</sub>O 5. Pb(OH)<sub>2</sub> + HCl → H<sub>2</sub>O + PbCl<sub>2</sub> 6. AlBr<sub>3</sub> + K<sub>2</sub>SO<sub>4</sub> → KBr + Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> 7. CH<sub>4</sub> + O<sub>2</sub> → CO<sub>2</sub> + H<sub>2</sub>O 8. C<sub>3</sub>H<sub>8</sub> + O<sub>2</sub> → CO<sub>2</sub> + H<sub>2</sub>O 9. C<sub>8</sub>H<sub>18</sub> + O<sub>2</sub> → CO<sub>2</sub> + H<sub>2</sub>O 10. FeCl<sub>3</sub> + NaOH → Fe(OH)<sub>3</sub> + NaCl 11. P + O<sub>2</sub> → P<sub>2</sub>O<sub>5</sub> 12. Na + H<sub>2</sub>O → NaOH + H<sub>2</sub> 13. Ag<sub>2</sub>O → Ag + O<sub>2</sub> 14. S<sub>8</sub> + O<sub>2</sub> → SO<sub>3</sub> 15. CO<sub>2</sub> + H<sub>2</sub>O → C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> + O<sub>2</sub> 16. K + MgBr → KBr + Mg 17. HCl + CaCO<sub>3</sub> → CaCl<sub>2</sub> + H<sub>2</sub>O + CO<sub>2</sub> 18. HNO<sub>3</sub> + NaHCO<sub>3</sub> → NaNO<sub>3</sub> + H<sub>2</sub>O + CO<sub>2</sub> 19. H<sub>2</sub>O + O<sub>2</sub> → H<sub>2</sub>O<sub>2</sub> 20. NaBr + CaF<sub>2</sub> → NaF + CaBr<sub>2</sub> 21. H<sub>2</sub>SO<sub>4</sub> + NaNO<sub>2</sub> → HNO<sub>2</sub> + Na<sub>2</sub>SO<sub>4</sub> ## Balancing Chemical Equations - Answer Key Balance the equations below: 1. 1 N<sub>2</sub> + 3 H<sub>2</sub> → 2 NH<sub>3</sub> 2. 2 KClO<sub>3</sub> → 2 KCl + 3 O<sub>2</sub> 3. 2 NaCl + 1 F<sub>2</sub> → 2 NaF + 1 Cl<sub>2</sub> 4. 2 H<sub>2</sub> + 1 O<sub>2</sub> → 2 H<sub>2</sub>O 5. 1 Pb(OH)<sub>2</sub> + 2 HCl → 2 H<sub>2</sub>O + 1 PbCl<sub>2</sub> 6. 2 AlBr<sub>3</sub> + 3 K<sub>2</sub>SO<sub>4</sub> → 6 KBr + 1 Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub> 7. 1 CH<sub>4</sub> + 2 O<sub>2</sub> → 1 CO<sub>2</sub> + 2 H<sub>2</sub>O 8. 1 C<sub>3</sub>H<sub>8</sub> + 5 O<sub>2</sub> → 3 CO<sub>2</sub> + 4 H<sub>2</sub>O 9. 2 C<sub>8</sub>H<sub>18</sub> + 25 O<sub>2</sub> → 16 CO<sub>2</sub> + 18 H<sub>2</sub>O 10. 1 FeCl<sub>3</sub> + 3 NaOH → 1 Fe(OH)<sub>3</sub> + 3 NaCl 11. 4 P + 5 O<sub>2</sub> → 2 P<sub>2</sub>O<sub>5</sub> 12. 2 Na + 2 H<sub>2</sub>O → 2 NaOH + 1 H<sub>2</sub> 13. 2 Ag<sub>2</sub>O→ 4 Ag + 1 O<sub>2</sub> 14. 1 S<sub>8</sub> + 12 O<sub>2</sub> → 8 SO<sub>3</sub> 15. 6 CO<sub>2</sub> + 6 H<sub>2</sub>O → 1 C<sub>6</sub>H<sub>12</sub>O<sub>6</sub> + 6 O<sub>2</sub> 16. 1 K + 1 MgBr → 1 KBr + 1 Mg 17. 2 HCl + 1 CaCO<sub>3</sub> → 1 CaCl<sub>2</sub> + 1 H<sub>2</sub>O + 1 CO<sub>2</sub> 18. 1 HNO<sub>3</sub> + 1 NaHCO<sub>3</sub> → 1 NaNO<sub>3</sub> + 1 H<sub>2</sub>O + 1 CO<sub>2</sub> 19. 2 H<sub>2</sub>O + 1 O<sub>2</sub> → 2 H<sub>2</sub>O<sub>2</sub> 20. 2 NaBr + 1 CaF<sub>2</sub> → 2 NaF + 1 CaBr<sub>2</sub> 21. 1 H<sub>2</sub>SO<sub>4</sub> + 2 NaNO<sub>2</sub> → 2 HNO<sub>2</sub> + 1 Na<sub>2</sub>SO<sub>4</sub>
