PDF Answers of Chemistry Questions

Lecture 1 A. Choose the correct answer: 1. Bose Einstein condensate 2. Gas>liquid>solid 3. Vaporization B. Give scientific term for the followings: 1. Plasma 2. Chemical property 3. Extensive property 4. Candela Lecture 2 I. Choose the correct answer: a. Protons...

Lecture 1 A. Choose the correct answer: 1. Bose Einstein condensate 2. Gas>liquid>solid 3. Vaporization B. Give scientific term for the followings: 1. Plasma 2. Chemical property 3. Extensive property 4. Candela Lecture 2 I. Choose the correct answer: a. Protons b. Same number of electrons c. Atoms can be neither created or destroyed II. Complete the followings: 1. Neutron 2. 10-13 cm 3. Homonuclear and heteronuclear 4. Zwitter ion Lecture 3 I. Multiple choices questions: 1. High melting point 2. Loses electrons and becomes positively charged 3. Two non-metals 4. They have shorter bond lengths than single covalent bonds 1 5. NaOH 6. Covalent bond 7. Iron 8. 1 II. Complete the followings: 1. Coulombic force 2. Positive and negative 3. Share 4. Double Lecture 4 I. Choose the correct answer: a. Van der Waals b. NaOH c. Van der Waals attraction d. Hydrogen bonds e. Highly directed bonds f. Decrease in energy g. Electrostatic forces II. Put (√) or (×) and correct the wrong one: 1. False (low) 2. False (covalent) 3. True 4. False (covalent only) III. Choose the correct answer: 1. Weak intermolecular attractions between atoms or molecules. 2. Weak forces caused by temporary dipoles in nonpolar molecules. 3. Helium (He) 4. Molecules with permanent dipoles. 5. A polar molecule induces a dipole in a nonpolar molecule. 2 Lecture 5 I. Choose the correct answer: 1. P1= 1240 torr V1= 47.2 L T1=25+273=298 K P2= 730 torr V2=? T2= 25+273=298 K P1V1/T1=P2V2/T2 47.2×1240/298=730×V2/298 V2= 80.17 L= 80.2 L 2. P1= 900 torr V1= 3 L T1=25°C P2= 900 torr V2=10 T2= ? P1V1/T1=P2V2/T2 900×3/25=900×10/T2 T2= 83.3°C 3. I, II, and III 4. P1= 740 torr V1= 6 L T1=35+ 273= 308 K P2= 760 torr V2=? T2= 273 K P1V1/T1=P2V2/T2 740×6/308=760×V2/273 V2= 5.18L 5. P= 2 atm. T= 273+ 25= 298 K M.wt of NH3= 14+3=17 PV = (W/M.wt) RT D= (P×M.wt)/RT= (2×17)/0.082×298= 1.39= 1.4 g/L 6. P= 10.4 atm. V= 71.9 mL= 0.0719 L T= 273+ 465= 738 K M.wt of H2O= 2+16=18 PV = (W/M.wt) RT 10.4×0.0719= (W/18) ×0.082×738 W= 0.222 g 3 7. Low P and high T 8. P, V 4