Titration GCSE Chemistry Calculation Guide PDF

Sure! Here\'s the same explanation formatted for easy copying and pasting: \-\-- Let's go through the steps of solving a titration question like you might see on a GCSE exam. \#\#\# Example Question: You are titrating hydrochloric acid (HCl) with sodium hydroxide (NaOH). You use 25.0 cm³ of 0.1...

Sure! Here\'s the same explanation formatted for easy copying and pasting: \-\-- Let's go through the steps of solving a titration question like you might see on a GCSE exam. \#\#\# Example Question: You are titrating hydrochloric acid (HCl) with sodium hydroxide (NaOH). You use 25.0 cm³ of 0.1 mol/dm³ NaOH to neutralize 20.0 cm³ of HCl. What is the concentration of the HCl solution? \#\#\# Step 1: Write the Balanced Equation First, you need to know the reaction happening between the two substances: HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O (l) This is a 1:1 reaction, meaning 1 mole of HCl reacts with 1 mole of NaOH. \#\#\# Step 2: Use the Formula The main formula you'll use in titration questions is: Moles = Concentration (mol/dm³) × Volume (dm³) \- The volume must always be in dm³ (so divide cm³ by 1000). \- For NaOH: concentration is 0.1 mol/dm³, and volume is 25.0 cm³ = 25.0 ÷ 1000 = 0.025 dm³. \#\#\# Step 3: Calculate Moles of NaOH Now, calculate the number of moles of NaOH: Moles of NaOH = 0.1 mol/dm³ × 0.025 dm³ = 0.0025 mol Since it's a 1:1 reaction, the moles of HCl are also 0.0025 mol. \#\#\# Step 4: Calculate the Concentration of HCl Now use the moles of HCl and the volume of the HCl solution to find the concentration of HCl. Rearrange the moles formula to solve for concentration: Concentration = Moles ÷ Volume (dm³) The volume of HCl is 20.0 cm³ = 20.0 ÷ 1000 = 0.020 dm³. Concentration of HCl = 0.0025 mol ÷ 0.020 dm³ = 0.125 mol/dm³ \#\#\# Final Answer: The concentration of the HCl solution is \*\*0.125 mol/dm³\*\*. \-\-- This should work for you in Google Docs!