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## Question 16 In the figure, $ABCD$ is a rectangle. $E$ is a point on $AB$ such that $AE : EB = 1 : 4$. $F$ is a point such that $CEDF$ is a parallelogram. $BF$ cuts $CE$ and $CD$ at $G$ and $H$ respectively. If the area of $\triangle BEG$ is $320 cm^2$, then the area of $\triangle DFH$ is A. $40...

## Question 16 In the figure, $ABCD$ is a rectangle. $E$ is a point on $AB$ such that $AE : EB = 1 : 4$. $F$ is a point such that $CEDF$ is a parallelogram. $BF$ cuts $CE$ and $CD$ at $G$ and $H$ respectively. If the area of $\triangle BEG$ is $320 cm^2$, then the area of $\triangle DFH$ is A. $405 cm^2$ B. $500 cm^2$ C. $605 cm^2$ D. $720 cm^2$ **Diagram Description**: The image displays a rectangle, labeled $ABCD$. * Point $E$ is on side $AB$. * The line segments $CE$ and $DF$ connect opposite corners. * Their intersection points are not explicitly noted. * Line segment $BF$ intersects $CE$ at point $G$ and $CD$ at point $H$. * A triangle is formed $\triangle BEG$ * Another larger triangle is formed $\triangle DFH$