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(1) If the middle term in the expansion of: $(\frac{2a}{3} + \frac{b}{a^2})^{8n}$ is the ninth term, then n = _______. - (a) 1 - (b) 2 - (c) 3 - (d) 4 $T\frac{8n + 2}{2} = T_{4n + 1} = T_9$ $4n + 1 = 9$ $4n = 8$ $n = 2$
(1) If the middle term in the expansion of: $(\frac{2a}{3} + \frac{b}{a^2})^{8n}$ is the ninth term, then n = _______. - (a) 1 - (b) 2 - (c) 3 - (d) 4 $T\frac{8n + 2}{2} = T_{4n + 1} = T_9$ $4n + 1 = 9$ $4n = 8$ $n = 2$