JEE MAIN GRAND TEST PDF 2025

Sri Chaitanya IIT Academy.,India.  A.P  T.S  KARNATAKA  TAMILNADU  MAHARASTRA  DELHI  RANCHI A right Choice for the Real Aspirant ICON Central Office - Madhapur - Hyderabad SEC: Sr.S60_Elite, Target & LIIT-BT...

Sri Chaitanya IIT Academy.,India.  A.P  T.S  KARNATAKA  TAMILNADU  MAHARASTRA  DELHI  RANCHI A right Choice for the Real Aspirant ICON Central Office - Madhapur - Hyderabad SEC: Sr.S60_Elite, Target & LIIT-BTs JEE-MAIN Date: 19-01-2025 Time: 09.00Am to 12.00Pm GTM-19/14 Max. Marks: 300 IMPORTANT INSTRUCTION: 1. Immediately fill in the Admission number on this page of the Test Booklet with Blue/Black Ball Point Pen only. 2. The candidates should not write their Admission Number anywhere (except in the specified space) on the Test Booklet/ Answer Sheet.! 3. The test is of 3 hours duration. 4. The Test Booklet consists of 75 Questions. The maximum marks are 300. 5. There are three parts in the question paper 1,2,3 consisting of Mathematics, Physics and Chemistry having 25 Questions in each subject and subject having two sections. (I) Section –I contains 20 Multiple Choice Questions with only one correct option. Marking scheme: +4 for correct answer, 0 if not attempt and -1 in all other cases. (II) Section-II contains 05 Numerical Value Type Questions. ∎ The Answer should be within 0 to 9999. If the Answer is in Decimal then round off to the Nearest Integer value (Example i,e. If answer is above 10 and less than 10.5 round off is 10 and If answer is from 10.5 and less than 11 round off is 11). To cancel any attempted question bubble on the question number box. For example: To cancel attempted Question 21. Bubble on 21 as shown belo w  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P. Question Answered for Marking Question Cancelled for Marking Marking scheme: +4 for correct answer, 0 if not attempt and -1 in all other cases. 6. Use Blue / Black Point Pen only for writing particulars / marking responses on the Answer Sheet. Use of pencil is strictly prohibited. 7. No candidate is allowed to carry any textual material, printed or written, bits of papers, mobile phone any electron device etc, except the Identity Card inside the examination hall. 8. Rough work is to be done on the space provided for this purpose in the Test Booklet only. 9. On completion of the test, the candidate must hand over the Answer Sheet to the invigilator on duty in the Hall. However, the candidate are allowed to take away this Test Booklet with them. 10. Do not fold of make any stray marks on the Answer Sheet Name of the Candidate (in Capital): ________________________________________________ Admission Number: Candidate’s Signature:________________ Invigilator’s Signature: ________________ 19-01-2025_Sr.S60_Elite, Target & LIIT-BTs_Jee-Main-GTM-19/14_Test Syllabus MATHEMATICS : TOTAL SYLLABUS PHYSICS : TOTAL SYLLABUS CHEMISTRY : TOTAL SYLLABUS Sec: Sr.S60_Elite, Target & LIIT-BTs Page 2  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P MATHEMATICS Max Marks: 100 SECTION-I (SINGLE CORRECT ANSWER TYPE) This section contains 20 Multiple Choice Questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and –1 in all other cases. 1. Let f(x) = x and g(x) = x be two functions defined over the set of non- negative real m numbers. The point wise multiplication of these functions is of the form a where m, n xn are two prime numbers. Then a  m  n  1) 3 2) 6 3) 5 4) 4 2. Let A = {1, 2, 3}. Then number of relations containing (2, 1) and (2, 3) which are reflexive and symmetric but not transitive is 1) 1 2) 2 3) 3 4) 4  x , x2  1 3 3. Let f  x    then the domain of f 1 (x ) is______  x, x 1 2 1) R-{1} 2) R-{-1,1} 3) R - {±1, 0} 4) R - {- 1} 4. STATEMENT –1: A bag contains 51 coins. It is known that 20 of these have head on both sides whereas the remaining 31 coins are fair. A coin is picked up at random from the bag and tossed. The probability that the toss results is a head is 71/102. STATEMENT–2: Let {Ei} i = 1, 2,... n, be n events such that Ei  E j   for i  j & n  Ei  S ( S isthe sample space). i 1 Suppose P  Ei   0 for1  i  n , then for any event A of the sample space, n P  A    P ( Ei ) P ( A / Ei ) i 1 1) Statement–1 is True, Statement–2 is True 2) Statement–1 is False, Statement–2 is False 3) Statement–1 is True, Statement–2 is False 4) Statement –1 is False, statement–2 is True. Sec: Sr.S60_Elite, Target & LIIT-BTs Page 3  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 5. tan  + 2 tan 2 + 4 tan 4 + 8 cot 8 = _______ 1) - tan  2) cot  3) tan  4) - cot  6. Match the following Column I Column II a  f  x  2 sec x (A)   sec x  tan x  2 dx   b  a  f  x  2  C then a  b  (P) 5  4 0  tan 6  x   x   tan  x   x   dx  4 (B) 25 (Q) 3 x x (C) If  1  2 tan x (tan x  sec x ) dx = a log cos  sin  c 2 2 (R) 2 then a is equal to (0  x   / 2) 3 2  1 x 1 x  1  2  1  (D)  tan  tan  dx  (S) 2 x2  1 x  1) A Q, B P, C R, D S 2) A Q, B P, C S , D R 3) A Q, B P, C R, D R 4) A Q, B R, C P, D S 7. Solution of the differential equation 2 2  dy  x y  dy  x  1   xy   2     xy   dy 3 3 ............... is  dx  2!  dx  3!  dx  1) y  ln(x)  C 2) y  (ln x)2  C 3) y   (ln x)2  C 4) y 2 = ln x + c 2 a 8.  2 a f ( x)dx is equal to (where f (2 – ) = f (2 + )    R) 2 a a 2 1) 2  f(x)dx 2 2) 2  f(x)dx 0 3) 2  f(x)dx 0 4) 0 x x 9. The maximum value of 4Sin 2 x + 3 cos2x + sin  cos is 2 2 1) 4 + 2 2) 3 + 2 3) 9 4) 4 10. If n1 , n2 are the sizes, x1, x 2 the means and  1,  2 the standard deviations of two series, then the combined variance of these two series is Sec: Sr.S60_Elite, Target & LIIT-BTs Page 4  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 1 1)  2  [ n1 ( 12  d12 )  n2 ( 22  d 22 )] where d1  x1  x , d 2  x2  x and n1  n2 n x  n2 x2 x 11 n1  n2 1 2)  2  [ n1 ( 12  d12 )  n2 ( 22  d 22 )] , where d1  x1  x , d 2  x2  x and n1  n2 n1x1  n2 x2 x n1  n2 1  2 n1n2  3)  2  2  n1 1  n2 2  ( x1  x2 )2  n1  n2  n1  n2  1  n1n2  4) 2  2 2  n1 1  n2 2  ( x1  x2 ) 2  n1  n2  n1  n2      2 11. If a  4, b  5, a  b  10 then.b =___________ a 1) 30 2) 10 3 3) 300 4) 3 10 x 3 y 8 z 3 x3 y7 z6 12. The shortest distance between the lines   and   3 1 1 3 2 4 1) 30 2) 2 30 3) 5 30 4) 3 30 13. The remainder when 599 is divided by 13 is 1) 6 2) 8 3) 9 4) 10 14. The number of real solutions of 3x 7 + 4 x3 + 9 x + 109 = 0 is 1) 3 2) 1 3) 4 4) 5 15. The sum of the common terms of the following two arithmetic progressions 3, 7, 11, 15,………., 399 AND 2, 5, 8, 11, ………., 359 is equal to _______ 1) 5550 2) 6699 3) 9100 4) 11396 x2 y2 16. If   1 represents an ellipse with major axis as y-axis and f is a decreasing f(4a) f  a2  5  function, then 1) a  (–, 1) 2) a  (5, ) 3) a  (1, 4) 4) a (–1, 5) Sec: Sr.S60_Elite, Target & LIIT-BTs Page 5  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 17. The foci of an ellipse coincide with the vertices of a hyperbola and vertices of the ellipse coincide with the foci of the hyperbola. If e1, e2 are their eccentricities then 1) e12 + e22 = 1 2) e12  e22 = e12 e22 3) e1  e2  2 4) e1e2  1 18. The diagonals of a rhombus ABCD intersect at the point (1, 2) and its sides are parallel to the lines x – 3y  2 3 = 0 and 3 x – y + 3 = 0. Then the equations of the diagonals are 1) y = x + 1, y = - x - 3 2) y = x - 1, y = x + 3 3) y = x + 1, y = - x + 3 4) y = x - 1, y = - x + 3 19. If sin 1  sin 6   tan 1  tan12  = _________ 1) 18 2) 6  18 3) 18  4 4) 18  6 4 2  20. Let A   .If A2   A  18 I  0, then A    1) 18 2) 18 3) 50 4) 50 SECTION-II (NUMERICAL VALUE TYPE) This section contains 5 Numerical Value Type Questions. The Answer should be within 0 to 9999. If the Answer is in Decimal then round off to the Nearest Integer value (Example i,e. If answer is above 10 and less than 10.5 round off is 10 and If answer is from 10.5 and less than 11 round off is 11). Marking scheme: +4 for correct answer, 0 if not attempt and -1 in all other cases. 21. If Z lies on Z  2  i  5 , then sum of the maximum and minimum values of Z  14  6i is Let  ,      be the roots of the quadratic equation x  2x  5  0. If 2 22. n n P15 P16  2 P14 P16  2P152  4 P14 P15 Pn     , n  N , then is equal to _______. P13 P14 23. All the letters A,A,A,B,N,N, are arranged in all possible ways and the words are arranged in serial order as in English dictionary. Then serial number of the word BANANA is _______  2 x  1 , x  0 24. If f  x    2 then the number of points where the function f(|x|) is not  2 x  4 x, x  0 differentiable is______ 25. If a is an integer lying in the closed interval [- 5 ,30], then the probability that the graph of 2 y  x2  2  a  4 x  5a  64. is strictly above the x-axis is , where m is  m  2 Sec: Sr.S60_Elite, Target & LIIT-BTs Page 6  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P PHYSICS Max Marks: 100 SECTION-I (SINGLE CORRECT ANSWER TYPE) This section contains 20 Multiple Choice Questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and –1 in all other cases. 26. The magnitude of charge in steady state on either of the plates of condenser C in the adjoining circuit is CER 2 CER 2 CER1 1) CE 2) 3) 4) (R1 + r ) (R 2 + r ) (R 2 + r ) 27. A small block slides down from top of hemisphere of radius R=3m as show in figure. The speed of ball when it leaves surface is_____(hemisphere is fixed and is smooth)  R gR 2 5 1) gR 2) 3) gR 4) gR 3 3 3 28. Four particles each of mass M move along a circle of radius R symmetrically, under action of their mutual gravitational attraction. The time period of each 3 3 3 3 4 R 4 R 1) 2 R 4) 4 R 2 2 2 2 2) 3) GM  GM 2 2  1   GM 2 2  1  GM Sec: Sr.S60_Elite, Target & LIIT-BTs Page 7  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 29. Consider the nuclear fission reaction W→X + Y. What is the Q-value (energy released) of the reaction? 1) E1N1 -(E2N2  E3N3 ) 2) E2 N2  E1N1 - E3 N3 3) (E2 N2  E3N3 - E1N1) 4) E1N1  E3N3 - E2 N2 30. A uniform solid cylinder of mass m and radius R is placed on a rough horizontal surface. a horizontal constant force F is applied at the top point P of the cylinder so that it starts pure rolling. The acceleration of the cylinder is 1) F/3m 2) 4F/3m 3) 2F/3m 4) 5F/3m 31. For two thermodynamic process temperature and volume diagram are given. In first process, it is a straight line having initial and final coordinates as (V0, T0) and (2V0, 2T0), where as in second process it is a rectangular hyperbola having initial and final coordinates (V 0, T0) and (2V0, T0/2). Then ratio of work done (W1:W2) in the two processes must be Sec: Sr.S60_Elite, Target & LIIT-BTs Page 8  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 1) 1: 2 2) 2:1 3) 1:1 4) None of these 32. The magnetic field at the origin due to the current flowing in the wire is 0 I ˆ ˆ 0 I ˆ ˆ 0 I ˆ ˆ 1)  8 a  i k  2) 2 a  i k  3) 8 a  i  k  4)  0 I ˆ ˆ 4 a 2 i k   33. An alternating current is given by i = i1 cost + i2 sint. The rms current is given by i1  i2 i1  i2 i12  i22 i12  i22 1) 2) 3) 4) 2 2 2 2 Sec: Sr.S60_Elite, Target & LIIT-BTs Page 9  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 34. The output Y of following circuit for given input is  1) A. B 2) 0 3) A.B (A+B) 4) A.B 35. Assertion: In a pressure cooker, the water is brought to boil. The cooker is then removed from the stove. Now on removing the lid of the pressure cooker, the water starts boiling again. Reason: The impurities in water bring down its boiling point. 1) Both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion. 2) Both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion. 3) The Assertion is correct but Reason is incorrect. 4) Both the Assertion and Reason are incorrect. 36. Figure shows a part of circuit. Find the magnitude of rate of change of the current (in A/s). 1) 0.6 2) 1.4 3) 2.6 4) 3.6 Sec: Sr.S60_Elite, Target & LIIT-BTs Page 10  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 37. Statement – 1: Newton’s equation for speed of sound in air was found wrong because, he assumed process as isothermal Statement – 2: Flow of sound wave in a medium is very fast. Quick process suppress heat exchange, hence this process must be adiabatic in nature. 1) Statement – 1 is true, Statement – 2 is true; Statement – 2 is a correct explanation for Statement – 1 2) Statement – 1 is true, Statement – 2 is true; Statement – 2 is not a correct explanation for Statement – 1 3) Statement – 1 is true, Statement – 2 is false 4) Statement – 1 is false, Statement – 2 is true 38. Statement –I:- If the Brewster’s angle for the light, propagating from air to glass is  , then  Brewster’s angle for the light propagating from glass to air is . 2 Statement –II: - The Brewster’s angle for the light propagating from glass to air is tan  1   g  Where g m is the refractive index of glass. In the light of above statements, choose the correct answer from the options given below; 1) Both Statement I and II are true 2) Statement I is true but Statement II is false 3) Both statements I and II are false 4) Statement I is false but statement II is true Sec: Sr.S60_Elite, Target & LIIT-BTs Page 11  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 39. Matching Column I Column II (A) Graph of kinetic energy (on y-axis) (p) with momentum (on x-axis) (B) Graph of square root of kinetic energy (q) (on y-axis) with momentum (on x- axis) (C) Graph of square root of kinetic energy (r) with (1/momentum) (on x-axis) (D) Graph of kinetic energy with velocity (s) by (on x axis) 1) A -p, B-q, C -r, D-p 2) A- s, B- q,C- r, D- s 3) A- r, B- q, C- r, D - s 4) A- s, B- q,C- q, D -s 40. The reading of voltmeter is 1) 50V 2) 60V 3) 40V 4) 80V Sec: Sr.S60_Elite, Target & LIIT-BTs Page 12  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 41. Two particles X and Y having equal charges, after being accelerated through the same potential difference, enter a region of uniform magnetic field and describe circular paths of radii R1 and R2 respectively. The ratio of the masses of X to that of Y 1 2  R1  2 R R  R 1)   2) 2 3)  1  4) 1  R2  R1  R2  R2 42. A spherical insulator of radius R is charged uniformly with a charge Q throughout its volume and contains a point charge Q/4 located at its centre. Which of the following graphs best represents qualitatively, the variation of electric field intensity E with distance r from center? 1) 2) 3) 4) 43. Calculate equivalent resistance of two resistors R1 and R2 in parallel where, R1 = (6±0.2) ohm and R2 =(3±0.1) ohm 1) 2±0.07 2) 2±0.02 3) 2±0.09 4) 2 ± 0.01 44. Assertion: In displacement method of finding focal length of a convex lens its magnification in one position of lens is +2, then magnification in another position of lens should be 1 2 Reason: This method can’t be applied for a concave Lens 1) If both Assertion and Reason are true and the Reason is correct explanation of the Assertion. 2) If both Assertion and Reason are true but Reason is not the correct explanation of Assertion. 3) If Assertion is true, but the Reason is false. 4) If Assertion is false but the Reason is true. Sec: Sr.S60_Elite, Target & LIIT-BTs Page 13  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 45. Four massless springs whose force constants are 2k, 2k, k and 2k respectively are attached to a mass M kept on a frictionless plane (as shown in figure). If the mass M is displaced in the horizontal direction, then the frequency of the system. 1 k 1 4k 1 k 1 7k 1) 2) 3) 4) 2 4M 2 M 2 7M 2 M SECTION-II (NUMERICAL VALUE TYPE) This section contains 5 Numerical Value Type Questions. The Answer should be within 0 to 9999. If the Answer is in Decimal then round off to the Nearest Integer value (Example i,e. If answer is above 10 and less than 10.5 round off is 10 and If answer is from 10.5 and less than 11 round off is 11). Marking scheme: +4 for correct answer, 0 if not attempt and -1 in all other cases 46. A block of 3 kg is attached to a string whose other end is attached to the wall A force F is applied so that string makes an angle  0 with wall find  in degree if tension T is 20N 47. Temperature difference of 1200c is maintained between two ends of a uniform rod AB of 3L length 2L another bent rod SPQR of same cross section as AB and length is 2 connected a cross as shown find temperature difference between PQ in degree Celsius. Sec: Sr.S60_Elite, Target & LIIT-BTs Page 14  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 48. A particle of mass 2 m is projected at an angle of 45° with horizontal with a velocity of 20√2 m/s. After 1 s, explosion takes place and the particle is broken into two equal pieces. As a result of explosion one part comes to rest. Find the maximum height attained by the other part. (Take g= 10 m/s2) 49. The given Wheatstone bridge is showing no deflection in the galvanometer joined between the points B and D (Figure). Calculate the value of R. 50. A particle of mass m moves in a circular orbit in a central potential field  r   0 r 4 1  Bohr's quantisation conditions are applied, radii of possible orbitals rn vary with n , where  is Sec: Sr.S60_Elite, Target & LIIT-BTs Page 15  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P CHEMISTRY Max Marks: 100 SECTION-I (SINGLE CORRECT ANSWER TYPE) This section contains 20 Multiple Choice Questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and –1 in all other cases. 51. What is the molarity of 4.9% H3PO4 solution by mass (density of H3PO4 = 1.22 g/ml)? 1) 0.61 M 2) 4.9 M 3) 1.22 M 4) 1 M 52. STATEMENT-1: First I.E (Ionisation enthalpy) of helium is maximum in periodic table STATEMENT-2: Helium has its electronic configuration 1s2 it is fully filled extra stable configuration and helium has very small size and high nuclear attraction for electrons 1) statement I & II both are correct and statement II is Correct explanation for statement I 2) statement I & II both are correct, but statement II is not Correct explanation of statement I 3) statement I is correct but statement II is incorrect 4) statement I & II both are incorrect 53. STATEMENT-1: Entropy of egg increases after boiling. STATEMENT-2: As boiling causes the denaturation of proteins. 1) statement I & II both are correct and statement II is Correct explanation for statement I 2) statement I&II both are correct, but statement II is not Correct explanation for statement I 3) statement I is correct but statement II is incorrect 4) statement I & II both are incorrect 54. Which of the following is the most reactive? 1) I2 2) BrCl 3) Br2 4) Cl2 55. ASSERTION(A): It is difficult to distinguish between the strengths of the strong acids like HCl , HNO3 , HClO4 etc. in dilute aqueous solution. REASON(R): In dilute aqueous solution, all strong acids donate a proton to water and are essentially 100% ionised to produce a solution containing H 3O  ions the anions of strong acid. Sec: Sr.S60_Elite, Target & LIIT-BTs Page 16  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 1) Both assertion(A) and reason (R) are Correct, and reason (R) is the correct explanation of (A) 2)Both assertion (A) and reason (R) are Correct but reason (R) is not Correct explanation of (A) 3) Assertion (A) is correct but reason (R) is incorrect 4) Assertion (A) and reason (R) both are incorrect 56. Photoelectric effect can be represented as (v = frequency K.E = Kineticenergy ) v v KE KE 1) 2) v v KE KE 3) 4) 57. Which of the following shows geometrical isomerism CH 2 CHBr CHCl CHBr Cl C2 H 5 1) 2) 3) 4) Sec: Sr.S60_Elite, Target & LIIT-BTs Page 17  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 58. Br H O 2 Major product 'A'is  NaOH  OH 1) 2) OH OH OH 3) 4) 59. In the given reaction identify the product – (P) O C  OH  2  ii  H 2O / Red P  P  i Br  O O C  OH CH 1) Br 2) Br O O C  OH C  Br Br 3) 4) Sec: Sr.S60_Elite, Target & LIIT-BTs Page 18  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 3 60. The number of stereo isomers possible in Co en 2  NH3  2  is  en  Ethane  1, 2  diamine 1) 3 2) 4 3) 5 4) 2 61. Match the following Column-I Column-II A) Number of carbon atoms in 1 g molecule of CO2 (P) 0.5 N0 B) Number of molecules in 48 g O2 (q) N0 C) No. of molecules in 11.2 L H2 at STP (r) 3 N0 D) No. of hydrogen atoms in 1 Mole of NH3 (s) 1.5 N0 (N0=Avogadro's Number) 1) A(q),B(s),C(p),D(r) 2) A(q),B(r),C(s),D(p) 3) A(r),B(p),C(s),D(q) 4) A(p),B(r),C(s),D(r) 62. How many nodal planes are present in 4d 2 ? z 1) 2 2) 1 3) Zero 4) 3 63. Correct order of bond angle for I. NO2 II. NO2 III. NO3 IV. CH4 1) I>II>III>IV 2) IV>III>II>I 3) II>III>I>IV 4) III>II>IV>I 64. ASSERTION(A): Ionization energy of s-electrons are more than the p-electrons for the same shell. REASON(R): s-electrons are closer to the nucleus than p-electrons, hence, more tightly attached. 1) Both assertion(A) and reason (R) are Correct, and reason (R) is the correct explanation of (A) 2) Both assertion (A) and reason (R) are Correct but reason (R) is not Correct explanation of (A) 3) Assertion (A) is correct but reason (R) is incorrect 4) Assertion (A) and reason (R) both are incorrect M M 65. Equivalent weight of Potash alum is 1 and equivalent weight of gypsum is 2 , Then x y x  y will be 1) 6 2) 4 3) 5 4) 8 Sec: Sr.S60_Elite, Target & LIIT-BTs Page 19  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 66. Most acidic species among the following is 1) BF3 2) BI 3 3) BCl3 4) BBr3 67. Most stable and least stable species respectively among the following are CH 2  CH  CH 2 CH 3  CH 2 CH 2  CH CH 3 II III IV I 1) II and I 2) IV and II 3) III and II 4) II and IV 68. Point out ’A’ in the given reaction sequence Cl / light A 2 NaOH /  B Benzoic acid 1) Phenol 2) Benzene 3) Toluene 4) Chlorobenzene 69. N 2Cl   A  NaOH Product  P  Orange dye  The degree of unsaturation of A is 1) 5 2) 4 3) 6 4) 8 E   a  70. Arrhenius equation is given as K  Ae  RT  , here A is called as 1) Pre-exponential factor 2) Frequency factor 3) Arrhenius constant 4) All of the above SECTION-II (NUMERICAL VALUE TYPE) This section contains 5 Numerical Value Type Questions. The Answer should be within 0 to 9999. If the Answer is in Decimal then round off to the Nearest Integer value (Example i,e. If answer is above 10 and less than 10.5 round off is 10 and If answer is from 10.5 and less than 11 round off is 11). Marking scheme: +4 for correct answer, 0 if not attempt and -1 in all other cases Sec: Sr.S60_Elite, Target & LIIT-BTs Page 20  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P 71. What is screening constant for outer electron of H(Hydrogen atom) ? 72. When a system is taken from A to C through path ABC, 10J of heat flows to the system and 4J of work is done by the system. B C A D How much heat flows into the system in path ADC(Joule), if the work done by the system is 3J? 73. The basicity of H 3 PO4 is 74. The number of 4f electrons in the ground state electronic configuration of Gd ( Z  64) is _____. 75. How many lone pairs are there in the most stable structure of perchloric acid. Sec: Sr.S60_Elite, Target & LIIT-BTs Page 21  SRI CHAITANYA IIT ACADEMY, INDIA 19-01-25_ Sr.S60_Elite, Target & LIIT-BTs _Jee-Main_GTM-19/14_Q.P Sec: Sr.S60_Elite, Target & LIIT-BTs Page 22