Edexcel GCSE Chemistry Atomic Structure Notes PDF

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University Hospitals of Leicester

Edexcel

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atomic structure chemistry gcse chemistry science

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These notes cover atomic structure, including the Dalton, Thomson, and Rutherford models. It details the concepts and explains how the discovery of subatomic particles changed our understanding of atoms. Key concepts like isotopes and their effect on the relative atomic mass are included.

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Edexcel​ ​GCSE​ ​Chemistry Topic​ ​1:Key​ ​concepts​ ​in​ ​chemistry Atomic​ ​Structure Notes www.pmt.education 1.1 Describe​ ​how​ ​the​ ​Dalton​ ​model​ ​of​ ​an​ ​atom​ ​has​ ​changed​ ​over​ ​time because​ ​of​ ​the​ ​disc...

Edexcel​ ​GCSE​ ​Chemistry Topic​ ​1:Key​ ​concepts​ ​in​ ​chemistry Atomic​ ​Structure Notes www.pmt.education 1.1 Describe​ ​how​ ​the​ ​Dalton​ ​model​ ​of​ ​an​ ​atom​ ​has​ ​changed​ ​over​ ​time because​ ​of​ ​the​ ​discovery​ ​of​ ​subatomic​ ​particles John​ ​Dalton​ ​(1803) : He​ ​published​ ​his​ ​own​ ​three-part​ ​atomic​ ​theory: 1. All​ ​substances​ ​are​ ​made​ ​of​ ​atoms.​ ​Atoms​ ​are​ ​small​ ​particles​ ​that​ ​cannot be​ ​created,​ ​divided,​ ​or​ ​destroyed.​ ​ 2. Atoms​ ​of​ ​the​ ​same​ ​element​ ​are​ ​exactly​ ​alike,​ ​and​ ​atoms​ ​of​ ​different elements​ ​are​ ​different.​ ​ 3. Atoms​ ​join​ ​with​ ​other​ ​atoms​ ​to​ ​make​ ​new​ ​substances.​ ​ Much​ ​of​ ​Dalton’s​ ​theory​ ​was​ ​correct,​ ​but​ ​some​ ​of​ ​it​ ​was​ ​later​ ​proven​ ​incorrect and​ ​revised​ ​as​ ​scientists​ ​learned​ ​more​ ​about​ ​atoms. J.J.​ ​Thomson​ ​(1897) : Used​ ​a​ ​cathode-ray​ ​tube​ ​to​ ​conduct​ ​an​ ​experiment This​ ​discovery​ ​identified​ ​an​ ​error​ ​in​ ​Dalton’s​ ​atomic​ ​theory.​ ​Atoms​ ​can​ ​be divided​ ​into​ ​smaller​ ​parts. Because​ ​the​ ​beam​ ​moved​ ​away​ ​from​ ​the​ ​negatively​ ​charged​ ​plate​ ​and​ ​toward the​ ​positively​ ​charged​ ​plate,​ ​Thomson​ ​knew​ ​that​ ​the​ ​particles​ ​must​ ​have​ ​a negative​ ​charge. Thomson​ ​proposed​ ​a​ ​model​ ​of​ ​an​ ​atom​ ​called​ ​the​ ​“plum-pudding”​ ​model,​ ​in which​ ​negative​ ​electrons​ ​are​ ​scattered​ ​throughout​ ​soft​ ​blobs​ ​of​ ​positively charged​ ​material. Ernest​ ​Rutherford​ ​(1909) : Shot​ ​a​ ​beam​ ​of​ ​positively​ ​charged​ ​particles​ ​into​ ​a​ ​sheet​ ​of​ ​gold​ ​foil. Most​ o ​ f​ ​the​ ​particles​ ​did​ ​continue​ ​in​ ​a​ ​straight​ ​line​ ​(as​ ​you​ ​would​ ​expect​ ​from plum​ ​pudding​ ​model).​ ​However​ ​some​ ​of​ ​the​ ​particles​ ​were​ ​deflected​ ​to​ ​the​ ​sides a​ ​bit,​ ​and​ ​a​ ​few​ ​bounced​ ​straight​ ​back. Rutherford​ ​developed​ ​a​ ​new​ ​model​ ​which​ ​said​ ​that​ ​most​ ​of​ ​the​ ​atom’s​ ​mass​ ​is found​ ​in​ ​a​ ​region​ ​in​ ​the​ ​center​ ​called​ ​the​ ​nucleus. In​ ​Rutherford’s​ ​model​ ​the​ ​atom​ ​is​ ​mostly​ ​empty​ ​space,​ ​and​ ​the​ ​electrons​ ​travel in​ ​random​ ​paths​ ​around​ ​the​ ​nucleus. 1.2 Describe​ ​the​ ​structure​ ​of​ ​an​ ​atom​ ​as​ ​a​ ​nucleus​ ​containing​ ​protons and​ ​neutrons,​ ​surrounded​ ​by​ ​electrons​ ​in​ ​shells www.pmt.education 1.3 Recall​ ​the​ ​relative​ ​charge​ ​and​ ​relative​ ​mass​ ​of​ ​protons,​ ​neutrons​ ​and electrons particle relative​ ​charge relative​ ​mass proton +1 1 neutron 0 1 electron -1 1/1836 1.4 Explain​ ​why​ ​atoms​ ​contain​ ​equal​ ​number​ ​of​ ​protons​ ​and​ ​electrons Atoms​ ​are​ ​neutral​ ​and​ ​the​ ​charges​ ​on​ ​a​ ​proton​ ​are​ ​+1​ ​and​ ​on​ ​an​ ​electron​ ​are​ ​-1 therefore​ ​amount​ ​of​ ​protons​ ​=​ ​amount​ ​of​ ​electrons,​ ​so​ ​that​ ​the​ ​charges​ ​cancel 1.5 Describe​ ​the​ ​nucleus​ ​of​ ​an​ ​atom​ ​as​ ​a​ ​very​ ​small​ ​compared​ ​to​ ​the overall​ ​size​ ​of​ ​the​ ​atom 1.6 Recall​ ​that​ ​most​ ​of​ ​the​ ​mass​ ​of​ ​an​ ​atom​ ​is​ ​concentrated​ ​in​ ​the nucleus 1.7 Recall​ ​the​ ​meaning​ ​of​ ​the​ ​term​ ​mass​ ​number​ ​of​ ​an​ ​atom Mass​ ​(nucleon)​ ​Number​ ​=​ ​number​ ​of​ ​protons​ ​+​ ​neutrons 1.8 Describe​ ​atoms​ ​of​ ​a​ ​given​ ​element​ ​as​ ​having​ ​the​ ​same​ ​number​ ​of protons​ ​in​ ​the​ ​nucleus​ ​and​ ​that​ ​this​ ​number​ ​is​ ​unique​ ​to​ ​that​ ​element 1.9 Describe​ ​isotopes​ ​as​ ​different​ ​atoms​ ​of​ ​the​ ​same​ ​element​ ​containing the​ ​same​ ​number​ ​of​ ​protons​ ​but​ ​different​ ​numbers​ ​of​ ​neutrons​ ​in their​ ​nuclei 1.10 Calculate​ ​the​ ​numbers​ ​of​ ​protons,​ ​neutrons​ ​and​ ​electrons​ ​in​ ​atoms given​ ​the​ ​atomic​ ​number​ ​and​ ​mass​ ​number Atomic​ ​(proton)​ ​Number​ ​=​ ​number​ ​of​ ​protons​ ​(=​ ​number​ ​of​ ​electrons​ ​if​ ​it’s​ ​an atom,​ ​because​ ​atoms​ ​are​ ​neutral) therefore,​ ​you​ ​can​ ​calculate​ ​number​ ​of​ ​neutrons​ ​by​ ​doing​ ​mass​ ​number​ ​§ atomic​ ​number 1.11 Explain​ ​how​ ​the​ ​existence​ ​of​ ​isotopes​ ​results​ ​in​ ​relative​ ​atomic masses​ ​of​ ​some​ ​elements​ ​not​ ​being​ ​whole​ ​numbers because​ ​isotopes​ ​have​ ​the​ ​same​ ​number​ ​of​ ​protons​ ​but​ ​different​ ​numbers​ o ​ f neutrons,​ ​they​ ​are​ ​still​ ​atoms​ ​of​ ​the​ ​same​ ​element,​ ​but​ ​they​ ​have​ ​different atomic​ ​masses the​ ​relative​ ​atomic​ ​mass​ ​is​ ​calculated​ ​using​ ​the​ ​abundance​ ​of​ ​different​ ​isotopes and​ ​because​ ​it​ ​is​ ​an​ ​average​ ​it​ ​can​ ​lead​ ​to​ ​the​ ​relative​ ​atomic​ ​mass​ ​not​ ​being​ a​ whole​ ​number​ ​(atomic​ ​number​ ​and​ ​mass​ ​number​ ​will​ ​always​ ​be​ ​whole​ ​numbers- they​ ​are​ ​not​ ​averages) since​ ​the​ ​mass​ ​of​ ​atoms​ ​is​ ​so​ ​small,​ ​we​ ​compare​ ​their​ ​masses​ ​to​ ​each​ ​other.​ ​A carbon​ ​atom​ ​having​ ​a​ ​mass​ ​number​ ​12,​ ​i.e.​ ​(​12​C)​ ​is​ ​taken​ ​as​ ​standard​ ​for​ t​ his comparison​ ​and​ ​its​ ​relative​ ​atomic​ ​mass​ ​is​ ​12. It​ ​is​ ​written​ ​as​ ​Ar​ ​ ​or​ ​R.A.M.​. 1.12 (higher​ ​tier)​ ​Calculate​ ​the​ ​relative​ ​atomic​ ​mass​ ​of​ ​an​ ​element​ ​from the​ ​relative​ ​masses​ ​and​ ​abundances​ ​of​ ​its​ ​isotopes A​ ​sample​ ​of​ ​chlorine​ ​gas​ ​is​ ​a​ ​mixture​ ​of​ ​2​ ​isotopes, chlorine-35​ ​and​ ​chlorine-37.​ ​These​ ​isotopes​ ​occur​ ​in specific​ ​proportions​ ​in​ ​the​ ​sample​ ​i.e.​ ​75%​ ​chlorine-35 and​ ​25%​ ​chlorine-37.​ ​Calculate​ ​the​ ​R.A.M.​ ​of​ ​chlorine​ ​in the​ ​sample. The​ ​average​ ​mass,​ ​or​ ​R.A.M.​ ​of​ ​chlorine​ ​can​ ​be​ ​calculated using​ ​the​ ​following​ ​equation: ​ ​ ​(mass​ ​of​ ​isotope-A ​ ​x ​ ​%​ ​of​ ​isotope-A)​ ​+​ ​(mass​ ​of​ ​isotope-B​ ​ x ​ ​%​ ​of​ ​isotope-B) R.A.M. = ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​100 (35​ ​x​ ​75)​ ​+​ ​(37​ ​x​ ​25) ​ ​ ​= ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ ​100 3550 = 100 R.A.M. = 35.5 www.pmt.education

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