y = (4x² - 16) / (2x + 9)
Understand the Problem
The question presents a mathematical function in the form of a rational expression. It requires analyzing or simplistically solving for the variable y based on the provided equation.
Answer
The rational function is \( y = \frac{(2x - 4)(2x + 4)}{2x + 9} \).
Answer for screen readers
The function is ( y = \frac{(2x - 4)(2x + 4)}{2x + 9} ).
Steps to Solve
- Identify the numerator and denominator
The function given is ( y = \frac{4x^2 - 16}{2x + 9} ). The numerator is ( 4x^2 - 16 ) and the denominator is ( 2x + 9 ).
- Factor the numerator
We notice that the numerator ( 4x^2 - 16 ) can be factored as a difference of squares: $$ 4x^2 - 16 = (2x - 4)(2x + 4) $$
- Rewrite the function
Substituting the factored form into the function gives: $$ y = \frac{(2x - 4)(2x + 4)}{2x + 9} $$
- Simplifying the function
Since the denominator ( 2x + 9 ) cannot be factored or canceled with the numerator, the function remains: $$ y = \frac{(2x - 4)(2x + 4)}{2x + 9} $$
- Finding the value of ( y )
To find specific values of ( y ), substitute various values for ( x ). For example, substituting ( x = 0 ): $$ y = \frac{4(0)^2 - 16}{2(0) + 9} = \frac{-16}{9} $$
The function is ( y = \frac{(2x - 4)(2x + 4)}{2x + 9} ).
More Information
This function can take on different values based on the input ( x ). The major feature of this function is that it is a rational expression, which means its behavior is determined by its polynomial numerator and denominator.
Tips
- Forgetting to factor the numerator where applicable.
- Attempting to cancel terms without ensuring they are common factors of the numerator and denominator.
- Not checking the values of ( x ) that would make the denominator zero, which makes the function undefined.
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