y = (4x² - 16) / (2x + 9)

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Understand the Problem

The question presents a mathematical function in the form of a rational expression. It requires analyzing or simplistically solving for the variable y based on the provided equation.

Answer

The rational function is \( y = \frac{(2x - 4)(2x + 4)}{2x + 9} \).
Answer for screen readers

The function is ( y = \frac{(2x - 4)(2x + 4)}{2x + 9} ).

Steps to Solve

  1. Identify the numerator and denominator

The function given is ( y = \frac{4x^2 - 16}{2x + 9} ). The numerator is ( 4x^2 - 16 ) and the denominator is ( 2x + 9 ).

  1. Factor the numerator

We notice that the numerator ( 4x^2 - 16 ) can be factored as a difference of squares: $$ 4x^2 - 16 = (2x - 4)(2x + 4) $$

  1. Rewrite the function

Substituting the factored form into the function gives: $$ y = \frac{(2x - 4)(2x + 4)}{2x + 9} $$

  1. Simplifying the function

Since the denominator ( 2x + 9 ) cannot be factored or canceled with the numerator, the function remains: $$ y = \frac{(2x - 4)(2x + 4)}{2x + 9} $$

  1. Finding the value of ( y )

To find specific values of ( y ), substitute various values for ( x ). For example, substituting ( x = 0 ): $$ y = \frac{4(0)^2 - 16}{2(0) + 9} = \frac{-16}{9} $$

The function is ( y = \frac{(2x - 4)(2x + 4)}{2x + 9} ).

More Information

This function can take on different values based on the input ( x ). The major feature of this function is that it is a rational expression, which means its behavior is determined by its polynomial numerator and denominator.

Tips

  • Forgetting to factor the numerator where applicable.
  • Attempting to cancel terms without ensuring they are common factors of the numerator and denominator.
  • Not checking the values of ( x ) that would make the denominator zero, which makes the function undefined.

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