Write a Python function to determine whether two integer values are amicable or not.

Steps to Solve

1. Define a helper function to calculate the sum of proper divisors. Create a function sum_proper_divisors(n) that calculates the sum of proper divisors of a given number n. Proper divisors are all positive divisors of n excluding n itself.

2. Iterate through potential divisors. In sum_proper_divisors(n), iterate from 1 up to n // 2 + 1. If i is a divisor of n (i.e., n % i == 0), then add i to the sum of divisors.

3. Return the sum of proper divisors. After the loop in sum_proper_divisors(n) finishes, return the calculated sum.

4. Define the main function to check for amicable numbers. Create a function are_amicable(num1, num2) that takes two numbers, num1 and num2, as input.

5. Handle edge cases. Inside are_amicable(num1, num2), check if the numbers are equal or if either number is non-positive. If any of these conditions are true, return False because amicable numbers must be distinct positive integers.

6. Calculate the sum of proper divisors for both numbers. Call sum_proper_divisors() for both num1 and num2 to get their respective sums of proper divisors. Store the results in sum1 and sum2.

   sum1 = sum_proper_divisors(num1)
   sum2 = sum_proper_divisors(num2)
   

7. Check if the sums are equal to the original numbers. Check if sum1 is equal to num2 and sum2 is equal to num1. If both conditions are true, then num1 and num2 are amicable numbers, so return True. Otherwise, return False.

   return sum1 == num2 and sum2 == num1
   

def sum_proper_divisors(n):
    """Calculates the sum of proper divisors of a number n."""
    if n <= 0:
        return 0
    sum_divisors = 0
    for i in range(1, n // 2 + 1):
        if n % i == 0:
            sum_divisors += i
    return sum_divisors

def are_amicable(num1, num2):
    """Checks if two numbers are amicable."""
    if num1 <= 0 or num2 <= 0 or num1 == num2:
        return False

    sum1 = sum_proper_divisors(num1)
    sum2 = sum_proper_divisors(num2)

    return sum1 == num2 and sum2 == num1