What is the product of the reaction between a compound containing OH and LiAlH4 in dry ether?
Understand the Problem
The question involves a chemical reaction where a compound with a hydroxyl group (OH) is being treated with lithium aluminium hydride (LiAlH4) in dry ether. The student is likely asking what the product of this reaction would be.
Answer
Diol (cyclic ester reduced to alcohol).
The compound is a lactone, and its reaction with LiAlH4 in dry ether leads to the formation of a diol, opening the cyclic structure.
Answer for screen readers
The compound is a lactone, and its reaction with LiAlH4 in dry ether leads to the formation of a diol, opening the cyclic structure.
More Information
The reaction involves a lactone, a cyclic ester, being reduced by LiAlH4, leading to the opening of the ring and conversion to two alcohol functional groups.
Tips
Assuming LiAlH4 is selective and only reduces carbonyl groups might lead to missing other functional transformations.
Sources
- Reduction of Carboxylic Acids and their derivatives - masterorganicchemistry.com
- Reductions using NaBH4, LiAlH4 - Chemistry LibreTexts - chem.libretexts.org
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