# What is the molecular mass of Na2CO3?

#### Understand the Problem

The question is asking for the molecular mass of sodium carbonate (Na2CO3). To find this, we will need to sum the atomic masses of its constituent elements: sodium (Na), carbon (C), and oxygen (O).

105.99 g/mol

The final answer is 105.99 g/mol

#### Steps to Solve

1. Find the atomic masses of each element in Na2CO3: Sodium (Na), Carbon (C), and Oxygen (O)

The atomic masses are as follows:

• Na: 22.99 g/mol
• C: 12.01 g/mol
• O: 16.00 g/mol
1. Multiply the atomic mass of each element by the number of atoms of that element in the compound

Na2CO3 contains:

• 2 atoms of Sodium (Na)
• 1 atom of Carbon (C)
• 3 atoms of Oxygen (O)
1. Calculate the total mass contributed by each element

$$2 \times 22.99 \text{ g/mol} = 45.98 \text{ g/mol}$$ (for Na) $$1 \times 12.01 \text{ g/mol} = 12.01 \text{ g/mol}$$ (for C) $$3 \times 16.00 \text{ g/mol} = 48.00 \text{ g/mol}$$ (for O)

1. Sum the contributions of each element to find the molecular mass of Na2CO3

$$45.98 \text{ g/mol} + 12.01 \text{ g/mol} + 48.00 \text{ g/mol} = 105.99 \text{ g/mol}$$

The final answer is 105.99 g/mol